If a 46 kg person walks up two floors in the Physics building (about 10 meters up), this person's potential energy has increased by _____ J.a. 1400 J b. 10,000 J. c. 1000 J. d. 100 J

Answer:

not too sure but i think it is : force - multiplied by -mass

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

Answer:

(1.8 × 10^9) meters in one minute

Explanation:

To determine how far light can travel in one minute, we need to multiply its speed by the number of seconds in a minute.

The speed of light is 3 × 10^8 meters per second.

There are 60 seconds in a minute.

Therefore, the distance light can travel in one minute is:

Distance = Speed × Time

Distance = (3 × 10^8 meters per second) × (60 seconds)

Calculating this, we get:

Distance = 3 × 10^8 meters/second × 60 seconds

Distance = 18 × 10^8 meters

Distance = 1.8 × 10^9 meters

So, light can travel approximately 1.8 billion (1.8 × 10^9) meters in one minute.

Answer:

=125 tysm for points

Explanation:

Answer: 125

Explanation: I good at addition

Let both the balls have the same mass equals to m.

Let \(v_1\) and \(v_2\) be the speed of the ball1 and the ball2 respectively, such that

\(v_1>v_2\;\cdots(i)\)

Assuming that both the balls are at the same level with respect to the ground, so let h be the height from the ground.

The total energy of ball1= Kinetic energy of ball1 + Potential energy of ball1. The Kinetic energy of any object moving with speed, \(v\), is \(\frac 12 m v^2\)

and the potential energy is due to the change in height is \(mgh\) [where \(g\) is the acceleration due to gravity]

So, the total energy of ball1,

\(=\frac 12 m v_1^2 + mgh\;\cdots(ii)\)

and the total energy of ball1,

\(=\frac 12 m v_2^2 + mgh\;\cdots(iii)\).

Here, the potential energy for both the balls are the same, but the kinetic energy of the ball1 is higher the ball2 as the ball1 have the higher speed, refer equation (i)

So, \(\frac 12 m v_1^2 >\frac 12 m v_2^2\)

Now, from equations (ii) and (iii)

The total energy of ball1 hi higher than the total energy of ball2.

Answer:

9800 m

Explanation:

During acceleration, given:

v₀ = 0 m/s

a = 39.2 m/s²

t = 10.0 s

Find: v and Δy

v = at + v₀

v = (39.2 m/s²) (10.0 s) + 0 m/s

v = 392 m/s

Δy = v₀ t + ½ at²

Δy = (0 m/s) (10.0 s) + ½ (39.2 m/s²) (10.0 s)²

Δy = 1960 m

During free fall, given:

v₀ = 392 m/s

v = 0 m/s

a = -9.8 m/s²

Find: Δy

v² = v₀² + 2aΔy

(0 m/s)² = (392 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 7840 m

Therefore, h = 1960 m + 7840 m = 9800 m.

Answer:

Explanation:

Ideal gas equation- The volume (V) occupied by the n moles of any gas has pressure(P) and temperature (T) Kelvin,

the relationship for these variables PV=nRT where R gas constant is called the ideal gas law

Derivation of the Ideal Gas Equation

Let us consider the pressure exerted by the gas to be ‘p,’

The volume of the gas be – ‘v’  

Temperature be – T  

n – be the number of moles of gas

Universal gas constant – R

According to Boyle’s Law,

it constant n & T, the volume bears an inverse relation with the pressure exerted by a gas.

i.e. v∝1p ………………………………(i)

According to Charles’ Law,

When p & n are constant, the volume of a gas bears a direct relation with the Temperature.

i.e. v∝T ………………………………(ii)

According to Avogadro’s Law,

When p & T are constant, then the volume of a gas bears a direct relation with the number of moles of gas.

i.e. v∝n ………………………………(iii)

Combining all the three equations, we have-

v∝nTp

or pv=nRT

where R is the Universal gas constant, which has a value of 8.314 J/mol-K

A. Δx = 384,400 km (distance between Earth and Moon)

B. Δt = 384,400 km / (0.930 * 299,792 km/s) ≈ 1.421 s

C. s² ≈ (-2.781 * 10^10) km² (imaginary number, time-like separated events)

D, E, F. Cannot answer without specified primed frame.

G. Δx for laser beam = 384,400 km

H. Δt for laser beam = 384,400 km / 299,792 km/s ≈ 1.282 s

I. s² for laser beam ≈ 0 km² (light-like separated events)

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Answer:

191 cm³

Explanation:

We'll begin by converting celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 20 °C

Initial temperature (T₁) = 20 °C + 273

Initial temperature (T₁) = 293 K

Final temperature (T₂) = 100 °C

Final temperature (T₂) = 100 °C + 273

Final temperature (T₂) = 373 K

Finally, we shall determine the final volume of the air. This can be obtained as follow:

Initial volume (V₁) = 150 cm³

Initial temperature (T₁) = 293 K

Final temperature (T₂) = 373 K

Pressure = constant

Final volume (V₂) =?

V₁/T₁ = V₂/T₂

150 / 293 = V₂ / 373

Cross multiply

293 × V₂ = 150 × 373

293 × V₂ = 55950

Divide both side by 293

V₂ = 55950 / 293

V₂ ≈ 191 cm³

Thus, the final volume of the air is 191 cm³

Answer:

Nuclear fusion

Explanation:

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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The displacement of the train after 2.23 seconds is 25.4 m.

The resultant velocity of the train is calculated as follows;

R² = vi² + vf² - 2vivf cos(θ)

where;

R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)

R² = 129.75

R = √129.75

R = 11.39 m/s

The displacement is calculated as follows;

Δx = vt

Δx = 11.39 m/s x 2.23 s

Δx = 25.4 m

Thus, the displacement of the train after 2.23 seconds is 25.4 m.

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Answer:

C 0.81 m/s (I think, I got around 0.8163, so C seems to be the correct answer)

Explanation:

First, we need the acceleration formula:

a = \(\frac{delta v}{delta t} = \frac{v_{f} - v_{i} }{t}\)

where:

- \(v_{f}\) is the final velocity (speed with direction, which we have, it's west)

- \(v_{i}\) is the starting velocity

- t is total time

Then we plug in what we know and solve:

a = \(\frac{7 - 5}{2.45}\)

a = \(\frac{2}{2.45}\)

a = 0.81632 etc

So our answer becomes 0.82 (they did not round and just cut it off, so we get) C 0.81 m/s as our answer!

Hope this helps :))

Answer:

19

Explanation:

I legit did this and it took 19.

Explanation:

Downstream: you just sum the magnitude of the velocity vectors:

3km/h + 4km/h = 7km/h

Upstream: difference of the magnitudes of the velocity vectors, in absolute value:

|3km/h - 4km/h| = 1km/h

The sentence that best describes the motion is "the motion is a circular motion and has completed one revolution".

Question: "If a car moved one full circular track of 15 Km, which sentence describes its motion?​"

An object moves in a circle at a constant speed in a motion known as uniform circular motion. Any point on a propeller, for instance, that is spinning continuously, is moving uniformly in circles.

There are two types of circular motion: uniform and non-uniform.

Circular motion can be seen in the orbit of a satellite, ice skaters moving at a constant speed in a circle, and vehicles traveling in a circle.

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A) To find the spring constant of the spring, we can use the conservation of energy. The spring constant of the spring is 1378.8 N/m.

B) The equilibrium point is at a height of 0 meters.

C)  The frequency of the oscillation is: f = 1/T ≈ 6.25 Hz

y(t) = 0.05 cos (2 π × 6.25 where y is in meters and t is in seconds.

The positive direction is from the equilibrium point.

a) To find the spring constant of the spring, we can use the conservation of energy. At the maximum height, the ball has no kinetic energy, so all the energy stored in the spring has been transferred to potential energy in the ball. The potential energy stored in a spring is given by:

PE = (1/2) k S^2

where k is the spring constant and S is the distance the spring is compressed. The potential energy stored in the spring must be equal to the potential energy of the ball at its maximum height. Using the given values, we can set up the equation:

(1/2) k S^2 = M g H

where M is the mass of the ball, g is the acceleration due to gravity, and H is the maximum height reached by the ball. Solving for k, we get:

k = 2 M g H / S^2

Substituting the given values, we get:

k = 2 × M × 9.81 m/s^2 × 0.35 m / (0.05 m)^2 = 1378.8 N/m

Therefore, the spring constant of the spring is 1378.8 N/m.

b) The equilibrium point of the ball when it is sitting on the spring with no forces other than gravity and the spring acting on it is the unscratched point of the spring. We can choose this point as the origin of our coordinate system, and take the upward direction as positive. Therefore, the equilibrium point is at a height of 0 meters.

c) When the ball is glued onto the spring and oscillates up and down, its motion can be described by a simple harmonic motion equation:

y(t) = A cos (ω t)

where y is the position of the ball, A is the amplitude of the oscillation, ω is the angular frequency, and t is the time. The amplitude of the oscillation is equal to the initial compression of the spring, which is 0.05 meters. The angular frequency is given by:

ω = 2 π f

where f is the frequency of the oscillation. The frequency of the oscillation is related to the period of the oscillation T by:

T = 1/f

The period of the oscillation can be found using the formula for the period of a simple harmonic motion:

T = 2 π √(m/k)

where m is the mass of the ball and k is the spring constant. Substituting the given values, we get:

T = 2 π √(0.1 kg / 1378.8 N/m) ≈ 0.16 s

Therefore, the frequency of the oscillation is:

f = 1/T ≈ 6.25 Hz

Substituting these values in the equation for the position of the ball, we get:

y(t) = 0.05 cos (2 π × 6.25 t)

where y is in meters and t is in seconds. The positive direction is upward from the equilibrium point.

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The wavelength of an electromagnetic wave is inversely proportional to the  frequency of the wave. Thus, the one with less frequency have longer wavelength. Therefore, routers and Bluetooth electronics work at comparatively longer wavelength.

The wavelength of an electromagnetic wave is the distance between two consecutive crests or  troughs. Wavelength and frequency are in inverse proportionality.

The speed of a an electromagnetic wave is equal to the speed of light that is 3 × 10⁸ m/s. The wavelength of microwave operate at 2.45 GHz or 2.45 × 10⁹ Hz is :

wavelength = speed / frequency

                    = 3 × 10⁸ m/s / 2.45 × 10⁹ Hz

                    = 0.122 m.

The wavelength for electronics and routers with 2.4 GHz is:

=  3 × 10⁸ m/s / 2.4 × 10⁹ Hz

                    = 0.125 m.

Therefore, electronic gadgets and routers will have relatively higher wavelength.

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The work done in dragging an object along a straight path is  173.2 J.

Work done is equal to product of force applied and distance moved.

Given You are trying to drag an object 5.0 m along a straight path. You are pulling with a force of 40 N along a rope that is inclined 30° to the horizontal.

Work = Force x Distance x cos(angle)

W= 40 x 5 x cos 30°

W = 173.2 Joules

Thus, the work done is  173.2 Joules

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-- If the two resistors are connected in series, then they behave like a single resistor whose resistance is (R₁ + R₂) ohms.

-- For any resistance, the potential difference (volts) across the resistance is   V = (current) x (resistance) .

-- So in THIS circuit,  V = I x (R₁ + R₂) .

A box puts a pressure of 50 N/\(m^{2}\) on an area of 0.25 \(m^{2}\). The force of the box on the floor is 12.5 Newton (N)

Pressure is defined as the physical force exerted on an object. The force applied is perpendicular to the surface of objects per unit area. The basic formula for pressure is \(\frac{F}{A}\) (Force per unit area). Unit of pressure is Pascals (Pa). Types of Pressures are Absolute, Atmospheric, Differential, and Gauge Pressure.

Using the formula Force = Pressure × Area

given Pressure = 50 N/\(m^{2}\)

area = 0.25 \(m^{2}\)

Substituting the values ,

Force = 12.5 Newton

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5.8N. is the correct answer .

What is Torque ?

In physics and engineering, "torque" is a measure of the twisting force that can cause an object to rotate around an axis or pivot point The magnitude of torque depends on both the force being applied and the distance between the axis of rotation and the point of application of the force. The direction of the torque is determined by the right-hand rule, with the thumb pointing in the direction of the applied force and the fingers curling in the direction of rotation. Torque is a key concept in the study of mechanics and is used in a wide range of applications, such as engines, motors, and machines.

τ1=+r1w1sin90=+r1m1g(counterclockwise rotation, positive sense)

τ2=+r2w2sin90°=r2m2g(counterclockwise rotation, positive sense)

τ=+rwsin90°=+rmg(gravitational torque)

τS=rSFSsinθS=0(because S=0cm)τ3=−r3w3sin90°=−r3m3g(clockwise rotation, negative sense)

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Light is perceived as having color because of the way our brains interpret the wavelengths of light that reach our eyes.

This statement above is based on the scientific understanding of color and light. Light is a type of electromagnetic radiation that travels through space in waves. The color we perceive depends on the wavelength of the light; different wavelengths are perceived as different colors. However, light itself does not have a color, it is simply a form of energy.

Our brain interprets the wavelength of light that enters our eye and assigns it a color based on past experiences and cultural norms. This means that the concept of color is a subjective interpretation, and is not inherent in the light itself. So, it can be said that color exists only in our minds.

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Answer:

The kinetic energy of a spinning disk will be reduced to a tenth of its initial kinetic energy if its moment of inertia is made five times larger, but its angular speed is made five times smaller.

Explanation:

Let us first consider the initial characteristics of the angular motion of the disk

moment of inertia = \(I\)

angular speed = ω

For the second case, we consider the characteristics to now be

moment of inertia = \(5I\)  (five times larger)

angular speed = ω/5  (five times smaller)

Recall that the kinetic energy of a spinning body is given as

\(KE = \frac{1}{2}Iw^{2}\)

therefore,

for the first case, the K.E. is given as

\(KE = \frac{1}{2}Iw^{2}\)

and for the second case, the K.E. is given as

\(KE = \frac{1}{2}(5I)(\frac{w}{5} )^{2} = \frac{5}{50}Iw^{2}\)

\(KE = \frac{1}{10}Iw^{2}\)

this is one-tenth the kinetic energy before its spinning characteristics were changed.

This implies that the kinetic energy of the spinning disk will be reduced to a tenth of its initial kinetic energy if its moment of inertia is made five times larger, but its angular speed is made five times smaller.

A spinning disk's kinetic energy will change to one-tenth if its moment of inertia was five times larger but its angular speed was five times smaller.

Relation between Kinetic energy and Moment of Inertia:

Now, let's consider moment of inertia =  I  and angular speed = ω

It is asked that what would be change in Kinetic energy if

moment of inertia =   (five times larger)

angular speed = ω/5  (five times smaller)

The kinetic energy of a spinning body is given as:

\(K.E.=\frac{1}{2} I. w^2\)

On substituting the values, we will get:

\(K.E.= \frac{1}{2} (5I) (\frac{w}{5} )^2 \\\\K.E. =\frac{1}{10} I. w^2\)

Kinetic energy will be one-tenth to the kinetic energy before its spinning characteristics were changed.

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Answer: False

Explanation:

It's received in elliptical cavities.

False. The statement is not entirely accurate. Condyloid joints are a type of synovial joint that allow movement in two planes, similar to an ellipsoid joint.

These joints are characterized by an oval-shaped projection of one bone fitting into an elliptical cavity of another bone. The term "condyle" does refer to a rounded projection or bump on a bone, but not all condyle bone markings create condyloid joints.

Condyloid joints are found in various parts of the body, such as the wrist (between the radius and carpal bones) and the knuckles (between the metacarpal bones and phalanges). They allow for movements such as flexion, extension, abduction, adduction, and circumduction.

It's important to note that the formation of a condyloid joint involves not only the presence of condyle bone markings but also the specific structural arrangement of the bones and the presence of articular cartilage, joint capsule, and synovial fluid. Therefore, while the term "condyle" is related to these joints, it does not accurately capture the complexity of their formation and function.

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Answer:

Explanation:

The time taken to travel from Fort Worth to Dallas is:

t = 3:23 pm - 2:41 pm = 42 minutes = 0.7 hours

The distance covered is:

d = 58 km

The average speed is:

v = d/t = 58 km / 0.7 hours = 82.86 km/h

To convert km/h to m/s, we can use the conversion factor:

1 km/h = 0.2778 m/s

Therefore, the average speed in m/s is:

v = 82.86 km/h × 0.2778 m/s/km = 23.06 m/s (rounded to two decimal places)

So the average speed is 23.06 m/s.

Answer: The focal length of the cornea-lens system in his eye must be LESS THAN the distance between the front and back of his eye.

Explanation:

The human eye the front part of the eye is the CORNEA. This is the tough white transparent part of the eye that helps in the refraction of light rays. While the backside of the eye is the RETINA. This is the part of the eye when images are focused.

When a normal eye is at rest, parallel rays from a distant object are focused on the retina. The ability of the eye - lens to focus points at different distances on the retina is known as accomodation. The adjustment of the eye lens to focus objects of varying distances is brought about by the ciliary muscles. The have the ability to change the shape of the eye which leads to change in focal length.

When a person with normal vision looks at a distant object at infinity, the lens brings parallel rays to focus on the retina. Thus, the furthest point which the eye can see distinctly is called the far point of the eye and it's infinity for a normal eye. But Joe was able to focus his eye on the tree, meaning that the tree was within his near point. This is the nearest point at which an object is clearly seen. Therefore, when the effective focal length of the cornea-lens system changes, it changes the location of the image of any object in one's field of view.

Segment a, which is drawn from the center of the polygon perpendicular to one of its sides, is called the apothem.

The typical hexagon has a surface area of around 874.6 square meters.

To find the area of a regular polygon, use the formula:

Area = (1/2) x Perimeter x Apothem

Find the perimeter of the polygon. Since the polygon has n sides, use the formula:

Perimeter = n x s

where s = length of one side.

Since s = 18m, find n by using the formula:

n = 360° / (180° - (360° / n))

where n = number of sides.

Plugging in the values:

n = 360° / (180° - (360° / n))

n = 360° / (180° - (360° / 6))

n = 6

So the polygon has 6 sides, which makes it a hexagon.

Now find the perimeter:

Perimeter = n x s

Perimeter = 6 x 18

Perimeter = 108m

Next, find the apothem, use the formula:

Apothem = s / (2 x tan(π/n))

Plugging in the values:

Apothem = 18 / (2 x tan(π/6))

Apothem = 9√3 m

Now use the formula for the area:

Area = (1/2) x Perimeter x Apothem

Area = (1/2) x 108 x 9√3

Area ≈ 874.6 m²

Therefore, the area of the regular hexagon is approximately 874.6 square meters.

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