Factor the greatest common factor: 12a3b 8a2b2 − 20ab3. 4ab(3a 2ab − 5b2) 4ab(3a2 2ab − 5b2) 4a2b(3a3b − 2a2b2 − 5ab3) 4a2b(3a2 2ab − 5)

It can be inferred that due to the relatively slight difference in electronegativity between carbon and hydrogen, and because of its symmetrical tetrahedral shape, methane CH4 is a nonpolar molecule.

Methane is a colorless, odorless gas that occurs naturally in large quantities and is also a byproduct of some human activities. Methane is the most basic hydrocarbon in the paraffin family and one of the most potent greenhouse gases. It has the molecular formula CH4.

Methane is the second most prevalent anthropogenic GHG after CO2, accounting for approximately 20% of world emissions. Compared to carbon dioxide, methane traps heat in the atmosphere 25 times more effectively.

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Answer:

851 mmHg

Explanation:

Using pressure law equation as follows:

P1/T1= P2/T2

Where;

P1 = initial pressure (mmHg)

V2 = final pressure (mmHg)

P1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

P1 = 760mmHg

P2 = ?

T1 = 20°C = 20 + 273 = 293K

T2 = 55°C = 55 + 273 = 328K

Using P1/T1= P2/T2

760/293 = P2/328

Cross multiply

293 × P2 = 760 × 328

293P2 = 249280

P2 = 249280 ÷ 293

P2 = 850.78

Approximately, P2 = 851 mmHg.

Group B is incorrect,They most likely added too much acid .

Let's check the reaction

\(\\ \tt\hookrightarrow HCl+NaOH=NaCl+H_2O\)

1. B, the energy associated with the motion of an object

2. C, 12.4 g/mL

3. C, 5

1) B) Kinetic energy is energy associated with the motion of an object.

2) B) Density equals mass divided by volume: 1.38 g/mL

3) C) There are 5 significant figures in 20.300

4) A) 80 is the atomic number for mercury on the periodic table.

5) E) The formula for copper (II) sulfate pentahydrate is CuSO4•5H2O

So in summary:

• Kinetic energy is the energy of a moving object due to its motion.

• Density is calculated by dividing an object's mass by its volume.

• Significant figures refer to the known precision of a measurement based on the digits reported.

• Atomic symbols represent elements on the periodic table.

• Chemical formulas use symbols of the elements to show the proportions of atoms in a compound.

word equation: HCl + barium --> barium chloride + hydrogen

formula equation: 2HCl + Ba --> BaCl2 + H2

given: 1.25×10^23 molecules HCl

Find: g BaCl2

given#moleculesSubA × 1molSubA/6.022×10^23 moleculeSubA × #molSubB/#molSubA × g SubB/1molSubB

The mass of barium chloride produced is 21.6 grams.

It is an inorganic compound with the chemical formula BaCl₂.

The equation: HCl + barium --> barium chloride + hydrogen

The  chemical equation : 2HCl + Ba --> BaCl₂ + H₂

Given the  1.25×10²³ molecules HCl

First, we calculate the amount of HCL

Amount of moles of HCl=

(1.25×10²³ molecules × 1 mole)/ 6.023×10²³ atoms

=0.2075 moles.

Then the number of moles is multiplied by the molar mass of barium chloride

208.24 g/mol × 0.2075 = 21.6 grams.

Thus, the mass of barium chloride produced is 21.6 grams.

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Arsenic, hydraulic fracturing, lead, and PFAS present chemical threats to global drinking water supplies in different ways.

Let's discuss each of them in detail:

(a) Arsenic - The origin of arsenic exposure is natural deposits or contamination from agricultural or industrial practices. Human health consequences include skin, lung, liver, and bladder cancers. It can also lead to cardiovascular diseases, skin lesions, and neurodevelopmental effects. Drivers of continued exposure include poor regulation and monitoring. Modern solutions include rainwater harvesting and treatment.

(b) Hydraulic fracturing - Hydraulic fracturing involves using a mixture of chemicals, water, and sand to extract natural gas and oil from shale rock formations. The origin of exposure is contaminated surface and groundwater due to the release of chemicals from fracking fluids and other sources. Human health consequences include skin, eye, and respiratory irritation, headaches, dizziness, and reproductive and developmental problems. Drivers of continued exposure include lack of regulation and poor oversight. Modern solutions include alternative energy sources and regulation of the industry.

(c) Lead - Lead contamination in drinking water can occur due to corrosion of plumbing materials. Human health consequences include neurological damage, developmental delays, anemia, and hypertension. Drivers of continued exposure include aging infrastructure and poor maintenance. Modern solutions include replacing lead service lines, testing for lead levels, and implementing corrosion control.

(d) PFAS - PFAS (per- and polyfluoroalkyl substances) are human-made chemicals used in a variety of consumer and industrial products. They can enter the water supply through wastewater discharges, firefighting foams, and other sources. Human health consequences include developmental effects, immune system damage, cancer, and thyroid hormone disruption. Drivers of continued exposure include the continued use of PFAS in consumer and industrial products. Modern solutions include reducing the use of PFAS in products and treatment methods such as granular activated carbon.

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Explanation:

Orbitals are filled according to the aufbau principle. That is, lower energy orbitals are filled before higher energy orbitals are filled. Therefore, fill each energy level before moving up

Answer:

The second last option is correct.

I think the answer will be:

Sir isaac newton.

Answer : The identity of the substance is gypsum.

Explanation : Given,

Mass of weighing boat = 2.69 g

Mass of unknown pieces including weighing boat = 18.01 g

Initial volume = 25.7 mL

Final volume = 32.3 mL

First we have to calculate the mass of unknown pieces.

Mass of unknown pieces = Mass of unknown pieces including weighing boat - Mass of weighing boat

Mass of unknown pieces = 18.01 g - 2.69 g

Mass of unknown pieces = 15.32 g

Now we have to calculate the volume of unknown pieces.

Volume of unknown pieces = Final volume - Initial volume

Volume of unknown pieces = 32.3 mL - 25.7 mL

Volume of unknown pieces = 6.6 mL

Now we have to calculate the density of unknown pieces.

\(\text{Density of unknown pieces}=\frac{\text{Mass of unknown pieces}}{\text{Volume of unknown pieces}}\)

Now putting all the given values in this formula, we get:

\(\text{Density of unknown pieces}=\frac{15.32g}{6.6mL}\)

\(\text{Density of unknown pieces}=2.32g/mL\)

From the given table we conclude that the unknown piece is gypsum whose density is 2.32 g/mL.

Therefore, the identity of the substance is gypsum.

The material with the density equivalent to the unknown piece has been Gypsum. Thus, the unknown piece has been gypsum.

Density can be defined as the mass of the substance per unit volume.

To calculate the density of the unknown piece, the mass has been calculated as:

Mass of unknown piece = Mass of weighing boat with the unknown piece - Mass of weighing boat

Mass of unknown piece = 18.01 g - 2.69 g

Mass of unknown piece = 15.32 grams.

The volume of the unknown piece can be calculated as:

The volume of unknown piece = Final volume - Initial volume

The volume of the unknown piece = 32.3 mL - 25.7 mL

The volume of the unknown piece = 6.6 mL.

The density can be expressed as:

Density = \(\rm \dfrac{Mass}{Volume}\)

The density of the unknown piece = \(\rm \dfrac{15.32\;g}{6.6\;ml}\)

The density of the unknown piece = 2.32 g/mL.

From the given set of pieces, the material with the density equivalent to the unknown piece has been Gypsum. Thus, the unknown piece has been gypsum.

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Answer:

The chemical elements most likely to form covalent bonds are those that share electrons, such as carbon, as opposed to those that take them from another element to form an ionic bond. In general, they are nonmetals with similar electronegativities.

Explanation:

Answer:a

Explanation:

Answer:

C4H6O4

Explanation:

First, the empirical formula needs to be calculated as follows

- Divide each element mass by its molar mass to convert to moles

C = 40.68/12 = 3.39moles

H = 5.08/1 = 5.08moles

O = 54.24/16 = 3.39moles

Next, we divide each mole value by the smallest (3.39moles)

C = 3.39/3.39 = 1

H = 5.08/3.39 = 1.5

O = 3.39/3.39 = 1

To get the empirical formula of this molecule, we multiply all by 2 to have:

C = 2

H = 3

O = 2

The empirical formula of C,H,O = 2:3:2

That is, C2H3O2

Next, we find the molecular formula as follows:

(C2H3O2)n = 118.1

{12(2) + 1(3) + 16(2)}n = 118.1

24 + 3 + 32 = 118.1

59n = 118.1

n = 118.1/59

n = 2.001

Therefore, the molecular formula is:

(C2H3O2)2

= C4H6O4

The actual yield of the oxygen in the reaction is 4.32 g.

The equation of the reaction is;

Ba(ClO3)2 → BaCl2 + 3O2

Now we have that ;

Number of moles of the barium chlorate is;

Number of moles = mass/Molar mass

= 15 g/304 g/mol

= 0.049 moles

If 1 mole of barium chlorate produced 3 moles of oxygen

0.049 moles of barium chlortae will produce 0.049 * 3/1

= 0.147 moles

Mass of the oxygen produced = 0.147 moles * 32 g/mol

= 4.7 g

Then we have that;

Percent yield = Actual/Theoretical * 100/1

92 = x/4.7 * 100/1

92 * 4.7 = 100x

x = 92 * 4.7/100

x = 4.32 g

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Answer:

it produces amino acids and proteins. It is also needed to make chlorophyll in plants, which is used in photosynthesis to make their food.

As the kb value for a base increases, base strength increases is true statement. The correct answer is A.

The base is stronger the lower the Kb number. Therefore, base strength grows as the Kb value for a base increases.

How readily a base may accept a proton from an acid is shown by its Kb value. The base gains base strength as the Kb value rises because it can receive protons with greater ease. This implies that the base strength grows as the Kb number increases.

Therefore,  if the kb value for a base increases, base strength increases is true statement.

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The mass of calcium phosphate, Ca₃(PO₄)₂ that can be produced from the reaction of 3.75 g of calcium chloride with 4.25 g of potassium phosphate is 3.11 g

Let us begin by obtaining the limiting reactant. This obtained as follow

3CaCl₂ + 2K₃PO₄ → Ca₃(PO₄)₂ + 6KCl

From the balanced equation above,

333 g of CaCl₂ reacted with 424 g of K₃PO₄

Therefore,

3.75 g of CaCl₂ will react with = (3.75 × 424) / 333 = 4.77 g of K₃PO₄

From the above calculation, we can see that a higher amount (i.e 4.77 g) of K₃PO₄ than what was given (i.e 4.25 g) is needed to react with 48 g of CaCl₂

Thus, the limiting reactant is K₃PO₄

Finally, we shall determine mass of calcium phosphate, Ca₃(PO₄)₂ produced. Details below:

3CaCl₂ + 2K₃PO₄ → Ca₃(PO₄)₂ + 6KCl

From the balanced equation above,

424 g of K₃PO₄ reacted to produce 310 g of Ca₃(PO₄)₂

Therefore,

4.25 g of K₃PO₄ will react to produce = (4.25 × 310) / 424 = 3.11 g of Ca₃(PO₄)₂

Thus, the mass of calcium phosphate, Ca₃(PO₄)₂ produced is 3.11 g

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Answer:

Specular reflection is correct answer by my views

hope it helps you

Answer:

Put sand in one cup and water in the other. Put two heat lamps at equal height and under each one put the water and sand, this must be done at the same exact time. Set a timer for 5, then 10, then 15, and so forth minutes. Each time measure the temperature of each with the thermometers and write the down. Have a certain temperature you want them to get to and see which gets to it quicker. Then set a new temp 3 times to see if the answer is consistent.

Explanation:

Doing this would test whether land or water heats quicker... Hope this helps!!!...

Answer:

The concentration of a conjugate base is twice that of the concentration of a conjugate acid

Explanation:

This is because at the midpoint, the number of moles of acid equals half the number of moles of base at the midpoint. This means that at the midpoint, half the analyte has been titrated.

Since the concentration of the conjugate acid is half that of the conjugate base at the midpoint, this implies that the concentration of the conjugate base is twice that of the conjugate acid.

Thus, at the midpoint of a titration curve the concentration of a conjugate base is twice that of the concentration of a conjugate acid

Bubbling and color changes indicates the occurring of a chemical reaction but does not indicate precipitation formation.

In Chemistry, when two supersaturated solutions are mixed together, precipitation refers to the formation of an undissolved solid that settles down at the bottom of the container.

In a precipitation reaction, the solution becomes colloidal i.e. a cloudy liquid is formed.

On the other hand, when a chemical reaction takes place bubbling occurs.

Other significant signs of a precipitation reaction include change in energy and temperature, formation of gas bubbles and precipitate formation and color change also happens.

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Answer:

Tbh i rlly dont think that many will.  Most may succeed  in doing so. But i mean come on its 2020 anything can happen.

Explanation:

Answer:

yes 100% what reasons r there to not tho

Explanation:

When the reaction is subjected to pressure, the equilibrium will shift to the side with fewer gas molecules, which is the left side. Therefore, the answer is c. left.

According to Le Chatelier's principle, when a system at equilibrium is subjected to a change in pressure, it will respond by shifting in a way that reduces the effect of the change. In this case, increasing the pressure would cause the equilibrium to shift towards the side with fewer gas molecules to alleviate the increase in pressure.

Since there are fewer gas molecules on the left side of the reaction (2 CO + O2), the equilibrium will shift to the left to reduce the total number of gas molecules. This means that the concentrations of CO and O2 will increase, while the concentration of CO2 will decrease until a new equilibrium is established. Thus, the equilibrium will shift to the left.

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Answer:

The RMM of Ca (OH)2 is

40+ (16+1)2

40+(17)2

40+34

74

The RMM of Al2SO4 is

(27×2)+32+(16×4)

54+32+64

=150

Explanation:

Note that the RAM of:

Ca=40

O=16

H=1

Al=27

S=32

To confirm Newton’s Second Law using a laboratory report, you will need to conduct an experiment using a simulation and gather data. Newton’s Second Law states that force equals mass times acceleration.

Here's how you can write a laboratory report to confirm Newton’s Second Law using the simulation and gathered data. Introduction: This section should include a brief explanation of the theory behind Newton’s Second Law and what you will be testing in your experiment. It should also include your hypothesis.

Procedure: This section should explain the steps you took to conduct your experiment. In this case, it would involve using the simulation to apply different forces to objects with different masses and measuring their acceleration.

Data: This section should present the data you collected during your experiment. It can be presented in tables or graphs, and should include measurements of force, mass, and acceleration for each trial.

Analysis: This section should analyze the data you collected to determine if it supports your hypothesis and confirms Newton’s Second Law.

Conclusion: This section should summarize your findings and draw conclusions based on the data you collected. It should also discuss any errors or limitations of the experiment and suggest areas for further research.

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The atmosphere over the equator is thicker than over the poles.

Part (i) The hydrostatic balance equation ∂z∂p​=−rhog, combined with the ideal gas law p=rhoRT gives an expression that describes how pressure p changes with height z if the temperature T is independent of z.

To derive the required expression, the hydrostatic equation is integrated from an arbitrary altitude z to a higher altitude z+∆z.

∂z∂p​=−rhog and p=rhoRT.

In order to determine the expression that describes how pressure p changes with height z if the temperature T is independent of z,

substitute rho= p/RT into the hydrostatic equation. This gives:

∂z∂p​=−1gRTp

Integrating both sides of the equation, we obtain:

∫z+z∗z​dz​=−(RTg)∫ps​p​dp​∫z+z∗z​dz​=−(RTg)ln⁡(pp_s​) z+z∗z​=RTgln⁡(pp_s​)

If the surface pressure is ps​, then at an altitude of z=0, the pressure is p=ps​. Thus:

z∗=RTgln⁡(0.01ps​)

Part (ii) Based on the answer to Part (i), the expression for the height z∗ below which 99% of the mass of the atmosphere lies is given by:

z∗=RTgln⁡(0.01ps​)

According to the hydrostatic balance equation, the thickness of the atmosphere is proportional to the surface pressure. Therefore, the atmosphere over the equator is thicker than over the poles.

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5.625 atm will be the pressure of the gas at 250 K temperature of the gas at constant volume.

Pressure of the gas will be calculated by using the ideal gas equation as:

PV = nRT,

From the question, it is clear that:

Moles of the gas and volume is constant here, so we calculate the pressure by rearranging the above equation as:

P/T = nR/V

And required equation will be:

P₁/T₁ = P₂/T₂, where

P₁ = pressure of gas = 4.50 atm

T₁ = temperature of gas = 200 K

P₂ = pressure of gas = to find?

T₂ = temperature of gas = 250 K

On putting all these values in the above equation, we get

P₂ = 4.50 × 250 / 200 = 5.625 atm

Hence, 5.625 atm is the pressure of the gas.

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Explanation:

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Answer:

amount of compost is the first answer

Answer:

In the Lewis structure for PF3 there are a total of 26 valence electrons. Three pairs will be used in the chemical bonds between the P and F.

Explanation:

Explanation:

pH = 14 - pOH

= 14 - 4.91

= 9.09

Significant figures are the number of digits in a number. To count the significant figures we must take into account that the zeros before the digit should not be counted, but the intermediate zeros or after the digit should be counted.

Now, when we do the two-digit division, the significant figures of the quotient will be equal to those of the digit with the fewest number of significant figures. Let's see what are the figures of the terms of the division and the final result:

We see that the quotient of the division is 0.746899..., but we have to write the answer only with 3 significant figures. If the number after the last figure to which we want to approximate is greater than 5, we must add 1 to the last figure, so the result will be: 0.747.

Answer: 0.747

The possible molar ratios for 2\(H_{3}\)P\(O_{4}\) in the equation are 2:3:4. The chemical equation is 2\(H_{3}\)P\(O_{4}\) → 3\(H_{2}\)O + 2\(H_{3}\)P\(O_{3}\). This means that for every two molecules of 2\(H_{3}\)P\(O_{4}\), three molecules of \(H_{2}\)O and two molecules of \(H_{3}\)P\(O_{3}\)are produced, creating a molar ratio of 2:3:4.
The possible molar ratios for 2\(H_{3}\)P\(O_{4}\) in the equation are 1:2 and 2:1.

Explanation:

A molar ratio is the ratio of the number of moles of one substance to the number of moles of another substance in a balanced chemical equation. In the given equation, 2\(H_{3}\)P\(O_{4}\), there are two moles of \(H_{3}\)P\(O_{4}\). The possible molar ratios for this equation are:

1:2 - This ratio represents the relationship between one mole of another substance and two moles of \(H_{3}\)P\(O_{4}\).

2:1 - This ratio represents the relationship between two moles of \(H_{3}\)P\(O_{4}\) and one mole of another substance.

These molar ratios can be used to calculate the amounts of reactants and products in a chemical reaction. It is important to remember that the coefficients in a balanced chemical equation represent the number of moles of each substance, not the number of molecules.

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