- What is the value of x in the figure
(5x)
140

Answer:

The third answer is correct.

Step-by-step explanation:

You are going to translate the smaller quadrilateral (4 sided figure) to the larger quadrilateral.  Then you need the scale factor from the smaller figure to the larger.  

Side EF times the scale factor will give you side AB.  Let's call the scale factor s then our equation would be:

EF x s = AB  To find s divide both sides by EF

\(\frac{EF(s)}{EF}\) = \(\frac{AB}{EF}\)

s = \(\frac{AB}{EF}\)  This is our scale factor.

Helping in the name of Jesus.

Answer:

90, 64

Step-by-step explanation:

Rottweiler is 90

German Shepard is 64

To express the corresponding holomorphic function f(z) = u(x, y) + iv(x, y) in terms of z, we can use the relationship between the trigonometric functions and the hyperbolic functions.

By utilizing the identity cos z = cos x cosh y - i sin x sinh y, we can rewrite the real and imaginary parts of the function in terms of z. This allows us to express the function f(z) directly in terms of z. The given hint provides the relationship between the trigonometric functions (cos and sin) and the hyperbolic functions (cosh and sinh) for any z = x + iy. Using this identity, we can express the real part (u(x, y)) and the imaginary part (v(x, y)) of the function f(z) in terms of z.

The real part, u(x, y), can be rewritten as u(z) = Re[f(z)] = Re[cos z] = Re[cos x cosh y - i sin x sinh y] = cos x cosh y. Similarly, the imaginary part, v(x, y), can be expressed as v(z) = Im[f(z)] = Im[cos z] = Im[cos x cosh y - i sin x sinh y] = -sin x sinh y.

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Answer:

1433.09

Step-by-step explanation:

4,000,000 divided by 64 = 62,500

62,500 divided by 42 1,433.09

He makes 1433.09 per minute

Answer:

In the pic

Step-by-step explanation:

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there are 528 positive integers less than 1,000,000 that have exactly one digit equal to 9 and have a sum of digits equal to 13

To solve this problem, we need to consider the possible positions of the digit 9 in the number. Since we know that the number has exactly one digit equal to 9, there are six possible positions for the digit: in the ones place, in the tens place, in the hundreds place, in the thousands place, in the ten-thousands place, or in the hundred-thousands place.

Let's consider each of these cases separately:

Ones place: In this case, the remaining digits must sum up to 4, which is only possible if the number has the form 4XY, where X and Y are digits different from 9. There are 8 choices for X and 8 choices for Y, since they can be any digit from 0 to 8. Therefore, there are 8 * 8 = 64 numbers with 9 in the ones place and sum of digits equal to 13.

Tens place: In this case, the remaining digits must sum up to 3, which is only possible if the number has the form 3X9Y or 3Y9X. There are 8 choices for X and 7 choices for Y, since Y cannot be equal to X or 9. Therefore, there are 2 * 8 * 7 = 112 numbers with 9 in the tens place and sum of digits equal to 13.

Hundreds place: In this case, the remaining digits must sum up to 4, which is only possible if the number has the form 2X9Y or 2Y9X. There are 8 choices for X and 7 choices for Y, since Y cannot be equal to X or 9. Therefore, there are 2 * 8 * 7 = 112 numbers with 9 in the hundreds place and sum of digits equal to 13.

Thousands place: In this case, the remaining digits must sum up to 4, which is only possible if the number has the form 1X9Y or 1Y9X. There are 8 choices for X and 7 choices for Y, since Y cannot be equal to X or 9. Therefore, there are 2 * 8 * 7 = 112 numbers with 9 in the thousands place and sum of digits equal to 13.

Ten-thousands place: In this case, the remaining digits must sum up to 4, which is only possible if the number has the form X9Y0, where X and Y are digits different from 9. There are 8 choices for X and 8 choices for Y, since they can be any digit from 0 to 8. Therefore, there are 8 * 8 = 64 numbers with 9 in the ten-thousands place and sum of digits equal to 13.

Hundred-thousands place: In this case, the remaining digits must sum up to 4, which is only possible if the number has the form 9XY0, where X and Y are digits different from 9. There are 8 choices for X and 8 choices for Y, since they can be any digit from 0 to 8. Therefore, there are 8 * 8 = 64 numbers with 9 in the hundred-thousands place and sum of digits equal to 13.

To get the total number of numbers, we just add up the numbers from each case:

64 + 112 + 112 + 112 + 64 + 64 = 528

Therefore, there are 528 positive integers less than 1,000,000 that have exactly one digit equal to 9 and have a sum of digits equal to 13

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To adjust the length of the pendulum, we need to make it 9.7922 times longer than its current length.

To adjust the length of the pendulum, we can use the formula for the period of pendulum, which is T = 2π√(L/g), where T is the period (time it takes for one swing), L is the length of the pendulum, and g is the acceleration due to gravity.

Since we don't know the exact value of g, we can use the fact that the clock loses 27 s per day, which means it runs at a rate of (24 hours - 27 s)/(24 hours) = 0.9990625 times the actual time. This means that the period of the clock is 0.9990625 times the actual period.

Setting the period of the clock equal to 0.9990625 times the actual period, we get:
0.9990625 T = 2π√(L/g)
Squaring both sides and rearranging, we get:
L = (g/4π^2) (0.9990625 T)²
Substituting T = 24 hours = 86400 s and solving for L, we get:
L = (g/4π²) (0.9990625 x 86400 s)²
L = (g/4π²) (86338.13 s)²
L = 9.7922(g) m

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Answer:

80% of the fish in the school pond are goldfish.

Step-by-step explanation:

To find the percentage of goldfish in the pond, we need to divide the number of goldfish by the total number of fish and multiply by 100.

percent of goldfish = (number of goldfish / total number of fish) x 100%

So, in this case:

percent of goldfish = (296 / 370) x 100%

percent of goldfish = 0.8 x 100%

percent of goldfish = 80%

Answer:

-53

Step-by-step explanation:

-25-32-14-14+45-13

=53

Answer:

ANS IS -53

AS +45 &-45 WILL GET CANCELLED

AND -14-14-25 WILL GET ADDED

THAT IS -53

a.  The probability is approximately \(0.1847\).

b. The probability of exactly 2 times falling between 1 and 5 seconds is approximately \(0.3038\).

(a) To find the probability that between 1 and 5 seconds elapse between emits, we can use the Poisson distribution. Given a mean rate of 3 emits per second, the parameter \($\lambda$\) for the Poisson distribution is also 3.

Let \($X$\) be the random variable representing the waiting time between emits. We want to find \($P(1 \leq X \leq 5)$\).

Using the Poisson distribution formula, we can calculate this probability:

\($P(1 \leq X \leq 5) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$\)

\(P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!}\)

Substituting \($\lambda = 3$ and $k = 1, 2, 3, 4, 5$\), we have:

\($P(1 \leq X \leq 5) = \frac{e^{-3} 3^1}{1!} + \frac{e^{-3} 3^2}{2!} + \frac{e^{-3} 3^3}{3!} + \frac{e^{-3} 3^4}{4!} + \frac{e^{-3} 3^5}{5!}$\)

Calculating this expression, we find that the probability is approximately \(0.1847\).

(b) When selecting 10 times between emissions randomly, the number of times falling between 1 and 5 seconds follows a binomial distribution. The probability of exactly 2 times falling in this range can be calculated using the binomial distribution formula:

\($P(X = 2) = \binom{10}{2} \cdot (P(1 \leq X \leq 5))^2 \cdot (1 - P(1 \leq X \leq 5))^{(10 - 2)}$\)

Substituting the probability from part (a), we have:

\($P(X = 2) = \binom{10}{2} \cdot (0.1847)^2 \cdot (1 - 0.1847)^{(10 - 2)}$\)

Calculating this expression, we find that the probability of exactly 2 times falling between 1 and 5 seconds is approximately 0.3038.

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As per the given statement a.) The probability that between 1 and 5 seconds elapse between emits is 5.26%. b.) The probability that exactly 2 of the emissions are between 1 and 5 seconds is 27.05%.

a. To find the probability that between 1 and 5 seconds elapse between emits in a Poisson process with a mean rate of 3 per second, we can use the exponential distribution.

The exponential distribution is characterized by the parameter lambda \((\(\lambda\))\), which is equal to the mean rate of the process. In this case, \(\(\lambda = 3\).\) The probability density function (PDF) of the exponential distribution is given by:

\(\[ f(t) = \lambda e^{-\lambda t} \]\)

To find the probability that between 1 and 5 seconds elapse between emits, we need to calculate the integral of the PDF from 1 to 5 seconds:

\(\[ P(1 \leq t \leq 5) = \int_{1}^{5} \lambda e^{-\lambda t} dt \]\)

Integrating the PDF, we have:

\(\[ P(1 \leq t \leq 5) = \left[ -e^{-\lambda t} \right]_{1}^{5} \]\)

\(\[ P(1 \leq t \leq 5) = -e^{-3 \cdot 5} - (-e^{-3 \cdot 1}) \]\)

\(\[ P(1 \leq t \leq 5) = -e^{-15} + e^{-3} \]\)

\(\[ P(1 \leq t \leq 5) \approx 0.0526 \]\)

Therefore, the probability that between 1 and 5 seconds elapse between emits is approximately 0.0526, or 5.26%.

b. If we randomly select 10 times between emissions, and we assume they are independent, we can model the situation as a binomial distribution.

The probability of having exactly 2 times between emissions between 1 and 5 seconds can be calculated using the binomial probability formula:

\(\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]\)

where \(\( n \)\) is the number of trials (10), \(\( k \)\) is the number of successful trials (2), and \(\( p \)\) is the probability of success (probability that between 1 and 5 seconds elapse between emits).

From part a, we know that \(\( P(1 \leq t \leq 5) \approx 0.0526 \).\)

Plugging in these values into the formula:

\(\[ P(X = 2) = \binom{10}{2} (0.0526)^2 (1 - 0.0526)^{10 - 2} \]\)

\(\[ P(X = 2) = 45 \cdot (0.0526)^2 \cdot (0.9474)^8 \]\)

\(\[ P(X = 2) \approx 0.2705 \]\)

Therefore, the probability that exactly 2 of the times between emissions are between 1 and 5 seconds is approximately 0.2705, or 27.05%.

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We fail to reject the hospital's claim that the proportion of full-term babies born in the community that weigh more than 7 pounds is 41% at the 0.10 level of significance.

To determine if there is enough evidence to reject the hospital's claim that the proportion of full-term babies born in the community that weigh more than 7 pounds is 41%, we can conduct a hypothesis test.

Let's assume that the hospital's claim is true, that the population proportion of babies born in the community that weigh more than 7 pounds is p = 0.41. Then the null hypothesis would be

H0: p = 0.41

The alternative hypothesis would be that the proportion is different from 0.41, i.e., a two-tailed test

Ha: p ≠ 0.41

The significance level of the test is α = 0.10.

We can use the normal approximation to the binomial distribution, since n = 135 and np = 0.41 × 135 ≈ 55 and n(1 − p) = 80 are both greater than 10.

The test statistic is calculated as:

z = (x − np) / sqrt(np(1 − p))

where x = 44 is the number of babies in the sample who weigh more than 7 pounds.

Substituting the values, we get

z = (44 − 0.41 × 135) / sqrt(0.41 × 135 × 0.59) = 1.53

Using a standard normal distribution table, we find that the probability of getting a z-value of 1.53 or more extreme under the null hypothesis is 0.064.

Since this probability is greater than the significance level of 0.10, we fail to reject the null hypothesis. There is not enough evidence to conclude that the proportion of full-term babies born in the community that weigh more than 7 pounds is different from 41% at the 0.10 level of significance.

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26400 is what they travel in feet in a day divide that by 24 and that should be your answer

The number of ways are there of choosing ten balls from the box if the number of green balls must be in even numbers =15946 ways

To determine the number of ways of choosing ten balls from the box such that the number of green balls chosen is even, we need to consider the different possible combinations of green balls that could be chosen.

First, we can select 0 green balls, in which case we would need to choose all 10 balls from the 5 red and 8 yellow balls. This can be done in (5+8) choose 10 ways, which is 13 choose 10, or 286 ways.

Alternatively, we could choose 2, 4, or 6 green balls, and then select the remaining balls from the red and yellow balls. To count the number of ways of doing this, we can use the binomial coefficient formula.

The total number of ways of selecting 10 balls from the box is (6+5+8) choose 10, which is 19 choose 10, or 92,378 ways.

Therefore, the number of ways of choosing 10 balls from the box such that the number of green balls chosen is even is the sum of the number of ways of choosing 0, 2, 4, or 6 green balls, which is:

(6 choose 0)(13 choose 10) + (6 choose 2)(5 choose 8)(8 choose 0) + (6 choose 4)(5 choose 6)(8 choose 0) + (6 choose 6)(5 choose 4)*(8 choose 0)

Simplifying this expression gives a total of 15,946 ways.

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200 is the mean absolute deviation. Therefore, choice three (200) is the right one.

The absolute difference between the predicted and actual values must be determined, added together, and divided by the total number of periods.

Forecasted values are as follows: 1,500 and 1,400

Values in actuality: 1,200 and 1,500

Absolute differences:

|1,500 - 1,200| = 300

|1,400 - 1,500| = 100

Now, we calculate the MAD:

MAD = (300 + 100) / 2 = 400 / 2 = 200

Therefore, 200 is the mean absolute deviation. Therefore, choice three (200) is the right one.

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Answer:

Step-by-step explanation:(t-by)(4t+3by)

The first term in the first bracket is multiplied by the last bracket

t(4t+3by)=4t^2+3bty

The second term in the first bracket is multiplied by the last bracket

-by(4t+3by)=-4bty-3b^2y^2

Add the results together and simplify where possible

4t^2+3bty-4bty-3b^2y^2=4t^2-bty-3b^2y^2

Answer:

Step-by-step explanation:

The graph should start with an y-intercept of 100 because even if zero people attend, it costs $100 for the DJ. Then, the line should have a slope of 20 because for each additional person it costs another $20. when you reach the point (10,200) the line will plateau where every y value after that will be 200

answer is c because if it's not a and b then the only answers will be c and d and d is the same as the number so it's c

Answer:

c(10) = 10c i believe

Step-by-step explanation:

or the answer in the picture

X is used as a Place holder for the value(s) in math. Oh and angle BAG should be around 135!

1. Perpendicular lines

2. True variable

3. Sequence

4. Slope

5. Solution

6. Term

7. variable

Given,

1. Lines that intersect to form right (90 degree) angles – perpendicular lines

2. How the dependent variable changes with respect to the independent variable – true variable

3. A set of numbers that follow a pattern, with a specific first number – sequence

4. The rate of change of a line; change in y over change in x; rise over run – slope

5. A value or values of the variable that make an algebraic sentence – solution

6. An individual quantity or number in a sequence- term

7. A letter or symbol used to represent an unknown rate of change – variable

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Answer:

125/8

is the final answer

Step-by-step explanation:

1.transform the expression

2.calculate

3.(final answer)

Answer:

I Believe the answer is either 3 5/8 or 29/8

Step-by-step explanation:

You have to find the most common denominator which for 1/2 and 1/8 is 8 and then you would do 1/2 1*3 and 2*4 to get 4/8 add them together for 5/8 then would would either add 24/8 to equal the 3 or you would leave the three by itself (depends on what your teacher says for simplification)

As for defining simplification it is solving the problem best you can with the information you are given.

The missing value that completes the frequency table is 100

A frequency table is just a two-column "t-chart" or table that lists all of the potential outcomes and their corresponding frequencies as seen in a sample.

How to solve:

From the graph given,

The battery life(hours) from x = 15  to x= 20 has a frequency of 130

The battery life(hours) from x= 28 to x= 30 has a frequency of 100

It can be inferred that from the battery life of the different models, the missing value is 100 and when you crosscheck the data, you would find this is correct and accurate.

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Answer:

Rule 1: Adding positive numbers to positive numbers—it's just normal addition.

Rule 2: Adding positive numbers to negative numbers—count forward the amount you're adding.

Rule 3: Adding negative numbers to positive numbers—count backwards, as if you were subtracting.

When booking a show for a future date, it is normal practice for the booking agent to collect a 50% advance fee when the advances are not given for shows. This is to ensure that the performer is fully committed to performing at the event and to cover any expenses that may be incurred in the process.

The advance fee is usually non-refundable and is paid by the promoter or venue operator to the booking agent. This is to show their commitment to the performer and to demonstrate that they are serious about booking them for the event. The remaining balance is then usually paid on the day of the performance or shortly after.

The booking agent should also ensure that all parties involved in the booking are aware of the terms and conditions and have signed a contract or agreement to confirm their agreement.

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Each outcome represents the result of two spins, with the first element indicating the outcome of the first spin and the second element indicating the outcome of the second spin in the sample space.

The sample space is the set of all possible outcomes of an experiment. In this case, the experiment is spinning a spinner twice with two equally sized sections labeled "stop" and "go."

The possible outcomes of the first spin are "stop" (s) and "go" (g). Similarly, the possible outcomes of the second spin are also "stop" and "go."

Therefore, the sample space can be represented by all possible combinations of the first and second spin outcomes, which gives us the following four outcomes:

(s,s): the spinner stops on "stop" twice

(s,g): the spinner stops on "stop" on the first spin and on "go" on the second spin

(g,s): the spinner stops on "go" on the first spin and on "stop" on the second spin

(g,g): the spinner stops on "go" twice

Hence, the sample space for spinning a spinner twice with two equally sized sections labeled "stop" and "go" is given by the set: {(s,s), (s,g), (g,s), (g,g)}.

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The profit when the company spent zero dollars on advertising. The correct option is B.

In the context of the problem, the y-intercept represents the profit when the company spent zero dollars on advertising.

The y-intercept is the value of the dependent variable (profit, denoted as P) when the independent variable (advertising expense, denoted as x) is equal to zero.

In this case, when the company spends zero dollars on advertising (x = 0), the equation becomes:

P = -250(0) + 1,505(0)^2 - 300

P = 0 + 0 - 300

P = -300

Therefore, the y-intercept of -300 (in tens of thousands of dollars) represents the profit when the company spent zero dollars on advertising.

Thus, the correct answer is B. The profit when the company spent zero dollars on advertising.

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Answer:

21 cm

Step-by-step explanation:

V = (4/3)(pi)r^3

(4/3)(3.14)(r^3) = 4851 cm^3

r^3 = 1158.1 cm^3

r = 10.5 cm

d = 2r = 2(10.5 cm) = 21 cm

Answer:

Yah, it can as long as it has three sides

Answer:

Yes because..... (see explanation)

Step-by-step explanation:

Triangle Inequality Theorem. The sum of the lengths of any two sides of a triangle is greater than the length of the third side.

According to the first triangle inequality theorem, the lengths of any two sides of a triangle must add up to more than the length of the third side. This means that you cannot draw a triangle that has side lengths 2, 7 and 12, for instance, since 2 + 7 is less than 12.

Approximately 2,401 college students need to be contacted to estimate the proportion of all college students who do not have a sibling with a 95% confidence level and a 2.00% margin of error.

To determine the sample size required for estimating a proportion with a specified confidence level and margin of error, we can use the formula.

Confidence level (1 - α) = 95% (corresponding to a Z-value of 1.96)

Margin of error (E) = 2.00% or 0.02

Estimated proportion (p) = 0.56

n ≈ (3.8416 * 0.56 * 0.44) / 0.0004

n ≈ 0.876544 / 0.0004

n ≈ 2,191.36

Rounding up to the nearest whole number, the required sample size is approximately 2,401 college students.

To estimate the proportion of college students who do not have a sibling with a 95% confidence level and a 2.00% margin of error, approximately 2,401 college students need to be contacted. This estimation is based on assuming a prior estimate of 0.56 for the proportion.

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