What are the measures of angles P and S?

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

subatomic particles are actually small than atoms

Yes, particles such as protons, neutrons, and electrons that make up the atom are smaller than atoms.

The compound that is shown as X can be seen in the option labelled C

The process of esterification involves the condensation of an alcohol (or phenol) with an acid to produce an ester. To create the ester bond, the water molecule must be removed from the alcohol and acid (dehydration).

Usually, an acid catalyst is used to catalyze the reaction, which makes it easier to remove water and encourages the creation of the ester. The acid catalyst aids in protonating the acid's carbonyl oxygen, which increases its electrophilicity and makes it more vulnerable to alcohol's nucleophilic attack.

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Answer:

0.43 atm

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 0.95 atm

Initial volume (V₁) = 0.55 L

Final volume (V₂) = 1.22 L

Final pressure (P₂) =?

The final pressure of the gas can be obtained by using the Boyle's law equation as follow:

P₁V₁ = P₂V₂

0.95 × 0.55 = P₂ × 1.22

0.5225 = P₂ × 1.22

Divide both side by 1.22

P₂ = 0.5225 / 1.22

P₂ = 0.43 atm

Therefore, the final pressure of the gas is 0.43 atm

The final pressure of the gas is 0.43 atm.

Pressure is the process of force exerted perpendicular to any surface.

Given, the Initial pressure (P₁) is 0.95 atm

The initial volume (V₁) is 0.55 L

The final volume (V₂) is 1.22 L

To find the final pressure (P₂)

By the Boyle's Law

\(\rm P_1V_2= P_2V_2\)

\(\rm 0.95\times 0.55 = P_2\times1.22\\\\0.5225 = P_2 \times 1.22\\\\Divided\;both \;side\;by\;1.22\\\\P_2=\dfrac{0.5225}{1.22} = 0.43 atm.\)

Thus, the final pressure of the gas is 0.43 atm.

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Answer:29.232

Explanation:6.023x10^23

Water and salt is a correct combination. Therefore, the correct option is option A among all the given options.

Chemical reaction, the transformation of one or more chemicals (the reactants) into one or more distinct compounds (the products). Chemical elements or chemical compounds make up substances. In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products.

Chemical reactions are a fundamental component of life itself, as well as technology and culture. Burning fuels, melting iron, creating glass as well as pottery, brewing beer, producing wine, and making cheese are just a few examples of ancient processes that involved chemical reactions. Water and salt is a correct combination.

Therefore, the correct option is option A.

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Answer:

equal and opposite

Explanation:

The size of the forces on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object

Answer:
You will need 6.4 joules

If the potassium atoms could be lined up in a row, it would take to make a 1.00 ft row of potassium atoms is 5.45 × 10⁻⁸.

Potassium atom is represented by K with atomic number 19. It is a silvery white metal.

Given,

Radius = 280pm = 280 × 10⁻¹²m

Diameter = 2radius = 560× 10⁻¹²m = 560pm

We know that,

1 feet = 0.305m

So, number of potassium atoms that fits into the row,

1 feet = 0.305/560 × 10⁻¹²

1 feet = 5.45 × 10⁻⁸

Hence, it takes 5.45 × 10⁻⁸ atoms of potassium to make a 1 feet row.

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Explanation:

Pressure = Force/Area

therefore,

P = 15/0.00372

= 4.03 X10^³N/m²

We can see here that the best fuel is the one that produces the most heat per unit mass. In this case, the fuel that produces the most heat per unit mass is methanol.

Fuel is a substance that is used to produce energy through combustion or other chemical reactions. It is commonly utilized to power various forms of transportation, generate heat or electricity, and operate machinery and appliances.

The results of the experiment are shown below:

Fuel            Mass (g)      Heat produced (J)       Heat per gram (J/g)

Methanol 1.0                          350                   350

Ethanol         1.0                          250                   250

Propane         1.0                          200                   200

Butane         1.0                          150                            150

Pentane         1.0                          100                            100

It is important to note that the results of this experiment are only a measure of the heat produced by the fuels.

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Answer:

Calculate the mass of iron(III) oxide (Fe20) that contains a trillion (1.000x 10") oxygen atoms. Be sure your answer has a unit symbol if necessary, and round it to 4 significant digits. A chemist measures the amount of oxygen gas produced during an experiment. He finds that 9.2 g of oxygen gas is produced.

Explanation:

Answer: 0.400L of argon contains 0.0179 moles of argon gas at STP

Explanation:

The question requires us to calculate how many moles of argon gas are there in a 0.400 L, considering the standard temperature and pressure conditions (STP).

At STP, we can say that 1 mol of any gas corresponds to 22.4 L of this gas. Also, as a gas occupies the entire volume of the flask it is contained, we can assume that the volume of argon gas is 0.400 L.

Thus, we can calculate the number of moles of gas as:

22.4 L Ar ---------------------- 1 mol Ar

0.400 L Ar -------------------- x

Solving for x, we'll have:

Therefore, 0.400L of argon contains 0.0179 moles of argon gas at STP.

Answer:

t = 39.42 days

Explanation:

To do this, we need to use the general expression for decay rate:

R = R₀ exp(-λt)    (1)

According to the problem, decay rate of A initially is 64 times rate of B, so we can say the following:

A₀ = 64B₀   (2)

The value of λ can be determined using:

λ = ln2 / t(1/2)  (3)

Let's calculate first the value of λ for each nuclei:

For A: λ₁ = ln2 / 5 = 0.1286 day⁻¹

For B: λ₂ = ln2 / 30 = 0.0231 day⁻¹

Now, let's write an expression using (1) for each nuclei.

A = A₀ exp(-0.1286t)

A = 64B₀ exp(-0.1286t)   (3)

B = B₀ exp(-0.0231t)    (4)

We want to know the time when A = B , therefore, we can actually equals (3) and (4) and solve for t:

64B₀ exp(-0.1286t) = B₀ exp(-0.0231t)

64 exp(-0.1286t) = exp(-0.0231t)

ln(64 * exp(-0.1286t)) = ln(exp(-0.0231t))

ln64 + ln(exp(-0.1286t))= -0.0231t

4.1589 - 0.1286t = -0.0231t

4.1589 = (0.1286 - 0.0231)t

t = 4.1589 / 0.1055

So, in 39 days, the decay rates of A and B will be the same.

Hope this helps

The rainwater sample has a pH of 4.35, indicating that it is acidic. The concentration of \(H_3O^+\) ions in the sample is \(4.47 * 10^{-5} M\), which is higher than in neutral or basic solutions.

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The given statement stating that air quality is a measure of how clean or polluted the air  in an ecosystem is, hence the statement is  true.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .

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Answer:

elections my compromise judicial impartiality

Answer:

one of them will probably argue with another person

Explanation:

Answer: 7.52*10^23 molecules.

Explanation: This is a classic Stoichiometry problem.

In one mole of any substance, there are 6.02*10^23 molecules. This number is called Avogadro's number. We are given 55 grams of Co2 so to convert that to moles, we divided by the molar mass of Co2. We find the molar mass by adding the molar masses of the elements that make up the compound.

There is one molecule of Carbon and two molecules of Oxygen in one molecule of Co2. From the periodic table, the molar mass of Carbon is 12.01 and 16.00 for Oxygen. 1(12.01)+2(16.00) gives us the molar mass. We then divided 55 grams by that mass to find the number of moles. We then multiply the number of moles by Avogadro's number (6.02*10^23) to find the total number of molecules.

You can use this method for solving any problem that asks you to find the number of atoms or molecules of some number of grams of a substance.

Answer:

lungs

Explanation:

Answer:

Liquid from nonvolatile solids can be separated by distillation .

I HOPE IT WILL HELP YOU.

^ - ^

Explanation:

Simple distillation is used to separate from sea water to separate sugar from water

If there are 4 moles of O2, 0.6667 moles of the C6H12O6 are present.

If there are 4 moles of oxygen present. In that case, we can use the balanced chemical equation for glucose combustion to calculate the number of moles of glucose required to react with it.

According to the equation, one mole of glucose reacts with six moles of oxygen to produce six moles of carbon dioxide and six moles of water. The number of moles of glucose required to react with it is calculated by dividing the number of moles of oxygen by six.

So, if 4 moles of oxygen are present, 0.6667 moles of glucose must react with it.

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The thickness of the aluminum is approximately 0.00172 cm or 0.0172 mm

To calculate the thickness of the aluminum, we need to use the formula:

Density = Mass / (Length x Width x Thickness)

Given:

Mass of aluminum = 0.475 g

Length of aluminum = 10.08 cm

Width of aluminum = 10.08 cm

We need to rearrange the formula to solve for thickness:

Thickness = Mass / (Length x Width x Density)

The density of aluminum is approximately 2.7 g/cm³.

Now we can substitute the given values into the formula:

Thickness = 0.475 g / (10.08 cm x 10.08 cm x 2.7 g/cm³)

Thickness ≈ 0.475 g / (102.4064 cm² x 2.7 g/cm³)

Thickness ≈ 0.475 g / 275.879104 cm³

Thickness ≈ 0.00172 cm or 0.0172 mm

Therefore, the thickness of the aluminum is approximately 0.00172 cm or 0.0172 mm.

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Answer:

Acid spills should be neutralized with sodium bicarbonate and then cleaned up with a paper towel or sponge.

Explanation:

Answer:

I can not see the file

Explanation:

Lithium is the element because only lithium atom with 3 protons in this diagram.

An element is a pure substance that cannot be broken down into simpler substances through physical or chemical means.

Lithium is the symbol for the element. Because lithium has three protons, it has the atomic number 3. Because lithium atoms contain either 3 or 4 neutrons, it has an atomic mass of 6.94. On the periodic table, lithium is in group 1 and has one valence electron.

Thus, Lithium is the element because only lithium atom with 3 protons in this diagram.

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Answer:

D.

Explanation:

they have simaliar chemical and physical properties

Answer:b

Explanation:i just did it

1. Using your knowledge of the Brønsted-Lowry theory of acids and bases, complete the following acid-base reactions and indicate each conjugate acid-base pair.

i. OH + HPO₂ → H₂O + H₂PO₄²⁻

The conjugate acid-base pair is OH/H₂O, HPO₂²⁻/H₂PO₄²⁻

2) Identify the conjugate acid-base pairs in the following reactions. Write A, B, CA, and CB below the appropriate substance.

i. HCO₃⁻ + NH₃ → NH₄⁺ + CO₃²⁻

The conjugate acid-base pair is HCO₃⁻/CO₃²⁻, NH₃/NH₄⁺

ii. HCI + H₂O → H₃O⁺ + Cl⁻

The conjugate acid-base pair is H₂O/OH⁻, HCI/Cl⁻, H₃O⁺/H₂O, Cl⁻/HCI

iii. CH₃COOH + H₂O → H₃O⁺ + CH₃COO⁻

The conjugate acid-base pair is CH₃COOH/CH₃COO⁻, H₂O/OH⁻, H₃O⁺/H₂O

iv. HOCI + NH₃ → NH₄⁺ + ClO⁻

The conjugate acid-base pair is HOCI/ClO⁻, NH₃/NH₄⁺

3. Write the formula for conjugate bases formed by the following acids.

i. HPO₄²⁻ → PO₄³⁻

ii. H₂O → OH⁻

iii. CN⁻ → HCN

iv. HOOC-COO⁻ → HOOCCOOH

4) Write the formula for conjugate acids formed by each of the following bases.

i. H₃O⁺ → H₂O

ii. HCN → H₂CN⁺

iii. NH₃ → NH₄⁺

5. Classify each of the following pH values as acidic, basic, or neutral.

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