What is the average rate of change from x = 0 to x = 2?

Answer:

1 / 5^11

Step-by-step explanation:

5^ -6  * 5 ^ -5

We know that a^ b * a^ c = a^( b+c)

5^ ( -5+-5)

5^ -11

We also know that

a^-b = 1/ a^b

1 / 5^11

Answer:

1/5^11

Step-by-step explanation:

5^-6 * 5^-5

5^-6+(-5)

5^-6-5

5^-11

1/5^11

Note : In multiplication if the bases are same then u can add their exponent and when the base have ngative exponent just do it's reciprocal.Then u the base will have positive exponent.

The slope of the line that passes through points (2, 8) and (-3, 14) is -6/5.

The equation of a line is given by:

y = mx + c

where m is the slope of the line and c is the y-intercept.

Example:

The slope of the line y = 2x + 3 is 2.

The slope of a line that passes through (1, 2) and (2, 3) is 1.

We have,

The line passes through points (2, 8) and (-3, 14).

(2, 8) = (a, b) and (-3, 14) = (c, d)

The slope of the line.

= (d - b) / (c - a)

= (14 - 8) / (-3 - 2)

= 6 / -5

= -6/5

Thus,

The slope of the line is -6/5.

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Answer:

0.08 ounces is interpreted as the Mean Absolute Deviation and this means that

the various weights of each of the 48 eggs deviates from the mean of the egg (2.1 ounces)by 0.08 ounces.

Step-by-step explanation:

Mean Absolute Deviation of a data set is defined as the distance or the deviation between a given data set and the calculated mean.

Mean Absolute Deviation tells us about how much a data set varies from it's mean.

From the above question, we are told that after weighing 48 eggs we have a mean of 2.1 ounces and mean deviation of 0.08 ounces

Therefore this means that the various weights of each of the 48 eggs deviates from the mean of the egg (2.1 ounces)by 0.08 ounces

Answer:

12.5

Step-by-step explanation:

Keep dividing by 2, 25 divided by 2 is 12.5

The pairing is not a function, as the input 2 is mapped to two different outputs.

A relation represents a function if each value of the input is mapped to only one value of the output, that is, one input cannot be mapped to multiple outputs.

From the table, the mappings are given as follows:

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A pair of random variables such that Var(X) = Var(Y) = 1 and Cov(X, Y) = 2, by scaling the range of X and Y from 0 to 2 to 0 to 4.

Let's define two random variables X and Y, such that X and Y are independent and follow a uniform distribution.

Let's assume X and Y have a range from 0 to 2 and a mean of 1. This would mean that the variance of X and Y is equal to 1 (Var(X) = Var(Y) = 1).

Now, let's calculate the covariance between X and Y. The covariance between two independent random variables with a uniform distribution is given by the formula Cov(X, Y) = E[XY] - E[X]*E[Y].

By substituting the values, we get Cov(X, Y) = (2/3)*(1) - (1)*(1) = 2/3.

Thus, we have Var(X) = Var(Y) = 1 and Cov(X, Y) = 2/3. To get the required covariance of 2, we can scale the range of X and Y from 0 to 2 to 0 to 4, such that the mean remains 1. This would result in a covariance of Cov(X, Y) = (4/3)*(1) - (1)*(1)

Thus, we can construct a pair of random variables such that Var(X) = Var(Y) = 1 and Cov(X, Y) = 2, by scaling the range of X and Y from 0 to 2 to 0 to 4.

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Answer:

there is not any correct answer among the options.

the answer is

\( \frac{ - 21}{45} \)

Simplify the expression!

-7/15

A place value chart can help us in finding and comparing the place value of the digits in numbers through millions. The place value of a digit increases by ten times as we move left on the place value chart and decreases by ten times as we move right.

Answer:

A place value chart can help us in finding and comparing the place value of the digits in numbers through millions. The place value of a digit increases by ten times as we move left on the place value chart and decreases by ten times as we move right.

Step-by-step explanation:

The solution of the integrals are a) 3 ln|x - 1| + 4 ln|x - 2| - 4 / (x - 2) + C and b) (1/3) [2/3 ln|x^(1/3) - 5| - ln|x^(1/3) + 1|] + C and c) (1/2) e^(2x² + 1) + C.

Partial fraction is a technique used to integrate a function that has a fraction form. This technique is used for integrating a rational function that includes polynomial expressions in its denominator.

We use the partial fraction decomposition technique when we have a fraction that can be broken down into simple fractions. Let us use the partial fractions technique to find the following integrals:

a.) [(x² + 3x² - 6x + 4) / ((x-1)(x - 2)²)]

First, factorize the denominator:(x - 1)(x - 2)²

When we expand the denominator, we get:

x³ - 5x² + 8x - 4

The denominator has two roots of order one and one root of order two, as such, it can be broken down into partial fractions as shown below:

A/ (x - 1) + B/ (x - 2) + C/ (x - 2)²

Where A, B, and C are constants.

To find A, B, and C, we have to multiply the given equation by the denominator and substitute the values of x and solve for A, B, and C.

Then we integrate the fractions.

A/ (x - 1) + B/ (x - 2) + C/ (x - 2)²= [(x² + 3x² - 6x + 4) / ((x-1)(x - 2)²)](x - 1) (x - 2)²

= A(x - 2)² + B(x - 1)(x - 2) + C(x - 1)x

= 1A + B + Cx

= 2A - B + Cx

= 2 - 3A + 2B + C

After solving the above system of equations, we find A = 3, B = -4, and C = 4.

After that, we substitute the values of A, B, and C back into our equation to get:

A/ (x - 1) + B/ (x - 2) + C/ (x - 2)²

= 3/ (x - 1) - 4/ (x - 2) + 4/ (x - 2)²

Now, we can integrate each of the terms separately as shown below:

∫ [(x² + 3x² - 6x + 4) / ((x-1)(x - 2)²)]dx

= ∫ [3/ (x - 1) - 4/ (x - 2) + 4/ (x - 2)²]dx

= 3 ln|x - 1| + 4 ln|x - 2| - 4 / (x - 2) + C

b.) ∫ [(√x³) / (x² - 4x - 5)]dx

= ∫ [(√x³) / ((x - 5)(x + 1))]dx

Here, we use u-substitution to simplify the expression. We set u = x³ so that our integral becomes:

∫ [(√x³) / ((x - 5)(x + 1))]dx

= (1/3)∫ [(u^½) / ((u^(1/3) - 5)(u^(1/3) + 1))]du

We then use partial fraction decomposition technique to break down the rational function into two simple fractions, as shown below:

A/ (u^(1/3) - 5) + B/ (u^(1/3) + 1)

Now we integrate each of the terms separately as shown below:

(1/3)∫ [(u^½) / ((u^(1/3) - 5)(u^(1/3) + 1))]du

= (1/3) ∫ [A/ (u^(1/3) - 5) + B/ (u^(1/3) + 1)]du

= (1/3) [2/3 ln|u^(1/3) - 5| - ln|u^(1/3) + 1|] + C

Substituting back u = x³, we get:

(1/3) [2/3 ln|x^(1/3) - 5| - ln|x^(1/3) + 1|] + C

c.) ∫ [e^(2x² + 1)]dx

= ∫ [(e^(2x²)) (e^1)]dx

= e^1 ∫ (e^(2x²)) dx

Here, we can use the u-substitution technique to simplify the expression.

We set u = 2x² so that our integral becomes:

∫ (e^(2x²)) dx

= (1/2) ∫ e^u du

We then integrate the term as shown below:

(1/2) ∫ e^u du

= (1/2) e^u + C

Substituting back u = 2x², we get:

(1/2) e^(2x²) + C

Therefore, ∫ [e^(2x² + 1)]dx

= e^1 (1/2) e^(2x²) + C

= (1/2) e^(2x² + 1) + C.

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Answer:

he bought 60 stamps

Step-by-step explanation:

6*5=30

30*2=60

Answer:

There is a ÷ symbol or a / symbol.

Step-by-step explanation:

Answer:

usually there is a divide function that looks like / or ÷ but the 'slash' symbol works online

Step-by-step explanation:

This is a line portrayed in point-slope form.

First, put a point at (0, -1). This is your y-intercept.

Next, go down 4 units and to the right one unit. Place a point at (1, -4). Then go down another 4 units and right once more. Place a point at (2, -8).

Now, go back to your y-intercept and go up 4 units and to the left one unit. Place a point at (-1, 3).

Finally, draw a line connecting all your points.

I think its 625, deeply sorry if it is not.

Answer:

$600

Step-by-step explanation:

The output will be False as expected since the function always returns False for any input vectors.

To implement the function Indy4Vec that checks whether four 3-dimensional vectors are linearly independent, you can use the concept that four vectors in a three-dimensional space are always linearly dependent. Therefore, the function should always return False. Here's the implementation in Python:

def Indy4Vec(v1, v2, v3, v4):

   return False

This implementation simply returns False regardless of the input vectors, as it is guaranteed that four vectors in a three-dimensional space are linearly dependent. The assertion provided in the question confirms that the function should return False when tested with the given vectors.

You can use the function as follows:

v1 = np.array([-1, 3, 4])

v2 = np.array([6, -2, 9])

v3 = np.array([3, 8, 5])

v4 = np.array([5, 6, 7])

result = Indy4Vec(v1, v2, v3, v4)

print(result)  # Output: False

The output will be False as expected since the function always returns False for any input vectors.

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Using a system of equations, it will take 5 weeks for Shop B to repair as many cars as Shop A.

A system of equations is called simultaneous equations.

Simultaneous equations are two or more equations solved concurrently.

                                                              Shop A  Shop B

The number of cars already repaired      55         30

The number of cars repaired per week   5           10

Let the number of cars repaired by Shop A in w weeks = 5w + 55

Let the number of cars repaired by Shop B in w weeks = 10w + 30

For the number of cars repaired by each shop to equate, 5w + 55 = 10w + 30

5w - 10w = 30 - 55

-5w = -25

w = 5

Thus, using simultaneous equations, we can conclude that it will take Shop B 5 weeks to repair as many cars as Shop A.

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Answer:

7/16

Step-by-step explanation:

\(\dfrac78 \times \dfrac24=\dfrac{7 \times 2}{8 \times 4}=\dfrac{14}{32}=\dfrac{7}{16}\)

Answer:

(x,y)=(-18/113,117/113)

Step-by-step explanation:

there you go

Answer:

(1,-1)

Step-by-step explanation:

Two isosceles right triangles are the two triangles formed by the cut.

A quadrilateral is a four-sided polygon, having four edges and four corners.

Given that Nathan cut a square tile in half for his kitchen, he made one cut along a diagonal from one vertex to another,

We need to find the triangles formed by cutting the square diagonally.

Every square has 4 right angles, so each triangle will have one right triangle, which makes the triangles, right triangles.

They are isosceles because all sides of the square are the same, though the diagonal is not.

Hence,  Two isosceles right triangles are the two triangles formed by the cut.

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Answer:

It’s false

Step-by-step explanation:

It doesn’t need to be the same

Answer:

B

Step-by-step explanation:

On a coordinate plane, parallel lines have the same slope as geometric figures are true. Thus option B is correct.

Marks, splines, spheres, and curved are used to build enclosed geometric shapes. We can see these shapes all around us. Illustrations of geometric shapes include circles, rectangles, triangles, and others. Any configuration of points, columns, or angles is a geometry figure.

A point is the most fundamental algebraic concept because it has no boundaries. Simply put, a point upon that plane is a location. A dot is used to symbolize it. A plane can be identified by three non-straight-line points.

As two or much more vectors seldom cross each other and are located on the same dimension, these are said to be parallel. The slope of these lines is constant. Coplanar lines that seem to be parallel are the ones that don't cross. Therefore, option B is the correct option.

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Answer:

Step-by-step explanation:

The rise of the line is -5 units. The run is 4 units. The slope of the line is -5/4.

If these answers are correct, please make me Brainliest!

Answer:

-6/2=-3

slope is -3

Step-by-step explanation:

Answer:

sin 67° = 0.92050

Hope this helps

Answer:

0.9205

Step-by-step explanation:

just type sin (67) in your calculator

Answer:

y = 1/2x - 3

Step-by-step explanation:

Slope: Up 1 over 2

Y-Int: -3

y=mx+b

Answer:

Step-by-step explanation:

Solving systems of equations gives the points of intersection when the equations are graphed.

The answer is 3.

Answer:

18

Step-by-step explanation:

4.5 liters / .25 liters/pcup = 18 pcups

The sample proportion will have the smallest p-value is for Z=3 that can be calculated by taking comparisons between Z=1,2 and 3.

Null hypothesis H0= P=0.45

Alternative hypothesis H1= P>0.45

The null hypothesis assumes that any form of distinction among the selected traits which you see in a fixed of records is because of chance. For example, if the predicted income for the playing recreation are truely same to 0, then any distinction among the common income withinside the records and 0 is because of chance.

H=1000, x1=500, x2=600 and x3=700

P1= x1/h=500/1000=0.5

P2=x2/h=600/1000=0.6

P3=x3/h=700/1000=0.7

Z1=P1-P/(P(1-P)/h)61/2 = 0.5-0.45/(0.45*0.55/1000)^1/2 = 0.32

P-value for Z1=P(Z1>0.32)=0.37748

Z2=P2-P/(P(1-P)/h)61/2 = 0.6-0.45/(0.45*0.55/1000)^1/2 = 0.95

P-value for Z2=P(Z2>0.95)=0.17106

Z3=P3-P/(P(1-P)/h)61/2 = 0.7-0.45/(0.45*0.55/1000)^1/2 = 1.59

P-value for Z3=P(Z3>0.95)=0.055917

Thus, the smallest P-value will be for Z3.

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Answer:

  order of operations

Step-by-step explanation:

You want to know why -4² = -16 and (-4)² =16.

The calculator properly applied the order of operations to -4². In evaluating, this expression, the exponentiation operation is performed first. That means this is evaluated as ...

  -4² = -(4×4) = -16

When the parentheses include the minus sign, as in the second expression, the squaring operation is applied to -4, not to 4:

  (-4)² = (-4)×(-4) = 16

Answer:

Step-by-step explanation:

Let x and y stand for the numbers of Wreath and Flower bouquets, respectively.

We are told that:

 x + y \(\geq\) 8

and that:

 x \(\leq\) 10

plus:

x + y \(\leq\) 25

-----------------

We can plot these inequalities to define the combinations of x and y that meet the requirements they set forth.  See the attached image.

Any combination of wreath and flower bouquets found within the marked trapezoid are valid combinations of bouquets.  The sample point (5,10) means that 5 wreath and 10 flower bouquets is a possible solution that meets all the requirements set forth above.

==============

Is (5,10) a valid combination?

x + y \(\geq\) 8      5+10≥ 8?  YES

x \(\leq\) 10            5 \(\leq\) 10?    YES

x + y \(\leq\) 25      5 + 10 \(\leq\) 25?   YES

Many other combinations are also possible.  We need additional information to determine anythng more specific.