what does a notational anaylist do?

The motorbike travels at a speed of 40 m/s

the speed at which an object's location changes in any direction. The distance traveled divided by the time it took to travel that distance indicates how fast something is moving.

Kinetic energy, which may be seen in the movement of an item or subatomic particle, is the energy of motion. Kinetic energy is present in every particle and moving object.

KE = ½ m\(V^{2}\)

We have kinetic energy of 200,000 j, mass of 250 kg , so to fine \(v^{2}\)

using KE = ½ m\(V^{2}\)

kinetic energy will be multiply by 2 and divided by mass

\(v^{2}\)= KE / 1/2 * m

\(v^{2}\) = 200000 * 2 / 250

\(v^{2}\) = 1600

v = \(\sqrt{1600}\)

v = 40 m/s

The motorbike travels at a speed of 40 m/s

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Answer:

Explanation:

This problem bothers on the simple harmonic motion of a loaded spring

Given data

mass attached, m= 0-.675 kg

spring constant, k= 72.4 N/m

the period of oscillation can be solved for using the formula bellow

\(T= 2\pi \sqrt{\frac{m}{k} }\)

Substituting the given data into the expression above we have

\(T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6\)

T= 0.6 sec

Answer:

0.607

Explanation:

Trust me

Answer:

¿Podrías poner la pregunta en inglés por favor?

Explanation:

The example that is NOT an example of Simple Harmonic Motion is:

A ball rolling down a hill.

Simple Harmonic Motion is a type of periodic motion where the restoring force is proportional to the displacement from equilibrium and is directed towards the equilibrium point. The classic example of simple harmonic motion is the motion of a mass attached to a spring that is oscillating back and forth. Other examples of simple harmonic motion include a pendulum swinging back and forth and the vibration of a guitar string.

A ball rolling down a hill does not exhibit simple harmonic motion because it does not have a restoring force that is proportional to the displacement from equilibrium. The motion of the ball is affected by the force of gravity, which is not directed towards the equilibrium point, and the frictional force between the ball and the surface of the hill, which is not proportional to the displacement from equilibrium. Therefore, it is not an example of simple harmonic motion.

Isolate the variable by dividing each side by factors that don't contain the variable.

m

=

32.021

¯

3

s

b. False

When using accelerated depreciation, the present value of future cash flows does not increase. Accelerated depreciation methods, such as the double-declining balance or sum-of-the-years'-digits, allocate more depreciation expense in the early years of an asset's life, resulting in lower taxable income and tax savings in those years. However, the total amount of depreciation remains the same over the asset's useful life.

The present value of future cash flows is determined by discounting future cash flows to their present value using an appropriate discount rate. Accelerated depreciation methods do not directly impact the timing or magnitude of future cash flows, and therefore do not increase the present value of those cash flows.

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The drag force on the skydiver at terminal velocity is 72.8 pounds.

This can be calculated by using the formula for drag force, which states that drag force is equal to the drag coefficient multiplied by the density of the fluid (in this case, air), multiplied by the velocity of the object squared, multiplied by the cross-sectional area of the object. At terminal velocity, the drag force acting on the skydiver is equal to the weight of the skydiver, which is 200 pounds. Therefore, the drag force on the skydiver is approximately 72.8 pounds.

Fd = 0.5 × ρ × Cd × A × V²

where Fd is the drag force, ρ is the density of air, Cd is the drag coefficient, A is the cross-sectional area of the skydiver, and V is the velocity.

Substituting the given velocity of 180 miles per hour (or 80.5 m/s) and solving for the drag force, we get:

Fd = 0.5 × 1.2 kg/m³ × 1.0 × 0.7 m² × (80.5 m/s)²

= 633 lbs

After opening the parachute, the cross-sectional area of the skydiver increases, which decreases the terminal velocity. Assuming the same drag coefficient and air density, but with a cross-sectional area of 4.6 m², we can use the same formula to find the new drag force at 10 miles per hour (or 4.47 m/s):

Fd' = 0.5 × 1.2 kg/m³ × 1.0 × 4.6 m² × (4.47 m/s)²

= 72.8 lbs

After opening the parachute, the skydiver experiences a significantly increased drag force, causing her to decelerate rapidly and reach a much slower terminal velocity of 10 miles per hour. The drag force increases because the cross-sectional area of the skydiver and parachute combination is much larger than just the skydiver alone, and the parachute also increases the drag coefficient.

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The wire is insulated with a layer of plastic or paint around the outside when wound into a coil to form an electromagnet to prevent the wire from shorting out against itself or other conductive materials.

When an electric current flows through a wire, it generates a magnetic field around the wire. By coiling the wire, the magnetic field is strengthened, creating a more powerful electromagnet.

However, if the wire is not insulated, the coils can touch each other, creating a short circuit that can damage the wire or the power source. Insulating the wire with a layer of plastic or paint prevents this from happening by creating a barrier between the wire and other conductive materials.

This allows the electric current to flow through the wire and generate the magnetic field, while also protecting the wire and ensuring that the electromagnet works properly.

​

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Answer:

B

Explanation:

if the object has momentum it can be any other answer except at rest. if it's at rest, it does not have momentum

The correct answer is:

a. Because, without the action potential, changes in Vm at the stimulus site might not reach the axon terminal.

Neurons generate action potentials as a means of efficiently transmitting information over long distances within the nervous system. While the opening of ion channels near the stimulus site can cause local changes in membrane potential, these changes alone may not be sufficient to propagate the signal along the entire length of the neuron.

An action potential is a rapid and coordinated change in membrane potential that occurs when the neuron is depolarized above a certain threshold. This depolarization triggers the opening of voltage-gated ion channels along the axon, allowing the action potential to propagate along the entire length of the neuron.

By generating an action potential, the neuron ensures that the signal is effectively transmitted from the site of stimulation to the axon terminal, where it can then be passed on to other neurons or effector cells. This allows for long-distance communication and coordination within the nervous system.

Therefore, without the action potential, changes in membrane potential at the stimulus site may not reach the axon terminal, hindering the effective transmission of information within the nervous system.

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skin cancer and it cause to lost transportating process

Answer:

more

Explanation:

the higher the density the more closely/tighter the particles in the object will be

Answer:

Explanation:

Given:

E₁ = E₂ = E₃ = 1.5 V

I₁ = 2 A

I₂ = 0.5 A

_________

I₃ - ?

Current strength in the common circuit:

I₁ = 2 V

The lamps are connected in parallel.

I₁ = I₂ + I₃

Ammeter 3 read:

I₃ = I₁ - I₂ = 2V - 0.5V = 1.5 V

Answer:1.5

Explanation:

Answer:

Mass, M = 4 kilograms.

Explanation:

Given the following data;

Kinetic energy = 50 J

Velocity = 5 m/s

To find the mass of the object;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

\( K.E = \frac{1}{2}MV^{2}\)

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Making mass the subject formula;

\( M = \frac{2K.E}{V^{2}}\)

Substituting into the equation, we have;

\( M = \frac{2*50}{5^{2}}\)

\( M = \frac{100}{25}\)

Mass, M = 4 kg

The angular velocity of the propeller in radians per second is 125.66 rad/s.

To convert revolutions per minute to radians per second, we need to multiply by 2π/60. Therefore:

Angular velocity = (1200 rev/min) x (2π/60) = 125.66 rad/s

So the angular velocity of the propeller is 125.66 rad/s.

The angular velocity is a measure of the rate of rotation of an object. In this case, the propeller is rotating at a high speed of 1200 revolutions per minute, which corresponds to an angular velocity of 125.66 rad/s. This high angular velocity is necessary to provide the necessary thrust for the fighter plane to fly at high speeds and perform various maneuvers.

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Answer:

Hello!

I do not have all ten listed out, however I can show you how to find out. First things first understand what the numbers mean on the table of elements. The number at the top is the atomic number. This represents how many protons an element has. This is also how many neutrons it has, because there is always the same number of protons and neutrons. The number at the bottom is the atomic mass. This is how much the atom weighs. To find the first 10 look for the elements with atomic numbers 1-10. It should be easy. I’ll give you the first one for example.

Hydrogen is the element with a atomic number of 1. Its atoms contain

-1 proton

- 1 neutron

-1 electron (also note the amount of electrons is equal to the amount of protons and neutrons)

Hydrogens atomic mass is (1.00784 u)

Lastly the symbol for hydrogen is (H)

Hope this helps!!!

Without the values of the spring constant (k) or mass (m), we can only express the time taken to reach the new equilibrium position in terms of these variables: T = 2π√(m/k).

To solve this problem, we need to use the following terms: spring constant (k), mass (m), displacement (x), and oscillation period (T). We will use Hooke's Law and the formula for the period of oscillation for a spring-mass system.
1. Hooke's Law: F = -kx,

where F is the restoring force, k is the spring constant, and x is the displacement from the equilibrium position.
2. Since we are not given the spring constant (k) or mass (m), we can only determine the period (T) of oscillation in terms of these variables. The formula for the period of oscillation of a spring-mass system is given by T = 2π√(m/k).
3. We are given the displacement from the equilibrium position as 0.130 m, but this value doesn't affect the period of oscillation, as T is independent of the amplitude.
In conclusion, without the values of the spring constant (k) or mass (m), we can only express the time taken to reach the new equilibrium position in terms of these variables: T = 2π√(m/k). If you provide the values for k and m, we can then calculate the exact period of oscillation for this spring-mass system.

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The period of a simple pendulum can be calculated using the equation:

T = 2π√(L/g)

Where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Plugging in the values for a 1.0 m pendulum on Earth, with g = 9.81 m/s^2, we get:

T = 2π√(1.0/9.81) = 2.0064 s

Therefore, the period of a 1.0 m pendulum on Earth is approximately 2.0064 seconds.

On the moon, the acceleration due to gravity is much weaker than on Earth, with g ≈ 1.62 m/s^2. Using the same equation, we can calculate the period of the 1.0 m pendulum on the moon:

T = 2π√(1.0/1.62) = 3.137 s

Therefore, the period of the 1.0 m pendulum on the moon is approximately 3.137 seconds, which is longer than on Earth due to the weaker gravitational force.The period of a pendulum is the time it takes for the pendulum to complete one full swing, from one extreme to the other and back again. The period depends on the length of the pendulum and the acceleration due to gravity. A longer pendulum will have a longer period, while a stronger gravitational force will result in a shorter period. Therefore, the period of a pendulum can be used as a standard unit of time, which can in turn be used to define a standard unit of length. In the case of the 1.0 m pendulum on Earth, its period is approximately 2.0064 seconds, while on the moon, its period is approximately 3.137 seconds, due to the weaker gravitational force.

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A line from second to home creates a right triangle with 45 degree angles.

This makes the diagonal line the side length of the square multiplied by the sqrt(2)

Second to home = 90sqrt(2) = 127.279 feet ( round answer as needed)

Answer:

Explanation:

As per the given information, 18(O) is struck by a proton, and 18(F) and another particle are produced. The reaction has a Q value of -2.453 MeV, and the atomic mass of 18(O) is 17.999 160 u.

We have to find the atomic mass of 18(F). The Q value of a nuclear reaction can be given as Q = (Mi - Mf - Mp) × c²WhereQ = Q

value of the nuclear reaction = initial massMf = final massMp = mass of the projectile = speed of light

The Q value of the given nuclear reaction is -2.453 MeV. Since we know the initial mass (Mi) and the mass of the projectile (Mp), we can calculate the final mass (Mf) as follows: Mf = Mi - Mp - (Q / c²)Now, let's calculate the final mass of 18(F).

Initial mass (Mi) = mass of 18(O) = 17.999 160 UMass of the projectile (Mp) = mass of a proton = 1.007 825 uQ value (Q) = -2.453 MeVSpeed of light (c) = 2.998 × 10⁸ m/sMf = 17.999 160 u - 1.007 825 u - (-2.453 MeV / (2.998 × 10⁸ m/s)²)Mf = 18.000 674 therefore, the atomic mass of 18(F) is 18.000 674 u.

Answer:

120

Explanation:

KE = (mv^2)/2

= ((0.15)(40)^2)/2

= ((0.15)(1600))/2

= 240/2

Answer:

below

Explanation:

that is the procedure above

Answer:

68

Explanation:

because 8.50 x 8 is 68

The frequencies of the electromagnetic waves that have the mentioned wavelengths are as follows : A) f ≈ 4.29 × 10^14 Hz, B) f ≈ 5 × 10^14 Hz, C) f ≈ 6 × 10^14 Hz, D) f = 7.5 × 10^14 Hz, E) f = 3 × 10^15 Hz, F) f ≈ 9 × 10^16 Hz, G) f = 6 × 10^11 Hz, H) f ≈ 4.74 × 10^18 Hz.

To calculate the frequency of an electromagnetic wave, you can use the formula:

f = c / λ

where f is the frequency, c is the speed of light (approximately 3 × 10^8 meters per second), and λ is the wavelength.

Let's calculate the frequencies for each given wavelength:

A. λ = 700 nm

Convert 700 nm to meters: λ = 700 nm = 700 × 10^(-9) meters

Calculate the frequency: f = c / λ = (3 × 10^8 m/s) / (700 × 10^(-9) m)

f ≈ 4.29 × 10^14 Hz

B. λ = 600 nm

Convert 600 nm to meters: λ = 600 nm = 600 × 10^(-9) meters

Calculate the frequency: f = c / λ = (3 × 10^8 m/s) / (600 × 10^(-9) m)

f ≈ 5 × 10^14 Hz

C. λ = 500 nm

Convert 500 nm to meters: λ = 500 nm = 500 × 10^(-9) meters

Calculate the frequency: f = c / λ = (3 × 10^8 m/s) / (500 × 10^(-9) m)

f ≈ 6 × 10^14 Hz

D. λ = 400 nm

Convert 400 nm to meters: λ = 400 nm = 400 × 10^(-9) meters

Calculate the frequency: f = c / λ = (3 × 10^8 m/s) / (400 × 10^(-9) m)

f = 7.5 × 10^14 Hz

E. λ = 100 nm

Convert 100 nm to meters: λ = 100 nm = 100 × 10^(-9) meters

Calculate the frequency: f = c / λ = (3 × 10^8 m/s) / (100 × 10^(-9) m)

f = 3 × 10^15 Hz

F. λ = 0.0333 nm

Convert 0.0333 nm to meters: λ = 0.0333 nm = 0.0333 × 10^(-9) meters

Calculate the frequency: f = c / λ = (3 × 10^8 m/s) / (0.0333 × 10^(-9) m)

f ≈ 9 × 10^16 Hz

G. λ = 500 μm

Convert 500 μm to meters: λ = 500 μm = 500 × 10^(-6) meters

Calculate the frequency: f = c / λ = (3 × 10^8 m/s) / (500 × 10^(-6) m)

f = 6 × 10^11 Hz

H. λ = 63.3 pm

Convert 63.3 pm to meters: λ = 63.3 pm = 63.3 × 10^(-12) meters

Calculate the frequency: f = c / λ = (3 × 10^8 m/s) / (63.3 × 10^(-12) m)

f ≈ 4.74 × 10^18 Hz

So the frequencies for the given wavelengths are:

A. f ≈ 4.29 × 10^14 Hz

B. f ≈ 5 × 10^14 Hz

C. f ≈ 6 × 10^14 Hz

D. f = 7.5 × 10^14 Hz

E. f = 3 × 10^15 Hz

F. f ≈ 9 × 10^16 Hz

G. f = 6 × 10^11 Hz

H. f ≈ 4.74 × 10^18 Hz

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Explanation:

TRUE

Your eyes detect electromagnetic waves that are roughly the size of a virus. Your brain interprets the various energies of visible light as different colors, ranging from red to violet. ... On the other end of the spectrum are gamma rays, with wavelengths billions of times smaller than those of visible light

Answer:

Explanation:

b )

Normal force R = mgcosθ

= 76.6 x 9.8 x cos 38

R = 591.5 N

c )

Force of friction

= μ R

μ is coefficient of friction .

= .15 x 591.5

= 88.73 N

d )

Net force

= mg sinθ - friction

= 76.6 x 9.8 x sin 38 - 88.73

= 462.16 - 88.73

= 373.43 N

Acceleration = 373.43 / 76.6

a = 4.87 m / s²

e )

v² = u² + 2 a s

s = 40.5 m

a = 4.87

u = 0

v² = 0 +2 x 4.87 x 40.5

= 394.5

v = 19.86 m /s

f )

v = u + a t

19.86 = 0 + 4.87 t

t = 4 .07 s

Answer: the process by which businesses or other organizations develop international influence or start operating on an international scale.

Explanation:

Answer:

Globalization is the free movement of goods, services and people across the world in a seamless and integrated manner. Globalization can be thought of to be the result of the opening up of the global economy and the concomitant increase in trade between nations.

hope that helps

Answer:

Blood alcohol content (BAC) is a measure of the amount of alcohol that is present in the blood.

A heavier person will have a lower blood alcohol level due to a greater amount of water in their body. The more a person weighs, the more water he/she tends to have in his/her body. The water has a diluting effect on the alcohol so the BAC will be lower in comparison with a person who is slimmer  and has less water in the body.

Explanation: