Answer:
2.20 × 104 J
Explanation:
How much energy must be transferred out of the system as heat Q to lower its temperature to 0?C? ANSWER Q = 2.20 x 10^4. Cooling Power of P is 36.6 W.
Yash traveled 8 miles West and then 12 miles North, How far is he from his starting point?
A. 10 miles
B. 14.42 miles
C. 20 miles
D. 8.94 miles
I need help because I don't get it
Atmospheric pressure decreases as we move from the sea level to the high altitude
Explanation:
The air at higher altitude get rarer
In complete sentences describe the energy flow between the Sun, the Earth, and space
A car starts with velocity of 3m/s and moves in a straight line with a constant acceleration if the velocity at the end of 5sec is 5.5 m/s find the uniform acceleration and the distance travelled in 10sec
Answer:
\huge{\underline{\underline{.........Answer.........}}}
.........Answer.........
Given:-
u = 0.3 m/s
v = 5.5 m/s
t = 5 seconds
Explanation:-
Case-1
Acceleration = ?
From the first law of motion.
v = u + atv=u+at
a = \frac{v - u}{t}a=
t
v−u
a = \frac{5.5 - 0.3}{5}a=
5
5.5−0.3
a = \frac{5.2}{5}a=
5
5.2
a = 1.04a=1.04
\boxed{\boxed{a = 1.04 m/s^2}}
a=1.04m/s
2
So,the acceleration produced is 1.04 m/s^2.
Case-2
Distance travelled = ?.
From second equation of motion.
s = ut + \frac{1}{2} a {t}^{2}s=ut+
2
1
at
2
s = 0.3 \times 10 + \frac{1}{2} \times1.04 \times 100s=0.3×10+
2
1
×1.04×100
s = 3 + \frac{1}{2} \times 104s=3+
2
1
×104
s = 3 + 52s=3+52
s = 55 \: meterss=55meters
\boxed{\boxed{s = 55 meters}}
s=55meters
So,the distance travelled is 55 meters.
Explanation:
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Sally drove from New York to Washington and back again. She
averaged 50 mph on the way and 60 mph on the way back. The round
trip took her 18 hours. How far apart are the two cities?
Sally drove from New York to Washington and back again. The distance between New York and Washington is 490.91 miles.
The average speed is = Distance/time,
x/50 + x/60 = 18
6x/300 + 5x/300 = 18
11x / 300 = 18
11x = 18 × 300
11x = 5400
x = 5400 / 11
x = 490.91 Miles.
Hence, the distance between New York and Washington is 490.91 miles.
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what is the mass of metal if it has a density of 12.459 hg/cm^3 and displaces 28.7cm^3 of water
Answer:
357.6g
Explanation:
Given parameters:
Density = 12.459g/cm³
Volume of metal = 28.7cm³
Unknown:
Mass of metal = ?
Solution:
The density of a substance is its mass per unit volume.
To find the mass;
Mass of metal = density x volume
Now insert the parameters and solve;
Mass of metal = 12.459 x 28.7 = 357.6g
Suppose you drop a feather and a hammer on the moon from the same height at the same time. what will happen?
The feather fell at the same rate as the hammer.
The Moon's surface gravity is about 1/6th as powerful or about 1.6 meters per second per second. The Moon's surface gravity is weaker because it is far less massive than Earth. A body's surface gravity is proportional to its mass, but inversely proportional to the square of its radius.
Gravity accelerates both objects at the same rate, but if no other force than gravitational force act on the object , and as we know that air resistance affect the rate of fall but at moon their is no air resistance. Hence their is no other force acting on the feather and hammer than the gravitation force of moon .
Because the Apollo crew were essentially in a vacuum, there was no air resistance, the feather fell at the same rate as the hammer. This is exactly what Galileo had concluded hundreds of years before: all objects released together fall at the same rate regardless of mass.
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it is idea being transmitted by the sender to the receiver. it includes three aspects-content, structure, and style
Answer: The options are not given,
Here are the options.
A. channel
B. feedback
C. message
D. sender
The correct option is C
MESSAGE.
Explanation:
It is message because it is written or verbal or recorded words or communication or ideas transmitted by the sender to the receiver.
It include three aspects, content, structure and style.
The content entails the information and communication, how the information is important, useful and can be read to comprehend.
The structure of a message entails the tone .
The style include how the sender compose and write the message.
Communication is an activity that involves encoding, and decoding, medium and feedback processes
The correct option for the idea transmitted from the sender to the receiver is message
The reason why message is correct is as follows:
Question: The possible question options are;
Channel
Message
Feedback
Sender
Channel: A channel is a means of communicating a message. It does not always have the features of content, or style
Feedback: A feedback is the information pertaining to a reaction to a message. It does not have a specific structure or depend on style
Sender: A sender is the person from whom a message originates. A sender does not have a content
Message
A message is a unit of communication, that is sent by a sender, to reach an audience which is the receiver. A message may written, verbal or recorded, a message is meant for a recipient that cannot be reached directly
A message contains contains
Information which is the content. The structure of a message relates to the ordering of the information to achieve the message's purpose. The style of a message refers to the way words are used in the message, which may be formal, informal, original, journalistic, or archaicTherefore;
Message is the idea being transmitted by the sender to the receiver. It includes three aspects-content, structure, and style
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a baseball is hit with a horizontal speed of 16 m/s and a vertical speed of 12 m/s upward. what are these speeds 5 s later?
After t = 4 seconds, ascertain the baseball's vx and vy horizontal and vertical speeds. Only the pressure applied on the object's vertical component—gravity—is recognized by us. This indicates that the perpendicular speed is unchanged.
What is the easiest way to define gravity?A planet and maybe other bodies pull objects toward their centers through their gravitational force. The gravitational attraction of the sun keeps all of the planets in their orbit around it.
How do these two things affect gravity?The size of an object and its distance from other things both have an impact on gravity. The mass of a thing is a gauge for its matter content. A heavier object will fall to the ground more quickly than a lighter one. Gravitational pull weakens when the separation between two objects grows.
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A spring of k=500 N/m that is initially compressed 2m is used to launch a 100N load of bricks up a 2 m tall
hill. Find the speed of the bricks at the top of the hill.
a. Qualitatively complete the energy flow diagram and the energy bar graphs.
c. Determine the speed
e. What would the speed at the top of the hill be with 2m of initial compression if 15% of the energy is
dissipated through friction?
d. What is the minimum compression of the spring necessary to get to the top of the hill? (v=0 at top, no
friction)
Speed of the bricks at the top of hill is 6.26 m/s. c.)speed of the bricks at the top of hill is 14.14 m/s. d)minimum compression of spring necessary to get to the top of hill is 6.26 m. e) speed of the bricks at the top of hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.
What is energy?The capacity or power to do work, such as the capacity to move an object by application of force is called energy.
Initial potential energy of compressed spring is:
Ep = 1/2 kx^2 = 1/2 * 500 N/m * (2 m)^2 = 1000 J
k is spring constant, x is compression of the spring, and J is unit of energy in joules.
Final potential energy of the bricks is:
Ep = mgh = 100 N * 9.81 m/s^2 * 2 m = 1962 J
Ep = Ep
1/2 kx^2 = mgh
v = sqrt(2gh) = sqrt(2 * 9.81 m/s^2 * 2 m) = 6.26 m/s
Therefore, the speed of the bricks at the top of the hill is 6.26 m/s.
c. Initial potential energy of compressed spring is: 1000 J
Ek = Ep = 1000 J
Kinetic energy of the bricks is given by:
Ek = 1/2 mv^2
1000 J = 1/2 * 100 N * v^2
v = sqrt(200 / 1) = 14.14 m/s
Therefore, the speed of the bricks at the top of the hill is 14.14 m/s.
d. As, Ep = m g h
where m is mass of the bricks, g is acceleration due to gravity, and h is height of the hill.
Ep = 100 N * 9.81 m/s^2 * 2 m = 1962 J
Ep = 1/2 kx^2 = 1962 J
1/2 * 500 N/m * x^2 = 1962 J
x = sqrt(2 * 1962 J / 500 N/m) = 6.26 m
Therefore, the minimum compression of the spring necessary to get to the top of the hill is 6.26 m.
e. If 15% of the energy is dissipated through friction, final kinetic energy of the bricks at the top of the hill will be 85% of initial potential energy of the compressed spring. Therefore,
0.85 * 1000 J = 1/2 mv^2
v = sqrt(170 / 1) = 13.04 m/s
Therefore, the speed of the bricks at the top of the hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.
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What separates the two sections of the solar system?.
Answer:
These two groups of planets are separated by the asteroid belt, a disk of small rocky bodies orbiting the sun between Mars and Jupiter.
Explanation:
Your welcome!
What is the possible unit for the current VI would be is a petition difference across the resistor and I is a current through the same resister
Answer:
The unit of potential difference generated between two points is called the Volt and is generally defined as being the potential difference dropped across a fixed resistance of one ohm with a current of one ampere flowing through it. In other words, 1 Volt equals 1 Ampere times 1 Ohm, or commonly V = I*R.
Explanation:
For example, the potential difference (voltage) across a resistor can be found by multiplying its resistance by the current flowing through it. The unit of voltage is the Volt (V). Current is measured in Amperes (A
What is it called when two waves combine to form a new wave?
Answer:
interference
Explanation:
You can just search this.
How do I get my Ollie higher??? I can do an Ollie well but I can’t get any height it only goes about 3 inches in the air. Any tips?
when you’re trying to ollie higher, your front foot will be slightly farther back than it normally is. this lets you drag more on the board, helping you get the height you need. hope this helped :)
Answer: I had the same problem if I was you I would use my phone and record a slowdown of your ollie. Also pop hard and focus on how much you jump, your ollie is only going to go as high as you jump so try to get some Hight also do moving first it helps in the long run trust if you dont its just as hard as learning how to ollie in the first place.
Explanation: keep riding I hope the best
In a 200.0-m relay race (each leg of the race is 50.0 m long), one swimmer has a 0.450 second lead
and is swimming at a constant speed of 3.90 m/s towards the opposite end of the pool. What minimum
speed must the second swimmer have in order to catch up with the first swimmer by the end of the
pool?
The minimum speed that the second swimmer must have in order to catch up with the first swimmer by the end of the pool is; 4.04 m/s
We are given the following facts;
Both swimmers swim the same distance of 50 m for a leg of the relay race.Swimmer 1 swims at constant speed of 3.9 m/s. Swimmer 1 has a 0.450 second head start.Formula for time taken is;
time = distance/speed
Time taken by swimmer 1 for one leg;
t₁ = 50/3.9
t₁ = 12.82 s
Since swimmer 1 has a head start of 0.45 s, then time that swimmer 2 must use in order to catch up is;
t₂ = 12.82 -0.45
t₂ = 12.37 s
Thus, speed of swimmer 2;
v = 50/12.37
v = 4.04 m/s
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Hi I don’t understand question and can really use some help! :D
Given
Mass of one of the object is doubled and the distance between the object is doubled.
To find
What happens to the gravitational force
Explanation
The gravitational force is directly proportional to the masses and inversely proportional to the distance between them
Keeping all other parameters constant,
\(F\propto\frac{m}{d^2}\)So when the mass doubles and the distance doubles we have,
\(\begin{gathered} F^{\prime}\propto\frac{2m}{(2d)^2} \\ \Rightarrow F\propto\frac{m}{2d}=\frac{F}{2} \end{gathered}\)Conclusion
A. The gravitational force becomes half as great.
3. What gases compose the lower atmosphere, and what are examples of variable gases?
4. How does the atmosphere change in properties of air pressure and temperature with rise or fall in altitude, and what rates are useful to estimate how much change occurs with altitude in the Troposphere layer?
The lower atmosphere is primarily composed of nitrogen and oxygen (about 21%). Variable gases present in smaller amounts include carbon dioxide, water vapor, methane, ozone, and trace amounts of other gases.
The lower atmosphere, also known as the troposphere, is the layer closest to the Earth's surface. It is primarily composed of nitrogen, accounting for approximately 78% of the gases present, and oxygen, which makes up about 21%. These two gases are considered the main components of the lower atmosphere.
In addition to nitrogen and oxygen, there are variable gases present in smaller amounts. One example is carbon dioxide (CO2), which plays a crucial role in the Earth's climate system as a greenhouse gas. Another variable gas is water vapor (H2O), which can vary in concentration depending on the humidity of the air. Water vapor is an important component for the Earth's weather patterns and can influence temperature and precipitation.
Other variable gases include methane (CH4), which is another greenhouse gas with a significant impact on climate change; ozone (O3), which is found in the upper troposphere and stratosphere and plays a crucial role in absorbing ultraviolet radiation from the Sun; and trace amounts of other gases such as noble gases (argon, neon, helium, etc.) and pollutants like sulfur dioxide (SO2), nitrogen oxides (NOx), and volatile organic compounds (VOCs).
The properties of air pressure and temperature change with altitude in the troposphere. Air pressure refers to the force exerted by the weight of the air molecules above a given point. As altitude increases, the density of air decreases, leading to lower air pressure. Temperature, on the other hand, generally decreases with an increase in altitude in the troposphere.
The rate at which the temperature changes with altitude is called the lapse rate. On average, the lapse rate in the troposphere is about 6.5 degrees Celsius per kilometer (3.6 degrees Fahrenheit per 1,000 feet). This means that for every kilometer you ascend in the troposphere, the temperature decreases by approximately 6.5 degrees Celsius. However, it's important to note that the actual lapse rate can vary depending on various factors such as weather conditions, geography, and time of day.
Estimating changes in air pressure with altitude can be done using the barometric formula, which takes into account the decrease in air density as altitude increases. However, it's worth mentioning that air pressure can also be influenced by weather patterns, temperature variations, and local geography.
In summary, the lower atmosphere is primarily composed of nitrogen and oxygen, with variable gases such as carbon dioxide, water vapor, methane, ozone, and trace amounts of other gases. As altitude increases in the troposphere, air pressure decreases, while temperature generally decreases at a rate of approximately 6.5 degrees Celsius per kilometer.
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The force required to accelerate a 0.50kg ball at 50 m/s2 is (Remember F=ma) 25N 25K 50N 250N
Answer:
25n
Explanation:
I hope this helps:)
50 x 0.50
The force required to accelerate a 0.50 kg ball at 50 m/s² is 25 N.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Force = mass*acceleration
Force = 50 x 0.50
Force = 25 N
The force required to accelerate a 0.50 kg ball at 50 m/s² is 25 N.
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Through which material do sound waves tend to move the most quickly
When a sound wave passes through a material, it causes the particles of that material to vibrate back and forth in the same direction as the wave.
In solids, the particles are tightly packed together and have strong intermolecular forces holding them in place. This means that when a sound wave passes through a solid, the vibrations are transmitted quickly from one particle to next. In liquids, particles are still close together, but they are not held in place as tightly as in solids. In gases, the particles are much more spread out and have weaker intermolecular forces. Sound waves tend to move more quickly through solids because of the tight packing of the particles.
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what is ccl4 compound name
Tetrachloromethane is the name given to the CCl4 chemical.
Structure of carbon tetrachloride chemically. The liquid CCl4 is transparent, nonflammable, and heavy. It evaporates quickly and has a distinctive sweet smell that is similar to that of chloroform. The term "volatile organic compound" refers to CCl4 (VOC).
The secondary prefix for four carbon atoms is tetra. The first prefix for chlorine is chloro. Meth represents the word's root, which is carbon. Tetrachloromethane, which may also be written as 1,1,1,1, is the name of the substance. a week ago With the chemical formula CCl4, carbon tetrachloride is an organochlorine chemical compound that goes by several different names.
covalent substance Since it has four non-polar covalent connections between carbon and chlorine, carbon tetrachloride (CCl4) is classified as a covalent molecule.
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a) A cell of dry air is moved vertically from its original position under adiabatic conditions. Depending on the temperature profile of the surrounding atmosphere, this gas cell can keep on moving in the same direction, or it may come back to its original position. Considering the temperature profile of the atmosphere, change of the air cell temperature as it moves up and down in the surrounding atmosphere, as well as relative densities of the air cell and atmosphere, explain why and when the atmosphere is considered to be convectively stable and convectively unstable. In answering this question, use diagrams of temperature change with altitude. (13 marks) b) Explain why the adiabatic lapse rate of dry air is different from the adiabatic lapse rate of wet saturated air. Show them both in a diagram. (5 marks) c) Wet unsaturated air rises from the ocean surface. The ambient lapse rate is higher than the adiabatic lapse rate for dry air. There is a temperature inversion layer at higher altitudes. Show in a schematic diagram how the temperature of the wet air changes with altitude, in comparison with the ambient temperature. Explain at what altitudes the cumulus clouds are formed and why. (7 marks)
The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.
a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.
In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.
b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).
This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.
c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.
In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.
Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.
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a man weighing 660 n and a woman weighing 440 n have the same momentum. what is the ratio of the man's kinetic energy km to that of the woman kw ?
The ratio of the man's kinetic energy to the woman's kinetic energy is 4:3.
The ratio of the man's kinetic energy (Km) to the woman's kinetic energy (Kw) can be found using the formula for momentum (P) and kinetic energy (K):
P = mv (momentum equals mass times velocity)
K = (1/2)mv² (kinetic energy equals one-half mass times velocity squared)
Given that both individuals have the same momentum:
Pm = Pv (man's momentum equals woman's momentum)
660 * vm = 440 * vw (where vm and vw are the velocities of the man and woman, respectively)
Solve for the ratio of their velocities:
vm/vw = 440/660
vm/vw = 2/3
Now, find the ratio of their kinetic energies:
Km/Kw = (1/2) * (660) * vm² / [(1/2) * (440) * vw²]
Km/Kw = (660 * vm²) / (440 * vw²)
We already know that vm/vw = 2/3, so substitute and square both sides:
(vm/vw)² = (2/3)²
vm²/vw² = 4/9
Now plug this back into the kinetic energy ratio equation:
Km/Kw = (660 * (4/9)) / 440
Km/Kw = (4/3)
So the ratio of the man's kinetic energy to the woman's kinetic energy is 4:3.
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what is the difference between true north and magnetic north called?
true North is fixed point on the globe
magnetic North is the direction that a compass needle points to as it aligns with the earths magnetic field and what is interesting is that the magnetic North pole shifts and changes over time in response to change in the earth's magnetic core
4) A drag racer starts her car from rest and accelerates at 10.0 m/s² for a distance of 400 m (1/4 mile). (a) How long did it take the race car to travel this distance? (b) What is the speed of the race car at the end of the run?
Answer:
A) s=1/2at^2
t=√(2s/a)=√(2x400)/10.0)=9.0s
B) v=at
v=10.0x9=90m/s
Jane measures a piece of metal and determines it has a mass of 10 grams and a volume of 2 mL. What is the density of the piece of metal?
Answer: 5g/ml
Explanation:
A block of aluminum has a volume of 15.0 ml and a mass of 50.5 g. the density is ___________. group of answer choices
A block of aluminum has a volume of 15.0 ml and a mass of 50.5 g. the density is: 3.36 g/ml
To solve this problem the density formula and the procedure that we have to use is:
d = m/v
Where:
v= volumed= densitym= massInformation about the problem:
v= 15.0 mlm= 50.5 gd = ?Applying the density formula we get:
d = m/v
d = 50.5 g/15.0 ml
d= 3.36 g/ml
What is density?It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.
What is volume?
It is the space occupied by a body, it is calculated by multiplying its dimensions, for example: length, height and width.
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The bus covered a distance of 120 km in 2 hours and covered 80 km in the first half of the time and 40 km in the second half. What is the average speed of the bus?
The average speed of the bus is 60 km/hr.
What is the average speed of the bus?To find the average speed of the bus, we can use the formula:
Average speed = total distance traveled / total time taken
The total distance traveled by the bus is 80 km + 40 km = 120 km, which is given in the problem statement.
The total time taken by the bus is also given as 2 hours.
Therefore, the average speed of the bus can be calculated as:
Average speed = total distance traveled / total time taken
= 120 km / 2 hours
= 60 km/hr
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Compare the magnitude of the electromagnetic and gravitational force between two electrons separated by a distance of 2.00 m. Assume the electrons have a mass of 9.11 × 10–31 kg and a charge of 1.61 × 10–19 C. Round to two decimal places. Fe = × 10–29 N Fg = × 10–71 N F Subscript e baseline over F Subscript g baseline.= × 1042
Two metal spheres with the same charge, q, are in contact and experience an electrostatic force of magnitude F. 2.3x10 N 66.
What connection can be seen between the mass of the items, their distance from one another, and the strength of the gravitational pull between them?A mass-bearing item will pull toward another mass-bearing object. The strength of the force is directly proportional to the masses of the two objects and inversely proportional to the square of their distances from one another.
How much do two electrons separated in space weigh in terms of electrostatic and gravitational forces?Consequently, the ratio of electric to gravitational force between two electrons is 4.17 1042.
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