Evaluate.
10 3/4 plus 8 3/4 subtract 6 1/2

Answer:

Cost for each pound of jelly beans:  $2.75

Cost for each pound of almonds:  $3.75

Step-by-step explanation:

Let J be the cost of one pound of jelly beans.

Let A be the cost of one pound of almonds.

Using the given information, we can create a system of equations.

Given 3 pounds of jelly beans and 5 pounds of almonds cost $27:

\(\implies 3J + 5A = 27\)

Given 9 pounds of jelly beans and 7 pounds of almonds cost $51:

\(\implies 9J + 7A = 51\)

Therefore, the system of equations is:

\(\begin{cases}3J+5A=27\\9J+7A=51\end{cases}\)

To solve the system of equations, multiply the first equation by 3 to create a third equation:

\(3J \cdot 3+5A \cdot 3=27 \cdot 3\)

\(9J+15A=81\)

Subtract the second equation from the third equation to eliminate the J term.

\(\begin{array}{crcrcl}&9J & + & 15A & = & 81\\\vphantom{\dfrac12}- & (9J & + & 7A & = & 51)\\\cline{2-6}\vphantom{\dfrac12} &&&8A&=&30\end{array}\)

Solve the equation for A by dividing both sides by 8:

\(\dfrac{8A}{8}=\dfrac{30}{8}\)

\(A=3.75\)

Therefore, the cost of one pound of almonds is $3.75.

Now that we know the cost of one pound of almonds, we can substitute this value into one of the original equations to solve for J.

Using the first equation:

\(3J+5(3.75)=27\)

\(3J+18.75=27\)

\(3J+18.75-18/75=27-18.75\)

\(3J=8.25\)

\(\dfrac{3J}{3}=\dfrac{8.25}{3}\)

\(J=2.75\)

Therefore, the cost of one pound of jelly beans is $2.75.

Using relations in a right triangle, the secant of angle θ is given by:

D. 5/4.

The relations in a right triangle are given as follows:

Using the Pythagorean Theorem, the hypotenuse of the triangle is given as follows:

h² = 9² + 12²

h = sqrt(9² + 12²)

h = 15.

The secant of an angle is 1 divided by the cosine, hence:

Which means that option D is correct.

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Option b is likely to give the teachers the most accurate data for deciding the end of the year field trip for the 8th graders.

In statistics, a sample is a subset of individuals or observations taken from a larger population. The sample is used to gain insights and make inferences about the population from which it was drawn. Samples are often used when it is not feasible or practical to gather data from every individual in a population, which could be too large or too time-consuming to survey.

Here,

A random sample of 8th graders are directly affected by the decision and are therefore the most appropriate group to survey. Asking a random sample of 6th, 7th, and 8th graders (option a) would include students who are not directly affected by the decision, and may not have the same level of understanding or investment in the trip. Asking the football team (option c) would likely provide biased results, as the football team may have different preferences and priorities than the wider 8th grade class. Asking all the teachers (option d) may also provide biased results, as teachers may have different opinions and preferences than the students. Ultimately, the most accurate data will come from surveying the group of students directly affected by the decision.

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Answer:

4 and -7

Step-by-step explanation:

a coefficient is a number that is being multiplied with a variable (ex:5a) in this case the coefficients are 4 and -7

Answer:

4 and -7

Step-by-step explanation:

the coefficient is the number in front of the letter.

Step-by-step explanation:

1. 22+5x+3=90

2.3+5x+82=180

3. 89=6x+5

4. 4x+3= 43

you can solve them luv

Answer:

6 1/3

Step-by-step explanation:

You just have to see how many times it goes into it

Given that the population can be represented by the equation;

The current population (Initial population) is the population at time t=0;

Substituting;

Therefore, the current population of the habitat is;

The long term population would be the population as t tends to infinity;

Therefore, the long term population of the habitat is;

Answer: The quotient is 3y² + 2y - 1.

Step-by-step explanation:

You can use long division to solve this expression by setting the dividend under the roof and the divisor outside as you would normally do when dividing numbers.

1) Look at the first term of the dividend, 15y³, and the first term of the divisor, 5y. Determine what value multiplied by 5y would give you 15y³. The answer is 3y², and given the number, you multiply it by the WHOLE divisor.

3y²(5y + 6) = 15y³ + 18y² <-- subtract this from the dividend.

2) Continue this process and make sure to drag down the next term for each new value you form after subtracting. Keep in mind of any negative values! When you reach up to -5y, determine what value multiplied by 5y would give you the value of -5y, which would be -1.

3) You should be left with a remainder of 0, leaving you with a quotient of 3y² + 2y - 1.

Answer:

Step-by-step explanation:

"To find the probability that a randomly selected point within the circle falls in the red shaded square, you can compare the areas of the circle and the square. The area of the circle is pi times the radius squared, which is pi times 8 squared, or 64pi. The area of the square is the length of one side squared, which is (4 times the square root of 2) squared, or 32. Therefore, the probability is 32/64pi, or approximately 0.159. Does that help?"

Answer:

29.8

Step-by-step explanation:

\(64.3 - 3 \times 23 \div 2 \\ \\ = 64.3 - 3 \times 11.5 \\ \\ = 64.3 - 34.5 \\ \\ = 29.8\)

Hey there!

64.3 - 3 * 23 ÷ 2
[3 * 23 = 69]

= 64.3 - 69/2

= 64.3 - 34.5

= 29.8

Therefore, your answer is: 29.8

Good luck on your assignment & enjoy day!

~Amphitrite1040:)

The only automorphism of a well-ordered set is the identity.

To prove this statement, we need to show that any automorphism of a well-ordered set must be the identity function. An automorphism is a bijective function that preserves the order structure of the set.

Assume we have a well-ordered set (W, ≤), where W is the set and ≤ is the order relation.

Let f: W → W be an automorphism of the set.

We aim to prove that f is the identity function, i.e., f(x) = x for all x ∈ W.

Suppose, for contradiction, that there exists an element a ∈ W such that f(a) ≠ a.

Since f is a bijective function, there must exist some b ∈ W such that f(b) = a.

Since (W, ≤) is well-ordered, there is a least element c in the set {x ∈ W : f(x) ≠ x}.

Let d = f(c). Since f is an automorphism, f(c) ≠ c, and thus d ≠ c.

Since (W, ≤) is well-ordered, there is a least element e in the set {x ∈ W : f(x) = d}.

Consider the element f(e). Since f is a bijective function, there must exist some f^{-1}(f(e)) = e' ∈ W such that f(e') = f(e) = d.

By the definition of automorphism, f(f^{-1}(y)) = y for all y ∈ W. Applying this property to e', we have f(f^{-1}(f(e'))) = f(e') = d.

However, f^{-1}(f(e')) = e' ≠ c, and thus f(e') ≠ d. This contradicts the fact that e is the least element in the set {x ∈ W : f(x) = d}.

Therefore, our assumption that there exists an element a such that f(a) ≠ a is false.

Since we assumed f(a) ≠ a for arbitrary a ∈ W, it follows that f(x) = x for all x ∈ W.

Hence, the only automorphism of a well-ordered set is the identity function.

Therefore, we have proven that the only automorphism of a well-ordered set is the identity function.

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In the quadrilateral ABCD and LBNM the corresponding angles and line segments are as follow,

∠A = ∠L, ∠D =∠M , ∠C = ∠N , and

AB = LB , CD = NM ,  DA = ML.

Quadrilateral ABCD rotates 180 degrees around point B,

New quadrilateral formed named LBMN

The corresponding angle after rotation of 180 degrees around B is equals to,

B remain at same position.

A rotates and point L take the position of A.

D rotates and point M take the position of D.

C rotates and point N take the position of C.

Corresponding angle to A is angle L.

Corresponding angle to D is angle M.

Corresponding angle to C is angle N.

Similarly corresponding segments are of ABCD and LBNM are

Line segment AB corresponds to line segment LB.

Line segment CD corresponds to line segment NM

Line segment DA corresponds to line segment ML.

Therefore, in the quadrilateral the corresponding angles and line segments are ∠A = ∠L, ∠D =∠M , ∠C = ∠N , AB = LB , CD = NM , and DA = ML.

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Answer:r=3sinθ/4cos^2 θ.

Step-by-step explanation:

To convert to polar coordinates, we use the relationships

xy=rcosθ=rsinθ.

Substituting these into the given equation, we find

3y3rsinθ3rsinθ=4x2=4(rcosθ)2=4r2cos2θ

Divide each side of the equation by the common factor r to get

Answer:

1305 female students

Step-by-step explanation:

Total no. of students = 2900

Percentage of students male = 55%

No. of students male = 55% of 2900

                                 = 55/100*2900

                                 = 1595

No. of female students = 2900 - 1595 = 1305

Answer:

1314

Step-by-step explanation:

First I found the number of male students

\(\frac{x}{2920} =\frac{55}{100} \\\\160600=100x\\1606=x\)

Then I subtracted the number of male students from the number of total students

\(2920-1606=1314\)

Answer:

m<GED = 126°

Step-by-step explanation:

The base angles of an isosceles are equal.

This implies that:

m<FEG = m<F

Thus:

m<F = ½(180° - 72°)

m<F = ½(108°)

m<F = 54°

Based on the exterior angle theorem, we have the following equation:

m<F + m<FGE = m<GED

Substitute

54° + 72° = m<GED

126° = m<GED

m<GED = 126°

The statement that most accurately describes patterns of Irish immigration in the mid-19th century is: its peaked in approximately 1851. The Option D is correct.

Irish immigration to the United States in the mid-19th century was characterized by several factors:

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(a) To compute the experimental probability of rolling a 1 or 6 from Latoya's results, we need to determine the number of times a 1 or 6 was rolled and divide it by the total number of rolls Latoya made.

Let's assume that Latoya rolled the dice 100 times and obtained 20 1's and 10 6's. The total number of successful outcomes (rolling a 1 or 6) is 20 + 10 = 30.

Therefore, the experimental probability of rolling a 1 or 6 is 30/100 = 0.3 or 30%.

(b) Assuming the cube is fair, the theoretical probability of rolling a 1 or 6 can be determined by considering the favorable outcomes (rolling a 1 or 6) divided by the total possible outcomes (rolling any number from 1 to 6).

Since there are two favorable outcomes (1 and 6) out of six possible outcomes (1, 2, 3, 4, 5, 6), the theoretical probability is 2/6 = 1/3 or approximately 0.3333.

(c) The correct statement is B. As the number of rolls increases, we expect the experimental and theoretical probabilities to become closer, though they might not be equal. This is due to the law of large numbers, which states that as more trials are conducted, the experimental probability tends to converge towards the theoretical probability. However, it is not necessary for them to be exactly equal. Random variations can cause some discrepancy, but with a larger number of rolls, the experimental probability should approach the theoretical probability more closely.

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The only true statement about the domain of the given function is:

B. f(x) is negative for all x < -5

The domain of a function is defined as the set of values that we can possibly plug into our function. This set is the x values in a function such as f(x).

Now, we are given the function as:

f(x) = \(\frac{2}{x^{2} } + 3x - 10\)

When x < -5, we have:

f(-4) = \(\frac{2}{(-4)^{2} } + 3(-4) - 10\)

f(-4) = -21.875

This suggests that for all values below x = -5 will result in negative values

When x > 2

f(3) = \(\frac{2}{3^{2} } + 3(3) - 10\)

f(3) = -0.78

Thus, it will get positive for higher values but it can also be negative as seen here.

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The effect that does NOT relate to one's driving ability is breathalyzer test results indicating a high BAC. Option B.

While the breathalyzer test measures the blood alcohol concentration (BAC), it is a method used to determine the level of alcohol in a person's system and is commonly used in assessing impairment for driving under the influence.

Therefore, it directly relates to one's driving ability and is not excluded from the effects on driving ability caused by a BAC of .2 percent.

On the other hand, options, lack of coordination, impaired gross motor skills, and impaired reactions all directly relate to one's driving ability as they affect the physical and cognitive abilities necessary for safe and efficient driving.

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Answer:

It's wrong.  The correct answer is -3 1/8x + 6 3/10

Step-by-step explanation:

You don't need to do the first two numbers of each equation but you want to consider the last part of the equation since each of them is different.  Convert 2 1/5 to 2 2/10 to make it easier.  Because you are subtracting two negative numbers, they will actually add so 2 2/10 + 4 1/10 equals 6 3/10 which makes the second option applicable.

Answer:

-2 , -1,  2,  5

Step-by-step explanation:

Answer:

-2,-1,2,5

Step-by-step explanation:

Answer:

2.19kg

Step-by-step explanation:

10.95/5= 2.19 kg per container

2.19 kg per container

given,

5 container contains 10.95/5

= 2.19 kg

therefor, in one container there is 2.19 kg

Answer:

answer is 26

Step-by-step explanation:

1%= 0.42

0.42 x 38 = 15.96

round to 16

42-16=26

Answer: 62% of the class was absent on that day.

Step-by-step explanation: 100% - 38% = 62%

Step-by-step explanation:

s1 = 5

s2 = s1 × -2 = 5×-2 = -10

s3 = s2 × -2 = -10 × -2 = 20

...

now, we could do all that manually.

but there is also a formula for geometric sequence.

in fact, there are 2 - one for finite and one for infinite sequences.

and I was not completely honest, each of these 2 had some sub-forms depending on the size of the multiplier or ratio.

since we need the sum of the first 5 terms, which of the 2 do you think we need ?

of course, finite, because 5 is a normal number we can "touch". it is not infinity.

so, the formulas for finite sums of geometric sequences are :

if |r| < 1, Sn = a(1 - r^n)/(1 - r)

if |r| > 1, Sn = a(r^n - 1)/(r - 1)

if r = 1, Sn = na

if r = -1, then Sn = a or 0 depending on if n is odd or even.

the sequence is in general

s1 = a

sn = sn-1 × r

in our case a = 5, r = -2.

so, what form of the formula do we need ?

|-2| = 2, and 2 > 1, so ...

S5 = 5(-2^5 ‐ 1)/(-2 - 1) = 5(-32 - 1)/-3 = 5×-33/-3 =

= 5 × 11 = 55

quick check, as the 5 terms are

5

-10

20

-40

80

and their sum is : 55

correct !

Based on the limited information provided, it is not possible to definitively determine the type of economy in Country A. More specific details and factors would be necessary to make a conclusive determination.

9514 1404 393

Answer:

  (c)  1/(36·a^4·b^10)

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

  a^-1 = 1/a

__

  \(\left(\dfrac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}\right)^{-1}=\dfrac{(3a^5b)^{-2}}{(2a^{-3}b^4)^2}=\dfrac{3^{-2}a^{-10}b^{-2}}{2^2a^{-6}b^8}=\dfrac{1}{3^22^2}a^{-10-(-6)}b^{-2-8}\\\\=\boxed{\dfrac{1}{36a^4b^{10}}}\)

Answer: There are 52 cards in a standard deck and half of them, 26 in all, are red.

Suppose that you are drawing 4 cards without replacement from a thoroughly shuffled deck. You have 26 cards choose 4 over 52 choose 4.

∴  P(pulling 4 cards from deck) =  (264)(524)

ANSWER

10i - 13j

EXPLANATION

The unit vectors are: