WILL MARK BRAINLIST!!! Bryan earns $200 each week, and 12% commission for each car sale he makes while working at a used car dealership. If he sells a used car for $2,000, how much total money does he make that week?

Hello.

Let's find the multiplicative inverse of -100.

In order to do that, we need to write -100 as a fraction:

\(\bf{\displaystyle\frac{-100}{1}\)

Now, in order to find the multiplicative inverse of -100, we should flop the fraction over:

\(\bf{\displaystyle\frac{1}{-100}\)

I hope it helps.

Have an outstanding day. :)

\(\boxed{imperturbability}\)

Therefore, the rate of change, in cm per minute, of the height when the height is 6 cm is approximately -6 cm/min.

Given,The width of the box = 10 cm Length of the box = 17 cmThe volume of the box = 527 cubic cm/minWe need to find the rate of change, in cm per minute, of the height when the height is 6 cm.We know that the volume of the box is given as:V = l × w × h where, l, w and h are length, width, and height of the box respectively.It is given that the width and length are being held constant.

Therefore, we can write the volume of the box as

:V = constant × h Differentiating both sides with respect to time t, we get:dV/dt = constant × dh/dtNow, it is given that the volume of the box is decreasing at a rate of 527 cubic cm per minute.

Therefore, dV/dt = -527.Substituting the given values in the above equation, we get:

527 = constant × dh/dt

We need to find dh/dt when h = 6 cm.To find constant, we can use the given values of length, width and height.Substituting these values in the formula for the volume of the box, we get:

V = l × w × hV = 17 × 10 × hV = 170h

We know that the volume of the box is given as:V = constant × hSubstituting the value of V and h, we get:

527 = constant × 6 cm

constant = 87.83 cm/minSubstituting the values of constant and h in the equation, we get

-527 = 87.83 × dh/dtdh/dt = -6.0029 ≈ -6 cm/min

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Answer:

Step-by-step explanation:

Answer:

x > -2

Step-by-step explanation:

2(3x–1)>4x–6

Divide each side by 2

2/2(3x–1)>4x/2–6/2

3x-1 > 2x-3

Subtract 2x from each side

3x-2x-1 > 2x-3-2x

x-1 > -3

Add 1 to each side

x-1+1 > -3+1

x > -2

Answer:

wowo

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

The standard deviation of random variable K is 15.49  (option D ) and this can be determined by using the formula of mean and standard deviation.

Given,

The mean of geometric distribution of random variable K = 16

Formulae for finding mean,

                                      mean = 1/p

Substitute the value of the mean in the above formula in order to determine the value of 'p'.

\(16 =\frac{1}{p}\)

\(p = 0.0625\)

The formulae for standard deviation :

   S.D.=\(\frac{\sqrt{1-p} }{p}\)

Now substitute the value of p in the above equation,

S.D. \(= \frac{\sqrt{1-0.0625} }{0.0625}\)

       \(= 15.49\)

Hence, the answer is option D.

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Answer:

\(\frac{1 }{200^4} \\\)

Step-by-step explanation:

\((\frac{5^{-2} }{2^{3} } )^{4}\\\\(\frac{1 }{2^{3} *5^{2}} )^{4} \\\\(\frac{1 }{8 *25} )^{4} \\\\\frac{1 }{200^4} \\\)

Answer:

(-7,5)

Step-by-step explanation:

the question was cut off, but I'm assuming that you want to find the location of Denver. Looking at the coordinate plane, Denver, would sit at (-7,5) as you find what x and y values they meet up at. Hopefully this answers your question

If we are looking for the location of Dallas (that is all I see), the coordinates would be as follows.

(2,-4)

Hope this helps.

The solution is, the required cost of the used game X= 19.

An equation which can be expressed as a mathematical statement that is made up of two expressions connected by an equal sign.  In its simplest form in algebra, the definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.

here, we have,

So he bought the $120 game with $82

and 2 equally priced game.

This can be changed to an equation: 120= 82+2X.

The X represents the cost of the used game.

120= 82+2X

-82 -82

——————-

38= 2X

38= 2X

Divide by 2 on both sides

X= 19

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Type I error is "Megan's results show significant improvements in health associated with a whole foods diet."

A Type I error occurs when the null hypothesis is rejected, even though it is true.

In this case, the null hypothesis states that a whole foods diet would not have any impact on general health.

Therefore, a Type I error would occur if Megan's results show significant improvements in health associated with a whole foods diet.

This means that Megan would reject the null hypothesis and conclude that a whole foods diet does have an impact on general health, even though it is not true.

So, the statement that would indicate a Type I error is "Megan's results show significant improvements in health associated with a whole foods diet."

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Answer:

10 m

Step-by-step explanation:

\(bh/2\)

\(20h/2=100\)

\(20h=200\)

\(h=10\)

Answer:

10m

Step-by-step explanation:

Use the formula,

A=H B B/2

2x 100/20=10m

Answer:

y' = 3x² + 2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

Step-by-step explanation:

Step 1: Define

Identify

y = x³ + 2x - 1

Step 2: Differentiate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

a) The highway affected the growth of many plant species, which serve as food for the deer. Option D

b) There will be fewer population of the birds. Option C

The carrying capacity of an ecosystem is the maximum number of individuals of a particular species that can be supported by the available resources in that ecosystem.

It is the point at which the population growth rate becomes zero, as the resources needed to sustain the population (such as food, water, and space) become limited. Carrying capacity can change over time due to factors such as climate change, pollution, and human activity.

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0.137606 the standard error of the average amount of coffee a stat 107 student drinks per day is greater than 12.7 oz.

Data dispersion in regard to the mean is quantified by a standard deviation, or "σ". Statisticians can assess if the data fits into a normal distribution or another mathematical connection using the standard deviation. The average, or mean, data point will be within one standard deviation of 68% of the data points if the data follow a normal curve.

Given that,

Standard deviation (σ) = 5.2 oz

mean (μ) = 10 oz

Number of students (n) = 120

As we know,

P ( z > 12.7 oz.) = P (z > [{x(avg.) - μ\(\sqrt{n}\)}/σ])

                        = P (z > [{12.7 - 10\(\sqrt{120}\)}/5.2])

                        = P (z > 1.86)

                        = 1 - P ( z < 1.86)

                        = 1 - 0.862394

                        = 0.137606

Thus, P( z > 12.7 oz.) = 0.137606

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Answer:

x=5

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Desmos Graphing Calculator

Answer:

a.  the control limits should be set at (10.72, 11.28)

b. \(\mathbf{P(10.72<x<11.28) = 0.4526}\)

c. \(\mathbf{P(10.72<x<11.28) = 0.0065}\)

Step-by-step explanation:

Given that:

population mean μ = 11

standard deviation \(\sigma\) = 1.0

sample size n = 35

5% of the sample means will be greater than the upper control limit, and 5% of the sample means will be less than the lower control limit.

Therefore, level of significance ∝ = 0.05+0.05 = 0.10

Critical value for \(z_{1-\alpha/2} =z_{1-0.10 /2}\)

\(\implies z_{1-0.05} = z_{0.95}\)

Using the EXCEL FORMULA: = NORMSINV (0.95)

z = 1.64

The lower control limit and the upper control limit can be determined by using the respective formulas:

Lower control limit = \(\mathtt{\mu - z_{1-\alpha/2} \times \dfrac{\sigma}{\sqrt{n}}}\)

Upper control limit = \(\mathtt{\mu + z_{1-\alpha/2} \times \dfrac{\sigma}{\sqrt{n}}}\)

For the lower control limit = \(11-1.64 \times \dfrac{1.0}{\sqrt{35}}\)

For the lower control limit = \(11-0.27721\)

For the lower control limit = 10.72279

For the lower control limit \(\simeq\) 10.72

For the upper control limit = \(11+1.64 \times \dfrac{1.0}{\sqrt{35}}\)

For the upper control limit = 11 + 0.27721

For the upper control limit = 11.27721

For the upper control limit  \(\simeq\)  11.28

Therefore , the control limits should be set at (10.72, 11.28)

b. If the population mean shifts to 10.7, what is the probability that the change will be detected?

i.e

\(\mathtt{P(10.72<x<11.28) = P( \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}<z < \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}})\)

\(\mathtt{P(10.72<x<11.28) = P( \dfrac{10.72- 10.7}{\dfrac{1.0}{\sqrt{35}}}<z < \dfrac{11.28- 10.7}{\dfrac{1.0}{\sqrt{35}}}})\)

\(\mathtt{P(10.72<x<11.28) = P( \dfrac{0.02}{\dfrac{1.0}{5.916}}<z < \dfrac{0.58}{\dfrac{1.0}{5.916}}})\)

\(\mathtt{P(10.72<x<11.28) = P(0.1183<z < 3.4313})\)

\(\mathtt{P(10.72<x<11.28) = P(z< 3.4313) - P(z< 0.1183) }\)

Using the EXCEL FORMULA: = NORMSDIST (3.4313) - NORMSDIST (0.118 ); we have:

\(\mathbf{P(10.72<x<11.28) = 0.4526}\)

c If the population mean shifts to 11.7, what is the probability that the change will be detected?

i.e

\(\mathtt{P(10.72<x<11.28) = P( \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}<z < \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}})\)

\(\mathtt{P(10.72<x<11.28) = P( \dfrac{10.72- 11.7}{\dfrac{1.0}{\sqrt{35}}}<z < \dfrac{11.28- 11.7}{\dfrac{1.0}{\sqrt{35}}}})\)

\(\mathtt{P(10.72<x<11.28) = P( \dfrac{-0.98}{\dfrac{1.0}{5.916}}<z < \dfrac{-0.42}{\dfrac{1.0}{5.916}}})\)

\(\mathtt{P(10.72<x<11.28) = P(-5.7978<z < -2.48472})\)

\(\mathtt{P(10.72<x<11.28) = P(z< -2.48472) - P(z< -5.7978) }\)

Using the EXCEL FORMULA: = NORMSDIST (-2.48472) - NORMSDIST (-5.7978); we have:

\(\mathbf{P(10.72<x<11.28) = 0.0065}\)

The probability that a defective component will be detected only by the first inspector is 0.19

The probability that a defective component will be detected by exactly one of the two inspectors is 0.38

The probability that all three defective components in a batch escape detection by both inspectors is 0.

It is given that The first inspector detects 81% of all defectives that are present, and the second inspector does likewise.

Therefore P(A)=P(B)=81%=0.81

At least one inspector does not detect a defect on 38% of all defective components.

Therefore, bar P(A∩B)=0.38

As we know:

bar P(A∩B)=1-P(A∩B)=0.38

P(A∩B)=1-0.38=0.62

A defective component will be detected only by the first inspector.

P(A∩barB)=P(A)-P(A∩B)

=0.81-0.62

P(A∩barB)=0.19

The probability that a defective component will be detected only by the first inspector is 0.19

Part (B) A defective component will be detected by exactly one of the two inspectors.

This can be written as: P(A∩barB)+P(barA∩B)

As we know:

P(barA∩B)=P(B)-P(A∩B) and P(A∩bar B)=P(A)-P(A∩B)

Substitute the respective values we get:

P(A∩ barB)+P(bar A∩B)=P(A)+P(B)-2P(A∩B)

=0.81+0.81-2(0.62)

=1.62-1.24

P(A∩ barB)+P(bar A∩B)=0.38

The probability that a defective component will be detected by exactly one of the two inspectors is 0.38

Part (C) All three defective components in a batch escape detection by both inspectors

This can be written as: P(bar A∪ bar B)-P(bar A∩B)-P(A∩ barB)

As we know bar P(A∩B)=P(bar A∪ bar B)=0.38

From part (B): P(bar A∩B)+P(A∩bar B)=0.38

This can be written as:

P(bar A∪ bar B)-P(bar A∩B)-P(A∩bar B)=0.38-0.38=0

The probability that all three defective components in a batch escape detection by both inspectors is 0

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Answer: The description of that transformation is the triangle is rotated 90 degrees clockwise. Then, it's moved to the right TWICE. Finally, you go down 2 times.

Step-by-step explanation:

Hope this helps :)

triangle B is in dofferent orientation from triangle B so we know it was either mirrored or rotated. Triangle B isnt in the exact opposite orientation as A so we know it wasnt mirrored. So we now know that it was rotated and know we have to find the point of rotation. we can tell that the rotation was 270 degrees anti clockwise since it cant be clockwise because no points of rotation match. since we know triangle A was rotated 270 degrees anti clockwise to get triangle B we cant find the point of rotation by seeing which point works and if we test the points we will see that (0;-1) is the point of rotation. So triangle A was rotated 270 degrees anti clockwise on the point (0;-1) to make triangle B

Solve for one half on the triangle with height 6 and base would be 4/2 = 2

Use the Pythagorean theorem:

X = sqrt( 6^2 + 2^2)

X = sqrt( 36 + 4)

X = sqrt(40)

The answer is D

The standard form of the equation is (x - 1)² - (y - 1)² + (z + 2)²  = 3

The equation is given as:

x² -y² + z² - 2x + 2y + 4z + 1 = 0

Subtract 1 from both sides

x² -y² + z² - 2x + 2y + 4z = -1

Rewrite the equation as:

x² - 2x -y² + 2y + z² + 4z = -1

Next, we complete the square on each variable term.

Using a graphing calculator, we have:

(x - 1)² - (y - 1)² + (z + 2)²  = -1 + 1 + 4 - 1

Evaluate the sum and difference

(x - 1)² - (y - 1)² + (z + 2)²  = 3

x^2 - 2x + 2 - (y^2 - 2y + 2) + z^2 + 4z + 4 = 3

Hence, the standard form of the equation is (x - 1)² - (y - 1)² + (z + 2)²  = 3

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Option B is the correct answer

In order to find whether or not a line is parallel to another line, both lines must have the same slope.

Given the slope_intercept form of the line equation as:

m must be equal for both lines.

Now let us proceed to analyse each option.

Option 1:

Therefore, the lines are parallel.

Option 2:

The correct statement is: g(x) is translated up 5 units compared to f(x).

The correct answer is A.

The correct answer is A.

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Number of car sold are 98.

Number of trucks sold are 66.

Given,

Dealer 1 sold 164 cars and trucks and dealer 2 sold 229 cars and trucks .

Let number of cars sold are x.

Let number of cars sold of y .

Now,

For dealership 1 equation will be,

x + y = 164  ......(1)

For dealership 2 equation will be,

As the cars are sold twice and trucks are sold half .

2x + y/2 = 229......(2)

Solving 1 and 2,

y = 66

x = 98

Thus number of car sold are 98.

Thus number of trucks sold are 66.

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Answer: y = –(3/4)x + 2.75

Step-by-step explanation:

Parallel lines have the same slope. Solve for the slope in the first line by converting the equation to slope-intercept form.

3x + 4y = 12

4y = –3x + 12

y = –(3/4)x + 3

slope = –3/4

We know that the second line will also have a slope of –3/4, and we are given the point (1,2). We can set up an equation in slope-intercept form and use these values to solve for the y-intercept.

y = mx + b

2 = –3/4(1) + b

2 = –3/4 + b

b = 2 + 3/4 = 2.75

Plug the y-intercept back into the equation to get our final answer.

y = –(3/4)x + 2.75

Answer:

y = \(\frac{1}{2}\) x + 4

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \(\frac{1}{2}\) x - 5 ← is in slope- intercept form

with slope m = \(\frac{1}{2}\)

• Parallel lines have equal slopes , then

y = \(\frac{1}{2}\) x + c ← is the partial equation

to find c substitute (4, 6 ) into the partial equation

6 = 2 + c ⇒ c = 6 - 2 = 4

y = \(\frac{1}{2}\) x + 4 ← equation of parallel line

The angle measure explained in the solution.

Given that, a || b, we need to find the missing angles,

∠1 = 42° [vertically opposite angles]

∠3 = 62° [vertically opposite angles]

∠2 = 180°-(∠1+62°) [angle in a straight line]

∠2 = 76°

∠4 = ∠2 [vertically opposite angle]

∠4 = 76°

∠4 = ∠9 = 76° [alternate angles]

∠9 = ∠12 = 76° [vertically opposite angle]

∠3 = ∠ 6 = 62° [alternate angles]

∠ 6 = ∠7 = 62° [vertically opposite angle]

∠3 + ∠5 = 180° [consecutive angles]

∠5 = 118°

∠5 = ∠8 = 118° [vertically opposite angle]

∠4 + ∠10 = 180° [consecutive angles]

∠10 = 104°

∠10 = ∠11 [vertically opposite angle]

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The speed of landing is 15.69 ft/sec.

"Differentiation, in mathematics, process of finding the derivative, or rate of change, of a function. In contrast to the abstract nature of the theory behind it, the practical technique of differentiation can be carried out by purely algebraic manipulations, using three basic derivatives, four rules of operation, and a knowledge of how to manipulate functions.    

The three basic derivatives (D) are: (1) for algebraic functions, D(xn) = nxn − 1, in which n is any real number; (2) for trigonometric functions, D(sin x) = cos x and D(cos x) = −sin x; and (3) for exponential functions, D(ex) = ex."

Let the length of the rope = r

Height of the balloon = h

we are given dr/dt = 15ft/sec

at any time t we know:

\(r = 125 + 15*t\)

By the Pythagoras theorem we know:

\(h^2 + 125^2 = r^2\)

We have to find dh/dt at time t = 20 sec

\(d/dh(h^2 + 125^2) = d/dt(r^2)\)

By chain rule:

\(d/dh(h^2 + 125^2)*dh/dt\\ = d/dr(r^2)*dr/dt\\2h*dh/dt = 2r* dr/dt\\h*dh/dt = r*dr/dt\\dh/dt = (r/h)*dr/dt\)

\(= [(125 + 15*20)/(425^2 - 125^2)^1/2]*15\)--------------------- at time t = 2

=15.69 ft/sec

Hence dh/dt = 15.69 ft/sec

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