6th grade math help me pozzzz

The area under the standard normal curve between z=â1.16 and z=â0.03 is 0.3663.

To find the area under the standard normal curve between z = -1.16 and z = -0.03, we will use the following steps:

1. Look up the z-values in the standard normal distribution table (or use a calculator or online tool that provides the corresponding probability values).
2. Subtract the probability value for z = -1.16 from the probability value for z = -0.03.
3. Round your answer to four decimal places.

Step 1: Look up the z-values in the standard normal distribution table.
- For z = -1.16, the corresponding probability value is 0.1230.
- For z = -0.03, the corresponding probability value is 0.4893.

Step 2: Subtract the probability values.
Area = P(-0.03) - P(-1.16) = 0.4893 - 0.1230

Step 3: Round the answer to four decimal places.
Area = 0.3663

So, the area under the standard normal curve between z = -1.16 and z = -0.03 is approximately 0.3663.

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Answer:

A

Step-by-step explanation:

Read the article and review the phases of mitosis.

Mitosis

What are the four phases of mitosis?

prophase

metaphase

anaphase

telophase

cytokinesis

The ways that we can choose 2 red, 1 yellow, and 2 blue marbles is ³C₂ ×  ⁵C₁ ×  ⁸C₂ / ¹⁶C₅

According to the question,

In a bag there are three different color of marbles

Number of red color marbles = 3

Number of yellow color marbles = 5

Number of blue color marbles = 8

Total number of marbles = 3 + 5 + 8

=> 16

We have to find number of ways to choose 2 red, 1 yellow, and 2 blue marbles

For choosing 2 red marbles from total 3 ,

Number of ways = ³C₂

For choosing 1 yellow marbles from total 5 ,

Number of ways = ⁵C₁

For choosing 2 blue marbles from total 8 ,

Number of ways =  ⁸C₂

Total number of ways to choose 5 marbles from 16 = ¹⁶C₅

Therefore , Numbers of ways we can choose n 2 red, 1 yellow, and 2 blue marbles =  ³C₂ ×  ⁵C₁ ×  ⁸C₂ / ¹⁶C₅

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To complete the Material Requirements Planning (MRP) table for product A, we need to calculate the Net Requirements and Planned Order Releases based on the given information. Here's the completed MRP table:

Lot Volume = multiples of 50

Delivery Time = 2 weeks

Starting Inventory: 30

| Period | Gross Need | Scheduled Receipt | Projected Inventory | Net Requirements |

| 1 | 25 | | 30 | 0 |

| 2 | 30 | | | |

| 3 | 56 | | | |

| 4 | 25 | | | |

| 5 | 100 | | | |

| 6 | 40 | | | |

| 7 | 30 | | | |

To calculate the Scheduled Receipt and Projected Inventory, we need to consider the lot volume and delivery time. Assuming a lot volume of 50 and a delivery time of 2 weeks, the calculations are as follows:

Period 1:

Scheduled Receipt = 0 (No orders scheduled to arrive in this period)

Projected Inventory = Starting Inventory + Scheduled Receipt - Gross Need = 30 + 0 - 25 = 5

Period 2:

Scheduled Receipt = 50 (Order placed to fulfill the gross need of 30)

Projected Inventory = Previous Projected Inventory + Scheduled Receipt - Gross Need = 5 + 50 - 30 = 25

Period 3:

Scheduled Receipt = 50 (Order placed to fulfill the gross need of 56)

Projected Inventory = Previous Projected Inventory + Scheduled Receipt - Gross Need = 25 + 50 - 56 = 19

Period 4:

Scheduled Receipt = 0 (No orders scheduled to arrive in this period)

Projected Inventory = Previous Projected Inventory + Scheduled Receipt - Gross Need = 19 + 0 - 25 = -6

Period 5:

Scheduled Receipt = 100 (Order placed to fulfill the gross need of 100)

Projected Inventory = Previous Projected Inventory + Scheduled Receipt - Gross Need = -6 + 100 - 100 = -6

Period 6:

Scheduled Receipt = 50 (Order placed to fulfill the gross need of 40)

Projected Inventory = Previous Projected Inventory + Scheduled Receipt - Gross Need = -6 + 50 - 40 = 4

Period 7:

Scheduled Receipt = 0 (No orders scheduled to arrive in this period)

Projected Inventory = Previous Projected Inventory + Scheduled Receipt - Gross Need = 4 + 0 - 30 = -26

The Net Requirements are calculated as the difference between the Gross Need and the Projected Inventory. If the Net Requirements are positive, it indicates the quantity needed to fulfill the demand. If the Net Requirements are negative, it means there is excess inventory.

Please note that this MRP table assumes no changes in demand, lead time, or lot sizing throughout the periods.

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The price that Maura sell each scarf would be =$33. Maura sells each scarf for $33. That is option A.

To calculate the amount of money that Maura spends on each scarf the following is carried out.

The amount of money that she spends on the scarf material = $5.50

The percentage selling price of each scarf = 600% of $5.50

That is ;

= 600/100 × 5.50/1

= 3300/100

= $33.

Therefore, each price that is sold by Maura would probably cost a total of $33.

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Answer:

linear relationship (or linear association) is a statistical term used to describe a straight-line relationship between two variables

Answer:

Below:

Step-by-step explanation:

A linear relationship (or linear association) is a statistical term used to describe a straight-line relationship between two variables. Linear relationships can be expressed either in a graphical format or as a mathematical equation of the form y = mx + b. Linear relationships are fairly common in daily life.

Hope it helps....

It's Muska...

To prove that AD ≅ DB, we can use the ASA (Angle-Side-Angle) congruence criterion.

Given:

∠CAD ≅ ∠CBD (Angle CAD is congruent to angle CBD)

∠CAB ≅ ∠CBA (Angle CAB is congruent to angle CBA)

To Prove:

AD ≅ DB (Segment AD is congruent to segment DB)

Proof:

Step 1: Draw segment AC and segment BC.

Step 2: By the given information, we have ∠CAD ≅ ∠CBD and ∠CAB ≅ ∠CBA.

Step 3: Draw segment CD to complete triangle ABC.

Step 4: Now, we have two pairs of congruent angles (∠CAD ≅ ∠CBD and ∠CAB ≅ ∠CBA).

Step 5: According to the ASA congruence criterion, if two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent.

Step 6: Apply the ASA congruence criterion to triangles CAD and CDB:

∠CAD ≅ ∠CBD (Given)

∠CAB ≅ ∠CBA (Given)

CD ≅ CD (Common side)

Step 7: By the ASA congruence criterion, triangles CAD and CDB are congruent.

Step 8: Since the triangles CAD and CDB are congruent, their corresponding sides are congruent.

Step 9: By the corresponding parts of congruent triangles (CPCTC), we can conclude that AD ≅ DB.

Therefore, we have proved that AD ≅ DB using the ASA congruence criterion.

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Answer:

x=25

Step-by-step explanation:

∠CDE is an exterior angle. I have enclosed an image of the formula below.

Using that formula, we can get a starting equation:

\(\frac{(4x+5)-50}{2}=x+2.5\)

Now, we just solve for x using algebra:

\(4x-45=2x+5\\2x=50\\x=25\)

If you need further explanation, let me know. Hope this helps!

Answer:

Aaron's family will use 3 gallons of milk in thirty days.

Step-by-step explanation:

1. Multiply the amount of milk (1/2) times the days (30)

1/2 x 30 = 15

2. Divide 15 by 5 (every 5 days)

15 / 5 = 3

Inequalities help us to compare two unequal expressions. The algebraic expression for fifteen more than n is at least 48 is n+15 ≥ 48; n≥33. Thus, the correct option is C.

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

The given statement "fifteen more than n is at least 48" can be written in the form of an algebraic expression as,

n+15 ≥ 48

Solving the inequality,

n ≥ 48 - 15

n  ≥ 33

Hence, the algebraic expression for fifteen more than n is at least 48 is n+15 ≥ 48; n≥33. Thus, the correct option is C.

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The monthly payment amount is $217.42 and the finance charge is $413.02.

The payment amount and finance charge can be found by using the formula below

Payment amount formula: PMT = (P x R x (1 + R)^N) / ((1 + R)^N - 1)

Finance charge formula: Finance charge = Total payment - Loan amount

Where P = Loan amount

R = Interest rate per period

N = Number of periods

Given that a loan is made for $4800 with an APR of 12% and payments made monthly for 24 months

Therefore,P = $4800R = 12% / 12 = 1% per month

N = 24

Using the Payment amount formula above: PMT = (P x R x (1 + R)^N) / ((1 + R)^N - 1)

PMT = ($4800 x 0.01 x (1 + 0.01)^24) / ((1 + 0.01)^24 - 1)

PMT = $217.42

Hence, the monthly payment amount is $217.42 (rounded to two decimal places).

Using the finance charge formula above: Finance charge = Total payment - Loan amount

Total payment = Payment amount x Number of periods

Total payment = $217.42 x 24 = $5213.02

Finance charge = $5213.02 - $4800

Finance charge = $413.02

Hence, the finance charge is $413.02 (rounded to two decimal places).

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Answer: look at the picture

Step-by-step explanation: Hope this help :D

The number of cookies in the jar initially was 42

To find out how many cookies were in the jar initially, we can use algebra to represent the problem. Let x be the number of cookies in the jar initially. After Latoya took half of the cookies, Mark took 1/3 of the remaining cookies, Kandi took 1/4 of the remaining cookies, and Shannon took 1 cookie, there are 2 cookies left in the jar.

We can use this information to set up the equation:

x/2 - (x/2)/3 - (x/2)/4 - 1 - 2 = 0.

By solving this equation, we get x = 42. This means there were 42 cookies in the jar initially. To find out how many cookies were there before Latoya came, we just add the 2/3 of a cookie that was left over to the 2 whole cookies we know of.

So, 42+2/3 = 42.67 which means 42 cookies were there before Latoya came.

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Answer:

5 r 2

Step-by-step explanation:

Tom wants to buy 3( 3)/(4) cups of almonds. There are ( 5)/(8) of a cup of almonds in each package.  Tom should buy 24 packages of almonds to obtain 3(3/4) cups of almonds.

To find the number of packages, we first convert the mixed number 3(3/4) to an improper fraction. The improper fraction equivalent of 3(3/4) is (4*3+3)/4 = 15/4 cups of almonds.

Next, we divide the total cups needed (15/4) by the amount of almonds in each package, which is (5/8) of a cup. To divide fractions, we multiply the first fraction by the reciprocal of the second fraction. So, (15/4) / (5/8) becomes (15/4) * (8/5).

Simplifying the multiplication of fractions, we cancel out common factors between the numerator of the first fraction and the denominator of the second fraction. After cancellation, we have (3/1) * (8/1) = 24.

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Answer:

7/15

Step-by-step explanation:

Using the Chain Rule to find dw/dt:

We have w = xey/z, where x = t^3, y = 3 - t, and z = 7 + 3t. To find dw/dt, we can use the Chain Rule:

dw/dt = (∂w/∂x)(dx/dt) + (∂w/∂y)(dy/dt) + (∂w/∂z)(dz/dt)

Taking the partial derivatives of w with respect to x, y, and z, we get:

∂w/∂x = ey/z * 3t^2

∂w/∂y = ex/z * (-1)

∂w/∂z = -exy/z^2

Substituting in the values for x, y, and z, we get:

∂w/∂x = (3t^2)(3-t)/(7+3t)

∂w/∂y = -(t^3)(3-t)/(7+3t)

∂w/∂z = -(t^3)(3-t)(3+7t)/(7+3t)^2

Taking the derivatives of x, y, and z with respect to t, we get:

dx/dt = 3t^2

dy/dt = -1

dz/dt = 3

Substituting in all the values, we get:

dw/dt = (3t^2)(3-t)/(7+3t) + -(t^3)(3-t)/(7+3t) + -(t^3)(3-t)(3+7t)/(7+3t)^2

Simplifying this expression, we get:

dw/dt = (-3t^4 + 9t^3 + 3t^2 - 9t)/(7+3t)^2

Using the Chain Rule to find dw/dt:

We have w = ln(vx^2 + y^2 + z^2), where x = 2sin(t), y = 4cos(t), and z = 5tan(t). To find dw/dt, we can use the Chain Rule:

dw/dt = (∂w/∂x)(dx/dt) + (∂w/∂y)(dy/dt) + (∂w/∂z)(dz/dt)

Taking the partial derivatives of w with respect to x, y, and z, we get:

∂w/∂x = 2vx^2/(vx^2 + y^2 + z^2)

∂w/∂y = 2vy/(vx^2 + y^2 + z^2)

∂w/∂z = 2vz/(vx^2 + y^2 + z^2)

Substituting in the values for x, y, and z, we get:

∂w/∂x = 4vsin(t)^2/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2))

∂w/∂y = 8vcos(t)/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2))

∂w/∂z = 10vtan(t)/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2))

Taking the derivatives of x, y, and z with respect to t, we get:

dx/dt = 4cos(t)

dy/dt = -4sin(t)

dz/dt = 5sec^2(t)

Substituting in all the values, we get:

dw/dt = (4vsin(t)^2)/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2)) + (8vcos(t))/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2)) + (10vtan(t))/(v(sin(t)^2 + cos(t)^2 + 25tan(t)^2))

Simplifying this expression, we get:

dw/dt = (16vsin(t)cos(t) - 32vcos(t)sin(t) + 50vtan(t)sec^2(t))/(sin(t)^2 + cos(t)^2 + 25tan(t)^2)^2

Using the Chain Rule to find az/as and az/at:

We have z = tan(u/v), where u = 7s + 9t and v = 9s - 7t. To find az/as and az/at, we can use the Chain Rule:

az/as = (∂z/∂u)(du/ds) + (∂z/∂v)(dv/ds)

az/at = (∂z/∂u)(du/dt) + (∂z/∂v)(dv/dt)

Taking the partial derivatives of z with respect to u and v, we get:

∂z/∂u = sec^2(u/v)(1/v)

∂z/∂v = -sec^2(u/v)(u/v^2)

Taking the derivatives of u and v with respect to s and t, we get:

du/ds = 7

dv/ds = 9

du/dt = 9

dv/dt = -7

Substituting in all the values, we get:

az/as = (sec^2(u/v)(1/v))(7) + (-sec^2(u/v)(u/v^2))(9)

az/at = (sec^2(u/v)(1/v))(9) + (-sec^2(u/v)(u/v^2))(-7)

Substituting in the expression for u and v, we get:

az/as = (sec^2((7s+9t)/(9s-7t))(1/(9s-7t)))(7) + (-sec^2((7s+9t)/(9s-7t))((7s+9t)/(9s-7t)^2))(9)

az/at = (sec^2((7s+9t)/(9s-7t))(1/(9s-7t)))(9) + (-sec^2((7s+9t)/(9s-7t))((7s+9t)/(9s-7t)^2))(-7)

Finding the rates of change of volume, surface area, and length of diagonal of a box:

At a certain instant, the dimensions of the box are l = 9 m, w = h = 5 m, and l and w are increasing at a rate of 7 m/s while h is decreasing at a rate of 4 m/s.

(a) To find the rate at which the volume is changing, we can use the formula for the volume of a box:

V = lwh

Taking the derivative of V with respect to time, we get:

dV/dt = (dh/dt)lwh + (dl/dt)wh + (dw/dt)lh

Substituting in the values for l, w, and h, as well as the rates of change for l, w, and h, we get:

dV/dt = (-4)(9)(5)(5) + (7)(5)(5)(9) + (7)(9)(5)(5)

Simplifying this expression, we get:

dV/dt = 385 m^3/s

Therefore, the volume of the box is increasing at a rate of 385 m^3/s at that instant.

(b) To find the rate at which the surface area is changing, we can use the formula for the surface area of a box:

S = 2lw + 2lh + 2wh

Taking the derivative of S with respect to time, we get:

dS/dt = (dl/dt)(2w + 2h) + (dh/dt)(2l + 2w) + (dw/dt)(2l + 2h)

Substituting in the values for l, w, and h, as well as the rates of change for l, w, and h, we get:

dS/dt = (7)(2(5) + 2(5)) + (-4)(2(9) + 2(5)) + (7)(2(9) + 2(5))

Simplifying this expression, we get:

dS/dt = 164 m^2/s

Therefore, the surface area of the box is increasing at a rate of 164 m^2/s at that instant.

(c) To find the rate at which the length of the diagonal is changing, we can use the formula for the length of the diagonal of a box:

D = sqrt(l^2 + w^2 + h^2)

Taking the derivative of D with respect to time, we get:

dD/dt = (1/2)(l^2 + w^2 + h^2)^(-1/2)(2l(dl/dt) + 2w(dw/dt) + 2h(dh/dt))

Substituting in the values for l, w, and h, as well as the rates of change for l, w, and h, we get:

dD/dt = (1/2)(9^2 + 5^2 + 5^2)^(-1/2)(2(9)(7) + 2(5)(7) + 2(5)(-4))

Simplifying this expression, we get:

dD/dt = 3.08 m/s

Therefore, the length of the diagonal of the box is increasing at a rate of 3.08 m/s at that instant.

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Answer:

Step-by-step explanation:

7 * 7 + \(\frac{1}{5}\) * ( 23 + 78 - 35)

49 + \(\frac{1}{5}\)*(66)

62.2

Answer:

your answer should be 15

Step-by-step explanation:

Answer:

Step-by-step explanation:

To convert, you will need to know how many times five will go into 42. Once found, that will be your whole number. The remainder will be the numerator, and the divisor of the current fraction will become the denominator.

Given fraction:

Knowing how many times five will go into 42.

The denominator of the given fraction will be the denominator of the created mixed fraction.

Hence, Option C is correct.

Answer:

hope it helps you..........

A is your answer just multiply it by 14 then add it by 5 it looks as if all sides are equal.

Answer:

x=28

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x+5+x−5=56

x+5+x+−5=56

(x+x)+(5+−5)=56(Combine Like Terms)

2x=56

2x=56

Step 2: Divide both sides by 2.

2x/2=56/2

x=28

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Answer:

68%

Step-by-step explanation:

85 divided by 125 = .68 * 100 = 68

Answer: The sale price is 40 percent of the regular price

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

You are subtracting 2 from y every step.

The solution of the equation y = (2/3)x + 3 is 5/3

The given equation is

y = (2/3)x + 3

The slope of the line is the change in y coordinates with respect to the change in x coordinates.

This is the linear equation in the the slope intercept form

y = mx + b

Where m is the slope of the line

b is the y intercept

y is the y coordinates

x is the x coordinates

The value of x = -2

Substitute the value of x in the equation

y = (2/3) × -2 + 3

Do the arithmetic operations

= -4/3 + 3

Add the numbers

= 5/3

Therefore, the solution is 5/3

I have solved the question in general, as the given question is incomplete

The complete question is:

What is the solution of the equation y = (2/3)x + 3x, when x = -2?

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The Values of (a+b)ab are undefined.

Given that, a = 3an and db = -2We need to find the values of (a+b)

Now, we have a = 3an... equation (1)Also, we have db = -2... equation (2)From equation (1), we get: n = 1/3... equation (3)Putting equation (3) in equation (1), we get: a = a/3a = 3... equation (4)Now, putting equation (4) in equation (1), we get: a = 3an... 3 = 3(1/3)n = 1

From equation (2), we have: db = -2=> d = -2/b... equation (5)Multiplying equation (1) and equation (2), we get: a*db = 3an * -2=> ab = -6n... equation (6)Putting values of n and a in equation (6), we get: ab = -6*1=> ab = -6... equation (7)Now, we need to find the value of (a+b).For this, we add equations (1) and (5),

we get a + d = 3an - 2/b=> a + (-2/b) = 3a(1) - 2/b=> a - 3a + 2/b = -2/b=> -2a + 2/b = -2/b=> -2a = 0=> a = 0From equation (1), we have a = 3an=> 0 = 3(1/3)n=> n = 0

Therefore, from equation (5), we have:d = -2/b=> 0 = -2/b=> b = ∞Now, we know that (a+b)ab = (0+∞)(0*∞) = undefined

Therefore, the values of (a+b)ab are undefined.

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If the difference of 3 times a number(n) and 10 is 5 , then the number is n = 5  .

In the question ,

it is given that

the number is = n

and also the statement is given as  " the difference of 3 times of a number "n" and 10 is = 5 "

which means

3×n - 10 = 5    ...because times means × and difference means " - " .

3n - 10 = 5

on adding 10 to both sides of the equation and solving further ,

we get ,

3n = 5 + 10

3n = 15

n = 15/3

n = 5

Therefore , If the difference of 3 times a number(n) and 10 is 5 , then the number is n = 5  .

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The inverse function value in degrees will be 45°. Option C is correct.

Assuming function 'f' is a one-to-one and onto function which is a need for inverses to exist. The inverse of the considered function is. f⁻¹(x).

The given function is;

f(x)=sin⁻¹(1/2)

The given function is arranged is;

x=sin⁻¹(1/2)

The given function in terms of  sin;

sinx=1/2

Putting the values in terms of sin we get;

sinx=sin30°

x=30°

The inverse function value in degrees will be 45°.

Hence,option C is correct.

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