What is the range of the function gx x 12 2?

Based on the above, the capacity of a 5-liter tin is about  500 cm³.

To be able to convert the capacity of a 5-liter tin to its volume in cm³, One need to use the conversion factor that is, 1 liter is equivalent to 100 cm³.

So, to be able to calculate the volume of a 5-liter tin in cm³, one have to multiply the capacity (5 liters) by the conversion factor (100 cm³/liter):

Volume in cm³ = 5 liters x 1000 cm³/liter

                           = 500 cm³

Therefore, the capacity of a 5-liter tin is about  500 cm³.

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Convert the capacity of a 5 litre tin to its volume in cm³.1litre is equivalent to 100cm³

Answer:

Step-by-step explanation:

diameter = 7⅜ inches

radius r = 3.6875 inches

You have a sphere with r = 3.6875 inches

volume of sphere = (4/3)πr³ = 171 in³

A is closest, but not very.

Answer

C and A

Step-by-step explanation:

The age of the decaying sample according to the decay formula is 42,009 years.

The rate of radioactive carbon-14 decay depends on the function

\(A(t) = A_{0} e^{-0.0001216t}\)

where \(A_{0}\) is the quantity found in living plants and animals, t is in years, and is the age.

60% of the carbon-14 of a current-day sample was present in a sample taken from a refuse deposit close to the Strait of Magellan. We need to evaluate the age of the sample,

A = 60 % of \(A_{0}\) = (3/5)\(A_{0}\)

Putting this in the decay equation, we have,

\(\frac{3}{5} A_{0} = A_{0} e^{-0.0001216t}\\\\ 0.6= e^{-0.0001216t}\\ \\ln0.6 = -0.00001216t\\\\-0.51082 = -0.00001216t\\\\t = 42,008.68\)

Thus, the age of the sample is 42,009 years.

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Lin collected 1.4 times that of Diego's recycling collection.

Let x be the amount Diego collected in kg of recycling.

Then, Lin collected 2/5 more than that is

x + 2/5x = 7/5x kg of recycling

.Let x be the amount of recycling Diego collected in kg.

Then, Lin collected 2/5 more than that, so Lin's collection is

x + 2/5x,

which is equivalent to 7/5x kg of recycling.

This means that Lin's recycling collection is 1.4 times that of Diego's.'

For example, if Diego collected 10 kg of recycling, then Lin collected

2/5 * 10 = 4 kg

more than that, which is a total of 14 kg.

Therefore, Lin collected 1.4 times that of Diego's recycling collection.
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Answer:

Definitions

At the most basic level, an exponential function is a function in which the variable appears in the exponent. The most basic exponential function is a function of the form y=bx where b is a positive number.

When b>1 the function grows in a manner that is proportional to its original value. This is called exponential growth.

When 0>b>1 the function decays in a manner that is proportional to its original value. This is called exponential decay.

Graphing an Exponential Function

Example 1

Let us consider the function y=2x when b>1. One way to graph this function is to choose values for x and substitute these into the equation to generate values for y. Doing so we may obtain the following points:

(−2,14), (−1,12), (0,1), (1,2) and (2,4)

As you connect the points, you will notice a smooth curve that crosses the y-axis at the point (0,1) and is increasing as x takes on larger and larger values. That is, the curve approaches infinity as x approaches infinity. As x takes on smaller and smaller values the curve gets closer and closer to the x-axis. That is, the curve approaches zero as x approaches negative infinity making the x-axis is a horizontal asymptote of the function. The point (1,b) is on the graph. This is true of the graph of all exponential functions of the form y=bx for x>1.

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Ahmad as a hirer has the right to contest the validity of the repossession by Easy Bank Bhd. as the repossession was not in compliance with the requirements under the Hire Purchase Act 1967.

The notice of repossession must be in writing, signed by or on behalf of the owner, and must state the default, the amount due and payable by the hirer and the right of the hirer to terminate the hire-purchase agreement by giving written notice of termination to the owner within twenty-one days after the date of the repossession.

If Ahmad disputes the validity of the repossession by Easy Bank Bhd., he can apply to the court to be relieved against the repossession.2. The rights of Mrs. Tan under the law on hire-purchase in the event of defect in the sewing machine are as follows: Mrs. Tan can reject the machine if it fails to comply with the implied conditions as to its quality or fitness for purpose. She must give notice of rejection to Happy Housewives Sdn. Bhd. within a reasonable time. The reasonable time depends on the nature of the goods and the circumstances of the case. If Mrs.

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Answer:

(2, 5)

Step-by-step explanation:

The longest side of the triangle will be the side with the coordinate (1,4) and (3,6) due the value of the distance between them;

Midpoint = (x1+x2/2, y1+y2/2)

X = 1+3/2

X = 4/2

X = 2

Y = 4+6/2

Y = 10/2

Y = 5

Hence the required midpoint (X, Y) will be at (2, 5)

Answer:

2x+1

Step-by-step explanation:

There is no way to simplify or solve any further.  It's not even an equation, it's an expression.

SOLUTION

Given the question on the question tab;

The angle is 4.0

The population of interest in this study is the youth population aged 15-24 years in British Columbia.

b) The sampling frame in this study is the list of colleges and high schools that were visited by the police department.

c) The bias in this survey is called social desirability bias.

Many students who have used cannabis may be afraid or hesitant to admit it to a uniformed police officer due to social stigma, fear of legal consequences, or other reasons.

This can lead to underreporting or inaccurate reporting of cannabis use.

d) The bias that can result from the sampling frame used is known as selection bias.

The sample of students selected may not be representative of the entire youth population in British Columbia.

For example, if certain schools or colleges were excluded from the sampling frame, it may not provide a comprehensive representation of all youth in the province.

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a) To solve the recurrence relation an = an-1 + 3(n-1), a0 = 1, we can expand the recurrence relation iteratively.

a1 = a0 + 3(1-1) = 1 + 0 = 1

a2 = a1 + 3(2-1) = 1 + 3 = 4

a3 = a2 + 3(3-1) = 4 + 6 = 10

a4 = a3 + 3(4-1) = 10 + 9 = 19

...

We can observe a pattern from the values:

a0 = 1

a1 = 1

a2 = 4

a3 = 10

a4 = 19

We can notice that an = \(n^2 + 1.\) We can prove this by induction, but in this case, we can also recognize that the given recurrence relation generates the triangular numbers (1, 3, 6, 10, 15, ...), which are defined by the formula Tn = n(n+1)/2.

Thus, the solution to the recurrence relation is an = \(n^2 + 1.\)

b) For the recurrence relation an = an-1 + n(n-1), a0 = 3, we can again expand it iteratively:

a1 = a0 + 1(1-1) = 3 + 0 = 3

a2 = a1 + 2(2-1) = 3 + 2 = 5

a3 = a2 + 3(3-1) = 5 + 6 = 11

a4 = a3 + 4(4-1) = 11 + 12 = 23

...

Observing the values, we can notice that an =\(n(n^2 + 1).\)

Thus, the solution to the recurrence relation is an = \(n(n^2 + 1).\)

c) For the recurrence relation an = an-1 +\(3n^2\), a0 = 10, we expand it iteratively:

a1 = a0 + \(3(1^2)\) = 10 + 3 = 13

a2 = a1 + \(3(2^2) =\) 13 + 12 = 25

a3 = a2 + \(3(3^2)\)= 25 + 27 = 52

a4 = a3 + \(3(4^2)\)= 52 + 48 = 100

...

We can notice that an = \(n^3 + 10.\)

Thus, the solution to the recurrence relation is an = \(n^3 + 10.\)

These are the solutions to the given recurrence relations.

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Two equal-size vectors at right angles to each other have a resultant that is equal to \(\sqrt{2}\) times the magnitude of each individual vector.

The magnitude of the resultant vector of two equal-size vectors at right angles to each other can be determined using the Pythagorean theorem.

Let's assume the magnitude of each vector is represented by "a".

According to the Pythagorean theorem, the magnitude of the resultant vector, denoted as "R", can be calculated as:

R =\(\sqrt{a^2 + a^2}\)

R = (\(\sqrt{2a^{2} )}\)

R = \(\sqrt{2}\) a

Therefore, the magnitude of the resultant vector is equal to \(\sqrt{2}\) times the magnitude of each individual vector.

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A U.S. dollar can buy approximately 0.21 Swiss francs (rounded to two decimal places). Thus, the answer is option d) 0.21.

To determine how much Swiss francs a U.S. dollar can buy, we need to use the given exchange rates between different currencies.

Given:

1 ounce of gold costs 15 U.S. dollars and 14.3028 Italian lira.

1 ounce of silver costs 0.7302 Italian lira and 0.1605 Swiss francs.

Let's calculate the exchange rate between the U.S. dollar and the Swiss franc using the given information:

1 ounce of silver = 0.7302 Italian lira

1 ounce of silver = 0.1605 Swiss francs

To find the exchange rate between the Italian lira and the Swiss franc, we can divide the price of 1 ounce of silver in Swiss francs by the price of 1 ounce of silver in Italian lira:

Exchange rate: 0.1605 Swiss francs / 0.7302 Italian lira

Simplifying this, we get:

Exchange rate: 0.2199 Swiss francs / 1 Italian lira

Now, let's find the exchange rate between the U.S. dollar and the Italian lira:

1 ounce of gold = 15 U.S. dollars

1 ounce of gold = 14.3028 Italian lira

To find the exchange rate between the U.S. dollar and the Italian lira, we can divide the price of 1 ounce of gold in Italian lira by the price of 1 ounce of gold in U.S. dollars:

Exchange rate: 14.3028 Italian lira / 15 U.S. dollars

Simplifying this, we get:

Exchange rate: 0.9535 Italian lira / 1 U.S. dollar

Finally, to find how much Swiss francs a U.S. dollar can buy, we multiply the exchange rate between the U.S. dollar and the Italian lira by the exchange rate between the Italian lira and the Swiss franc:

Exchange rate: 0.9535 Italian lira / 1 U.S. dollar * 0.2199 Swiss francs / 1 Italian lira

Simplifying this, we get:

Exchange rate: 0.2099 Swiss francs / 1 U.S. dollar

Therefore, a U.S. dollar can buy approximately 0.21 Swiss francs (rounded to two decimal places). Thus, the answer is option d) 0.21.

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Answer:

sin 60 = √3/2

means perpendicular (p)= √3

and

base (h)=2

find base(b)

using pythagoras theorem

h²=p²+b²

than base (b) will be 1

now

cos 60 =b/h

=1/2

Answer:

cos 60° = 1/2

SohCahToa

sin 60° = opposite / hypotenuse

sin 60° = √3 / 2

The bottom side = √3, the hypotenuse = 2

To find the right side's value, you use Pythagorean's Theorem

cos 60° = adjacent/hypotenuse

cos 60° = 1 / 2

The estimated probability of finding at most 50 acceptable circuits in a batch of 60 is approximately 0.6591.

To estimate the probability of finding at most 50 acceptable circuits in a batch of 60 from a certain factory, where the probability of passing the quality test is (p = 0.8) and the outcomes of the tests are mutually independent, we can use the Central Limit Theorem (CLT).

The CLT states that for a large enough sample size, the distribution of the sample mean approaches a normal distribution, regardless of the shape of the population distribution.

Let's denote (X) as the number of acceptable circuits in a batch of 60. Since each circuit passes the test with a probability of 0.8, we can model (X) as a binomial random variable with parameters (n = 60) and (p = 0.8).

To estimate the probability of finding at most 50 acceptable circuits, we can calculate the cumulative probability using the normal approximation to the binomial distribution.

Since the sample size is large \((\(n = 60\))\), we can approximate the distribution of (X) as a normal distribution with mean \(\(\mu = np = 60 \times 0.8 = 48\)\) and standard deviation \(\(\sigma = \sqrt{np(1-p)}\) = \(\sqrt{60 \times 0.8 \times 0.2} \approx 4.90\).\)

Now, we want to find the probability of\(\(P(X \leq 50)\)\). We can standardize the value using the z-score:

\(\[P(X \leq 50) = P\left(\frac{X - \mu}{\sigma} \leq \frac{50 - 48}{4.90}\right) = P(Z \leq 0.41)\]\)

Using the standard normal distribution table or calculator, we can find that \(\(P(Z \leq 0.41) \approx 0.6591\).\)

Therefore, the estimated probability of finding at most 50 acceptable circuits in a batch of 60 is approximately 0.6591.

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The correct option is (b) A C B.

Explanation:

(a) B n A = ∅: This option states that the intersection of class B and class A is empty. However, this is not correct because there are regular languages that can be accepted by finite automata, so there can be languages in common between the two classes.

(b) A C B: This option states that class A is a subset of class B. This is true because every language accepted by a finite automaton can be represented by a regular expression, so class A is contained within class B.

(c) A = B: This option states that class A is equal to class B. This is not correct because there are regular expressions that represent languages that cannot be accepted by finite automata. Therefore, the two classes are not equal.

(d) |A| > |B|: This option states that the cardinality of class A is greater than the cardinality of class B. It is not necessarily true as there can be an infinite number of languages represented by regular expressions and an infinite number of languages accepted by finite automata. Therefore, we cannot compare their cardinalities.

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a) x = 9

b) x = 2

collect like terms:

check: replace x with 2

3(2) + 2 = 2 + 6

6 +2 = 2+ 6

8 = 8

Hence, it is correct

Answer:

length = 3√5

distance = √13

Step-by-step explanation:

length = √[(lenght(1,-2)to(4,-2))² + (length(4,-2)to(4,4))²]

length = √ 3²+6²

=√9+36

=√45=3√5

distance

d = √(x1-x2)²+(y1-y2)²

d= √(5-3)² + (-2-1)²

d=√2²+(-3)²

d=√4+9

d=√13

Answer:

Jane is 12 years old. Harvey is 36 years old.

Step-by-step explanation:

We have to set up an equation.

Let j = Jane's age.

Let 3j = Harvey's age (He's 3 times Jane's age.)

So...

j + 3j = 48

4j = 48

j = 12

So Jane is 12 years old.

3 * j = 36

So Harvey is 36 years old.

To check, we can add 36 + 12.

36 + 12 = 48

Hope this helps!!! :)

The difference in the shortest collection times before and after the well installation is 20 minutes, calculated by subtracting the shortest time after installation (25 minutes) from before (45 minutes), as shown in the box and whiskers plot.

This is calculated by subtracting the shortest collection time after well installation (25 minutes) from the shortest collection time before well installation (45 minutes):

45 - 25 = 20 minutes.

This can be seen in the box and whiskers plot provided, where the lowest value for each distribution is denoted by the beginning of the whiskers.

So, the difference is before and after the well installation is 20 minutes.

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--The given question is incomplete, the complete question is given

" What is the difference in minutes between the shortest collection times before and after the well was installed"--

The value of the quantity after 6 weeks is 7694.5

Percentage Increase is the difference between the final value and the initial value, expressed in the form of a percentage.

How to determine this

When an initial value = 5500

Grows at a rate of 0.95%

i.e 0.95% of 5500 = 52.25, it grows 52.25 per day

What is the value of the quantity after 6 weeks

When 7 days = 1 week

6 weeks = x

x = 6 * 7 days

x = 42 days

If it grows 52.25 per day

let x represent the value of quantity in 42 days

When 52.25 = 1 day

x = 42 days

x = 42 * 52.25

x = 2194.5

Therefore the value of the quantity after 6 weeks

= 2194.5 + 5500

= 7694.5

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Answer:

y=\(\frac{1}{2}\)x-3

Step-by-step explanation:

slope intercept form is y=mx+b

b is y intercept

so we plug the coordinate into the equation

-3=\(\frac{1}{2}\)(0)+b

-3=b

so y intercept is -3

so we then write our equation which is,

y=\(\frac{1}{2}\)x-3

Answer:

y = \(\frac{1}{2}\) x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = \(\frac{1}{2}\) and crosses the y- axis at (0, - 3) ⇒ c = - 3

y = \(\frac{1}{2}\) x - 3 ← equation of line

In business calculus, the term "functions" refers to mathematical relationships that associate inputs (typically denoted as x) with corresponding outputs (typically denoted as y). Functions can represent various aspects of business operations, such as revenue, cost, profit, demand, and supply.

The concept of "limits" in calculus deals with the behavior of a function as the input approaches a particular value. It determines the value that the function approaches or tends to as the input gets arbitrarily close to a specified value. Limits are essential for analyzing the behavior of functions near certain points, understanding rates of change, and evaluating derivatives and integrals.

"Continuity" of a function refers to its smooth and unbroken nature, without any abrupt jumps, holes, or vertical asymptotes. A function is continuous if its graph can be drawn without lifting the pen from the paper. Continuity ensures that small changes in the input correspond to small changes in the output, which is crucial for reliable analysis and prediction.

For example, consider the function f(x) = 2x + 1. This linear function represents a business scenario where x represents the number of units sold, and f(x) represents the total revenue generated. The limit of f(x) as x approaches 2 is 5, indicating that as the number of units sold approaches 2, the total revenue approaches $5. Since f(x) = 2x + 1 is a linear function, it is continuous across its entire domain.

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Answer:

y = 7x

Step-by-step explanation:

The equation of a line passing through the origin is

y = mx ( m is the slope )

Calculate m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (0, 0 ) and (x₂, y₂ ) = (100, 700 ) ← 2 points on the line

m = \(\frac{700-0}{100-0}\) = \(\frac{700}{100}\) = 7

y = 7 x ← equation of line

The percentage of trench coats sold increased by 23. 3%. therefore, option D is correct.

A percentage is a minimum number or ratio that is measured by a fraction of 100.

First, we need to subtract the final from the initial, then divide the difference by the initial, then multiply your answer by 100 to get the percentage

the final is 127, and the initial is 103

127 - 103 = 24

24/103 = 0.233

0.233 x 100

= 23.3%

Thus, The percentage of trench coats sold increased by 23. 3%.

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The amount of money Justin saves in the first month would be 5 times the value of x, where x represents the number of months of gym membership, based on the discounted price provided.

A linear equation is an equation in mathematics that represents a relationship between two variables that is a straight line when graphed on a coordinate plane. It is an equation of the form:

y = mx + b

To calculate the amount of money Justin saves in the first month by joining the gym at the discounted price rather than the regular price, we need to know the discounted price.

The equation given is y = 15x + 20, where y represents the regular price in dollars and x represents the number of months of gym membership. However, we need to know the discounted price, which is not provided in the given information.

Once we have the discounted price, we can substitute it into the equation and calculate the savings. For example, if the discounted price is y = 10x + 20, then we can calculate the savings by subtracting the discounted price from the regular price:

Savings = Regular price - Discounted price

= (15x + 20) - (10x + 20)

= 15x - 10x

= 5x

Hence, the amount of money Justin saves in the first month would be 5 times the value of x, where x represents the number of months of gym membership, based on the discounted price provided.

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Answer:

132

Step-by-step explanation:

easy  66,000 * .002

Answer:

It should be 5 but my brain is literally dead

Step-by-step explanation:

Please give brainlest