Find the weight of a 70kg astronaut on earth?

Answer:

VOLTAGE

Explanation:

Potential difference is the difference in the amount of energy that charge carriers have between two points in a circuit. ... A potential difference of one Volt is equal to one Joule of energy being used by one Coulomb of charge when it flows between two points in a circuit

the circumference of the CD is moving at a constant speed of 120 cm/s when the CD is rotating at a constant angular speed of 20 radians per second.

The circumference of the CD can be calculated using the formula C = πd, where d is the diameter. So, for a CD with a diameter of 12.0 cm, the circumference is C = π(12.0 cm) = 37.7 cm (rounded to one decimal place).
The linear speed of a point on the circumference can be found using the formula v = ωr, where ω is the angular speed and r is the radius of the circle. Since the radius of the CD is half the diameter, it is 6.0 cm.
So, the linear speed of a point on the circumference is v = (20 rad/s) x (6.0 cm) = 120 cm/s.

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Answer:

1)  ΔE = -800 J, 2) ΔE = 200 J, 3)  ΔE = -200 J, 4) ΔE = 800 J

Explanation:

For this exercise let's use the first law of thermodynamics

          ΔE = Q + W

Where we will apply this expression to several cases

1) output Q = 500 J and does work of W = 300 J.

The two processes involve an energy output

         ΔE = - 500 - 300

         ΔE = -800 J

Therefore, the internal energy of the gas decreases by this amount,

2) enter Q = 500J and do work of W = 300 J

         Positive heat is added and does negative work

         ΔE = 500 - 300

         ΔE = 200 J

3) they leave Q = 500 J and do (work on the gas) W = 300J

negative heat and positive work come out

          ΔE = -500 + 300

          ΔE = -200 J

4) heat enters Q = 500 J, work on gas W = 300 J

both positive

         ΔE = 500 + 300

         ΔE = 800 J

The mass of an object that requires 15.0N to accelerate it at rate of 3 m/s² is 1.17 kg.

The mass of an object is the quantity of matter present in an object.

The mass of an object is related to its acceleration and the applied force by the given formula below:

force = mass * acceleration

mass = force/acceleration

From the data provided:

force applied = 15.0 N

acceleration = 3 m/s²

The force applied overcomes the weight of the body.

Total force applied = weight + net force

Total force = mg + ma

Total force = m(g + a)

m = force/(g + a)

mass = 15(9.8 + 3)

m = 1.17 kg

Therefore, the mass of the object is 1.17 kg.

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Answer:

5 Components of Physical Fitness

Cardiovascular Endurance.

Muscular Strength.

Muscular endurance.

Flexibility.

Body Composition.

Option a: if two hypotheses fit the facts equally well, choose the one with fewer assumptions.

Occam's razor states that principle of problem solving is that entities should not multiply more than necessary

Occam's Razor is the process of gathering information to make the search for the truth easier. In science, it gets rid of all assumptions that have no bearing on the predictions of the hypothesis. If you have several hypotheses that could explain an observation, it is usually best to start with the simplest one.

Occam's Razor is often at the root of a paradigm shift, where an established theory is replaced by a simpler alternative that also fits the data. For example, Ptolemy's epicycles were replaced by a simpler theory that explained the data without multiplying the elements.

Therefore Option (a) is correct.

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The value of Bx is determined to be zero based on the given information about the magnetic force and electron's velocity.

To Bx, we can equate the magnetic force experienced by the electron to the product of its charge and the cross product of its velocity and the magnetic field. By comparing the coefficients of the j^ unit vector, we can determine the value of Bx.

The magnetic force experienced by a charged particle moving in a magnetic field is given by the equation F = q * (v x B), where F is the magnetic force, q is the charge of the particle, v is its velocity, and B is the magnetic field.

In this case, the magnetic force acting on the electron is given as (3.82×10^(-19))k^N. The velocity of the electron is given as (1.89i^ + 4.70j^) m/s. The magnetic field is given as B = (Bx i^ + (2.12Bx) j^).

To Bx, we equate the magnetic force equation to the given values and solve for Bx. By comparing the coefficients of the j^ unit vector, we can determine the value of Bx.

By equating the coefficients, we have:

q * (v x B)_j = (3.82×10^(-19)) * j^.

Expanding the cross product and comparing the coefficients, we get:

(1.89 * Bx) - (4.70 * Bx) = 0.

Simplifying the equation, we find:

-2.81 * Bx = 0.

Therefore, Bx = 0.

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The magnitude of the charge on either capacitor plate is 5.4 × 10^-7 C. Therefore the correct option is option D.

Using the formula for capacitance of a parallel plate capacitor with dielectric material:

C = (kε0A)/d

where k is the dielectric constant, ε0 is the electric constant, A is the area of the plates, and d is the distance between them.

For capacitor 1:

C1 = (kε0A)/d = (2ε0A)/d = (2 * 8.85 x 10^-12 F/m * 3.0 x 10^-3 m^2) / 3.0 x 10^-4 m = 5.94 x 10^-11 F

For capacitor 2:

C2 = (kε0A)/d = (4ε0A)/d = (4 * 8.85 x 10^-12 F/m * 2.0 x 10^-3 m^2) / 4.0 x 10^-4 m = 3.54 x 10^-11 F

The total capacitance of the circuit is given by the equation:

\(1/C = 1/C1 + 1/C2\)

\(1/C = (1/5.94 x 10^-11) + (1/3.54 x 10^-11)\)

\(1/C = 3.33 x 10^-11\)

\(C = 3.00 x 10^-11 F\)

The potential difference across the plates is V = Q/C, where Q is the charge on either capacitor plate.

\(Q = CV = (3.00 x 10^-11 F) (120 V) = 3.60 x 10^-9 C\)

Therefore, the magnitude of the charge on either capacitor plate is 3.60 x 10^-9 C. Answer: D) 5.4 × 10^-7 C

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The momentum of the probe after the retrorocket ceases to fire is 9.9 * 10^7 Kg m/s

We know that the momentum of an object has to do with the product of the mass and the velocity of an object. The momentum of an object is a vector quantity and the direction of the momentum is the direction of the velocity of the object that is in motion.

According to the Newton second law of motion, we know that the rate of change of the momentum is equal to the impressed force that is acting on the body.

We know that;

\(F_{t}\) = \(p_{f}\) -\(p_{i}\)

F = force

t = time taken

\(p_{f}\)= final velocity

\(p_{i}\) = initial velocity

\(p_{f}\) = \(F_{t}\)  + -\(p_{i}\)

\(p_{f}\) = (2.0 * 10^6 * 12 s) + 7.5 * 10^7

\(p_{f}\)  = 2.4 * 10^7 + 7.5 * 10^7

\(p_{f}\)  = 9.9 * 10^7 Kg m/s

Hence, the momentum of the retrorocket is 9.9 * 10^7 Kg m/s.

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Missing parts;

A  space probe is traveling in outer space with a momentum that has a magnitude of  7.5 * 10^7 kgm/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 2.0  * 10^6 N and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases fire.

In determining the distance to a galaxy using observations of a Cepheid variable star, the star's spectral classification is not needed. So, option D is the accurate answer.

Cepheid variable stars are used to determine the distance measurement tool which is a standard candle in astronomical theories, because of their good relation with the light luminosity. The period of light availability helps to determine the intrinsic luminosity of the star.

The star's magnitude is also helpful to measure distance because it provides estimated information of how much the star is far away from Earth by its brightness of the star.

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The relative velocity with respect to the dock is 6.5j + 1.1 i m/s m/s.

We need to know about relative velocity to solve this problem. The relative velocity depends on the object and observer velocity. It can be written as

v = vo ± v'

where v is relative velocity, vo is object velocity and v' is observer velocity.

From the question above, we know that

vo = 6.5 j m/s

v' = 1.1 i m/s

The velocity will be added each other because the direction of the observer is different from the object.

v = vo + v'

v = 6.5j + 1.1 i

v = 6.5j + 1.1 i m/s

Thus, the relative velocity is in vector form.

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Answer:

162

Explanation:

When the amplitude of the wave is 8 units, the corresponding energy of the wave is 128 units. Therefore, option C is correct.

The term amplitude is defined as the maximum distance moved by a point on a vibrating body or wave calculated from its equilibrium position.

We have given,

first amplitude, A = 1, corresponding energy = 2

second amplitude, A = 2, corresponding energy = 8

The energy of a string at  a given amplitude is calculated as follows;

E ∝ A²

Energy varies as the square of the change in amplitude.

If amplitude of one has energy of two

Amplitude of 2 (double of 1)

= ( 2 x 2 ) = 4 x 2

= 8  4 times the energy at amplitude of 1.

Then for 8 units of amplitude change

8 x 8 = 64 x 2

= 128  

Thus, When the amplitude of the wave is 8 units, the corresponding energy of the wave is 128 units, option C is correct.

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Your question is incomplete, most probably your question was

The data table shows how the amplitude of a mechanical wave varies with the energy it carries. Analyze the data to identify the mathematical relationship between amplitude and energy. Use your equation to find the energy if the amplitude is 8 units.

Amplitude

1

2

3

4

energy

2

8

18

32

A.66 units

B. 108 units

C. 128 units

D. 88 units ​

The acceleration of the car as it slowed down is -3.75 m/s². We can use the following formula to find the acceleration of the car: final velocity (v) = 0 m/s

initial velocity (u) = 30 m/s

time (t) = 8s

acceleration (a) = ?

We can use the formula: v = u + at

Rearranging the formula: a = (v - u) / t

Substituting the values of v, u, and t into the formula: a = (0 m/s - 30 m/s) / 8 s

a = -3.75 m/s²

The negative sign indicates that the car was decelerating or slowing down.

Therefore, the acceleration of the car as it slowed down was -3.75 m/s².

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The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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Heat of fusion latent The latent fusion temperature of a specific solid is the quantity of heat energy needed to transform 1 kilogram of solid into liquids at that solid's melting point.

Energy must be added to overcome the forces holding the particles together in order to transform a solid into a liquid and just a liquid into a gas. The strength of the connections binding the particles together determines how much energy is needed to change their state.

Either Celsius degrees or Kelvin degrees might be used to indicate this. The formula for the quantity Q=mL Q=m L, where m represents the mass of the item and L is the latent fusion temperature for an opening or vaporization, determines the amount of heat necessary to change a material's phase.

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The work done by the force f(x, y) = 3yi 7xj (x y)k in moving an object along curve r(t) = cos(t)i sin(t)j 1 9 k, where 0 ≤ t ≤ 2, is (-3/4) cos(4) + (7/4) sin(4) - (1/9).

To find the work done by the force f(x, y) = 3yi 7xj (x y)k in moving an object along curve r(t) = cos(t)i sin(t)j 1 9 k, where 0 ≤ t ≤ 2, we need to use the formula for work done by a force on a curve:

W = ∫C f·dr

Here, C is the curve r(t) from t = 0 to t = 2, f(x, y) = 3yi 7xj (x y)k, and dr = dx i + dy j + dz k. We can parameterize the curve as:

r(t) = cos(t)i + sin(t)j + (1/9)k

So, dx = -sin(t) dt, dy = cos(t) dt, and dz = 0. Substituting these into the formula, we get:

W = ∫C f·dr = ∫0^2 (3sin(t) cos(t) dt) + (7cos(t) sin(t) dt) + [(cos(t) sin(t))(1/9) dt]

W = ∫0^2 [(3/2) sin(2t) + (7/2) cos(2t) + (1/9) sin(t) cos(t)] dt

W = [-(3/4) cos(2t) + (7/4) sin(2t) - (1/18) cos(t)^2] from 0 to 2

W = [-(3/4) cos(4) + (7/4) sin(4) - (1/18)] - [-(3/4) cos(0) + (7/4) sin(0) - (1/18)]

W = (-3/4) cos(4) + (7/4) sin(4) - (1/9)

Therefore, the work done is (-3/4) cos(4) + (7/4) sin(4) - (1/9).

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Answer: 36.257 m/s

Explanation:

The vertical and horizontal components of a projectiles motion are completely independent of each other. The only thing they share is the amount of time in the air. Because they are independent, the acceleration of gravity cannot affect the horizontal acceleration. This means horizontal acceleration is 0. If the acceleration is 0, this means the velocity does not change horizontally. So the final velocity of the x component is equal to the initial.

Now if you actually imagine these two vectors, it forms a right triangle. So you can use the Pythagorean Theorem to find the resultant vector.

\(a^2+b^2=c^2\\18.3^2+(-31.3)^2 = c^2\\c = 36.257 m/s\)

Answer:

carbon is that component :)

Explanation:

It should me QUARTZ AND... CLAY

Answer:

Explanation:

We will use the equation F - f = ma, which is a fancy way of stating Newton's 2nd Law.

F = +50.0,

f = -30.0,

m = 7.60 kg. Therefore:

50.0 - 30.0 = 7.60a and

20.0 = 7.60a and

a = 20.0/7.60 so

a = 2.63 m/s/s to the right

Answer:

Atoms are neutral if they have the same number of charged protons and electrons, balancing positive and negative charges. As long as the numbers of electron and protons are the same, the charges will balance.

Answer:

All of the inventors can be characterized as problem-solvers.

Explanation:

Took the practice

Answer:

All of the inventors can be characterized as problem-solvers.

Explanation:

Fertility fraud is a deceptive act that involves medical professionals using their own sperm or someone else's without the patient's consent during fertility treatments.

It is a violation of trust and a grave breach of ethical standards that can have significant emotional and psychological consequences for those who experience it.

Individuals and couples who undergo fertility treatments often do so with the hope and expectation of having a child. Fertility fraud can shatter that hope, leaving individuals feeling violated, betrayed, and devastated. The emotional pain and trauma that follow can be long-lasting, and can impact their personal relationships and mental health.

The desire to become a parent is a fundamental human need and is often accompanied by feelings of loss, grief, and despair when fertility treatments fail. The emotional burden of fertility fraud compounds these feelings, leading to an indescribable sense of betrayal and a loss of trust in the medical system.

It is important to acknowledge and support those who have experienced fertility fraud, and to advocate for legal and ethical standards that prioritize patient autonomy, informed consent, and transparency in all aspects of fertility treatments

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Answer:

a) Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2).

b) Using the equation  equals plus a half squared gives us is equal to 13.5 multiplied by 10 plus a half multiplied by an eighth multiplied by 10 squared. This gives us a value of of 141.25. Therefore, the total distance covered by the body in the first 10 seconds of its motion is 141.25 meter.

Explanation:

hy this isn't the proper answer but by checking these equations you can get your answer .

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A )

\(acceleration = \frac{∆v}{∆t} = slope \\ \)

Thus ;

\(acceleration = 2 \: \: \frac{m}{ {s}^{2} } \)

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B )

\(v(t) = 2t\)

So ;

\(v(60) = 2 \times (60)\)

\(v(60) = 120\)

_________________________________

Point :

The area which is under the figures in v-t graphs , shows the distance traveled.

_________________________________

Thus ;

\(distance \: traveled = \frac{1}{2} \times (60) \times 120 \\ \)

\(distance \: traveled \: = 30 \times 120 \\ \)

\(distance \: traveled \: = 3600 \: \: meters \\ \)

Done...

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In a deep vacuum, the pressure exerted by the atmosphere on a gauge line is negligible or close to zero. A vacuum is defined as a region with a low gas pressure, typically much lower than atmospheric pressure.

In a deep vacuum, the pressure is significantly lower compared to atmospheric pressure. The atmosphere exerts pressure on objects due to the weight of the air above them. However, in a deep vacuum where air or any other gas is absent, there is no medium to exert pressure on the gauge line.

A vacuum is defined as a region with a low gas pressure, typically much lower than atmospheric pressure. In a deep vacuum, the pressure is close to zero or negligible. This means that the atmosphere does not exert any significant pressure on a gauge line placed in a deep vacuum.

It is important to note that the absence of pressure in a deep vacuum does not mean the absence of other effects, such as radiation pressure or gravitational forces, which may still be present depending on the specific conditions. However, in terms of atmospheric pressure, it is essentially nonexistent in a deep vacuum.

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Sensory afferents are nerve fibers that carry sensory information from the periphery (e.g. skin, muscles, organs) to the central nervous system (CNS), where it is processed and interpreted.

These sensory afferents can be classified based on their diameter, myelination status, and the type of sensory information they transmit.

Myelination is the process by which a fatty coating called myelin is wrapped around nerve fibers.

Myelin acts as an insulator, allowing electrical impulses to travel more quickly and efficiently along the nerve fiber.

A-delta fibers and C fibers are small-diameter sensory afferents that are not myelinated, or are only thinly myelinated.

These fibers are responsible for transmitting information related to pain sensation, including noxious stimuli (e.g. tissue damage, inflammation).

A-delta fibers are typically associated with sharp, acute pain, while C fibers are associated with dull ,aching pain.

A-beta fibers, on the other hand, are large-diameter, myelinated sensory afferents that are responsible for transmitting information related to touch and pressure sensation.

These fibers are found in high numbers in the skin, joints, and muscles, and are responsible for detecting gentle pressure, vibration, and fine touch.

Therefore, the correct answer to the question is d. a-beta fibers, as they make up more than half of all sensory afferents in the body.

It is important to note that while a-delta and C fibers are responsible for transmitting pain sensation, they make up a smaller proportion of sensory afferents in the body compared to a-beta fibers.

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The driver produces a torque of 26.5 N-m while changing the flat tire using a tire iron 50.0 cm long and exerting a force of 53.0 N.

To calculate the torque produced by the driver when changing a flat tire using a tire iron 50.0 cm long and exerting a force of 53.0 N, you can follow these steps:

Step 1: Convert the length of the tire iron from centimeters to meters.
1 meter = 100 centimeters
50.0 cm = 50.0 / 100 = 0.5 meters

Step 2: Determine the angle between the force applied and the tire iron. Since the driver is applying the force perpendicularly to the tire iron, the angle is 90 degrees.

Step 3: Calculate the torque.
Torque (τ) = Force (F) × Distance (d) × sin(θ)
where θ is the angle between the force and the tire iron.

Step 4: Plug in the values.
τ = 53.0 N × 0.5 meters × sin(90°)

Step 5: Calculate sin(90°).
sin(90°) = 1

Step 6: Multiply the values.
τ = 53.0 N × 0.5 meters × 1
τ = 26.5 N-m

The driver produces a torque of 26.5 N-m while changing the flat tire using a tire iron 50.0 cm long and exerting a force of 53.0 N.

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Answer:

B

Explanation:

mine were worded a little differently. On mine it said "Making improvements to the original prototype in order to perform more tests" but i got it right sooo....hope this helps somebody

B. Improving its design based on the results from tests on the

prototype

The following information should be considered:

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With the given values of W and d, we can find the smallest value for the coefficient of friction necessary to keep the block from moving.

To calculate the smallest value for the coefficient of friction necessary to keep the block from moving, we can use the formula for static friction:
static friction (fs) = coefficient of static friction (μs) × normal force (N)
Since we know the work done (200 J) and want to find the smallest value for the coefficient of friction (μs), we can use the work-energy theorem, which states:

Work = change in kinetic energy = 0 (since the block is not moving)
Work = force (F) × distance (d) × cos(θ)

200 J = μs × N × d × cos(θ)
Now, let's consider the forces acting on the block.

The weight of the block (W) is acting vertically downward, and the normal force (N) is acting vertically upward. In this case, the angle (θ) between the force and the direction of motion is 0 degrees,

so cos(θ) = 1.
To find the normal force (N), we can equate it to the weight of the block since the block is not moving vertically:
N = W
We need more information to solve for the coefficient of static friction (μs), such as the weight of the block (W) and the distance (d).

Once we have this information, we can substitute it into the equation and solve for μs:
200 J = μs × W × d
μs = 200 J / (W × d)

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An appropriate force equation for the piston:

A piston is a a piece of metal in an engine, etc. that fits tightly inside a tube (cylinder). The piston is moved up and down inside the tube and causes other parts of the engine to move.

Pistons work by transferring the force output of an expanding gas in the cylinder to a crankshaft, which provides rotational momentum to a flywheel.

Force equation for the piston is given below:

∑ Fₓ = maₓ  yields  - P₀A - mg + PA = 0

Where P is the pressure exerted by the gas contained. Nothing that

V =Ah, and that n, T, m, g, A  and P₀ are given,

PV = n R T becomes,  \(P = \frac{nRT}{Ah}\)  ,

so we substitute to eliminate P:

- P₀A - mg + \(\frac{nRT}{Ah} A = 0\)  and  \(h = \frac{nRT}{P0A + mg}\)  ,

Finalize:

It is reasonable that n is on top in the fraction in the derived equation, because more gas will occupy more volume. Expansion makes it reasonable that T is on top. A heavier piston would compress the gas, so it is reasonable that the piston mass is on the bottom.

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