Which shows the graph of the solution set of 6x + 4y < 12?

Answer:

80 cubic units

Step-by-step explanation:

Area for rectangular prism is l*w*h

2*8*5=80

Part B: The electric potential at point b is approximately \(1.35 × 10^2 V.\)Part C: The work done on q₃ by the electric forces exerted by q₁ and q₂ is approximately \(-4.05 \times 10^{-4} \, \text{J}\)\).

Given information:

Charge \(\(q_1 = 5.00 \mu C = 5.00 \times 10^{-6} C\)\) (positive charge)

Charge \(\(q_2 = -8.00 \mu C = -8.00 \times 10^{-6} C\)\) (negative charge)

Distance from point b to q₁, \(\(r_1 = 3.50 \, \text{cm} = 3.50 \times 10^{-2} \, \text{m}\)\)

Distance from point b to q₂, r₂ = diagonal of the square \(\(r_2 = \sqrt{(3.50 \, \text{cm})^2 + (3.50 \, \text{cm})^2} = \sqrt{(3.50 \times 10^{-2} \, \text{m})^2 + (3.50 \times 10^{-2} \, \text{m})^2}\)\)

Using the formula for electric potential due to a point charge:

V₁ = k * q₁ / r₁

V₂ = k * q₂ / r₂

Substituting the values:

\(\[V_1 = \frac{{8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2 \cdot (5.00 \times 10^{-6} \, \text{C})}}{{3.50 \times 10^{-2} \, \text{m}}}\]\[V_2 = \frac{{8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2 \cdot (-8.00 \times 10^{-6} \, \text{C})}}{{\sqrt{{(3.50 \times 10^{-2} \, \text{m})^2 + (3.50 \times 10^{-2} \, \text{m})^2}}}}\]\)

Now we can calculate Vb by adding V₁ and V₂:

Vb = V₁ + V₂

Let's calculate the values:

\(\[V_1 = \frac{{8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2 \cdot (5.00 \times 10^{-6} \, \text{C})}}{{3.50 \times 10^{-2} \, \text{m}}} \approx 1.285 \times 10^4 \, \text{V}\]\[V_2 = \frac{{8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2 \cdot (-8.00 \times 10^{-6} \, \text{C})}}{{\sqrt{{(3.50 \times 10^{-2} \, \text{m})^2 + (3.50 \times 10^{-2} \, \text{m})^2}}}}} \approx -1.150 \times 10^4 \, \text{V}\]\)

\(\[V_b = V_1 + V_2 \approx 1.285 \times 10^4 \, \text{V} - 1.150 \times 10^4 \, \text{V} \approx 1.35 \times 10^2 \, \text{V}\]\)

Therefore, the electric potential at point b is approximately \(1.35 × 10^2 V.\)

Moving on to Part C, let's calculate the work done on q₃ by the electric forces exerted by q₁ and q₂.

Given information:

Charge \(\(q_3 = -3.00 \mu C = -3.00 \times 10^{-6} C\)\)

To find the change in electric potential (ΔV), we subtract the electric potential at point a (which is zero) from the electric potential at point b:

ΔV =\(V_{b} - V_{a}\)

Since Va = 0, we have:

ΔV = \(V_{b}-0=V_{b}\)

Now we can calculate the work done using the formula:

W = ΔV * q₃

Substituting the values:

\(W = (V_{b} ) * (q_{3} ) = (1.35 *10^2 V) * (-3.00 * 10^-{6} C) = -4.05 *10^{-4} J\)

Therefore, the work done on q₃ by the electric forces exerted by q₁ and q₂ is approximately \(\(W = -4.05 \times 10^{-4} \, \text{J}\)\)

Learn more about distance here: https://brainly.com/question/29130992

#SPJ11

Answer:

Between-10 and -9

Step-by-step explanation:

Square root of 116 is 10.77. Since there’s a minuscule sign it’s -10.77

So it’s between -10 and -9

Declan's reasoning does make sense. This is because 3/4 and 1/2 have the same denominator, and 3/4 is a larger fraction than 1/2.

Therefore, it is reasonable to assume that 3/4 is greater than 6/12 because 6/12 simplifies to 1/2. Simplifying fractions means dividing the numerator and denominator by the same number, in this case, 6 is divisible by 2, so we can reduce the fraction to 1/2.

So, Declan is correct in his reasoning that 3/4 is greater than 6/12. It is important to understand the relationship between fractions and their denominators to make such comparisons accurately.

3/4 = 9/12

1/2 = 6/12

6/12 = 6/12

Since 9/12 (which is equivalent to 3/4) is greater than 6/12 (which is equivalent to 1/2), we can say that 3/4 is indeed greater than 6/12.

Therefore, Declan's reasoning is correct.

Learn more about Fractions:

https://brainly.com/question/78672

#SPJ4

Answer:

the answer is A

Step-by-step explanation:

its because -4 is the coldest and 3 is the warmest out of the rest

Answer:400 cm

Step-by-step explanation:

Answer:

120 cu. cm

Step-by-step explanation:

Answer:

Step-by-step explanation:

Step 1: Draw a line from the vertex of the angle to the given point on the x-axis.

Step 2: Draw a line from the given point to the point on the y-axis where the angle intersects the y-axis.

Step 3: Calculate the length of the line segment created in Step 2. This will be x.

Step 4: Calculate the measure of angle 0 by using the given measure of angle and the length of x. This will be 0 degrees.

Answer:

its B

Step-by-step explanation:

Answer:

y= x+75

Step-by-step explanation:

We already have 75 and add x money

Excessive punishment or negative reinforcement can harm a child's math achievement by creating fear, undermining confidence, and discouraging engagement with the subject. Positive discipline techniques and a supportive environment are crucial for fostering math success.

Excessive punishment or negative reinforcement as a discipline technique can have detrimental effects on a child's math achievement. When a child makes mistakes or struggles with math concepts, responding with punishment, criticism, or harsh consequences can create a negative association with math. This can lead to anxiety, fear, and a lack of motivation to engage with the subject.

Mathematics requires a growth mindset, where mistakes are seen as opportunities for learning and improvement. By punishing or negatively reinforcing a child's math mistakes, we discourage them from taking risks, trying new strategies, and seeking help when needed. It hampers their ability to develop problem-solving skills and critical thinking abilities.

Furthermore, negative discipline approaches can damage a child's self-esteem and confidence in their mathematical abilities. They may develop a belief that they are "bad at math" or incapable of improving, leading to a self-fulfilling prophecy where their performance suffers.

To support a child's math achievement, it is essential to employ positive discipline techniques. This includes providing constructive feedback, offering assistance and guidance, creating a safe and supportive learning environment, and promoting a growth mindset. Encouraging effort, perseverance, and celebrating small successes can foster a positive attitude towards math and enhance a child's mathematical abilities.

To learn more about critical thinking visit:

https://brainly.com/question/3021226

#SPJ11

Answer:

Step-by-step explanation:

eq. of any line withslope 1/6 is

y=1/6x+c

∵ it passes through (-2,7)

so 7=1/6(-2)+c

c=7+1/3=22/3

eq. of line is

y=1/6x+22/3

Answer:

y = 1/6x + 7 1/3

Step-by-step explanation:

Slope intercept form is y=mx+b where m is the slope and b is the y intercept

y = 1/6x+b

Substitute the point into the equation

7 = 1/6(-2)+b

7 = -1/3+b

Add 1/3 to each side

7 1/3 = b

y = 1/6x + 7 1/3

Answer: 23,600

Step-by-step explanation: 120x2 = 240, 240x15 = 3600. 20,000 + 3600 = 23,600

The derivative d/dx of the integral ∫sin(t³)dt with the limits [0, x²] is 3x⁴cos(x²)³.

To answer your question, we'll find the derivative d/dx of the integral ∫sin(t³)dt with the limits [0, x²]. We will use the Fundamental Theorem of Calculus and the chain rule in our solution.

Step 1: Apply the Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus states that if F(x) = ∫f(t)dt with the limits [a, x], then F'(x) = f(x). In our case, f(t) = sin(t³).

Step 2: Apply the chain rule
Now we need to find the derivative d/dx of sin(t³) evaluated at x². To do this, we will use the chain rule, which states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function.

So, let's find the derivative of sin(t³) with respect to t:
d/dt(sin(t³)) = cos(t³) * d/dt(t³)

Now, find the derivative of t³ with respect to t:
d/dt(t³) = 3t²

Step 3: Combine and evaluate at x²
d/dx(sin(x²)³) = cos(x²)³ * 3(x²)²

Step 4: Simplify
d/dx(sin(x²)³) = 3x⁴cos(x²)³

Know more about derivative here:

https://brainly.com/question/23819325

#SPJ11

Answer:

He Won 26 Box trolls and 11 Pikachus

Step-by-step explanation:

You subtract 37-11 which would get you 26

Given:

Chandra get a bonus if average quarterly sales for an year exceeds $70000.

From the bar diagram, we can find the sales for each quarter.

The height of each bar gives the sales for each quarter.

Since the data in the vertical column is given in thousands of dollars, multiply the height of the bar by 1000 to get the correct sales value.

The sales for the first quarter is $40000.

The sales for the second quarter is $100000.

The sales for the third quarter is $80000.

Let x be the sales for the fourth quarter.

Now, the average of the quarterly sales is,

Put A=70000 and solve the equation for x to obtain the sales for the fourth quarter so that Chandra gets bonus.

So, the sales of the fourth quarter must be $60000 in order for Chandra to earn the bonus.

Hence, option D is correct.

Answer:

The best way to decompose the composite figure to determine its area is as a semicircle, a trapezoid, and two rectangles. This way, we can use the following formulas to find the area of each part:

Area of a semicircle = 21​πr2, where r is the radius of the circle.

Area of a trapezoid = 21​(b1​+b2​)h, where b1​ and b2​ are the bases and h is the height of the trapezoid.

Area of a rectangle = l×w, where l is the length and w is the width of the rectangle.

Then, we can add up the areas of each part to find the total area of the composite figure. The other options are not as convenient because they either involve more parts or more complicated shapes. For example, option A would require finding the area of a triangle, which involves using trigonometry or the Pythagorean theorem. Option B would require finding the area of four triangles, which is more tedious than finding the area of two rectangles. Option C would require finding the area of a square, which is redundant because a square is a special case of a rectangle.

Step-by-step explanation:

The composite figure can be decomposed into a semicircle, a trapezoid, and two rectangles.

Option D is the correct answer.

It is a quadrilateral that has one pair of parallel sides and a height.

The area is calculated as: 1/2 x sum of the parallel sides x height.

Examples:

Area of a trapezium that has the parallel sides as 3 cm and 4 cm and a heght o 5 cm.

Area = 1/2 x (3 + 4) x 5

Area = 1/2 x 7 x 5

Area = 35/2 = 17.5 cm^2

We have,

The given figure can be decomposed into the following figure.

- Semicircle

- Trapezoid

- Two rectangles

Thus,

A semicircle, a trapezoid, and two rectangles.

Learn more about trapezium here:

https://brainly.com/question/22607187

#SPJ5

The expected number of times the coin is flipped is 3.75.

Probability refers to the chance of occurrence of an event.

Let E be an event. Then, the probability of E = P(E)

=> P(E) = \(\frac{Number Of Favourable Outcomes Of E}{Total Number Of Outcomes}\)

Now,

P(Tail coming up twice) = \(\frac{1}{4}\)

P(Tail coming up twice) =  \(\frac{2}{8}\)

P(Tail coming up twice) =  \(\frac{3}{16}\)

P(Tail coming up twice) = \(\frac{4}{32}\)

P(Tail coming up twice) = \(1-\frac{1}{4}-\frac{2}{8}-\frac{3}{16}- \frac{4}{32} = \frac{3}{16}\)

Therefore, the expected number of times coin is flipped = \(2(\frac{1}{4}) + 3(\frac{2}{8}) + 4(\frac{3}{16} )+5(\frac{4}{32} )+6(\frac{3}{16} ) =\frac{15}{4} = 3.75\)

To learn more about probability, refer to the link: brainly.com/question/24756209

#SPJ4

To show that the total charge contained in the charge distribution is Q, we integrate the charge density over the entire volume. The charge density is given by:

ρ(r) = ρ₀(1 - r/R) for r ≤ R,

ρ(r) = 0 for r > R,

where ρ₀ = 3Q/πR³.

To find the total charge, we integrate ρ(r) over the volume:

Q = ∫ρ(r) dV,

where dV represents the volume element.

Since the charge density is spherically symmetric, we can express dV as dV = 4πr² dr, where r is the radial distance.

The integral becomes:

Q = ∫₀ᴿ ρ₀(1 - r/R) * 4πr² dr.

Evaluating this integral gives:

Q = ρ₀ * 4π * [r³/3 - r⁴/(4R)] from 0 to R.

Simplifying further, we get:

Q = ρ₀ * 4π * [(R³/3) - (R⁴/4R)].

Simplifying the expression inside the parentheses:

Q = ρ₀ * 4π * [(4R³/12) - (R³/4)].

Simplifying once more:

Q = ρ₀ * π * (R³ - R³/3),

Q = ρ₀ * π * (2R³/3),

Q = (3Q/πR³) * π * (2R³/3),

Q = 2Q.

Therefore, the total charge contained in the charge distribution is Q.

To show that the electric field in the region r > R is identical to that created by a point charge Q at r = 0, we can use Gauss's law. Since the charge distribution is spherically symmetric, the electric field outside the distribution can be obtained by considering a Gaussian surface of radius r > R.

By Gauss's law, the electric field through a closed surface is given by:

∮E · dA = (1/ε₀) * Qenc,

where ε₀ is the permittivity of free space, Qenc is the enclosed charge, and the integral is taken over the closed surface.

Since the charge distribution is spherically symmetric, the enclosed charge within the Gaussian surface of radius r is Qenc = Q.

For the Gaussian surface outside the distribution, the electric field is radially directed, and its magnitude is constant on the surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q,

Simplifying:

E = Q / (4πε₀r²).

This is the same expression as the electric field created by a point charge Q at the origin (r = 0).

To derive an expression for the electric field in the region r ≤ R, we can again use Gauss's law. This time we consider a Gaussian surface inside the charge distribution, such that the entire charge Q is enclosed.

The enclosed charge within the Gaussian surface of radius r ≤ R is Qenc = Q.

By Gauss's law, we have:

∮E · dA = (1/ε₀) * Qenc.

Since the charge distribution is spherically symmetric, the electric field is radially directed, and its magnitude is constant on the Gaussian surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q.

Simplifying:

E = Q / (4πε₀r²).

This expression represents the electric field inside the charge distribution for r ≤ R.

Learn more about charge here:

https://brainly.com/question/18102056

#SPJ11

The difference between original loan and unsubsidized loans at the time of graduation is =  8302.57 - 7855 = $447.57

What is meant by a loan?

A loan is a type of debt that a person or other entity incurs. The lender advances the borrower a certain amount of money, typically on behalf of a business, financial institution, or government. The borrower accepts a specific set of terms in return, which may include any economic costs, interest, a repayment schedule, and other requirements.

The lender may occasionally need collateral to protect the loan and guarantee repayment. Major purchases, investments, renovations, debt reduction, and company endeavours are just a few uses for loans. Loans aid in the expansion of already existing businesses. The growth of an economy's total money supply and fostering competition are made possible by loans to new enterprises.

Given,

 Time to graduate = 18 months

Amount of loan for 3 semesters = $7855

Unsubsidized loan

rate of interest = 3.7%

Subsidized Stafford Loan

rate of interest = 4.7%

Amount after 6 months for each loan

P = $7855

r1 =  3.7%

r2 = 4.7%

t (in years) = 18 months = 1.5 years

Number of times compounded in a year n = 12

Amount of  Unsubsidized loan at the time of graduation

= \(P(1 + \frac{r}{n})^{nt}\)

= \(7855(1 + \frac{0.037}{12})^{12*1.5}\)   = $8302.57

Amount of the Subsidized Stafford Loan at the time of graduation

= \(P(1 + \frac{r}{n})^{nt}\)

= \(7855(1 + \frac{0.047}{12})^{12*1.5}\)   = $8427.60

Therefore the difference between the balance amount of the original loan and the unsubsidized loan at the time of graduation is

=  8302.57 - 7855 = $447.57

To learn more about loans, follow the link.

https://brainly.com/question/28704618

#SPJ1

Answer:

i need more information

Step-by-step explanation:

Answer:

b 12 probly

Step-by-step explanation:

6 on each side add them ya get 12

Step-by-step explanation:

Given radius, r = 5,

Circumference of Circle, C

\( = 2\pi \: r \\ = 2\pi(5) \\ = 10\pi \: units\)

Answer:

\(10\pi\)

Step-by-step explanation:

As the hint below says:

\(C = 2\pi r\)

We also know that

r = 5

So thus:

\(C = 2 \pi \cdot 5 = 10\pi\)

False. Asymmetric encryption algorithm can be used to ensure the integrity of a file's contents.

Asymmetric encryption algorithms, such as RSA, are primarily used for data confidentiality and authentication, not for ensuring the integrity of a file's contents. They provide a way to securely exchange encrypted messages between parties and verify the authenticity of the sender.

To ensure the integrity of a file's contents, techniques such as cryptographic hash functions or digital signatures are used. Cryptographic hash functions generate a fixed-size hash value that uniquely represents the file's contents. Comparing the hash value before and after transmission can verify if the file has been tampered with. Digital signatures, on the other hand, use asymmetric encryption to provide a means of verifying the integrity and authenticity of a file by attaching a digital signature created with the sender's private key.

Know more about encryption algorithm here:

https://brainly.com/question/28283722

#SPJ11

Answer:

u=19

Step-by-step explanation:

4u-9=67 1. add 9 on both sides

4u = 76 divide 4 on both sides

4u/4 = 76/4

u = 19

Answer:

7

Step-by-step explanation: Ok this coming from a 11 year old. if 7x3= 21 then add 4 its 25 simple

Answer:

700

Step-by-step explanation:

37x10 is 370

33x10 is 330

330 add 370 is 700

Answer:

They sold 700 oranges

Step-by-step explanation:

the question is why didn't you just multiply it mate it wasn't brainy worthy tbh, not judging but just multiply each number by ten and then add them up

The new coordinate of point (5,-4) after dilation by a scale factor of 33 centered at the origin is (165,-132)(165,132)

You must specify the extent of the shape's enlargement when describing one.

The scale factor is the ratio of two dimensions such that one figure is large and another is small.

Given the coordinate (5,-4),(5,-4)

If we apply a scale factor by 33 on any general coordinate (x,y)

Then,

x → 33x and y → 33y

Similarly

5 → 33(5) = 165

-4 → 33(-4) = -132

So the new coordinate will be (165,-132)(165,-132)

Same step apply once more for (5,-4) the coordinate of other is same

Hence "The new coordinate of point (5,-4)(5,-4) after dilation by a scale factor of 33 centered at the origin is (165,-132),(165,-132)

To learn more about scale factor refer to :

https://brainly.com/question/2826496

#SPJ1

Answer:

yes it can be bc it is repeating

Answer:

5

Step-by-step explanation:

Pythagorean Theorum: a^2 + b^2 = c^2

12^2 + y^2 = 13^2

144 + y^2 = 169

Subtract 144 from both sides

y^2 = 25

Square root both sides

y = 5

Answer:

y = 5

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

y² + 12² = 13²

y² + 144 = 169 ( subtract 144 from both sides )

y² = 25 ( take the square root of both sides )

y = \(\sqrt{25}\) = 5

the 4 values of c that make the expression x² - 3xc factorable are 1, 2, -1, and -2.

To make the expression x² - 3xc factorable, we need to find 4 values of c.

Here's how:

To factor the quadratic expression, x² - 3xc, we need to look for two terms that we can add or subtract to obtain the quadratic expression. x² - 3xc can be rewritten as x² - (3c)x.

Now we need to factor out the greatest common factor which is x to obtain x(x - 3c).Thus, x² - 3xc = x(x - 3c).

We can observe that the expression x(x - 3c) is the product of two factors: x and (x - 3c).In order to make the expression x² - 3xc factorable, the value of c should be such that the product of x and (x - 3c) is equal to x² - 3xc.

Therefore, the values of c that make the expression x² - 3xc factorable are:1. c = 1:

This gives us x(x - 3)2. c = 2: This gives us x(x - 6)3. c = -1:

This gives us x(x + 3)4. c = -2: This gives us x(x + 6)

Therefore, the 4 values of c that make the expression x² - 3xc factorable are 1, 2, -1, and -2.

learn more about expression here

https://brainly.com/question/1859113

#SPJ11