if electrons are ejected from a given metal when irradiated with a red laser pointer, what will happen when the same metal is irradiated with a green laser pointer of comparable intensity?if electrons are ejected from a given metal when irradiated with a red laser pointer, what will happen when the same metal is irradiated with a green laser pointer of comparable intensity?electrons will be emitted, and the maximum kinetic energies of those electrons will be similar to those emitted when irradiated with the red laser pointer.electrons will be emitted, and the maximum kinetic energies of those electrons will be less than those emitted when irradiated with the red laser pointer.electrons will not be emitted.electrons will be emitted, and the maximum kinetic energies of those electrons will be greater than those emitted when irradiated with the red laser pointer.

As the height of the hole increases, the velocity of the stream increases, results in a higher distance from the beaker. Therefore, the distance of the stream from the hole Y will be less than that from X thus, less than 5 cm is correct.

The speed of stream can be determined using the height and acceleration due to gravity g. We can use the equation for velocity using the parameters g and h.

v = √2gh

Therefore, as the height h increases, v increases.

Similarly the distance s = vt

therefore, the distance increases with v.

Here, the hole x is above the hole Y. Then the stream from X will have the greater speed and it covers greater distance (5 cm )from the beaker. Stream from Y slow compared to that in X hence covers a distance less than 5 cm. Hence, option 2 is correct.

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Impedance of the input Z = (100 - j50) || (150 + j50) + j100 = 150 + j100

A current source is included in the series RLC circuit that is being provided. We must determine the equivalent impedance of the circuit as seen from the input terminals in order to determine the input impedance.

The capacitor and inductor's impedance at 400 rad/s can be computed as follows:

ZC = 1/jC = (400 x 10-6 x 400)/j = -j6.25

ZL = j,L = j x 400 x 10-3 x 20, which equals j8,

It is possible to determine the overall impedance of the parallel configuration of a 100 resistor and a -j6.25 capacitor as follows:

Z1 = (100 - j6.25) Ω

It is possible to compute the overall impedance of the parallel configuration of a 150 resistor and a j8 inductor as follows:

Z2 = (150 + j8) Ω

The series combination of Z1 and Z2 is the circuit's equivalent impedance, and it is:

Zeq = Z1 + Z2

= (100 - j6.25) || (150 + j8) = [(100 - j6.25)(150 + j8)] / (100 - j6.25 + 150 + j8) = (150 + j100) Ω

Last but not least, the circuit's input impedance at 400 rad/s is:

Z=Zeq+j100=(150 + j100)+j100=150 + j200 Ω

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The probability density function of X is plotted for a=1/2 and a=2.

The expected value of X (E[X]) is determined.

The expected value of 1/X (E[1/X]) is determined.

The variance of X (V[X]) is determined.

The median of X is determined.

When a=1/2, the probability density function of X is given by p(X=x∣a)=((1/2)+1)x(1/2)^0=(3/2)x for x∈[0,1]. When a=2, the probability density function becomes p(X=x∣a)=(2+1)x^2=3x^2 for x∈[0,1]. To plot the probability density function, we can assign different values of x within the range [0,1], calculate the corresponding probabilities using the given formulas, and plot the points on a graph.

The expected value of X (E[X]) is calculated by integrating the product of X and its probability density function over the range [0,1]. For a=1/2, E[X] = ∫(x * (3/2)x) dx from 0 to 1. For a=2, E[X] = ∫(x * 3x^2) dx from 0 to 1. By evaluating these integrals, we can determine the expected values.

The expected value of 1/X (E[1/X]) is calculated similarly to E[X], but instead of integrating X, we integrate 1/X using the respective probability density functions for different values of a.

The variance of X (V[X]) can be computed by taking the second moment of X (E[X^2]) minus the square of the first moment (E[X]) squared. V[X] = E[X^2] - (E[X])^2. By calculating E[X^2] using the probability density function and the expected values obtained in step 2, we can determine the variances for different values of a.

The median of X is the value of X such that the cumulative distribution function (CDF) is equal to 0.5. To find the median, we integrate the probability density function from 0 to the median value and set it equal to 0.5. Solving for the median provides its value in terms of the parameter a.

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Answer:

16.64 km/h

Explanation:

Think of the x and y components as the a and b sides of a triangle and simply do the Pythagorean Theorem:

\(a^2+b^2=c^2\)

\(14^2+9^2=c^2\)

\(\sqrt{196+81}=c\)

\(\sqrt{277}=c\)

\(16.64 km/h\)

The frictional force acting on the box is just opposite to the normal force acting on the box by its weight. Here, the frictional force is,

Friction is a kind force that opposes the normal force acting on an object. The frictional force, is a resistive force having a negative sign always. The frictional force increases as the roughness of the surface through which the object is moving.

Here, the mass of the box m = 11.54 kg

angle of sliding  = 31.04 °

acceleration due to gravity of earth = 9.8 m/s²

The frictional force that opposes the motion of the box sliding down the surface is just opposite to the normal force on the box by its own weight.

F = - mg cosθ

  = - 11.54 kg ×  9.8 m/s² × 31.04°

  = -105.9 N

Therefore, the frictional force acting on the box is -105.9 N.

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Answer:

The weight of the astronaut in Earth's orbit 400 km above the Earth's surface is 664.115 N

Explanation:

The given parameters are;

The weight of the astronaut on the ground = 750 N

The height of the orbit above the Earths surface = 400 km

The radius of the Earth = 6.38 × 10⁶ m

The mass of the Earth = 5.97 × 10²⁴ kg

The universal gravitational constant G = 6.674 × 10⁻¹¹ Nm²/kg²

From Newton's law of universal gravitation, we have;

\(Weight \ on \ ground \ of \ astronaut \ F_W =G\times \dfrac{M_{Earth} \times m_{astronouat}}{R_{Earth}^{2}} = 750 \ N\)

\(F_W =6.674 \times 10^{-11}\times \dfrac{5.97 \times 10^{24}\times m_{astronouat}}{(6.38 \times 10^6)^{2}} = 750 \ N\)

\(m_{astronaut}\) = ((6.38 × 10⁶)² × 750)/((6.674 × 10⁻¹¹) × (5.97 × 10²⁴)) ≈ 76.62 kg

The mass of the astronaut ≈ 76.62 kg

For the weight of the astronaut  in Earth orbit 400 km (400 × 10³ m) above the Earth's surface, we have;

\(F_{W \ in \ orbit} =6.674 \times 10^{-11}\times \dfrac{5.97 \times 10^{24}\times 76.62}{(6.38 \times 10^6 + 400 \times 10^3)^{2} } = 664.115 \ N\)

The weight of the astronaut in Earth's orbit 400 km above the Earth's surface = 664.115 N.

Answer:

465000 meters

Explanation:

kilometer to meter = ×1000

465 × 1000 = 465000

Answer:

465000 M

Explanation:

1Km = 1000m

465Km= (465)(1000)

465000

Answer:

B

Explanation:

When the ball is dropped, Earth's mass generates a gravitational force, making it fall downward towards the ground.

Answer:

example of adaptation in mangrove

Mangroves are salt-tolerant trees, also called halophytes, and are adapted to life in harsh coastal conditions. They contain a complex salt filtration system and complex root system to cope with salt water immersion and wave action. They are adapted to the low oxygen conditions of waterlogged mud.

adaptation of rainforest

Many animals have adapted to the unique conditions of the tropical rainforests.

hope this can help you

Answer:

An egg with a thick shell.

Explanation:

Hope this helps.

The point along the x-axis where the electric field is zero is approximately at x = 17.833 cm.

To find the point along the x-axis where the electric field is zero, we can use the principle of superposition for electric fields. The electric field at a point due to multiple charges is the vector sum of the electric fields created by each individual charge.

In this case, we have two point charges: +3.3 µC at x = 0 cm and -7.6 µC at x = 40 cm.

Let's assume the point where the electric field is zero is at x = d cm. The electric field at this point due to the +3.3 µC charge is directed towards the left, and the electric field due to the -7.6 µC charge is directed towards the right.

For the electric field to be zero at the point x = d cm, the magnitudes of the electric fields due to each charge must be equal.

Using the formula for the electric field of a point charge:

E = k × (Q / r²)

where E is the electric field, k is the Coulomb's constant, Q is the charge, and r is the distance.

For the +3.3 µC charge, the distance is d cm, and for the -7.6 µC charge, the distance is (40 - d) cm.

Setting the magnitudes of the electric fields equal, we have:

k × (3.3 µC / d²) = k × (7.6 µC / (40 - d)²)

Simplifying and solving for d, we get:

3.3 / d² = 7.6 / (40 - d)²

Cross-multiplying:

3.3 × (40 - d)² = 7.6 × d²

Expanding and rearranging terms:

132 - 66d + d² = 7.6 × d²

6.6 × d² + 66d - 132 = 0

Solving this quadratic equation, we find two possible solutions for d: d ≈ -0.464 cm and d ≈ 17.833 cm.

However, since we are considering the x-axis, the value of d cannot be negative. Therefore, the point along the x-axis where the electric field is zero is approximately at x = 17.833 cm.

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Answer:

The answer is C

Explanation:

I ave K12 and i just finished it.

The phrase which is not an example of intracellular communication is :

C) Molecule in a cell changes function of cell.

The phrase which is not an example of intracellular communication is the molecule in a cell changes function of cell.

The intracellular communication could be a sort of communication which takes put inside a cell or interior a cell.

The intracellular speaks to inside a cell, subsequently, the development of the particle inside a cell may be with cytoplasmic gushing, cargo vesicle transport or any other instrument will speak to the intracellular communication.

Thus, the correct answer is C.

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The magnetic field is tilted toward the east at point A because it is 12.3 degrees off the vertical. A measure of the strength of the magnetic field, 5 nt (nanotesla) is given as the magnitude of the field at point A.

The following formula describes the magnetic force exerted on a charged particle that is moving:

F = q v B sin(theta)

Where F is the force, q is the particle's charge (in this case, an electron's charge\(-1.6 x 10^{-19}\) \(C)\), v is the particle's velocity, B (465\(m/s\)) is the strength of the magnetic field, (5 nT =\(5 x 10^{-9}\) \(T\))and theta is the angle between the magnetic field vector, and the velocity vector (12.3 degrees = 0.214 radians).

(a) Plugging in the values, we get:

F =\((1.6 x 10^{-19}\) \(C)\)\((465)m/s(5 x 10^{-9}\) \(T)\)\(sin(0.214)\)

F ≈\(1.02 x 10^{-17}\) \(N\)

Therefore, the magnitude of the magnetic force on an electron at Point A is approximately \(1.02 x10^{-17}\)\(N.\)

(b) The acceleration of the electron can be found using the formula:

ᵃ = \(F/m\)

where F is the magnetic force calculated above, and m is the mass of the electron \((9.11 x 10^{-31}\) \(kg).\)

Plugging in the values, we get:

ᵃ =\((1.02 x 10^{-17}\)\(N)/(9.11 x 10^{-31}\) \(kg)\)

ᵃ ≈\(1.12 x 10^{13}\) \(m/s^{2}\)

Therefore, the magnitude of the acceleration of the electron at Point A is approximate \(1.12 x 10^{13}\) \(m/s^{2}\).

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An item obtains mechanical energy when an external force applies positive work to it.

The object experiences negative work when the force and displacement are in the opposite directions; as a result, the item loses mechanical energy.

The power needed, which is defined as energy per unit of time, depends on the velocity.

More power is needed to move a certain distance quickly, thus you must provide the same quantity of energy over a shorter period of time.

Work is defined as the energy transferred while exerting force to move an item across a distance. It is the result of distance and force.

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After considering the given data the height from which the gannet dived is approximately 51.84 m.

To evaluate the height from which a gannet dived if it hits the water at 32 m/s, assuming that the gannet was motionless before starting its dive, we can apply the law of conservation of energy, which projects  that the initial potential energy of the gannet is equivalent to its final kinetic energy prior to hitting the water. Then, we can write:
\(mgh = (1/2)mv^2\)
Here:
m = mass of the gannet
g = acceleration due to gravity
h = height from which the gannet dived
v = velocity of the gannet just before hitting the water
Considering that the mass of the gannet is 1 kg, and applying substitution of the given values, we get:
\((1 kg)(9.8 m/s^2)(h) = (1/2)(1 kg)(32 m/s)^2\)
\(h = (1/2)(32 m/s)^2 / (9.8 m/s^2)\)
h = 51.84 m
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The complete question is
A gannet is a seabird that fishes by diving from a great height. If a gannet hits the water at 32 m/s , what height did it dive from? Assume that the gannet was motionless before starting its dive.

Answer:

wrapping around the wire around iron core several times

Explanation:

adding more turns to the coil. increasing the current flowing through the coil.

Explanation

a uniformly accelerated motion is the one in which the acceleration of the particle throughout the motion is uniform,to fidn the time take we can use the formula:

Step 1

a)Let

b) now, replace

therefore, the answer is 2 seconds

I

a) The angular velocity, ω, is 1.2 rad/s counterclockwise. b) The velocity of the center O is 1.8 ft/s to the right.


a) To find the angular velocity ω, we can use the formula ω = vC / r, where vC is the linear velocity at point C (5 ft/s) and r is the radius of the gear. First, find the radius using the given linear velocity at point A (3 ft/s) and the known relationship v = rω. Rearrange the formula to get r = v / ω. Since v = 3 ft/s, r = 3 / ω. Now substitute r into the first formula: ω = 5 / (3 / ω). Solve for ω to get ω = 1.2 rad/s counterclockwise.

b) To determine the velocity of the center O, use the formula vO = v - ωr, where v is the linear velocity at point A (3 ft/s), ω is the angular velocity found in part a (1.2 rad/s), and r is the radius found earlier. Substitute the values into the formula: vO = 3 - (1.2)(3 / 1.2). Simplify to get vO = 1.8 ft/s to the right.

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The frequency of the horn heard by both drivers is approximately 152.1 Hz.

The beat frequency of 8.7 Hz indicates that the frequency of the horn heard by the stationary driver is slightly different from the frequency of the horn heard by the moving driver. This difference in frequency is caused by the Doppler effect, which occurs when the source of sound (the horn) is moving relative to the observer (the drivers).

The frequency of sound waves increases as the source moves toward the observer and decreases as the source moves away from the observer. Therefore, the frequency of the horn heard by the moving driver is slightly higher than the frequency of the horn heard by the stationary driver.

To calculate the actual frequency of the horn, we need to know the frequency of the beat that the stationary driver hears and the speed of sound in air. Assuming the speed of sound is approximately 343 m/s, the frequency of the horn can be calculated as follows:

Frequency of horn = Frequency of beat + (Speed of sound / Speed of moving driver) x Frequency of beat
Frequency of horn = 8.7 Hz + (343 m/s / 20 m/s) x 8.7 Hz
Frequency of horn = 152.1 Hz

Therefore, the frequency of the horn heard by both drivers is approximately 152.1 Hz.

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Answer:

The force exerted between the two charges is 0.0001248N

Explanation:

we will be using Columb's law to solve this problem.

Columb's law explains that the Force between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Mathematically,

\(F = K\frac{Q_1 \times Q_2}{r^2}\)

WHere K = constant of proportionality = \(8.9875 \times 10^9 N m^2/c^2\)

\(F = 8.9875 \times 10^9 \times\frac{2.5 \times10^{-6} \times 4.5 \times 10^{-7}}{9^2}= 0.0001248N\)

The force exerted between the two charges is 0.0001248N

In response to the embargo, the US government imposed fuel rationing and lowered speed limits to reduce consumption Nixon seriously considered military action to seize oil fields in Saudi Arabia, khuwait and Abu Dhabi as a last resort.

Hope these helps you.

Answer:

its electrons

Explanation:

only electrons stays outside the nucleus unlike protons and neutrons and it has little to no mass

Rounding to the nearest mile, the estimated distance you can travel is approximately 198 miles.

To estimate the distance you can travel in 4 hours and 50 minutes at an average speed of 41 miles per hour, we need to convert the time to hours.

4 hours and 50 minutes is equivalent to 4.83 hours (since 50 minutes is 50÷60 = 0.83 hours).

Now, we can calculate the distance traveled using the formula: distance = speed × time.

Distance = 41 miles/hour × 4.83 hours

Distance ≈ 198.03 miles

Rounding to the nearest mile, the estimated distance you can travel is approximately 198 miles.

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You have a circuit of four 4.5 v d-cell batteries in series, some wires, and a light bulb, the bulb is lit and the current flowing through the bulb is depends on its resistance.

When four 4.5 V D-cell batteries are connected in series, the total voltage is 18 V. This voltage pushes the current through the light bulb, causing it to light up. The exact amount of current that flows through the bulb depends on its resistance. However, the current flowing through the bulb can be calculated using Ohm's Law.

Ohm's Law states that the current through a conductor between two points is directly proportional to the voltage across the two points. The constant of proportionality is the resistance of the conductor, this means that I = V / R, where I is the current, V is the voltage, and R is the resistance. In this case, since the bulb is lit, we know that there is current flowing through it. However, without knowing the resistance of the bulb, we cannot calculate the exact value of the current. So therefore the bulb is lit and the current flowing through the bulb is depends on its resistance.

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Explanation:

The force would be net positive.

Answer:

yes,  majority of the weight will be supported by the front wheel and not by you.

Explanation: