five more than 3 times a number

Answer:

y = -x/2 + 2

what are those mutli choice answers?

if that point is (6,1)

y = -x/2 + 4

Step-by-step explanation:

the perpendicular line has a gradient which is the negative inverse, that is -1/m

so the equation will be of the form y = -x/2 + c

substituting in the point (6, -1)

-1 = -6/2 + c

c = 2

so y = -x/2 + 2

The actors should be positioned in the original coordinate system at locations A(-5, -4), B(-2, -7), and C(1, -4).

If they move 5 units left and 4 units down from each of the original points, then the following becomes the new coordinates:

A: (-5, -4)

B: (-2, -7)

C: (1, -4)

To graph these new coordinates, draw the new coordinate plane and plot the points:

So for Scene 2, the actors should be positioned at points A(-5, -4), B(-2, -7), and C(1, -4) with respect to the original coordinate system.

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Answer:

-7/3

Step-by-step explanation:

The first step is to combine like numbers. Although there are several different ways to go about doing this, I started by adding 2y to both sides which left me with -8-6y=6. I then added 8 to both sides and got 6y=14. Now divide 6 on both sides to get "y" by itself which left me with y = -14/6. When you simplify the answer you get -7/3.

Answer:

C

Step-by-step explanation:

Given

tanθ = \(\frac{1}{2}\) = \(\frac{opposite}{adjacent}\)

This is a right triangle with legs 1 and 2

Using Pythagoras' identity

hypotenuse² = 1² + 2² = 1 + 4 = 5 ( take square root of both sides )

hypotenuse = \(\sqrt{5}\)

θ is in the 3rd quadrant where sinθ < 0 , then

sinθ = \(\frac{opposite}{hypotenuse}\) = - \(\frac{1}{\sqrt{5} }\) ← rationalise the denominator

       = - \(\frac{1}{\sqrt{5} }\) × \(\frac{\sqrt{5} }{\sqrt{5} }\)

       = - \(\frac{\sqrt{5} }{5}\) → C

(a) The expression for Y(s) with non-zero initial conditions is given by:

Y(s) = 32/((s + 12)(s+32)) + y_0(s + 12)(s+32) Where, y_0 = y(t = 0)

(b) With zero initial conditions, the transfer function T(s) = Y(s)/U(s) is given by: T(s) = 32/((s + 12)(s+32))

(c) The impulse response of the system is given by the inverse Laplace transform of the transfer function: h(t) = 32(e^(-12t)-e^(-32t))

(d) The Routh table can be used to determine the BIBO stability of the system. If all of the entries in the Routh table are positive, then the system is BIBO stable. The impulse response of the system is related to its BIBO stability in that a BIBO stable system must have an impulse response that decays to zero as time increases. If the impulse response does not decay to zero, then the system is not BIBO stable.

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Answer:

VALEVENT

Step-by-step explanation:

no idea what that means but there you go

When x is negative, the absolute value is equal to the negation of x, which makes it positive.

To write the expression without absolute value symbols, you can simplify it as follows:

|3 + 1/3|

This expression represents the absolute value of the sum of 3 and 1/3. To simplify it further, we can calculate the sum:

3 + 1/3 = 3 1/3 or 10/3

Therefore, the expression without absolute value symbols simplifies to:

10/3

The absolute value, also known as the modulus, of a real number is a non-negative value that represents the distance of the number from zero on the number line. It is denoted by enclosing the number between vertical bars or using the symbol "|" before and after the number.

For example, the absolute value of 5 is written as |5| and equals 5. Similarly, the absolute value of -5 is also | -5 | and also equals 5. In both cases, the absolute value gives the positive distance of the number from zero.

More formally, the absolute value function can be defined as follows:

|x| = x, if x ≥ 0

|x| = -x, if x < 0

In this definition, when x is a non-negative number or zero, the absolute value is equal to x itself. However, when x is negative, the absolute value is equal to the negation of x, which makes it positive.

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The proper question is,

Write without absolute value symbols. (Simplify your answer completely.)  

\($\frac{|3|}{|3+1|}\)

By using logarithim quotient rule the given lograthimic expression log₅ x - 1/5 log₅ y can be written as log₅ (x/y^(1/5)).

According to the given question.

We have lograthimic expression.

log₅ x - 1/5 log₅ y

As we know that, a logarithmic expression is an expression that involves the logarithm of an expression containing a variable.

Also according to the logratimic quotient rule we know that

\(log_{b} (\frac{m}{n} ) = logm - logn\)

Thereofore,by using logarithim quotient rule the given lograthimic expression log₅ x - 1/5 log₅ y can be written as

log₅ x - 1/5 log₅ y

= log₅ x - log₅ (y^(1/5))

= log₅ (x/y^(1/5))

Hence, by using logarithim quotient rule the given lograthimic expression log₅ x - 1/5 log₅ y can be written as log₅ (x/y^(1/5)).

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Answer:

Let area be a and side be s :

\({ \tt{a \: \alpha \: s²}} \\ a = ks²\)

k is a constant, k=1

The Solution:

Given:

Part (a):

Find the sample means by the 4 students.

Student 1:

Student 2:

Student 3:

Student 4:

Part (b):

Find the range of the sample means.

Part (c):

Thus, the correct answers are [options B and D]

Answer:

311 Remainder 6

Step-by-step explanation:

Answer:

          75

-    _____________

        10x^4−27

Step-by-step explanation:

Answer:

Step-by-step explanation:

First we do all brcakets becuase we are following the law of BODMAS.

2×-5×3 = -10×3= -30

Now we do all powers and indices:

-5²= 25

10²= 100

3³ = 27

Now we do the top of the fraction:

25+100 = 125

Now we do the bottom bit of the fraction:

-30+27 = -3

Now we divide 125 by -3:

-41 2/3

-41.666.....

Answer:

the "^" symbol is called the exponent symbol

exponent is fast multiplication

in other words x^y means multiplying 'x' y times

Step-by-step explanation:

none of the provided options (a, b, c, d) appear to be accurate or close to the minimum space required.

To determine the minimum space required for a male restroom design with the given plumbing requirements, we need to consider the minimum space required for water closets and lavatories.

The minimum space required for water closets is typically around 30-36 inches per unit, and for lavatories, it is around 24-30 inches per unit.

Since the design requires a minimum of 12 water closets and 13 lavatories, we can estimate the minimum space required as follows:

Minimum space required for water closets = 12 water closets * 30 inches = 360 inches

Minimum space required for lavatories = 13 lavatories * 24 inches = 312 inches

Adding these two values together, we get a total minimum space requirement of 672 inches.

Among the given options, the closest value to 672 inches is option d) 249. However, this value seems significantly lower than the expected minimum space requirement.

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Therefore, in a 2x2 table, the pattern of cell frequencies that would indicate independence is d. All cell frequencies are exactly the same.

In a 2x2 contingency table, the expected cell frequencies under the null hypothesis of independence are equal for all cells. If the observed cell frequencies in the table are approximately equal to the expected cell frequencies, then we can conclude that there is no significant association between the two variables being studied. In other words, the pattern of observed cell frequencies is consistent with the null hypothesis of independence. Therefore, if all cell frequencies are exactly the same, it suggests that the variables are independent, as each cell has an equal chance of being filled by any observation regardless of the value of the other variable.

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The vertical asymptotes of the function f(x) = 6tan(x) are x = π/2 + kπ, where k is an integer.

To find the vertical asymptotes of the function f(x) = 6tan(x), we need to determine the values of x where the tangent function is undefined.

The tangent function is undefined at values where the cosine function is zero. Therefore, we need to find the values of x for which cos(x) = 0.

1. In the interval (0, π), the cosine function is equal to zero at x = π/2.

2. In the interval (π, 2π), the cosine function is equal to zero at x = 3π/2.

In general, the vertical asymptotes of the function f(x) = 6tan(x) occur at x = π/2 + kπ, where k is an integer.

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Answer:

I think it's B

Step-by-step explanation:

The width, is 4, multiplied by the height, which is 5. You then take the square root of that number and voila.

Answer:

Step-by-step explanation:

1). f(x) = 2x

   f(-3) = 2(-3) = -6

   f(1) = 2(1) = 2

   f(4) = 2(4) = 8

   Ordered pairs → (-3, -6), (1, 2), (4, 8)

2). f(x) = 2x + 1

    f(-3) = 2(-3) + 1 = -5

    f(1) = 2(1) + 1 = 3

    f(4) = 2(4) + 1 = 9

   Ordered pairs → (-3, -5), (1, 3) and (4, 9)

     x       -3        1        4      

    f(x)     -5       3        9

3). f(x) = -3x

    f(-3) = -3(-3) = 9

    f(1) = -3(1) = -3

    f(4) = -3(4) = -12

    Ordered pairs → (-3, 9), (1, -3), (4, -12)

       x       -3       1        4

     f(x)       9      -3     -12

1. Maximum value: The maximum value of the function P = 20x - 5y + 64 is 184.00.

2. Minimum value: The minimum value of the function P = 20x - 5y + 64 is 44.00.

3. Values of x and y: The maximum value occurs at x = 6.00 and y = 0, while the minimum value occurs at x = 0 and y = 4.00.

To find the maximum and minimum values of the function P = 20x - 5y + 64, we need to consider the given constraints: 6x + 7y ≤ 42, 0 ≤ y ≤ 4, and 0 ≤ x ≤ 6.

These constraints represent a feasible region in the x-y plane.

To find the maximum value, we optimize the objective function P within this feasible region.

By evaluating the objective function at each corner point of the feasible region, we determine that the maximum value of P is 184.00, which occurs at x = 6.00 and y = 0.

Similarly, to find the minimum value, we evaluate the objective function at each corner point of the feasible region.

The minimum value of P is 44.00, which occurs at x = 0 and y = 4.00.

By considering the given constraints and evaluating the objective function at the corner points of the feasible region, we can determine the maximum and minimum values of the function P and the corresponding values of x and y.

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Answer:

55%

Step-by-step explanation:

To find what percent of 260 is 143, we can set up a proportion:

x/100 = 143/260

Cross-multiplying, we get:

260x = 14300

Dividing both sides by 260, we get:

x = 55

Therefore, 143 is approximately 55% of 260.

The probability that a randomly selected finishing time is greater than 87 seconds is 14.08%. This can be calculated using the empirical rule.

The empirical rule states that for any data that is normally distributed, about 68% of the data will fall within one standard deviation of the mean (in this case, within 69 ± 6 seconds). Approximately 95% of the data will fall within two standard deviations (in this case, within 69 ± 12 seconds), and about 99.7% of the data will fall within three standard deviations (in this case, within 69 ± 18 seconds).Given the mean and standard deviation given, we can calculate the probability that a randomly selected finishing time is greater than 87 seconds.

We can do this by subtracting the area under the curve from the mean to the value we are interested in (in this case, 87 seconds). Since the total area under the curve is 1, subtracting the area from the mean to 87 seconds will give us the desired probability.To calculate the area under the curve, we need to calculate the Z-score, which is the number of standard deviations away from the mean a particular value is. In this case, the Z-score is (87 - 69) / 6, which is 2.16. Using a Z-table, the probability of a Z-score of 2.16 or higher is 0.8592. Therefore, the probability that a randomly selected finishing time is greater than 87 seconds is 1 - 0.8592, which is 0.1408. Rounding to two decimal places, this is 14.08%.

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Answer:

i think the answer is 8/12 but im not sure though

Step-by-step explanation:

Answer:

An example of a ratio equivalent that is similar to 2:3 is 4:6.

Step-by-step explanation:

The second number after the : must be divisible 3 based on what it is given.

Consumer surplus $5 as we solve the Q by given data

Consumer surplus is the difference between the consumer's willingness to pay and the price of the commodity.

Consumer surplus in economics, also called social surplus or consumer surplus, is the difference between the price a consumer pays for a commodity and the price the consumer is willing to pay in exchange for giving it up.

Producer surplus is the difference between the price of a commodity and the lowest price at which a seller is willing to sell it.

Consumer Surplus = Willingness to Pay - Price of the Good.

Item Price = $35 - $10 = $25

$30 - $25 = $5

Producer surplus is the difference between the price of a commodity and the lowest price at which a seller is willing to sell it.

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A critical value, z Subscript alphas is (c) z-score with an area of ?? to its left.

A critical value, denoted as z (Subscript α/2), is a point on the standard normal distribution curve, which is used in hypothesis testing. It helps to determine whether to accept or reject the null hypothesis. In this context, the critical value denotes the z-score with an area of ?? to its left, which represents the probability of observing a value more extreme than the critical value in the left tail of the distribution.

The critical value z Subscript α/2 signifies the z-score with an area of ?? to its left on the standard normal distribution curve, which is crucial for hypothesis testing.

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The general solution to the given differential equation is x^2 + 3y = e^(x + C).

To solve the differential equation dy = x^2 + 3yx dx, we can separate the variables and integrate both sides.

dy = (x^2 + 3yx) dx

Divide both sides by (x^2 + 3y):

dy / (x^2 + 3y) = dx

Now, we can integrate both sides:

∫(dy / (x^2 + 3y)) = ∫dx

To integrate the left-hand side, we can make a substitution by letting u = x^2 + 3y. Then, du = (2x + 3dy).

∫(1 / u) du = ∫dx

ln|u| = x + C

Replace u with x^2 + 3y:

ln|x^2 + 3y| = x + C

Exponentiate both sides:

|x^2 + 3y| = e^(x + C)

Since e^(x + C) is always positive, we can remove the absolute value signs:

x^2 + 3y = e^(x + C)

This is the general solution to the given differential equation.

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Answer:

  3

Step-by-step explanation:

The slope is the ratio ...

  slope = rise/run

You can find it by looking for two points where the graph crosses grid intersections, then counting the vertical and horizontal squares between those points.

It often works well to start at or near the y-axis. Here, the line crosses the y-axis at (0, -1). It crosses another grid intersection at (1, 2).

The latter point is 3 units up and 1 unit over (to the right) from the former, so ...

  slope = rise/run = 3/1 = 3

The slope of the line is 3.

d=

Let's simplify step-by-step.

p+6pq−2pq−129

=p+6pq+−2pq+−129

Combine Like Terms:

=p+6pq+−2pq+−129

=(6pq+−2pq)+(p)+(−129)

=4pq+p+−129

Answer:

=4pq+p−129

g=

Let's simplify step-by-step.

2x−3y+b(3y−2x)+2.718282−(2x−3y)

Distribute the Negative Sign:

=2x−3y+b(3y−2x)+2.718282+−1(2x−3y)

=2x+−3y+b(3y−2x)+2.718282+−1(2x)+−1(−3y)

=2x+−3y+b(3y−2x)+2.718282+−2x+3y

Distribute:

=2x+−3y+(b)(3y)+(b)(−2x)+2.718282+−2x+3y

=2x+−3y+3by+−2bx+2.718282+−2x+3y

Combine Like Terms:

=2x+−3y+3by+−2bx+2.718282+−2x+3y

=(−2bx)+(3by)+(2x+−2x)+(−3y+3y)+(2.718282)

=−2bx+3by+2.718282

Answer:

=−2bx+3by+2.718282

The best name for this quadrilateral is a trapezoid.

The quadrilateral can be plotted on a coordinate plane as follows:

 C(5, 3)          D(4, 0)

    +----------------+

    |                |

    |                |

    |                |

    |                |

    +----------------+

 B(1, 3)          A(0, 0)

The sides of the quadrilateral are AB, BC, CD, and DA.

Based on the properties of the sides and angles, this quadrilateral can be classified as a trapezoid.

A trapezoid is a quadrilateral with at least one pair of parallel sides. In this case, the pair of parallel sides are AB and CD.

So, the best name for this quadrilateral is a trapezoid.

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