KINEMATICS: MOTION ALONG STRAIGHT LINE
The nearest grocery is 60m, east from your house. You are walking at 1.2 m's for 15.Os toward
the grocery when it started to rain and you ran back to your house to get an umbrella. It took
you another 5.0s to go back to your house. You start walking again at 1.2m's until you reach
the grocery. (a) What is your average speed? (b) What is your average velocity?

The voltage drop across R3 is 34.5 volts.

Voltage, also known as electric potential difference, is a measure of the difference in electric potential energy between two points in an electrical circuit, and it is measured in volts. It is the driving force that moves electric charges through a circuit, from a higher potential to a lower potential.

To determine the voltage drop across R3 in this circuit, we need to first find the equivalent resistance of R2, R3, and R4, since they are connected in parallel. We can then find the total resistance of the circuit by adding the equivalent resistance in series with R1, and finally use Ohm's Law to calculate the voltage drop across R3.

The equivalent resistance of R2, R3, and R4 in parallel can be calculated as:

1/R_parallel = 1/R2 + 1/R3 + 1/R4

1/R_parallel = 1/20 + 1/25 + 1/10

1/R_parallel = 0.15

R_parallel = 1/0.15

R_parallel = 6.67 ohm

The total resistance of the circuit can be found by adding R1 and the equivalent resistance in series:

R_total = R1 + R_parallel

R_total = 15 + 6.67

R_total = 21.67 ohm

Now we can use Ohm's Law to calculate the current flowing through the circuit:

I = ET / R_total

I = 30 / 21.67

I = 1.38 A

Finally, we can use Ohm's Law again to calculate the voltage drop across R3:

V_R3 = I * R3

V_R3 = 1.38 * 25

V_R3 = 34.5 V

Therefore, the voltage drop across R3 is 34.5 volts.

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Atomic number(Z) is the number of protons present in an atom.

Answer:

M v^2 / R = centripetal force

For Red: M v^2 / R = 5 * 9^2 / 1.5 = 270

For Blue M v^2 / R = 270 = 25 * 1.8^2 / Rb

So Rb = 25 * 1.8^2 / 270 = .3 m

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Jupiter

Answer:

a) the torque required is  10.53 N-m

b) The magnitude force applied tangentially is 12.33 N

Explanation:

Given the data in the question;

mass m = 1.765 kg

radius r = 0.854 m

first we calculate the moment of inertia;

\(I\) = \(\frac{2}{5}\)mr²

we substitute

\(I\) = \(\frac{2}{5}\) × 1.765 × (0.854)²

\(I\) = 0.514897 kg.m²

a)

Find the torque required to bring the sphere from rest to an angular velocity of 317 rad/s, clockwise, in 15.5 s

ω\(_{initial\) = 0

ω\(_{final\) = 317 rad/s

t = 15.5 s

we know that; ω\(_{final\) = ω\(_{initial\) + ∝t

so we substitute

317 = 0 + ∝(15.5)

∝ = 317 / 15.5

∝ = 20.4514 rad/s²

so

ζ = \(I\) × ∝

we substitute

ζ = 0.514897 × 20.4514

ζ = 10.53 N-m

Therefore, the torque required is  10.53 N-m

b)

What magnitude force applied tangentially at the equator would provide the needed torque.

ζ = F × r

we substitute

10.53  = F × 0.854

F = 10.53 / 0.854

F = 12.33 N

Therefore, magnitude force applied tangentially is 12.33 N

Answer:

0.667 cm

Explanation:

|F_1on3| = |F_2on3|

k×q1×q3/x^2 = k×q2×q3/(d-x)^2

q1/x^2 = q2/(d-x)^2

(d-x)^2/x^2 = q2/q1

(d-x)/x = sqrt(q2/q1)

(2 - x)/x = sqrt(4×q/q)

(2 - x)/x = 2

2 - x = 2x

2 = 3x

x = 2/3

x= 0.667 cm

Answer:

Explanation:

Too much information.

At 60° the cord tension must have a vertical component to support the weight and a horizontal component to provide the required centripetal force

tan60 = (mv²/R) / mg = v²/Rg

tan60 = v² / (Lsin60)g

v² = Lgsin60tan60

v² = 2(9.8)sin60tan60

v² = 29.4

v = 5.42 m/s

The ball MUST be moving at 5.42 m/s for the string to make a 60° angle with the vertical.

Let's see if the string is strong enough to do the task

Vertical force requirement

Fy = mg = 0.400(9.8) = 3.92 N

Horizontal force requirement

Fx = mv²/R = 0.400(29.4)/(2sin60) = 6.7896 N

total tension in the cord

F = √(3.92² + 6.7896²) = 7.84 N

so the cord is strong enough and has a safety factor of 60 / 7.84 = 7.7

But the question is asking what is the highest speed the ball can achieve without breaking.

For this we MUST ignore the 60° limit. The cord will be much closer to 90° from the vertical.

We already know the tension must supply 3.92 N vertically.

So the cord on the verge of breaking is at an angle of

θ = arccos(3.92/60) = 86.25°

and has a centripetal force of

Fx = 60sin86.25 = 59.8715 N

Fx = mv²/R

v² = RFx/m = (Lsinθ)Fx / m

v = √(2sin86.25)(59.8715) / 0.400)

v = 17.28342...

v = 17 m/s

Answer: False

Explanation:

The statement that the environment affects people, but people don't affect the environment is incorrect. It should be noted that people also affect the environment.

Some of our impact on the environment include pollution, deforestation, overpopulation, burning of fossil fuels etc. Thus has resulted in changes such as erosion, climate change, etc.

Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

The air will be when it stops moving 180J.

The generally accepted boundary where space begins, which is also the point where the atmospheric pressure is assumed to be zero, is called the Kalman line. Simply put, gases move from areas of high pressure to areas of low pressure. And the greater the pressure difference, the faster air moves from high pressure to low pressure. This draft is the wind we experience.

As the air rises the surface pressure decreases. As the air rises, it expands and cools adiabatic cooling that is, it cools by changing volume rather than by increasing or decreasing heat. As a result, condensation/sedimentation occurs. Cold air sinks. The boundary between Earth and space is called the Kalman Line, an imaginary line 100 kilometers above Earth. This line is considered the boundary between space and the Earth's atmosphere.

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The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer: MAGNITUDE AND DIRECTION OF A VECTOR

Explanation: Given a position vector →v=⟨a,b⟩,the magnitude is found by |v|=√a2+b2. The direction is equal to the angle formed with the x-axis, or with the y-axis, depending on the application.

Answer:

sorry i didn't understand

Answer:

\(3 \times 10 {}^6\)

Answer:

the sun is larger than the moon so it creates a shadow

Answer: while electric fields aren’t visible or tangible, they are mensurable.

Explanation: you might want to attach the experiment notes to your question***

Answer: 13 miles.

Explanation:

ANSWER:

a. Velocity decreased

STEP-BY-STEP EXPLANATION:

If the person inside the bus experiences a forward movement, this means that the bus is braking, since by action-reaction to compensate for the movement, the body moves forward.

When braking, it means that there is a decrease in speed, therefore, the correct answer is a. Velocity decreased

Answer:

m₁ = 1720

m₂ = 413.46

m₃ = 586.54

mr = 720

Explanation:

Draw a diagram.  Sea water (1000 lb/h, 3.1% salt) is mixed with the recycled brine (mr, 5.25% salt) to create the inlet stream (m₁, 4.0% salt).  This inlet stream is fed into the osmosis cell.  The osmosis cell produces desalinated water (m₂, 500 ppm) and brine tailings.  Part of the tailings is recycled (mr, 5.25% salt), and the rest is removed (m₃, 5.25%).

The mass of water is conserved, so:

1000 + mr = m₁

m₁ = mr + m₂ + m₃

The mass of salt is conserved, so:

0.031 (1000) + 0.0525 mr = 0.040 m₁

0.040 m₁ = 0.0525 mr + 0.0005 m₂ + 0.0525 m₃

Four unknown variables, and four equations.  We can use the first and third to find mr and m₁.

0.031 (1000) + 0.0525 mr = 0.040 (1000 + mr)

31 + 0.0525 mr = 40 + 0.040 mr

0.0125 mr = 9

mr = 720

m₁ = 1720

Now we can use these values and the second and fourth equations to solve for the remaining variables.

1720 = 720 + m₂ + m₃

0.040 (1720) = 0.0525 (720) + 0.0005 m₂ + 0.0525 m₃

1000 = m₂ + m₃

68.8 = 37.8 + 0.0005 m₂ + 0.0525 m₃

68.8 = 37.8 + 0.0005 m₂ + 0.0525 (1000 − m₂)

68.8 = 37.8 + 0.0005 m₂ + 52.5 − 0.0525 m₂

0.052 m₂ = 21.5

m₂ = 413.46

m₃ = 586.54

Answer:

b. they both have permanent magnets and elctromagnetes

Answer:

A)    Magnetic and electric are part of the same force - see Maxwell's equations.

Answer:

3 maybe 4 seconds

Explanation:

The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.

Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.

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Answer:

60mph=26.8224meters per second

Explanation:

The examples of ohmic conductors​ are :

Silver(Ag), copper(Cu), aluminium(Al) etc.

Ohmic conductors means which conductors strictly obey the Ohm's law, are known as Ohmic conductors.  

Resistance= \(\frac{Voltage}{Current}\)

In other words there is a linear relationship between voltage and current for all values. That means all the ohmic conductor materials shows a linear character in the V-I characteristic graph.

So, the examples of ohmic conductors are:

Silver(Ag), copper(Cu), aluminium(Al) etc.

All the conductors we mentions here, they all show a linear line in the V-I characteristic graph.

From the above discussion we can conclude that, Silver(Ag), copper(Cu), aluminium(Al) etc. these are the ohmic conductors.

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Answer:

E. converging surface winds

Explanation:

For the formation of tropical cyclones to occur in the northeast of the tropical Pacific Ocean, it is necessary to have converging surface winds that present a strong convection. This allows for the formation of vertical movements of an ascending nature that have great strength and are intense and violent. This also allows closed cyclonic circulation to occur at the lower levels which together with a low frontal pressure system over the waters of the Pacific Ocean can form the tropical cyclone.

Answer:

If a ray of light hits the surface of a sheet of glass, some light will be reflected by the surface of the glass. However, much of the light will pass through the glass, because glass is transparent. ... This 'bending of a ray of light' when it passes from one substance into another substance is called refraction.

Explanation:

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Answer:

yea yes they can they lose their retina but they can dream

The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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