Why is it that continually displacing the ring from its equilibrium position, releasing it, and watching its subsequent behavior as you adjust the mass and/or angle of the equilibrant will give you more precise results then simply letting the ring move on its own?
Answers
Method of adjustment is a precise experimental technique, while allowing the system to move on its own can be influenced by external factors.
How does the method of adjustment help in determining the properties of a physical system?Continually displacing the ring from its equilibrium position, releasing it, and watching its subsequent behavior as you adjust the mass and/or angle of the equilibrant is known as an experimental technique called "method of adjustment". This technique is used to determine the value of a physical quantity with a high degree of precision.
When the ring is simply allowed to move on its own, it will oscillate back and forth until it comes to rest. This motion is affected by a number of factors, including the mass and angle of the equilibrant, the elasticity of the ring, and any other external factors that may be present. As a result, it can be difficult to accurately measure the period of oscillation or other properties of the system.
By contrast, the method of adjustment involves carefully adjusting the mass and/or angle of the equilibrant until the ring oscillates at a desired frequency or exhibits a desired behavior. This allows for a more precise determination of the system's properties, as the experimenter can fine-tune the system until it behaves in the desired manner. This method is particularly useful when working with systems that have small oscillations, as it allows for a more accurate determination of the period and other properties of the system.
In summary, the method of adjustment allows for a more precise determination of the properties of a physical system by allowing the experimenter to fine-tune the system until it behaves in the desired manner, whereas simply letting the system move on its own can be affected by a variety of external factors that can make accurate measurements difficult.
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Related Questions
The current through a certain heater wire is found to be fairly independent of its temperature. If the current through the heater wire is doubled, the amount of energy delivered by the heater in a given time interval will.
Answers
The amount of energy delivered by the heater in a given time interval will be increase by a factor of four
Given:
Current in wire = I
current is double = 2I
To Find:
amount of energy delivered by the heater
Solution:
Scientists define energy as the ability to do work.
The unit of energy is the joule, the unit of power is the watt, and the unit of time is the second.
E = Power x Time = P x T
P = (I)^2 x T
E' = (2I)^2 x T
E' 4I^2T
E' = 4E
So, amount of energy delivered by the heater will be four time initial energy
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A spider hangs from a strand of silk whose radius is 2.3×10
−6
m. The density of the silk is 1300 kg/m
3
. When the spider moves, waves travel along the strand of silk at a speed of 260 m/s. Determine the mass of the spider. Number Units
Answers
When the spider moves, waves travel along the strand of silk at a speed of 260 m/s.
Determine the mass of the spider.
Given:
Radius of silk strand,
r = 2.3×10⁻⁶ m
Density of silk,
ρ = 1300 kg/m³
Speed of wave,
v = 260 m/s
Let the mass of spider be m.
From formula for velocity of wave in a stretched string,
v = √(T/μ)
where T is tension and μ is linear mass density.
Tension,
T = μv²
For silk strand, linear mass density,
μ = ρ × (2r)² = 1300 × (2 × 2.3×10⁻⁶)² = 0.02 kg/m
Tension,
T = μv² = 0.02 × 260² = 135200 N
We know,
weight = mg
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Which of the following represents a state of depolarization of a neuron?
a. -70 mV
b. -70 mV to +30 mV
c. -70 mV to -85 mV
d. +30 mV to -70 mV
Answers
The state of depolarization of a neuron is represented by option d) +30 mV to -70 mV.
A neuron at rest has a resting membrane potential typically around -70 mV, which is maintained by the balance of ion concentrations across the cell membrane. Depolarization occurs when there is a temporary shift in the membrane potential towards a more positive value.
Option d) represents depolarization because it describes a change in the membrane potential from the resting potential of -70 mV to a more positive value of +30 mV and then back to the resting potential of -70 mV. This change in potential is characteristic of depolarization.
Option a) (-70 mV) represents the resting membrane potential, while options b) (-70 mV to +30 mV) and c) (-70 mV to -85 mV) do not accurately describe the state of depolarization, as they involve changes that move away from the resting potential rather than towards a positive value.
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Given the equation describing the displacement of an object undergoing simple harmonic motion, Find the maximum acceleration of the object.
Answers
The maximum acceleration of the object is 10.94 x 10² m/s².
The equation of displacement is given as,
y(t) = 4.8 cos(15.1 t)
It is in the form, y(t) = A cos(ωt)
So, the amplitude of the SHM, A = 4.8 m
Angular frequency, ω = 15.1 s⁻¹
The maximum acceleration,
a(max) = -Aω²
the -ve sign indicates that the acceleration is acting towards the mean position.
a(max) = 4.8 x 15.1²
a(max) = 10.94 x 10² m/s²
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Would Lincoln, Nebraska or San Diego, California have a smaller range in average monthly temperatures
Answers
Answer: San diego
Because it is closer to the ocean
100 times colder than room temperature. would you expect interstellar molecular hydrogen to act more like a particle or a wave?
Answers
When an object is 100 times colder than room temperature, molecular hydrogen in interstellar space would behave like a wave rather than a particle.
Hydrogen in the interstellar medium is in a gas phase, with a temperature of around 10 to 100 K. At this temperature, the thermal energy of the hydrogen molecules is low, which means the particles move slowly and have a low kinetic energy.According to quantum mechanics, when the wavelength of the particle is larger than the distance between the particles, the wave nature of the particle dominates. Because hydrogen molecules in interstellar space have a very low kinetic energy, their wavelengths are longer than the distances between them. As a result, hydrogen in interstellar space behaves more like a wave than a particle.
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answer questions show work #3
3. Determine the value of ID and VDs for the DS following amplifier. 10 RD 10V 3KD Points 0.47μF 01 G= 0.47μF Hilt RG 1.5MO -1V N5486 VGSoff = -4V IDSS = 14mA
Answers
The given amplifier circuit is a common-source amplifier. The equivalent circuit diagram of the amplifier includes a MOSFET N5486 transistor. We can determine the drain current (ID) and drain-source voltage (VDS) using the following equations:
1. Voltage at the source terminal (VS) is calculated using Ohm's law: VS = IS x RS.2. The drain current (ID) can be calculated using the equation ID = IS (1 + GVin), where Vin is the input voltage, G is the voltage gain, and IS is the current flowing through RD.Let's calculate the values of ID and VDS:
Given:- IS = VDD / RD = 10V / 10Ω = 1A- Vin = -1V / (1.5 x 10^6Ω + 0.47μF) = -0.6666667μA (using voltage divider rule)- G = -RD / RS = -10Ω / 3kΩ = -0.003333 Calculating ID:ID = 1A (1 - 0.003333 x 0.6666667 x 10^6)≈ 0.997A = 997mACalculating VDS:VDS = VDD - IDRD= 10V - 997mA x 10Ω≈ 10V - 9.97V≈ 0.03VTherefore, the values of ID and VDS are approximately ID = 997mA and VDS ≈ 0.03V, respectively.
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10. a 50.0-g ball moves at 30.0 m/s. if its speed is measured to an accuracy of 0.10%, what is the minimum uncertainty in its position?
Answers
The minimum uncertainty in the ball's position is 3.5 x 10^-32 meters.
To calculate the uncertainty, multiply the speed (30.0 m/s) by the accuracy (0.001). This results in an uncertainty in speed of 0.03 m/s.
Now, apply Heisenberg's Uncertainty Principle to find the minimum uncertainty in position. The formula is:
Δx * Δp ≥ ħ/2
where Δx is the uncertainty in position, Δp is the uncertainty in momentum, and ħ is the reduced Planck constant (approximately 1.05 x 10^-34 Js).
First, find Δp by multiplying the mass of the ball (50.0 g or 0.05 kg) by the uncertainty in speed (0.03 m/s). This gives a Δp of 0.0015 kg m/s.
Now, solve for Δx:
Δx ≥ ħ / (2 * Δp)
Δx ≥ (1.05 x 10^-34 Js) / (2 * 0.0015 kg m/s)
Δx ≥ 3.5 x 10^-32 m
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What is the mass of a blow dart that experiences a blowing force of 0.20 Newtons and travels the length of the 1.2 meter barrel in 0.04 seconds? (HINT: first find the acceleration)
Answers
The mass of a blow dart that experiences a blowing force of 0.20 Newtons and travels the length of the 1.2 meter barrel in 0.04 seconds is 0.26 g
a = v / t
v = d / t
a = Acceleration
v = Velocity
d = Distance
t = Time
d = 1.2 m
t = 0.04 s
v = 1.2 / 0.04
v = 30 m / s
a = 30 / 0.04
a = 750 m / s²
According to Newton's second law of motion,
F = m a
F = Force
m = Mass
F = 0.2 N
m = F / a
m = 0.2 / 750
m = 2.6 * \(10^{-4}\) kg
m = 0.26 g
Therefore, the mass of a blow dart is 0.26 g
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Find the average circumference of the two balloons with each amount of sugar. Show your work.
No sugar:
Some sugar:
More sugar:
Answers
The average circumference of the two balloons for each amount of sugar are as follows; No sugar: 31.4 cm Some sugar: 34.54 cm More sugar: 40.84 cm
The circumference of a balloon is given by the formula;
C = 2πr
where r is the radius of the balloon. We can find the average circumference of the two balloons for each amount of sugar as shown below. No sugar: The circumference of the balloon with no sugar is given by
C1 = 2πr1
We can find the average circumference of the two balloons as follows;
Average circumference = (C1 + C1)/2 = (2πr1 + 2πr1)/2= 2πr1= 2 × 3.14 × 5= 31.4 cm
(to one decimal place)Some sugar: The circumference of the balloon with some sugar is given by
C2 = 2πr2
We can find the average circumference of the two balloons as follows; Average circumference
= (C1 + C2)/2 = (2πr1 + 2πr2)/2= (2 × 3.14 × 5) + (2 × 3.14 × 6)/2= 2 × 3.14 × 5.5= 34.54 cm
(to two decimal places)More sugar: The circumference of the balloon with more sugar is given by
C3 = 2πr3
We can find the average circumference of the two balloons as follows; Average circumference
= (C2 + C3)/2 = (2πr2 + 2πr3)/2= (2 × 3.14 × 6) + (2 × 3.14 × 7)/2= 2 × 3.14 × 6.5= 40.84 cm (to two decimal places)
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A snail at position 3 cm moves to position 20 cm in 8 seconds.
Answers
Answer: 17cm.
Explanation:
The equation you're using is:
Δd = df - di
Which means the change in position is equal to the final position minus the starting position. In this case that works out to 20cm - 3cm = 17cm. We're only interested in how much the snail moved, not how long it took to move, so even though they give a time it actually doesn't matter for this question.
Three identical rocks are launched with identical speeds from the top of a platform of height Oh. The rocks are launched in the directions indicated above.
Which of the following correctly relates the magnitude vy of the vertical component of the velocity of each rock immediately before it hits the ground?
Answers
Answer:
All rocks hit the ground with the same speed.
Explanation:
The magnitude of the vertical velocity under gravity changes by approximately 9.81 m/s each second
The option that correctly relates the magnitude, \(v_{y}\), of the vertical velocity is the option;
\((v_{y1} = v_{y1}) \geq v_{y3}\)
Reason:
The possible question options are; \((v_{y1} = v_{y1}) \geq v_{y3}\), \(v_{y1}> v_{y3} > v_{y2}\), \(v_{y2}> v_{y3} > v_{y1}\), \(v_{y1}= v_{y2} = v_{y3}\)
Known parameters;
The speed of the rocks = u
The height of the platform from which the rocks are thrown = h₀
The given direction in which the balls are thrown are;
Rock 1; Direction = 45° above the horizontal
Rock 2; Direction = 45° below the horizontal
Rock 3; Direction = 0° or in the horizontal direction
The vertical component of the speed of Rock 1= -u·sin(45°)
Vertical component of the speed of Rock 2 = u·sin(45°)
Vertical component of the speed of Rock 3 = u·sin(0°) = 0
The velocity of the rock is given by
v² = u² - 2·g·h₀
\(v = \pm \sqrt{u^2 - 2 \cdot g \cdot h_0}\)
Where g is taken as negative, we have;
\(v = \pm \sqrt{u^2 + 2 \cdot g \cdot h_0}\)
Therefore, the vertical velocity the rocks, Rock 1 and Rock 2, thrown with magnitude of velocity, \(|v_y| = |u \cdot sin(45^{\circ})|\) is the same during the vertical motion of the ball at the same height, but change only in sign
\(At \ a \ given \ height, \ h_0, \ v_{y1} = v_{y2}\)
\(Therefore, \ before \ the \ rocks \ hit \ the \ ground, \ v_{y1} = v_{y2}\)
The initial vertical velocity of Rock 3, \(v_{y3}\) = 0, therefore;
\(v_{y3} = \pm \sqrt{0 + 2 \cdot g \cdot h_0} \leq \pm \sqrt{u^2 + 2 \cdot g\cdot h_0 } = (v_{y1} = v_{y1})\)Therefore, for the correct option, we have;
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You might need: CalculatorA box moves 5 m horizontally when force F 20 N is applied at angle 45 degree to the horizontalWhat is the work done on the box by F during the displacement?Choose 1 answer:
Answers
Given data:
* the displacement of the box in the horizontal direction is 5 m.
* The force applied on the box at an angle of 45 degree is 20 N.
Solution:
The representation of the given system is,
The work done by the force during the displacement is,
\(\begin{gathered} W=F\cdot d \\ W=Fd\cos (45^{\circ}) \end{gathered}\)Substituting the known values,
\(\begin{gathered} W=20\times5\times\cos (45^{\circ}) \\ W=70.71\text{ J} \end{gathered}\)Thus, the work done on the box by the force F during the given displacement is 70.71 J.
which of gardner's intelligences would be least important for a car salesperson?
Answers
The least important intelligence from Gardner's theory for a car salesperson would likely be the Intrapersonal Intelligence.
Gardner's theory of multiple intelligences suggests that individuals possess different types of intelligences, including linguistic, logical-mathematical, spatial, bodily-kinesthetic, musical, interpersonal, intrapersonal, naturalistic, and existential intelligence.
Intrapersonal Intelligence refers to self-awareness and understanding one's own thoughts, emotions, and motivations. It involves introspection, reflection, and the ability to set goals and manage oneself effectively. While this intelligence is valuable in many professions and aspects of life, it may not be as crucial for a car salesperson.
In the context of a car salesperson's role, other intelligences such as interpersonal intelligence, linguistic intelligence, and perhaps even logical-mathematical intelligence are likely to be more important. Effective car salespeople need to possess strong interpersonal skills to build rapport with customers, communicate persuasively, and understand their needs and preferences.
Additionally, linguistic intelligence is valuable for effective communication and conveying product knowledge. Logical-mathematical intelligence can aid in understanding financing options or calculating costs, although it may not be as central to the role as interpersonal and linguistic intelligences. While intrapersonal intelligence is valuable in various contexts, it may be less critical for a car salesperson's success.
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a ball with mass m travels in positive x-direction with a speed v and collides with two other balls (also of mass m). the two struck balls move with equal speeds at 45 degrees up and down with respect to the x-axis after the collision. what is the final speed of all three balls?
Answers
The final speed of all three balls is v \(\sqrt{m/2k}\).
What is speed?
Speed is the rate of movement along a path as opposed to velocity, which represents the speed and direction of an object's movement. As opposed to speed, which is a scalar quantity, velocity is a vector.
What is collision?
When two objects briefly make contact with one another physically, they collide. Or, to put it another way, a collision is an extremely brief reciprocal encounter between two masses that modifies momentum and energy.
Pxi= MV
Pyi= 0
Pxf= mv₁ + 2 mv₂ cos (45°)
Pyf = mv₂ sin (45°)- mv₂ sin (45°) = 0
now
Pxi=Pyi
v= v₁ + 2v₂ cos (45°)
v= \(\sqrt{2}\) v₂ ⇒1
1/2 mv²= 1/2mv₁² + 1/2 (2m) V₂²
V²= v₁² +2 V₂²
V²= (V- \(\sqrt{2}\) v₂)² +2 V₂²
4 V₂² +\(\sqrt[2]{2}\) V V₂
1/2 = 1/\(\sqrt{2}\) v
v₁= v- \(\sqrt{2}\)V₂
v₁= v-v =0
so find the speed will be v, 1/\(\sqrt{2}\) v, 1/\(\sqrt{2}\) v
now , energy conservation,
1/2 mv²- 1/2 2m (v/2)² = 1/2 kx²
mv²- mv²/2 = kx²
mv²/2k = x²
x= v \(\sqrt{m/2k}\)
Therefore, the final speed of all three balls is v \(\sqrt{m/2k}\).
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Resistor 1 Resistor 2 f) Resistor 3 Battery 2 Battery 3 Battery 1 Students are devising an experiment to determining the effect of changing resistors have on the power supplied by a battery to a circuit. The students create the circuit shown measure the current with the ammeter A. and determine the power. Which of the following procedures should the students use for their experiment? (A) Using the circuit with battery and resistor 1, measure the current in the circuit and determine the power supplied by the battery Using the circuit with battery 1 and resistor 1, measure the current in the circuit and determine the power supplied by the battery. Then repeat this step substituting resistor 2 for resistor 1. Then repeat this step substituting resistor 3 for resistor 2 Using the circuit with battery 1 and resistor 1, measure the current in the circuit and determine the power supplied by the battery. Then repeat this step substituting battery 2 for battery 1. Then repeat this step substituting battery 3 for battery2 Using the circuit with battery 1 and resistor 1. measure the current in the circuit and determine the power supplied by the battery. Then repeat this step substituting resistor 2 for resistor 1 Then repeat this step substituting resistor 3 for resistor 2. Then repeat all three steps substituting. Then repeat all three steps substituting battery 3 for battery 2 Using the circuit with battery 1 and resistor 1, measure the current in the circuit and determine the power supplied by the battery. Then repeat this step substituting resistor 2 for resistor 1 and battery 2 for battery 1. Then repeat this step substituting resistor 3 for resistor 2 and battery 3 for battery 2.
Answers
Measure the current in the circuit with battery 1 and resistor 1 and determine the power supplied and repeat this step substituting resistor 2 for resistor 1 and resistor 3 for resistor 2 is the correct procedure.
The students should use the following procedure for their experiment:
1. Using the circuit with battery 1 and resistor 1, measure the current in the circuit and determine the power supplied by the battery.
2. Repeat this step substituting resistor 2 for resistor 1. Measure the current in the circuit and determine the power supplied by the battery.
3. Repeat this step substituting resistor 3 for resistor 2. Measure the current in the circuit and determine the power supplied by the battery.
4. Repeat all three steps substituting battery 2 for battery 1. Measure the current in the circuit and determine the power supplied by the battery.
5. Repeat all three steps substituting battery 3 for battery 2. Measure the current in the circuit and determine the power supplied by the battery.
By performing these steps, the students can measure the current and power supplied by the battery with each of the three different resistors in the circuit. This will allow them to determine the effect that changing resistors have on the power supplied by the battery.
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when connected to a mains of 250v,the fuse rating in the plug of an electric dence of 1kw in ampere is?
Answers
The fuse rating in the plug of the electric device should be 4 amperes.
What is ampere ?
An ampere can be defined as a unit of measure of the rate of electron flow or current in an electrical conductor.
To calculate the fuse rating in amperes for an electric device with a power rating of 1 kW connected to a mains voltage of 250 V, we can use the formula:
P = IV
Where
P is the power in wattsI is the current in amperesV is the voltage in voltsIn this case, we have P = 1000 W (since 1 kW = 1000 W) and V = 250 V. Solving for I, we get:
I = P/V = 1000 W / 250 V = 4 A
Therefore, the fuse rating in the plug of the electric device should be 4 amperes.
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This is primarily in reference to the "Seasons and Earth-sun relationship" video (view around 3:52) as well as the first half of the readings: a) Why does the equator receive equal day and night (12 hours each) regardless of the day of the year? Mention the circle of illumination. b) On December 22nd, within which range of latitudes is 24 hours of day-light experienced? Why?
Answers
a) Answer: On the equator, the Circle of Illumination divides the earth into two equal parts, with each part receiving 12 hours of daylight and 12 hours of darkness.
The equator receives an equal day and night (12 hours each) regardless of the day of the year due to the Circle of Illumination, which is a line that separates the day side of the earth from the night side of the earth. The Circle of Illumination separates the sunlit and dark sides of the earth. The earth's axis is at a 23.5-degree angle to the plane of its orbit around the sun, causing different latitudes to receive different amounts of sunlight throughout the year. On the equator, the Circle of Illumination divides the earth into two equal parts, with each part receiving 12 hours of daylight and 12 hours of darkness.
b) Answer: The earth's axis is tilted at 23.5°, and during the December solstice, the North Pole is tilted away from the sun, causing the Arctic Circle and areas beyond it to experience a full day of daylight because the sun is above the horizon for 24 hours.
On December 22nd, between the latitudes of the Tropic of Cancer (23.5°N) and the Arctic Circle (66.5°N), 24 hours of daylight is experienced. This occurs because the earth's axis is tilted at 23.5°, and during the December solstice, the North Pole is tilted away from the sun, causing the Arctic Circle and areas beyond it to experience a full day of daylight because the sun is above the horizon for 24 hours.
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A spring with a spring constant of 100 N/m completes one oscillation in 2.4 seconds. What is the mass attached to the spring?
a. 9.7 kg
b. 14.6 kg
c. 13.3 kg
d. 5.2 kg
e. 12.3 kg
Answers
To solve this problem, we can use the formula for the period of oscillation of a spring-mass system:
T = 2π√(m/k)
where T is the period of oscillation, m is the mass attached to the spring, and k is the spring constant.
We are given that T = 2.4 seconds and k = 100 N/m. Substituting these values into the formula, we get:
2.4 = 2π√(m/100)
Squaring both sides and rearranging, we get:
m = (100/4π²) × (2.4²) = 12.3 kg (rounded to one decimal place)
Therefore, the mass attached to the spring is 12.3 kg.
Hi! I'd be happy to help you with your question. To find the mass attached to the spring, we need to use the formula for the period of a spring-mass system: T = 2π√(m/k), where T is the period (time for one oscillation), m is the mass, and k is the spring constant.
In this case, the spring constant (k) is 100 N/m, and the period (T) is 2.4 seconds. We can rearrange the formula to solve for the mass (m):
m = (T^2 * k) / (4π^2)
Substitute the given values into the formula:
m = (2.4^2 * 100) / (4π^2)
m ≈ (5.76 * 100) / (39.48)
m ≈ 14.61
The mass attached to the spring is approximately 14.61 kg.
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Can i get help on this guys plss
Answers
On a road trip, you travel from the 100 mile marker to the 250 mile marker in 2 hours. How fast are you going?
Answers
a ball is thrown horizontally from the top of s vertical tower and strikes the ground at point 50m from the bottom of the tower. Given that the height of the tower is 45m, determine the
a)time taken for the ball to hit the ground
b)the initial horizontal velocity of the ball
c)The vertical height of the ball just before striking the ground(take acceleration due to gravity as 10m/s)
Answers
Answer:
B
Explanation:
(20 points) What are wispy looking clouds, usually at high altitudes called?
stratus clouds
nimbus clouds
cirrus clouds
cumulus clouds
Answers
Answer:
the answer is c cirrus clouds
Explanation:
Why does a bus resist changes in its motion more than a motorcycle?
A. The motorcycle has more inertia than the bus
B. The bus had stronger force acting on it
C.the bus has more mass
D.the bus cannot accelerate as fast as the motorcycle
Answers
The reason why a bus resists changes in its motion more than a motorcycle is because the bus has more mass. So, option C is the correct answer.
What is the meaning of mass? Mass is defined as the amount of matter present in an object, which is expressed in kilograms (SI units). It is distinct from weight, which is the force exerted on the object due to gravity. Inertia, which is an object's ability to resist changes in motion, is directly related to mass. As mass increases, so does the amount of inertia of an object. As a result, a bus, which has more mass than a motorcycle, will have more inertia and will resist changes in its motion more than a motorcycle. This is why buses require more force to move than motorcycles, and why they take longer to stop once they're in motion.
The correct option is C.
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The tires of a car make 62 revolutions as the car reduces its speed uniformly from 90.0 km/h to 59.0 km/h. The tires have a diameter of 0.86 m.(A) What was the angular acceleration of the tires? (B) If the car continues to decelerate at this rate, how much more time is required for it to stop? (C) If the car continues to decelerate at how far does it go? Find the total distance.
Answers
A) Angular acceleration = -2.47 rad/s²
B) 23.54 seconds
C) The total distance covered = 294.23m
Explanations:The number of revolutions = 62
Angular distance, θ = 62 x 2π
θ = 62 x 2 x 3.142
θ = 389.608 radians
Diameter, d = 0.86 m
Radius, r = d/2 = 0.86/2
r = 0.43m
Initial velocity, v₁ = 90 km/h = 90 x (1000/3600)
v₁ = 25 m/s
Angular velocity, w₁ = v₁ / r
w₁ = 25/0.43
w₁ = 58.14 rad/s
Final velocity, v₂ = 59 km/h = 59 x (1000/3600)
v₂ = 16.39 m/s
Angular velocity, w₂ = v₂ / r
w₂ = 16.39 / 0.43
w₂ = 38.12 rad/s
Using the equation of motion:
\(\begin{gathered} w^2_2=w^2_1\text{ + 2}\alpha\theta \\ 38.12^2=58.14^2\text{ + 2}\alpha(389.608) \\ 38.12^2-58.14^2=\text{ }779.216\alpha \\ 779.216\alpha\text{ = }-1927.1252 \\ \alpha\text{ = }\frac{-1927.1252}{779.216} \\ \alpha\text{ = }-2.47rad/s^2 \end{gathered}\)Angular acceleration = -2.47 rad/s²
B) Amount of time required for the car to stop if it continues to decelerate at this rate
Initial angular speed, w₁ = 58.14 rad/s
When the car stops, final angular speed, w₂ = 0 rad/s
Using the equation of motion below:
\(\begin{gathered} w_2=w_1+\text{ }\alpha t \\ 0\text{ = 58.14 + (-2.47)t} \\ -2.47t\text{ = -58.14} \\ t\text{ = }\frac{-58.14}{-2.47} \\ t\text{ = }23.54\text{ seconds} \end{gathered}\)C) The total distance
Use the equation of motion below:
\(\begin{gathered} S=v_1\text{t + }\frac{1}{2}at^2 \\ a\text{ = }\alpha r \\ a\text{ = (-2.47)(0.43)} \\ a\text{ = }-1.0621m/s^2 \end{gathered}\)\(\begin{gathered} S=v_1\text{t + }\frac{1}{2}at^2 \\ S\text{ = }25(23.54)+0.5(-1.0621)(23.54)^2 \\ S\text{ = }588.5-294.27 \\ S\text{ = }294.23\text{ m} \end{gathered}\)The total distance covered = 294.23m
how do you find the radius of a cookie? i wish i could say V=pie•r^2•h but my science teacher is telling me that because a cookie can be irregular that’s not an accurate way to measure.
Answers
Answer:
See below
Explanation:
If the cookie is irregular, it will have no fixed number as a radius----depending on where you measure from the center to the circumference, it could be one of several values---
You COULD measure the circumference then perhaps the average diameter could be calculated as: circumference/ pi = diameter
then radius = 1/2 diameter
I think your teacher is saying the cookie is IRREGULAR in VOLUME (or thickness) but not in SHAPE
so you could use the method I mentioned above ....or you could use the AREA of the cookie ( rather than the VOLUME)
AREA = pi r^2 then radius would be = √ ( area / pi)
Five grams of nitrogen gas at an initial pressure of 3.0 atm and at 20? C undergo an isobaric expansion until the volume has tripled.
a. What is the gas volume after the expansion?
b. What is the gas temperature after the expansion? The gas pressure is then decreased at constant volume until the original temperature is reached.
Answers
a. To determine the gas volume after the isobaric expansion, we can use the ideal gas law:
PV = nRT
Where P is the pressure, V is the volume, n is the amount of substance (in moles), R is the ideal gas constant, and T is the temperature (in Kelvin).
Since the pressure remains constant during the expansion, we can write:
(V1)(P1) = (V2)(P2)
where V1 and P1 are the initial volume and pressure, respectively, and V2 and P2 are the final volume and pressure, respectively. We can solve for V2:
V2 = (V1)(P1)/(P2) = (5 g)/(28.0134 g/mol)(3.0 atm) x 3 = 6.39 L
Therefore, the gas volume after the isobaric expansion is 6.39 L.
b. To determine the gas temperature after the isobaric expansion and subsequent decrease in pressure at constant volume, we can use the combined gas law:
(P1)(V1)/(T1) = (P2)(V2)/(T2)
where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.
Since the volume remains constant during the pressure decrease, we can write:
(P1)/(T1) = (P2)/(T2)
Solving for T2:
T2 = (P2)/(P1)(T1) = (1 atm)/(3.0 atm)(293 K) x 20 + 273 = 300.8 K
Therefore, the gas temperature after the isobaric expansion and pressure decrease is 300.8 K (27.65 °C).
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A skier rides horizontally off of a 200 meter high cliff. If he lands 25 meters away from the base of the cliff, how fast was he skiing as he went off the edge?
A. 0.91 m/s
B. 2.91 m/s
C. 3.91 m/s
D. 25.91 m/s
Answers
Answer:
the answers, the correct one is C, v₀ₓ = vₓ = 3.91 m / s
Explanation:
This is a projectile launching exercise, in this case they indicate that when leaving the cliff it goes horizontally, therefore the initial vertical speed is zero, let's find the time to reach the base
y = y₀ + \(v_{oy}\) t - ½ g t²
at the base the height is zero (y = 0 m)
0 = y₀ + 0 - ½ g t²
t = √ (2y₀ / g)
we calculate
t = √ (2 200 / 9.8)
t = 6.389 s
with this time we calculate the horizontal speed
v₀ₓ = x / t
v₀ₓx = 25 / 6,389
v₀ₓ = vₓ = 3.91 m / s
When checking the answers, the correct one is C
A tugboat is pulling a barge into a harbor. The barge is exerting a force of 3000 N against the tugboat.
Answers
Available options are:
A. –4500 N
B. –2500 N
C. 2500 N
D. 4500 N
Answer:
-4500 N
Explanation:
Given that we have F₁ = 3000N? (force of the barge)
the force of the tugboat is F '
To pull the barge, the force of the tugboat must be greater than or equal to the force of the barge.
Hence, according to Newton's third law which states that for every action or force in nature, there is an opposite reaction.
Therefore considering the available option the correct answer is "- 4500N, " this is because it is greater than the force of the barge and it's in opposition to the force exerted.
Answer:
The answer is -4500 N
Explanation:
Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
Answers
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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