Answer:
v = 4.35m/s
Explanation:
covert the time in seconds
19 minutes x (60s/1 minute) + 10 s
= 1150s
then v = distance covered/ time elapsed
v= 5000m/1150s
= 4.348m/s or approximately
= 4.35m/s
Which force is represented by the arrow at A?
A
force of friction
B
force of gravity
C
normal force
D
tension force
The force represented by the arrow at A is the force of gravity .
What is force of gravity?The force of attraction between two objects having mass is called force of gravity. How earth applies force of gravity on the object on it's surface ? Any object having a certain mass if put on the surface of earth , the earth exerts a force on that object I.e. the force of gravity. In the figure the object put on the wedge had certain mass thus in downward direction the force of gravity is applied by the earth.Thus , we can conclude that the correct answer is option B.
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• Point A - the instant before the figure drops. It is at rest and the spring is not stretched.
• Point B - an instant when the figure is falling. It is lower than its original position, and
moving downwards, but the spring has not yet begun to stretch.
• Point C - the very last instant for which the figure is falling but the spring has not yet
begun to stretch.
• Point D - an instant when the figure is falling and the spring is stretching.
Point E - the instant at which the figure has reached its lowest position and is
momentarily motionless before rebounding.
Fill out Table 2 below to show how energy is transferred between forms during the
drop. In each box write either Maximum, Zero, Increasing, or Decreasing.
The magnitude of the GPE depends on the position of the object.
How does the GPE change as the object is falling?Some parts of the question appears to be missing but I will try to answer generally.
As an object falls, its gravitational potential energy (GPE) decreases.
Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. The GPE of an object is directly proportional to its mass, the acceleration due to gravity, and its height above a reference level. The formula for gravitational potential energy is:
GPE = mgh
where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the reference level.
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Please help !! With my hw
Covert the grams into kilograms.
Explanation:
Well the formula for Ke is simply 1/2(mv^2)
So by the use of SI units- (i.e. kg for mass and m/s for velocity) Hector could easily compute Ke
In the figure, a small spherical insulator of mass 6.00 x 10^-2 kg and charge +0.400 uC is hung by a thin wire of negligible mass. A charge of -0.220 uC is held 0.290 m away from the sphere and directly to the right of it, so the wire makes an angle with the vertical, as shown. What is the angle?
This angle is negative, which means that the wire is bent to the left instead of to the right, as shown in the diagram.
StepsThe electrostatic force on the charged insulator is given by Coulomb's law as:
F_electric = k * (q1 * q2) / r²
where k is the Coulomb constant (9 x 10⁹ N*m²/C²), q1 and q2 are the charges of the two objects, and r is the distance between them.
In this case, q1 = 0.400 uC and q2 = -0.220 uC. The distance between them is given as 0.290 m.
F_electric = (9 x 10⁹) * (0.400 x 10⁻⁶) * (-0.220 x 10⁻⁶) / (0.290)²
F_electric = -1.19 x 10⁻⁵ N
Since the insulator is in equilibrium, the electrostatic force must be balanced by the tension in the wire.
Let T be the tension in the wire, and θ be the angle that the wire makes with the vertical.
The horizontal component of the tension in the wire is given by T * sin(θ), and the vertical component is given by T * cos(θ).
Since the insulator is in equilibrium, the sum of the forces in the vertical direction must be zero:
T * cos(θ) - m * g = 0
where m is the mass of the insulator (6.00 x 10⁻² kg), and g is the acceleration due to gravity (9.8 m/s²).
Solving for T, we get:
T = m * g / cos(θ)
The sum of the forces in the horizontal direction must also be zero:
T * sin(θ) = F_electric
Substituting T and F_electric from the above equations, we get:
(m * g / cos(θ)) * sin(θ) = -1.19 x 10⁻⁵
Simplifying, we get:
tan(θ) = -1.19 x 10⁻⁵ / (m * g)
Substituting the given values, we get:
tan(θ) = -1.19 x 10⁻⁵ / (6.00 x 10⁻² kg * 9.8 m/s²)
tan(θ) = -2.06 x 10⁻⁵
Taking the inverse tangent, we get:
θ = -0.00118 degrees
However, this angle is negative, which means that the wire is bent to the left instead of to the right, as shown in the diagram.
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A block rests on a frictionless horizontal surface and is attached to a spring. When set into simple harmonic motion, the block oscillates back and forth with an angular frequency of 8.1 rad/s. The drawing shows the position of the block when the spring is unstrained. This position is labeled x= 0 m. The drawing also shows a small bottle located 0.080 m to the right of this position. The block is pulled to the right, stretching the spring by 0.050 m, and is then thrown to the left. In order for the block to knock over the bottle,it must be thrown with a speed exceeding v0. Ignoring the width of the block, find v0.
Answer:
v₀ = 0.5058 m/s
Explanation:
From the question, for the block to hit the bottle, the elastic potential energy of the spring at the bottle (x = 0.08 m) should be equal to the sum of the elastic potential energy of the spring at x = 0.05 m and the kinetic energy of block at x = 0.05 m
Now, the potential energy of the block at x = 0.08 m is ½kx²
where;
k is the spring constant given by; k = ω²m
ω is the angular velocity of the oscillation
m is the mass of the block.
Thus, potential energy of the spring at the bottle(x = 0.08 m) is;
U = ½ω²m(0.08m)²
Also, potential energy of the spring at the bottle(x = 0.05 m) is;
U = ½ω²m(0.05m)²
and the kinetic energy of the block at x = 0.05 m is;
K = ½mv₀²
Thus;
½ω²m(0.08)² = ½ω²m(0.05)² + ½mv₀²
Inspecting this, ½m will cancel out to give;
ω²(0.08)² = ω²(0.05)² + v₀²
Making v₀ the subject, we have;
v₀ = ω√((0.08)² - (0.05)²)
So,
v₀ = 8.1√((0.08)² - (0.05)²)
v₀ = 0.5058 m/s
A tape diagram. 0 dollars is 0 percent. Question mark dollars is 23 percent. 52 dollars is 100 percent. Jared has earned 23% of the $52 he needs to buy a new jacket. Find 23% of $52. Which expression can you use to find 23% of 52? 23% of $52 is $ . An easy way to check your answer is to use the friendly and divide 52 by to get .
Answer:
Jared has earned 23% of the $52 he needs to buy a new jacket. Find 23% of $52.
Which expression can you use to find 23% of 52?
✔ 0.23 × 52
23% of $52 is $
✔ 11.96
.
An easy way to check your answer is to use the friendly
✔ 25%
and divide 52 by
✔ 4
to get
✔ 13
.
Explanation:
What are patients most likely to prepare as part of their right to make decisions about end of life care under federal legislation
Science has been wrong in the past. For example, we now know that the original models of the atom were not fully correct. In response to this, a friend tells you, "Science cannot be trusted. Don't believe anything a scientist says." What is your response to this statement? (For full credit, you need to write at least a full sentence explanation"
Although it is true that scientific models and hypotheses have been updated and improved over time, this is not sufficient justification to reject science as a whole or to doubt what scientists claim.
Given that we are aware of their limitations, why do scientists continue to employ atomic model simulations?Models aid in our comprehension of systems and their characteristics. An atomic model, for instance, depicts what an atom's structure may like based on what is known about how atoms function. It may not accurately represent the precise makeup of an atom. Models are frequently condensed.
Why do scientific theories alter over time, including the atomic model?Over time, this atomic model has evolved. The model was used by scientists to make predictions. Their trials occasionally yielded unexpected outcomes that did not match the pre-existing model. The model was modified by scientists so that it could account for the fresh data.
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Wind farms are a source of renewable energy found around the world. The power p (in kilowatts) generated by a wind turbine varies directly as the cube of the wind speed v (in meters per second). If a turbine generates 600kw in a 13 m/s wind, how much power does it generate in a 14 m/s wind?.
The turbine generates approximately 781.78 kW of power in a 14 m/s wind.
The power generated by a wind turbine is directly proportional to the cube of the wind speed. Therefore, we can write:
p ∝ \(v^3\)
where "p" is the power generated in kilowatts (kW) and "v" is the wind speed in meters per second (m/s). We can also introduce a constant of proportionality "k" to get:
p = k \(v^3\)
To find the value of "k", we can use the given information that the turbine generates 600 kW in a 13 m/s wind. Thus:
600 = k x \(13^3\)
Solving for "k", we get:
k = 600 / \(13^3\)
k = 0.270270...
Now we can use this value of "k" to find the power generated by the turbine in a 14 m/s wind. Thus:
p = 0.270270... x \(14^3\)
p ≈ 781.78 kW
Therefore, the turbine generates approximately 781.78 kW of power in a 14 m/s wind.
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if i got rolled over and then survided and then i would go home then i died what happened
Answer:
you had probably died from the impact
Explanation:
because you got rolled over you would probably died due to your organs being damage and wouldn't function properly
Rocks in the asteroid belt are traveling around the Sun at a distance of 3.2 Astronomical Units (AU). According to Kepler's Third Law, what is the orbital period of these rocks?
Recall Kepler's Third Law can be written as
P 2 = a 3
if the period is measured in (Earth) years and the distance is measured in AU. Follow the steps in Example 3.1 (just with a different distance value).
Pick the answer that's closest to your result:
The orbital period of the rocks in the asteroid belt is approximately 5.73 years.
What is the average distance, a, between the sun and the asteroid, expressed in astronomical units?
The distance from the Sun to the asteroid belt is between 2-4 AU, or between 300 and 600 million kilometers (186-272 million mi).
Using Kepler's Third Law, we have:
P² = a³
where P is the orbital period of the rocks in years, and a is the semi-major axis of their orbit in astronomical units (AU).
Substituting a = 3.2 AU, we get:
P² = (3.2 AU)³
P² = 32.768 AU³
P = \(\sqrt{32.768}\) years
P ≈ 5.73 years
Therefore, the orbital period of the rocks in the asteroid belt is approximately 5.73 years.
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Light does not pass through some materials. What do you think happens
to the energy of photons when photons strike a surface and are
absorbed? What indicators would tell you that the energy of the photons
?
has been transformed?
Answer:
When an electron is hit by a photon of light, it absorbs the quanta of energy the photon was carrying and moves to a higher energy state. One way of thinking about this higher energy state is to imagine that the electron is now moving faster, (it has just been "hit" by a rapidly moving photon)
A photon is a quantum of EM radiation. Its energy is given by E = hf and is related to the frequency f and wavelength λ of the radiation by. E=hf=hcλ(energy of a photon) E = h f = h c λ (energy of a photon) , where E is the energy of a single photon and c is the speed of light.
give 2 reasons why a person should move away from "isolating muscles"
Answer:
1) - They should move away because its cold
2) - You can get hypothermia......
Explanation:
An average force of 62 N acts to move the piston 0.9 m. During the compression, 6 J of heat are conducted away from the gas. What is the change in internal energy (in J) of the gas?
The change in the internal energy of the gas is 49.8 J.
What is the work done on the gas?
The work done in compressing the gas by the force applied on the piston is calculated as follows;
W = Fd
where;
F is the applied forced is the distanceW = 62 N x 0.9 m
W = 55.8 J
The change in the internal energy of the gas is calculated as follows;
ΔU = - Q + W
where;
Q is the heat conducted awayW is the work done on the gasΔU = -6 J + 55.8 J
ΔU = 49.8 J
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the mass of a density bottle is 18.00g when empty 44.00g when full of water, and 39.84g when full up of a second liquid. calculate the density of the liquid where density of water =1000kgm³
The density of the second liquid is 0.812 g/cm³
To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:
mass of liquid = mass of bottle + liquid - mass of empty bottle
mass of liquid = 39.84g + x - 18.00g
where x is the mass of the liquid.
We can now use the density formula, which is:
density = mass/volume
The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:
volume of liquid = volume of bottle filled with liquid - volume of empty bottle
We can now substitute this expression into the density formula to get:
density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)
We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:
volume of water = mass of water / density of water
volume of water = 44.00g / 1 g/cm³
volume of water = 44.00 cm³
Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:
volume of bottle filled with liquid = volume of water - volume of liquid
volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³
volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³
volume of bottle filled with liquid = 22.16 cm³
Finally, we can substitute these values into the density formula to get:
density of liquid = x / 22.16 cm³
Solving for x, we get:
x = density of liquid x 22.16 cm³
Substituting x back into the mass equation, we get:
mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g
Solving for the density of the liquid, we get:
density of liquid = (mass of liquid - 21.84g) / 22.16 cm³
Substituting the given values, we get:
density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³
In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.
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what is electric potential
Answer:
The electric potential is the amount of work energy needed to move a unit of electric charge from a reference point to the specific point in an electric field with negligible acceleration of the test charge to avoid producing kinetic energy or radiation by test charge.
SI unit: volt
Other units: statvolt
In SI base units: V = kg⋅m^2⋅A^−1⋅s^−3
Dimension: M L^2 T^−3 I^−1
Explanation:
Hope it is helpful....
Explanation:
common symbol - V
SI unit - volt
other unit - statvolt
A science museum display about energy has a small engine that pulls on a rope to lift a block 1.00 m. The display indicates that 1.00 J
of work is done. What is the mass of the block?
Answer:
0.102 kg
Explanation:
Work is measured in Joules, an amount of energy. As the engine lifts the block, it will exert energy (doing work) to give that energy to the block in the form of gravitational potential energy.
Gravitational potential energy is given by the formula \(U=mgh\), where U is the gravitational potential energy, m is the mass of the object with the energy, g is the gravitational constant near the surface of the earth, and h is the height it was raised.
We can isolate "m" in the equation, substitute the known values into the equation, including g = 9.81 m/s^2, and calculate m.
\(\dfrac{U}{gh}=m\)
\(\dfrac{(1.00[J])}{(9.81[\frac{m}{s^2}])(1.00[m])}=m\)
Rewriting the units of Joules into its base SI units...
\(\dfrac{(1.00[\frac{kg \cdot m^2}{s^2}])}{(9.81[\frac{m}{s^2}])(1.00[m])}=m\)
Canceling units, and calculating...
\(0.1019367991845[kg]=m\)
Rounding to 3 sig figs...
\(0.102[kg]=m\)
Find the Peukert constants n and λ for Peukert’s equation for following two measurements available from a constant current discharge experiment of a battery : (i) (t1, I1) = (10, 25) (ii) (t2, I2) = (4,45)
The battery Peukert constants, n and, are around 1.223 and 2.486, respectively.
How many Peukerts can fit?Wilhelm Peukert, a German physicist, proposed Peukert's law in 1897, which quantifies a battery's capacity in terms of the rate of discharge. The battery's useful capacity reduces as the rate of discharge rises. The supplied capacity decreases as discharge rate increases.
C = I⁽⁻ⁿ⁾ * t * λ
log(C) = -n * log(I) + log(λ) + log(t)
log(C1) = -n * log(I1) + log(λ) + log(t1)
log(C1) = -n * log(25) + log(λ) + log(10)
Similarly, for the second measurement, we have:
log(C2) = -n * log(I2) + log(λ) + log(t2)
log(C2) = -n * log(45) + log(λ) + log(4)
log(C1) - log(C2) = -n * (log(25) - log(45)) + log(10/4)
Simplifying, we get:
log(C1/C2) = n * log(45/25) + log(2.5)
Substituting the values, we get:
log(25/45) = n * log(45/25) + log(2.5)
Solving for n, we get:
n = (log(25/45) - log(2.5)) / log(45/25)
n = 1.223
log(C1) = -1.223 * log(25) + log(λ) + log(10)
log(C1) = -1.223 * 1.39794 + log(λ) + 1
Solving for log(λ), we get:
log(λ) = log(C1) + 1.223 * 1.39794 - 1
log(λ) = log(25) + 1.223 * 1.39794 - 1
log(λ) = 0.39794
Therefore, λ = 2.486.
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Suppose an object’s initial velocity is 10 m/s and its final velocity is 4 m/s. Mass is constant. What can best be concluded about the object based on the work-energy theorem? A. Work is positive, the environment did work on the object, and the energy of the system increases. B. Work is positive, the object did work on the environment, and the energy of the system increases. C. Work is negative, the object did work on the environment, and the energy of the system decreases. D. Work is negative, the environment did work on the object, and the energy of the system decreases.
Explanation:
"Work is negative," the correct answer is, "the object did work on the environment, and the system's energy declines."
In fact, the work-energy theorem states that work done is equal to kinetic energy variation:
where W represents labor, Kf represents final kinetic energy, and Ki represents starting kinetic energy. Because the kinetic energy is proportional to the velocity v,
Since the final velocity is less than the initial velocity, the work is negative (the system's kinetic energy is reduced).
This also implies that the thing worked on the environment: in reality, by working, the object gave some of its kinetic energy to the environment, resulting in a decrease in kinetic energy.
Answer:
Work is negative, the object did work on the environment, and the energy of the system decreases.
Explanation:
A liquid fueled rocket is red on a test stand. The rocket nozzle has an exit diameter of 30 cm and the combustion gases leave the nozzle at a velocity of 3800 m/s and a pressure of 100 kPa, which is the same as the ambient pressure. The temperature of the gases in the combustion area is 2400 C. Find (a) the temperature of the gases at the nozzle exit plane, (b) the pressure in the combustion area, and (c) the thrust developed. Assume that the gases have a speci c heat ratio of 1.3, and a molar mass of 9. Assume that the ow in the nozzle is isentropic.
Answer:
1. Temperature= 869.35 K
2. Pressure of combustion = 12994.043 kpa
3. Thrust = 127x10⁶N
Explanation:
this problem has been fully explained in the attachment. please use it to get a clearer explanation of the answer.
1.
The temperature = (273+2400k) - (3800)²/2(4003)
= 2673 - 14440000/8006
= 2673 - 1803.65
= 869.35 K
Approximately 869.4K
2. We first get mach number
= 3800/√1.3(923.8)(869.35)
= 3800/1021.78
= 3.719
Pressure = 100kpa[1+2.07464415]^1.3/0.3
= 12995.043kpa
C. Thrust
Pi/4(3800)²(0.3)²(100x10³)/(923.8)(869.4)
= 12678.621
= 126.781 kN
Thrust is approximately 127kN = 127x10⁶N
How does the law of conservation of mass apply to chemical reactions?
Answer: mass is neither created nor destroyed
Explanation: For example, the carbon atom in coal becomes carbon dioxide when it is burned. The carbon atom changes from a solid structure to a gas but its mass does not change.
A boy is looking into a plane mirror. His nose is 30 cm in front of the mirror.
How far is his nose from where its image appears to be?
HELP I NEED TO SUBMIT MY SCIENCE HW IN LIKE 30 MINS!!!
Answer:
Hug g g fed gvgcgcgcg
Explanation:
G gcgvhcvkgj
A charge Q exerts a 1.2 N force on another charge q. If the distance between the charges is doubled, what is the magnitude of the force exerted on Q by q
Answer:
0.3 N
Explanation:
Electromagnetic force is F= Kq1q2/r^2, where r is the distance between charges. If r is doubled then the force will be 1/4F which is 0.3 N.
The magnitude of the force exerted on Q by q when the distance between them is doubled is 0.3 N
Coulomb's law equationF = Kq₁q₂ / r²
Where
F is the force of attraction K is the electrical constant q₁ and q₂ are two point charges r is the distance apart Data obtained from the question Initial distance apart (r₁) = rInitial force (F₁) = 1.2 NFinal distance apart (r₂) = 2rFinal force (F₂) =? How to determine the final forceFrom Coulomb's law,
F = Kq₁q₂ / r²
Cross multiply
Fr² = Kq₁q₂
Kq₁q₂ = constant
F₁r₁² = F₂r₂²
With the above formula, we can obtain the final force as follow:
F₁r₁² = F₂r₂²
1.2 × r² = F₂ × (2r)²
1.2r² = F₂ × 4r²
Divide both side by 4r²
F₂ = 1.2r² / 4r²
F₂ = 0.3 N
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What is an atom that has the same number of protons as other atoms of the same element but a different number of neutrons?
Answer:
isotopes
Explanation:
Isotopes are atoms of the same element that have different numbers of neutrons but the same number of protons and electrons. The difference in the number of neutrons between the various isotopes of an element means that the various isotopes have different masses.
BRAINLIEST PLSS
Which of the following scenarios describes an object being acted on by a conservative force?
A. A woman hikes up a mountain to a point 20 feet above ground.
B. A dishwasher was pulled up to a window by a rope, using a pulley system.
C. A feather falls from one end of a tube to the other inside a vacuum.
D. A puck glides across and slowly comes to a stop on an ice rink.
A puck glides across and slowly comes to a stop on an ice rink describes an object being acted on by a conservative force
What is conservative force?
This is the type of force that is known to do work on an object. This force is known to conserve mechanical energy. The KE and the PE would have to remain fixed or constant here. Gravity and elastic forces are good examples.
In the option D, the puck goes up the rink. Then it slows down because of friction. The frictional force is not conservative in nature
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What is the wavelength of a wave whose velocity is 12m/s and has a frequency of .75 Hz?
Answer:
16 meters
Explanation:
Use the formula that relates frequency velocity and wavelength:
velocity = wave-length x frequency
in our case:
12 m/s = wave-length * 0.75 Hz
wave-length= 12/0.75 m = 16 meters
The books on the bottom shelf experience more gravity than the books on top, because they are closer to the ground.
A True
B False
Answer:
B. FALSE
Explanation:
Gravity is a force that acts on all objects with mass, pulling them towards the center of the Earth. The force of gravity is the same for all objects, regardless of their mass or the location on the Earth's surface. Therefore, the books on the bottom shelf experience the same amount of gravity as the books on the top shelf.
The answer would be (B) False.
A carnival ride starts at rest and is accelerated
from an initial angle of zero to a final angle of 6.3 rad by a counterclockwise angular
rad acceleration of 2.0s²
What is the angular velocity at 6.3 rad?
Answer using a coordinate system where
counterclockwise is positive.
Round answer to two significant digits.
The final angular velocity of the carnival ride is determined as 5.02 rad/s.
What is the final angular velocity of the carnival ride?
The final angular velocity of the carnival ride is calculated by applying the following kinematic equation.
ωf² = ωi² + 2αθ
where;
ωf is the final angular velocityωi is the initial angular velocity α is the angular accelerationθ is the angular distanceThe given parameter include the following;
the final angular velocity = ?
the initial angular velocity = 0
the angular acceleration = 2 rad/s²
the angular distance = 6.3 rad
The final angular acceleration of the carnival ride is calculated as follows;
ωf² = ωi² + 2αθ
ωf² = 0 + 2αθ
ωf² = 2αθ
ωf = √ (2αθ)
ωf = √ (2 x 2 x 6.3)
ωf = 5.02 rad/s
Thus, the final angular velocity of the carnival ride is a function of the angular distance, angular acceleration and initial angular velocity of the carnival ride.
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Answer: \(5\frac{rad}{s}\)
Explanation:
Khan Academy
when a roller coaster gets to the bottom of a descent, describe the energy transfers and changes to energy stores that happen if:
a) the brakes are applied
b) it goes up and over a second hill
a) At the application of the brakes, there is a conversion of kinetic to potential energy.
b) When it climbs the second hill, the kinetic energy of the roller coaster is now converted to potential energy.
What is the conservation of energy?Let us recall that according to the principle of the conservation of energy, energy can neither be created nor destroyed but it can be transformed from one form to another. In the roller coaster, we can see the principle of energy transformation at work. This is one of the easiest ways that we could use to be able to describe the conservation of energy.
When a break has been applied in the roller coaster, there is a consversion of energy from kinetic energy to potential energy. Recall that the kinetic energy has to do with the energy that is in motion. This is converted to the potential energy of a stationary roller coaster.
Again when the roller coaster goes up a second hill, there is a change from kinetic to potential energy that the roller coaster would possess at the top of the hill.
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