How many moles are in 272 grams of hydrogen peroxide (H2O2) ?

Answer:

-376 kJ

Explanation:

The first step equation:

\(\mathsf{N_{2(g)} + 3H_2{(g)} \to 2NH_3{(g)} \ \ \ \Delta H = -92\ kJ}\)    ---- (1)

The second step equation:

\(\mathsf{NH_{3(g)} + 2O_2{(g)} \to HNO_3{(g)} +H_2O_{(g)} \ \ \ \Delta H = -330\ kJ}\)      ---- (2)

To determine the enthalpy of formation for 1 mole of HNO₃ (nitric acid), we have the following.

From the above equations; let multiply equation (1) by 1 and equation (2) by 2.

\(\mathsf{N_{2(g)} + 3H_2{(g)} \to 2NH_3{(g)} \ \ \ \Delta H = -92\ kJ}\)     ---- (3)

\(\mathsf{2NH_{3(g)} + 4O_2{(g)} \to 2HNO_3{(g)} +2H_2O_{(g)} \ \ \ \Delta H = 2(-330)\ kJ}\)      ----- (4)

adding the above two equations, we have:

\(\mathsf{N_{2(g)} + 3H_2{(g)}+ 2NH_{3(g)} + 4O_{2(g)} \to 2HNO_{3(g)} + 2NH_3{(g)} +2H_2O_{(g)} \ \ \ \Delta H = (-660 \ kJ -92\ kJ)}\)\(\mathsf{N_{2(g)} + 3H_2{(g)} + 4O_{2(g)} \to 2HNO_{3(g)} +2H_2O_{(g)} \ \ \ \Delta H = (-752 \ kJ)}\)

Now, from the recent equation, we have:

2 moles of nitric acid = -752 kJ

∴

1 mole of nitric acid will be: = (1 mole × (-752 kJ)) ÷ 2 moles

1 mole of nitric acid will be: = -376 kJ

The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Answer:

acetaldehyde

When acetaldehyde is heated with Fehling's solution, a red precipitate is formed.

Explanation:

Answer:

This is easy, first you just...

Explanation:

I lied I have no idea, good luck tho

The density of pure water is 1 g/cm^3.

Its density is 0.98 g cm 3 at room temperature, in comparison with the handiest zero.92 g cm 3 for ice, a reality that has to be defined through atomic, and molecular concepts. If ice has been no longer much less dense than water, it might sink, having a devastating impact on lake backside ecosystems. believe it or now not, ice is honestly about 9% much less dense than water. for the reason that water is heavier, it displaces the lighter ice, causing the ice to glide to the pinnacle.

The density of ice is about 90 percent that of water, but that could range because ice can contain air, too. meaning that about 10 percent of an ice cube or iceberg will be above the water line. The density of water is maximum at four∘C, and the density of the ice is much less than the water due to its susceptible intermolecular pressure of attraction. as the density of water is more, it's miles heavier than ice. therefore ice floats on the floor of the water. Ice continually floats due to the fact it's far less dense than everyday water. because frozen water molecules shape a crystal.

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Answer:

134.5 grams

Explanation:

There are 134.5 grams in 4.5 moles of Li2O (lithium oxide).

BRAINLIEST PLZZZZZ

Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 135g are in 4.5 moles of Li\(_2\)O.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance. we know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number. Mole is inversely proportional to molar mass of given substance. Mole is directly proportional to given number of atoms present in that substance.

Mathematically, molar mass and mole can be related as

mole of  Li\(_2\)O =given mass of Li\(_2\)O÷ Molar mass of  Li\(_2\)O

Molar mass of  Li\(_2\)O=30 g/mol

mole of  Li\(_2\)O=4.5 moles

Substituting the values

4.5 moles =mass of Li\(_2\)O÷ 30 g/mol

mass of Li\(_2\)O = 135g

Therefore, 135g are in 4.5 moles of Li\(_2\)O.

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The heating curve of water is the temperature of a given volume of water changes as heat is added at a consistent pace, as shown by the water heating curve. The temperature of the water does not vary throughout a phase shift, creating a plateau on the graph.

A meniscus is a curvature that appears on the surface of a molecular substance (water, of course) when it comes into contact with another material. You may imagine that happening with water when it adheres to the interior of a glass.

Hence, The relationship between the supply temperature of the heating system and the outside air temperature is known as the heating curve. The CH boiler's ability to heat water to a specific temperature at a specific outside temperature is determined by the heating curve.

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Structural isomers are molecules with the same molecular formula but with different structural formulae. This means that they have the same number and types of atoms, but they are arranged differently. The following two organic compounds are structural isomers of each other.

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Answer:

The correct answer is B

Explanation:

The rate constant and reaction are both increased

Answer:

B. are electrical signals.

Answer:

8.7 million species

Explanation:

Scientists have estimated that there are around 8.7 million species of plants and animals in existence.

The speed of sound is the speed at which sound travels from one point to another.

The speed of sound is the speed at which sound travels from one point to another. We know that the speed of sound varies from place to pace owing to the density ad the kind of particles that are found in the medium.

Thus, we are going to convert the following now to units of meter per second.

1) For 5.4 × 103 cm/s we have  5.4 × 10^3 cm/s /100 = 54 m/s

2) For 1.97 × 104 ft/s  we have r 1.97 × 10^4 ft/s / 0.3048 = 6.46 m/s

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Some types of solids that are insoluble in water are:

Many solids are insoluble in water, meaning they do not dissolve in water to a significant extent. Here are some examples of common solids that are generally insoluble in water:

Metals: Most metals, such as gold, silver, platinum, and copper, are insoluble in water.

Non-Metallic Elements: Many non-metallic elements, such as carbon (in the form of graphite or diamond), sulfur, phosphorus, and iodine, are insoluble in water.

Metal Oxides: Some metal oxides, particularly those of less reactive metals, are insoluble in water. Examples include aluminum oxide (Al2O3), iron(III) oxide (Fe2O3), and lead(II) oxide (PbO).

Metal Carbonates: Most metal carbonates are insoluble in water. Examples include calcium carbonate (CaCO3), lead(II) carbonate (PbCO3), and copper(II) carbonate (CuCO3).

Metal Sulfides: Many metal sulfides are insoluble in water. Examples include lead(II) sulfide (PbS), silver sulfide (Ag2S), and mercury(II) sulfide (HgS).

Insoluble Salts: Certain salts have limited solubility in water. Examples include silver chloride (AgCl), lead(II) iodide (PbI2), and calcium sulfate (CaSO4).

It's important to note that while these solids are generally insoluble in water, they may exhibit some solubility to a small extent. The solubility of a solid in water can vary depending on factors such as temperature, pressure, and the presence of other solutes.

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Answer:  

Neptune is 34 times bigger than Earth.

Earth has life, Neptune does not.

Neptune is a gas planet, Earth is not.

Neptune has rings, Earth does not.

Neptune has 13 moons, Earth has 1.

Explanation:

The planets Earth and Neptune are different from each other as Neptune is 34 times bigger than Earth.Earth has life, Neptune does not.Neptune is a gas planet, Earth is not.Neptune has rings, Earth does not.

A planet is a large, rounded astronomical body that is neither a star nor its remnant. The best available theory of planet formation is the nebular hypothesis, which posits that an interstellar cloud collapses out of a nebula to create a young protostar orbited by a protoplanetary disk.

Planets grow in this disk by the gradual accumulation of material driven by gravity, a process called accretion. The Solar System has at least eight planets: the terrestrial planets Mercury, Venus, Earth and Mars, and the giant planets Jupiter, Saturn, Uranus and Neptune.

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An element belongs to group 17 of the periodic table. This element exists most likely as a Halogen.

A solid of this element would have a black, metallic formation.

Halogen exists in any of the six nonmetallic elements that constitute Group 17 (Group VIIa) of the periodic table. The halogen elements exist as fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At), and Tennessee (Ts).

A unique feature of halogens exists that it exists the only group in the whole periodic table that exists formed of elements that belong to all three classical forms of matter (solid, liquid, and gas) when maintained under standard requirements of pressure and temperature.

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Answer:

because electron molecule in floirine are tightly held to the nuclei dispersion force are relatively weak and in iodine they are strong

Answer:

Decomposition

Explanation:

hope it helps you

The new molarity of a 1 liter solution of a 0.01 Molar NaCl, is boiled until 0.700 L is left is 0.014 M. The correct option to this question is C.

According to dilutional molarity equation

\(M_{1}V_{1} = M_{2}V_{2}\)

Substituting the vales in the above equation we get

0.01×1=\(M_{2}\) × 0.7

\(M_{2}\) = \(\frac{0.01*1}{0.7}\)

\(M_{2}\) = 0.014 M

The concentration of a solution can be determined by measuring its molarity. Reducing a solution's concentration through dilution is possible. For effectively carrying out chemical experiments in a laboratory, molarity and dilution are both crucial ideas.

Using the following equation, we can link the volumes and concentrations before and after a dilution: Where \(M_{1}\) and  \(V_{1}\)stand for the volume and molarity of the initial concentrated solution, respectively, and \(M_{2}\) and \(V_{2}\) for the volume and molarity of the final diluted solution, respectively, we have \(M_{1}V_{1} = M_{2}V_{2}\).

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The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.

In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.

The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.

During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.

The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.

The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.

In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.

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Answer: The molarity of \(HCl\) is 0.07 M

Explanation:

According to the neutralization law,

\(n_1M_1V_1=n_2M_2V_2\)

where,

\(n_1\) = basicity \(HCl\) = 1

\(M_1\) = molarity of \(HCl\) solution = ?

\(V_1\) = volume of  \(HCl\) solution = 25.0 ml

\(n_2\) = acidity of \(NaOH\) = 1

\(M_1\) = molarity of \(NaOH\) solution = 0.1000 M

\(V_1\) = volume of  \(NaOH\) solution = 17.5 ml

Putting in the values we get:

\(1\times M_1\times 25.0=1\times 0.1000\times 17.5\)

\(M_1=0.07M\)

Therefore, molarity of \(HCl\) is 0.07 M

Students can create chemical structures or reactions as responses to Smartwork questions using the 2D Molecule Drawing Module (MDM).

It is a picture of an MDM problem. In order to view the complete MDM, you might need to change the zoom based on your screen resolution or browser settings. The full MDM is depicted in the figure below, which consists of a white workspace encircled by a dark-gray border that houses various toolbars.

Within the MDM border, there are three main toolbar regions. The following toolbar areas are highlighted in the diagram below: elemental symbols (green), formatting tools (red), and blue drawing tools (green).

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Answer:

200 (kg / mol) x dL

Explanation:

Answer:

D: CH2=CH-CH(CH3)-CH2-CH3 (R & S enantiomers)

E: CH3-CH2-(CH3)-CH2-CH3

(Please see the figures enclosed )

Explanation:

D is a racemic mixture (R & S) of 3-metyl-pent-1-ene, so it is optically inactive (although each of two enantiomers is optically active, the mixture is optically  inactive. The reason is that two enantiomers are present in an equal amount).

E is optically inactive, so its structure has to be symmetric.

Answer:

The cell potential for the given galvanic cell is 0.188 V.

Explanation:

To calculate the cell potential, we can use the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where E°cell is the standard cell potential, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25°C = 298 K), n is the number of moles of electrons transferred (in this case, n = 2), F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.

First, we need to write the half-reactions and their standard reduction potentials:

Sn4+(aq) + 2e- → Sn2+(aq) E°red = 0.15 V

Fe3+(aq) + e- → Fe2+(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn2+(aq) + 2Fe3+(aq) → Sn4+(aq) + 2Fe2+(aq)

The reaction quotient Q can be expressed as:

Q = [Sn4+][Fe2+]^2 / [Sn2+][Fe3+]^2

Substituting the given concentrations, we get:

Q = (0.00655)(0.01139)^2 / (0.0624)(0.0437)^2 = 0.209

Now we can calculate the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe2+]^2/[Fe3+]) + 0.0592 V log([Sn4+]/[Sn2+])

= 0.15 V + 0.0592 V log(0.01139^2/0.0437^2) + 0.0592 V log(0.00655/0.0624)

= 0.188 V

Therefore, the cell potential for the given galvanic cell is 0.188 V.

The cell potential for the given galvanic cell in which the given reaction occurs at 25 °C is 0.188 V.

To find the cell potential, we take the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

In which R is the gas constant (8.314 J/mol·K) and E° cell is the standard cell potential.

T temperature in Kelvin (25°C = 298 K), and n is the number of moles of electrons transferred (n = 2), Q is the reaction quotient and F is the Faraday constant (96,485 C/mol).

Firstly, write the half-reactions and then their standard reduction potentials:

Sn⁴⁺(aq) + 2e⁻  → Sn²⁺(aq) E°red = 0.15 V

Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn²⁺(aq) + 2Fe³⁺(aq) → Sn⁴⁺(aq) + 2Fe²⁺(aq)

The Q reaction quotient can be written as:

Q = [Sn⁴⁺][Fe²⁺]² ÷ [Sn²⁺][Fe²⁺]²

Substituting the given concentrations, we observe:

Q = (0.00655)(0.01139)² ÷ (0.0624)(0.0437)² = 0.209

Next, we can find the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe²⁺]²/[Fe³⁺]) + 0.0592 V log([Sn⁴⁺]/[Sn²⁺])

= 0.15 V + 0.0592 V log(0.01139²÷0.0437²) + 0.0592 V log(0.00655÷0.0624)

= 0.188 V

Thus, the cell potential for the given galvanic cell is 0.188 V.

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The given statement "production associates are not allowed to view the process safety management documents. They are only for supervisors and upper management" is true.

These documents are typically intended for supervisors and upper management, as they contain information related to the management of hazards and risks associated with specific processes or operations. This is to ensure that the management team has the necessary information to make informed decisions about process safety and to ensure that appropriate safety measures are in place to protect workers and the surrounding community.

Hence, It is important to note that access to PSM documents should be based on an individual's specific job responsibilities and the level of access needed to perform their duties. Some production associates may have access to certain PSM documents if their job responsibilities require it.

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See full question below

production associates are not allowed to view the process safety management documents.They are only for supervisors and upper management? true or false.

The answer responses to  the structures shown in the diagram are:

A. chromosomes

C. They would be the same.

B. They are in pairs because each one comes from a different parent.

The chromosomes are in pairs because humans have a diploid number of chromosomes, meaning they have two sets of chromosomes, one inherited from each parent.

The nucleus is important in eukaryotic cells and has many important parts that help the cell work properly. There are some parts inside cells called the nuclear membrane, nucleoplasm, nucleolus, and chromatin. Chromatin is made up of DNA and other proteins.

Every part of a person's body has the same genes, but the way they are organized can be different in different types of cells. The chromosomes in our skin cells might not be the same as the chromosomes in our muscle cells, even if they come from the same person.

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Identify the structures shown.

A. chromosomes

B. mitochondria

C. nuclei

D. vacuoles

C

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Explain why the structures are in pairs.

A. They aren't in pairs.

B. They are in pairs because each one comes from a different parent.

C. This cell is making a copy of itself.

D. The cell always has 2 copies in case 1 is damaged.

Miscible liquids are separated via a kind of distillation called fractional distillation. he mixture is typically divided into component parts after a series of distillations and condensations.

Miscible liquids are separated via a kind of distillation called fractional distillation. The mixture is typically divided into component parts after a series of distillations and condensations. When the combination is heated to a specific temperature where some of the mixture begins to vaporise, the separation takes place.

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The temperature in Celsius and kelvin is 50°C and 323.15 K.

The three most used temperature scales for usage in business, science, and daily life are Kelvin, Celsius, and Fahrenheit.

A scale in Kelvin is absolute. There are no degree symbols after its values, which begin at absolute zero.

Both Celsius and Fahrenheit are relative scales. The degree symbol is used to indicate Fahrenheit and Celsius temperatures.

Given the temperature is 122°F

Temperature in Celsius is -

⇒ C = (F - 32)/1.80

⇒ C = (122 - 32) / 1.80

⇒ C = 90 / 1.80

⇒ C = 50°C

Temperature in Kelvin is -

K = 5/9(F - 32) + 273.15

⇒ K = 5/9 (122 - 32) + 273.15

⇒ K = 323.15 K

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