Extra questions Book Ch. 2.8 Q1: An object is subject to an acceleration of the form: a = 2.00-6t2 m/s². Knowing that the velocity and the position at time t = 0s are respectively 12 m/s and 40 m: a. Find the equation of motion for the velocity. b. Find the equation of motion for the position. c. Find the position after 3 s.

Answers

Answer 1

a. The equation of motion for the velocity is v = 2t - 2t³ + 12 m/s.

b. The equation of motion for the position is x = t² - (2/4)t⁴ + 12t + 40 m.

c. The position after 3 s is x = 43 m.

a. To find the equation of motion for velocity, we integrate the given acceleration with respect to time (t). The integral of a with respect to t gives the velocity (v). Integrating 2.00-6t² with respect to t, we get:

v = ∫(2.00 - 6t²) dt

  = 2.00t - 2t³ + C

Given that the velocity at t = 0s is 12 m/s, we can substitute the values into the equation to find the constant C:

12 = 2.00(0) - 2(0)³ + C

C = 12

Therefore, the equation of motion for velocity is v = 2t - 2t³ + 12 m/s.

b. To find the equation of motion for position, we integrate the velocity equation with respect to t. Integrating 2t - 2t³ + 12 with respect to t, we get:

x = ∫(2t - 2t³ + 12) dt

  = t² - (2/4)t⁴ + 12t + D

Given that the position at t = 0s is 40 m, we can substitute the values into the equation to find the constant D:

40 = (0)² - (2/4)(0)⁴ + 12(0) + D

D = 40

Therefore, the equation of motion for position is x = t² - (2/4)t⁴ + 12t + 40 m.

c. To find the position after 3 s, we substitute t = 3 into the position equation:

x = (3)² - (2/4)(3)⁴ + 12(3) + 40

x = 9 - (2/4)(81) + 36 + 40

x = 9 - 40.5 + 36 + 40

x = 44.5 - 4.5

x = 43

Therefore, the position after 3 s is x = 43 m.

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Related Questions

A rightward force of 302 N is applied to a 28.6-kg crate to accelerate it across the floor. The force of friction between the crate and the floor is 210. Determine the net force acting on the create. Determine the acceleration of the crate.

Answers

Answer:

Net Force is 92N and acceleration is 3.22 m/s/s

Explanation:

Fnet = Net force

FR = Force of friction

m = mass

a = acceleration

Fnet = ma

Fnet = F - FR = 302 - 210 = 92N

F - FR = ma

302 - 210 = (28.6)a

a = 3.22 m/s/s

solve for the BMI weight 58kg Height 1.61​

Answers

Answer:

Explanation:

BMI= weight/(height × height)          ; weight in kilogram and height in metter

     = 58kg / (1.61m  × 1.61m )

     = (58/ 2.5921) kg/\(m^{2}\)

     = 22.375  kg/\(m^{2}\)

     ≈ 22.4 kg/\(m^{2}\)


Santa Claus entered the North Pole Annual Elf Throwing Competition. He fired his elf with a
horizontal speed of 25 m/s from the top of an iceberg of height 110 m. What was the elf's range and
time of flight?

Answers

Answer:

To find the range and time of flight of the elf, we need to use the equations of motion under the influence of gravity. The range is the horizontal distance covered by the elf and the time of flight is the total time that the elf is in the air.

The initial velocity of the elf in the x-direction (horizontal direction) is 25 m/s and the initial velocity in the y-direction (vertical direction) is 0 m/s, since the elf is thrown horizontally from the top of the iceberg. The acceleration due to gravity is -9.8 m/s^2 in the downward direction.

Using these values, we can find the range and time of flight of the elf using the following equations:

Range:

x = x0 + v0x*t

Where x is the range, x0 is the initial position (in this case, x0 is 0 since the elf is thrown from the top of the iceberg), v0x is the initial velocity in the x-direction (25 m/s), and t is the time of flight.

Time of flight:

y = y0 + v0y*t + (1/2)at^2

Where y is the vertical position of the elf, y0 is the initial position (in this case, y0 is 110 m since the elf is thrown from the top of the iceberg), v0y is the initial velocity in the y-direction (0 m/s), a is the acceleration due to gravity (-9.8 m/s^2), and t is the time of flight.

We can solve for t in the second equation and then substitute it into the first equation to find the range.

Solving for t in the second equation:

t = (-v0y +/- sqrt(v0y^2 - 4a(y0 - y))) / (2*a)

Where y is the vertical position of the elf (0 m since the elf lands on the ground), y0 is the initial position (110 m), v0y is the initial velocity in the y-direction (0 m/s), and a is the acceleration due to gravity (-9.8 m/s^2).

Substituting this expression for t into the first equation:

x = x0 + v0x*((-v0y +/- sqrt(v0y^2 - 4a(y0 - y))) / (2*a))

Plugging in the values:

x = 0 + 25*((-0 + sqrt(0^2 - 4*(-9.8)(110))) / (2(-9.8)))

Simplifying:

x = 25*(sqrt(5832) / -19.6)

x = 25*(sqrt(5832) / -19.6)

x = (25*74.6) / -19.6

x = 1865.4 / -19.6

x = -95.1 m

So, the range of the elf is approximately -95.1 m. This means that the elf lands 95.1 m to the left of the starting point (the top of the iceberg).

The time of flight can be found by solving for t in the second equation:

t = (-v0y +/- sqrt(v0y^2 - 4a(y0 - y))) / (2*a)

Plugging in the values:

t =

Explanation:

10.A person drives 6 km in a car and sees a sign for Burger King. He turns around
and drives back 1 km to get some food.
a. What is his distance?
b. Displacement?

Answers

The distance covered by man is 7 km and displacement will be 5 km.

What are distance and displacement?

Distance is defined as the total path covered between two points. It is a scalar quantity.

Displacement is defined as the shortest path between two points. It is a vector quantity.

Distance is either always greater or equal to displacement. The distance can never be smaller than displacement.

According to the question, a person drives 6 km in the car, and he comes back 1 km to get some food means the distance traveled by him is 7 km.

However, the distance travelled will only be 5 kilometers if he travels straight to Burger King. Displacement is, after all, the shortest route between two places.

Hence, the distance will be 7 km and displacement will be 5 km respectively.

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Kory was on the porch when a loud sound caught his attention. Looking up, he saw a red car spinning across the intersection and a white car stopped in the intersection. He knew the typical sequence of events for a car collision involved two vehicles moving at speed. As he tried to make sense of the scene, he filled in missing details that he had not actually observed. This will likely result in:

Answers

The information illustrates that this will likely result in schema distortion.

What is schema?

It should be noted that schema simply means a mental model of an object that includes knowledge, beliefs, and expectations.

In this case, the information illustrates that this will likely result in schema distortion. This led to the missing details.

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QİYour pair of boots has a mass of 850g if each boot has
exactly the same mass what is the weight of each boot?

Answers

Answer:

It is 4,250 N

Explanation:

Mass of each boot:

\( = \frac{1}{2} \times 850 \\ \\ = 425 \: g\)

Weight:

\({ \sf{weight = mass \times acceleration}} \\ { \sf{weight = 425 \times 10}} \\ { \sf{weight = 4250 \: newtons}}\)

A sprinter Sarting from rest reaches a top speed of 10 m/s im 5 s calculate the average acceleration

Answers

Answer:

2 м/с

Explanation:

Скорость надо разделить на время, за которое она достигается (10/5=2)

a horizental force of 310n exerted on 2.0kg ball as it rotates ( at arm's length) uniformly in horizental circle of radius 0.0.90m calculate the speed of the ball ​

Answers

Answer:

v=11.8m/s

Explanation:

speed of the ball

Force=mass*centripetal acceleration

Centripetal acceleration= V2/r

F=M*V2/r

Data

F=310N

M=2.0kg

r=0.90m

v=?

310N=(2.0kg)*V2/0.90m

cross multiply

279Nm=(2.0kg)V2

V2= 279Nm/2.0kg

V2=139.5Nm/kg

apply square root both sides

√V2=√139.5

V=11.8m/s

1=3.78 ?=1.81 1=−0.04 2=−0.59 An aircraft performs a pullout manoeuvre at cruise with H n


=10%, pulling an exces normal acceleration of 2.0 g a) Calculate the change in elevator angle [in rad] relative to the level flight condition. b) Calculate the location of manoeuvre point [m] c) Calculate the manoeuvre margin for the controls-fixed configuration.

Answers

Given that, Hn′​=10%, pulling an excess normal acceleration of 2.0g1=3.782=1.811=−0.042=−0.59

To calculate the change in elevator angle, we need to use the formula:

Δθe= a/hn′ ∆θe = (2*9.8)/(0.1*9.8)

Δθe = 20 radb)

To calculate the location of maneuver point, we need to use the formula:

Pm= (W/S) * (V^2/2g) * (hn′ / n-1)

Pm = (W/S) * (V^2/2g) * (hn′ / n-1)

Pm = (60500/122) * (230^2/2*9.81) * (0.1 / 6.73-1)

Pm ≈ 256.7 mc)

To calculate the maneuver margin for the controls-fixed configuration, we need to use the formula: MM = θe / (π/2-θe) MM = 20 / (π/2-20)MM ≈ 6.8

Hence,The change in elevator angle is 20 rad. The location of the maneuver point is 256.7 m. The maneuver margin for the controls-fixed configuration is 6.8.

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as you increase the temperature of a gas in a sealed, rigid container, what happens to the density of the gas? would the results be the same if you did the same experi- ment in a container with a piston at constant pressure? explain.

Answers

When the temperature of a gas is raised in a tightly sealed, rigid container, the gas's density will not change. In contrast, when the piston is kept at the same temperature in a container, density decreases.

Charles Law: At constant pressure, the volume occupied by the fixed amount of gas is directly proportional to its absolute temperature.

A gas's mass per unit volume is its density. Volume is directly proportional to temperature, as stated by Charles's law. Volume increases as temperature rises. However, in a rigid container, the gas's mass is unaffected by changes in temperature and volume. As a result, even as the temperature rises, density does not change.

The pressure in a container with a piston stays the same. As a result, according to Charles' law, gas density decreases as temperature rises during heating.

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Identify the primary effect of each situation on capillary forces. Choose one for each of the following.
a. Increasing the surface tension of the liquid
b. Decreasing the contact angle between the liquid and solid surface
c. Increasing the viscosity of the liquid
d. Decreasing the temperature of the liquid

Answers

The primary effect of increasing the surface tension of the liquid is to increase the capillary force. Capillary forces arise due to the combined effects of adhesion and cohesion

When the surface tension of the liquid increases, the capillary rise will increase. It is because the increase in surface tension leads to an increase in the force that pulls the liquid upwards in a tube. is as follows;If you place a capillary tube in a beaker filled with water, the water surface inside the tube rises slightly higher than the level outside the tube.

This rise in water level is called capillary rise. The capillary rise is caused by the attraction between the molecules of the water and the molecules of the glass tube.This attraction is called capillary force or capillary action. The capillary force is due to the combined effect of adhesive and cohesive forces. The adhesive force is the attraction between the molecules of the liquid and the molecules of the solid surface, while the cohesive force is the attraction between the molecules of the liquid.

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The figure below shows the position of an object as a function of time. At which times is the particle moving to the right?

The figure below shows the position of an object as a function of time. At which times is the particle

Answers

Assuming that A represents movement to the right and -A movement to the left, we would have that the times at which the particle ismoving to the rigth are:

t = 0, 4, 8

A 235 kg object and a 1. 37×1012 kg are located 2. 59×104 m away from each other. What is the force due to gravity between the two objects?

Answers

The force due to gravity between the two objects is 3.2 x 10⁻⁵ N.

Gravity or attraction pulls objects with mass together. We often think about Earth's gravity. This force locks the body to the ground. However, all objects with mass exert gravitational force on all other objects with mass.

Solution:

The gravitational force of attraction between the two objects is:

\(F=G\frac{m1m2}{r^{2} }\)

where,

F = gravitational force = ?

Gravitational Constant (G)= 6.67 x 10⁻¹¹ Nm²/kg²

Mass of object 1 ()m1= 235 kg

Mass of object 2(m2) = 1.37 x 10¹² kg

Distance between objects(r) = 2.59 x 10⁴ m

Therefore,

\(F=6.67*10^{-11} \frac{235*1.37*10^{12} }{(2.59*10^{4}) ^{2} }\)

F = 3.2 x 10⁻⁵ N.

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Please help me with this, I will mark as Brianalist if right...​

Please help me with this, I will mark as Brianalist if right...

Answers

Explanation:

To me, it's option 1

Newton third law states that Every action produces an equal and opposite reaction. Hence, given the fact that the engine is on, it should be producing a constant force every time so, the speed should be constant as the force propelling it is the same

What does gravity, electricity, and magnesium have in common?

Answers

Answer:

magnesium (Mg), chemical element, one of the alkaline-earth metals of Group 2 (IIa) of the periodic table, and the lightest structural metal. Its compounds are widely used in construction and medicine, and magnesium is one of the elements essential to all cellular life.

Explanation:

hope it helps

A car is traveling in a counterclockwise circle. At the moment the car is at the north end of the circle, it is slowing down. At the same moment, the acceleration vector points to the

Answers

At the moment the car is at the north end of the circle and slowing down, the acceleration vector points to the south.

When an object moves in a circular path at a constant speed, it is still accelerating because its direction is changing. This acceleration is called centripetal acceleration and it always points towards the center of the circle. When the car is slowing down at the north end of the circle, its velocity vector is still pointing towards the east or west direction (tangent to the circle). Therefore, the acceleration vector must be pointing towards the center of the circle, which is south of the car. This is because the centripetal acceleration vector always points towards the center of the circle and is perpendicular to the velocity vector.

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The ice and steam points of an ungraduated thermometer are found to be 192mm apart. Calculate the length of the thermometric liquid above the ice point which will corresond to a temperature of 75 degree Celsius ​

Answers

Answer:

To find the length of the thermometric liquid above the ice point that corresponds to a temperature of 75 degrees Celsius, we need to know the size of the temperature interval between the ice point and the steam point, as well as the size of the temperature interval between the ice point and 75 degrees Celsius.

The size of the temperature interval between the ice point and the steam point can be calculated using the formula:

T = (S - I)/R

Where T is the size of the temperature interval, S is the length of the thermometric liquid above the steam point, I is the length of the thermometric liquid above the ice point, and R is the size of the temperature interval per unit length of the thermometric liquid.

Since the ice and steam points of the thermometer are 192mm apart, we know that S - I = 192mm. We also need to know the value of R in order to calculate T.

Once we know the size of the temperature interval between the ice point and the steam point, we can use this value to calculate the size of the temperature interval between the ice point and 75 degrees Celsius.

Let's assume that the size of the temperature interval per unit length of the thermometric liquid, R, is 0.5 degrees Celsius per millimeter. With this value of R, the size of the temperature interval between the ice point and the steam point can be calculated as follows:

T = (192mm - 0mm)/0.5 degrees Celsius/mm = 384 degrees Celsius

Now that we know the size of the temperature interval between the ice point and the steam point, we can use this value to calculate the size of the temperature interval between the ice point and 75 degrees Celsius.

The size of the temperature interval between the ice point and 75 degrees Celsius is 75 degrees Celsius - 0 degrees Celsius = 75 degrees Celsius.

We can now use the size of the temperature interval between the ice point and 75 degrees Celsius, along with the size of the temperature interval per unit length of the thermometric liquid, R, to calculate the length of the thermometric liquid above the ice point that corresponds to a temperature of 75 degrees Celsius:

I = (75 degrees Celsius)/(0.5 degrees Celsius/mm) = 150mm

Thus, the length of the thermometric liquid above the ice point that corresponds to a temperature of 75 degrees Celsius is 150mm.

PLEASE HELP, i really need the help because i dont understand

PLEASE HELP, i really need the help because i dont understand

Answers

The y-component of the vector is 4.97 m.

What is a vector?

A vector is a quantity that has both magnitude and direction.

To calculate the y-component of the vector in the diagram above, we use the formula below.

Formula:

Y = Hcos∅.......... Equation 1

From the question,

Given:

H = 22.3 m∅ = 77.1°

Substitute these values into equation 1

Y = 22.3(cos77.1)Y = 22.3×0.223Y = 4.97 m.

Hence, the y-component of the vector is 4.97 m.

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How to find the acceleration?

Answers

Answer:

speed/time

Explanation:

Answer:

a= (Vf - Vi)

         t

To find acceleration (a) you need to subtract the finale velocity (Vf) minus the initial velocity (vi) divided by time (t) as shown in the equation above.

Describe the method of obtaining pure drinking water from the sea water with a labelled diagram.​

( plzzzz answer correctly )

Answers

Answer:

Desalination is a process that takes away mineral components from saline water.

Explanation:

u welcome

Does earths gravitational force field act on objects that aren’t touching earths surface?

( Explanation needed ASAP NEEDED

Answers

Answer:

no the earth gravitational force field

Answer:

yes, it acts on everything within the earth

Explanation:

A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s,
how high is the cliff, if it took 12 s for the ball to reach the ground?

Answers

By using the equation speed = distance/time we can solve for distance. The speed is 4 m/s and the time is 12 seconds. We need to rearrange the equation to Speed * Time = distance. 4(12) = 48; 48 = distance. The cliff is 48 meters high.

A hydrochloric (hcl) solution has a molar concentration of 0. 0045 m, calculate the and ph of the solution. Remember that kw= 1. 0x10-14m2.

Answers

To calculate the pH of a hydrochloric acid solution with a molar concentration of 0.0045 M, we can use the following formula:

How to calculate pH?

pH = -log[H+]

where [H+] is the concentration of hydrogen ions in the solution, which can be calculated from the dissociation of HCl:

HCl → H+ + Cl-

The molar concentration of H+ is equal to the molar concentration of HCl, which is 0.0045 M.

[H+] = 0.0045 M

Substituting this value into the pH formula, we get:

pH = -log(0.0045) ≈ 2.35

To calculate the pOH of the solution, we can use the relationship:

pH + pOH = 14

pOH = 14 - pH ≈ 11.65

Finally, we can use the relationship between pH, pOH, and the ion product constant of water (Kw) to calculate the concentration of hydroxide ions ([OH-]) in the solution:

Kw = [H+][OH-] = 1.0 × 10^-14 M^2

[OH-] = Kw / [H+] = (1.0 × 10^-14) / (0.0045) ≈ 2.22 × 10^-12 M

Therefore, the pH of the hydrochloric acid solution is approximately 2.35, the pOH is approximately 11.65, and the concentration of hydroxide ions is approximately 2.22 × 10^-12 M.

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The pH of the hydrochloric acid solution is approximately 2.35, the pOH is approximately 11.65, and the concentration of hydroxide ions is approximately \(2.22 \times 10^{-12} M\).

How to calculate pH?

pH = -log[H+]

where [H+] is the concentration of hydrogen ions in the solution, which can be calculated from the dissociation of HCl:

HCl → H+ + Cl-

The molar concentration of H+ is equal to the molar concentration of HCl, which is 0.0045 M.

[H+] = 0.0045 M

Substituting this value into the pH formula, we get:

pH = -log(0.0045) ≈ 2.35

To calculate the pOH of the solution, we can use the relationship:

pH + pOH = 14

pOH = 14 - pH ≈ 11.65

Finally, we can use the relationship between pH, pOH, and the ion product constant of water (Kw) to calculate the concentration of hydroxide ions ([OH-]) in the solution:

\(Kw = [H+][OH-] = 1.0 \times 10^{-14} M^2\\[OH-] = Kw / [H+] = (1.0 \times 10^{-14}) / (0.0045) ≈ 2.22 \times 10^{-12} M\)

Therefore, the pH of the hydrochloric acid solution is approximately 2.35, the pOH is approximately 11.65, and the concentration of hydroxide ions is approximately \(2.22 \times 10^{-12} M\).

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Writing the Lab Report


Now you will use your answers from the questions above to write your lab report. Follow the directions below.

Section I: Experimental Overview


Use your answers from questions 1–3 as the basis for the first section of your lab report. This section provides your reader with background information about why you conducted this experiment and how it was completed. Outline the steps of the procedure in full sentences. It also provides potential answers (your hypothesis/es) relative to what you expected the experiment to demonstrate. This section should be 1–3 paragraphs in length.


This laboratory experiment focuses on ….

Section II: Data and Observations
Use your answers from questions 4–5 as the basis for the second section of your lab report. This section provides your reader with the data from the experiment, in a summarized and concise way. No paragraphs are required for this section, but you do need to include the key data and observations from which you will generate your analysis and discussion. This section is objective.

Section III: Analysis and Discussion
Use your answers from questions 6–8 as the basis for the third section of your lab report. This section provides your reader with your interpretation of the data set. You will also give an example of any calculations or formulas you used to analyze your data. Also, you will want to include any graphs that you made and interpret them for the reader.
If you did construct graphs, your Student Guide included information on which graphs to construct. Graphs should have the following:

a. Appropriate titles
b. Appropriate labels for each axis
c. Appropriate scales for each axis
d. Correct units for the data

Complete a rough sketch of each graph. Explain in one or two sentences what trend the reader should observe in each of your graphs.
Mention any problems, unusual or unexpected data, or other factors with the experiment here, and suggest possible causes. This section can be somewhat subjective, unlike Section II, because you are free to include your personal interpretations or even speculation if it adds constructive, reasonable insight to the discussion.
This section is variable in length, and should likely be the longest part of your report.

Section IV: Conclusions
Use your answers from questions 9-11 as the basis for the fourth section of your lab report. In this section you will summarize the outcome of the experiment, and discuss how the original hypothesis(es) was (were) either supported or refuted. Use logic and reason in explaining your statements, and be sure to refer to specific data from your experiment that supports your argument.

This section also demonstrates your understanding of the experiment, through your ability to offer constructive criticism about its design and make suggestions for future experimentation. There are always ways that experiments can be improved. Now that you are a veteran of this experiment and have experience with the procedure, offer some advice to the next scientist about what you suggest and why.

This section should be 1–2 paragraphs long.

Answers

The steps to follow are;

1) Explain the purpose of the experiment or the scientific principle that you will investigate.

You should just need one or two sentences for this.

2) Tell what you know about the scientific notion.

Simple labs may accomplish this in a paragraph after the learning context statement.

Complex labs may need additional background paragraphs.

This is further explained below.

What is are the required steps?

Generally, The lab's goal, or the scientific concept, procedure, etc., that you will be investigating, should be stated.

You can probably get by with only one or two phrases.

You may begin your laboratory report by saying something like,

In conclusion, provide context for the scientific idea by explaining what you already know about it (the main references you can use are the lab manual, the textbook, lecture notes, and other sources recommended by the lab manual or lab instructor; in more advanced labs you may also be expected to cite the findings of previous scientific studies related to the lab).

This may usually be accomplished in a single paragraph after the first presentation of the lab's learning environment in more straightforward experiments.

However, more paragraphs may be needed to provide enough context for more involved laboratories.

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State your primary mode of transportation and evaluate the energy efficiency of your transportation (in kW-hrs per 100 person-km). All modes of transportation use energy, even walking.

Answers

My primary mode of transportation is a car, and its energy efficiency is typically around 3 kW-hrs per 100 person-km.

As my primary mode of transportation, I rely on a car for commuting and traveling. While cars offer convenience and comfort, they are not the most energy-efficient option. On average, a car consumes approximately 3 kW-hrs of energy per 100 person-km. This energy consumption includes the fuel or electricity required to power the vehicle and accounts for the energy losses during the generation, distribution, and storage processes.

The energy efficiency of a car can vary depending on several factors, including the vehicle's make and model, driving conditions, and driving habits. Factors such as speed, acceleration, and braking can impact fuel consumption and efficiency. Additionally, the type of fuel or power source used by the car influences its energy efficiency. Electric vehicles (EVs) tend to have higher energy efficiency compared to traditional internal combustion engine (ICE) vehicles, as they convert a higher percentage of their energy into forward motion.

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Question 2

Any electricity charged object creates an electric field. Walking across carpet in wool socks can create an electric charge. This

observation is evidence for which characteristics of electrical forces?

They generate electricity by contact.

They can be generated by electricity.

OOO

They can exert a force across a distance.

They are moving due to magnetism.

Answers

Answer:

They generate electricity by contact.

Explanation:

The observation presented by the question above shows an example of electricity generated by the contact, which can also be called triboelectrification. This type of electricity is created when two objects made of different materials come into contact with each other, and that contact is interrupted soon afterwards, as occurs when someone, wearing woolen socks, walks over the carpet.

For triboelectrification to occur, it is necessary that at least one of the objects involved is electrically charged. This object, when in contact with another object, will transfer electrons carrying the neutral object, until the two objects have the same electrical potential. When interrupting the contact between the objects, the two are left with equal loads of energy.

Clancy has set up a pulley system to lift a 1400 n air conditioner 9.1m up. the pulley system is 68% efficient. if clancy has to exert a force of 110 n, how much rope will he have to pull to lift the air conditioner?
170m
13 m
140 m
79 m

Answers

The rope will Clancy have to pull to lift the air conditioner is 170m option (a) is correct.

We are given that,

F₁ = 1400 N

D₁ = 9.1 m

η = 68%;    η = 0.68

F₂ = 110 N

D₂ = ?

If the pulley system is perfectly functional then we can write as,

D₂'  = F₁·D₁  / F₂ = 1400·9.1 / 110 ≈ 115.8 m

If the code for the pulley system is 68% such as,

D₂ = D₂' / η = 115.8 / 0.68 ≈ 170 m

Option (a) is the correct answer since Clancy will need to pull a 170m rope to lift the air conditioner.

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NO LINKS PLEASE HELP The Spring Tide is found during which moon phases?
Question 5 options:

First and Last quarter

Full and New Moon

Waxing and Waning Gibbous

It varies each month

Answers

Answer:

Full and New Moon

Explanation:

How is a controlled variable different from a responding variable?

Answers

Answer:

The answer is a controlled variable stays the same throughout an experiment, but a responding variable changes

Explanation:

just did it on apex

given the atomic number,how would you know the number of protons?

Answers

The number of protons in the nucleus of the atom is equal to the atomic number.

The number of electrons in a neutral atom is equal to the number of protons.
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