Linear Algebra
Solve systems of equations using row reduction method
PLEASE do all part a-g Thank you!

x₁ +4x₂+2x₂=0
Given 2x₁ +5x₂+x3=0 (1)
3x1+6x2=0
(a) Write system (1) into augmented matrix_form
(b) Without using a calculator, reduce the augmented matrix to reduced row echelon form (rref). ▲ write out all elementary row operations in sequence order ▲
(c) Identify all basic variables and free variables.
(d) Find the general solutions of system (1). What is the role of free variable ?
(e) Write the solution of system (1) as parametric vector form.
(f) True or False? "This system of equations has unique solution (2, -1, 1)." why yes or why no.
(g) With the aid of a graphic calculator, solve system (1). Specify the calculator model, show formulas setup and answers.

Answers

Answer 1

(a) The augmented matrix of the system is:

[ 1  4  2 | 0 ]

[ 2  5  1 | 0 ]

[ 3  6  0 | 0 ]

(b)The reduced row echelon form is:

[ 1  0  0 | 0 ]

[ 0  1  0 | 0 ]

[ 0  0  1 | 0 ]

(c)The basic variables are x₁, x₂, and x₃

(d)  The general solution of the system is:

x₁ = 0

x₂ = 0

x₃ = 0

(e) The solution in parametric vector form is:

[x₁, x₂, x₃] = [0, 0, 0] + t[0, 0, 0]

(f) False.

(g)t = -1

x = 1

y = -1

z = 2

(a) The augmented matrix of the system is:

[ 1  4  2 | 0 ]

[ 2  5  1 | 0 ]

[ 3  6  0 | 0 ]

(b) To reduce the augmented matrix to reduced row echelon form (rref):

1. Multiply row 1 by -2 and add to row 2:

[ 1  4  2 | 0 ]

[ 0 -3 -3 | 0 ]

[ 3  6  0 | 0 ]

2. Multiply row 1 by -3 and add to row 3:

[ 1  4   2 | 0 ]

[ 0 -3  -3 | 0 ]

[ 0 -6  -6 | 0 ]

3. Multiply row 2 by -1/3:

[ 1  4   2 | 0 ]

[ 0  1   1 | 0 ]

[ 0 -6  -6 | 0 ]

4. Add row 2 to row 1 and row 2 to row 3:

[ 1  0   6 | 0 ]

[ 0  1   1 | 0 ]

[ 0  0  -3 | 0 ]

5. Multiply row 3 by -1/3:

[ 1  0   6 | 0 ]

[ 0  1   1 | 0 ]

[ 0  0   1 | 0 ]

6. Add -6 times row 3 to row 1 and add -1 times row 3 to row 2:

[ 1  0  0 | 0 ]

[ 0  1  0 | 0 ]

[ 0  0  1 | 0 ]

The reduced row echelon form is:

[ 1  0  0 | 0 ]

[ 0  1  0 | 0 ]

[ 0  0  1 | 0 ]

(c) The basic variables are x₁, x₂, and x₃, since they correspond to the columns with leading ones in the reduced row echelon form. The free variables are none, since there are no non-leading variables.

(d) The general solution of the system is:

x₁ = 0

x₂ = 0

x₃ = 0

The role of the free variable is to allow for infinitely many solutions.

(e) The solution in parametric vector form is:

[x₁, x₂, x₃] = [0, 0, 0] + t[0, 0, 0]

where t is any real number.

(f) False. The system has infinitely many solutions, since there is a free variable

(g)Formulas setup:

x = -t

y = t

z = 2t

Answers:

t = -1

x = 1

y = -1

z = 2

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Related Questions

The length of a
rectangle is 12 cm
more than the width.
The perimeter is 44
cm. What is the
length of the
rectangle?

Answers

Answer:

length= 5+ 12= 17

Step-by-step explanation:

will take width as x

then the length is x+12

perimeter = x+ x+12+x+x+12= 44

=4x= 44-24= 36

x= 20/4

x= 5

Rosie spent a total of $9.36 over 4 weeks. She spent the same amount of money each week. How much money did Rosie spend each week?

Answers

Answer:

2.34

Step-by-step explanation:

9.36÷4 =2.34

you divide on 4as showen

An automatic machine in a manufacturing process is operating groperly if the iengths of an important subcomponent are normally distributed with a mean of izal cri and a otandard deviation of 5.6 cm. A. Find the probability that one selected subcomponent is longer than 122 cm, Probability = B3. Find the probability that if 3 subcomponents are randomly selected, their mean length exceeds 122 cm. Probability win C. Find the probabilify that if 3 are randomly selected, ail 3 have lengths that exceed 122 cm. Probability =

Answers

A. The probability that one selected subcomponent is longer than 122 cm can be found by calculating the area under the normal distribution curve to the right of 122 cm. We can use the z-score formula to standardize the value and then look up the corresponding probability in the standard normal distribution table.

z = (122 - μ) / σ = (122 - 100) / 5.6 = 3.93 (approx.)

Looking up the corresponding probability for a z-score of 3.93 in the standard normal distribution table, we find that it is approximately 0.9999. Therefore, the probability that one selected subcomponent is longer than 122 cm is approximately 0.9999 or 99.99%.

B. To find the probability that the mean length of three randomly selected subcomponents exceeds 122 cm, we need to consider the distribution of the sample mean. Since the sample size is 3 and the subcomponent lengths are normally distributed, the distribution of the sample mean will also be normal.

The mean of the sample mean will still be the same as the population mean, which is 100 cm. However, the standard deviation of the sample mean (also known as the standard error) will be the population standard deviation divided by the square root of the sample size.

Standard error = σ / √n = 5.6 / √3 ≈ 3.24 cm

Now we can calculate the z-score for a mean length of 122 cm:

z = (122 - μ) / standard error = (122 - 100) / 3.24 ≈ 6.79 (approx.)

Again, looking up the corresponding probability for a z-score of 6.79 in the standard normal distribution table, we find that it is extremely close to 1. Therefore, the probability that the mean length of three randomly selected subcomponents exceeds 122 cm is very close to 1 or 100%.

C. If we want to find the probability that all three randomly selected subcomponents have lengths exceeding 122 cm, we can use the probability from Part A and raise it to the power of the sample size since we need all three subcomponents to satisfy the condition.

Probability = (0.9999)^3 ≈ 0.9997

Therefore, the probability that if three subcomponents are randomly selected, all three of them have lengths that exceed 122 cm is approximately 0.9997 or 99.97%.

Based on the given information about the normal distribution of subcomponent lengths, we calculated the probabilities for different scenarios. We found that the probability of selecting a subcomponent longer than 122 cm is very high at 99.99%. Similarly, the probability of the mean length of three subcomponents exceeding 122 cm is also very high at 100%. Finally, the probability that all three randomly selected subcomponents have lengths exceeding 122 cm is approximately 99.97%. These probabilities provide insights into the performance of the automatic machine in terms of producing longer subcomponents.

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The average score of students in the first group is 39, the second group is 32, and the third group is 43. If the numbers of students in the three groups are 24, 26, and 27, respectively, find the average score of all students.

Answers

The average score of all students, calculated by taking a weighted average based on the number of students in each group, is 38. The overall performance is slightly below the group averages.

The average score of students in the first, second, and third groups are 39, 32, and 43, respectively. There are 24 students in the first group, 26 students in the second group, and 27 students in the third group.

To find the average score of all students, we need to take a weighted average of the scores in each group, with the number of students in each group as the weights.

Here's how to do it: First, we calculate the total number of students:24 + 26 + 27 = 77. Then, we calculate the total score across all students: 39*24 + 32*26 + 43*27 = 936 + 832 + 1161 = 2929

Finally, we divide the total score by the total number of students to get the average score:2929/77 = 38. The average score of all students is 38.

This means that the overall performance of all the students is slightly below the average of the scores in each group.

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MARKING BRAINLIEST IF RIGHT
1.) During the school year, teens under the age of 16 cannot work past:

A.) 5:00 p.m.

B.) 6:00 p.m.

C.) 9:00 p.m.

D.) 7:00 p.m.

Answers

Answer:

A. 5 PM

Step-by-step explanation:

5 PM if they woke up at 7 AM as teens under 16 cannot work more than 9 hours

Answer:

the answer is C - 9:00 pm I guess

If profits decrease by 13.8% when the degree of operating
leverage (DOL) is 3.8, then the decrease in sales is:
A) 0.28%
B) 0.52%
C) 3.63%
D) 10%
E) 52.44%

Answers

Given that profits decrease by 13.8% when the degree of operating leverage (DOL) is 3.8.

The decrease in sales is: We have to determine the percentage decrease in sales Let the percentage decrease in sales be x.

Degree of Operating Leverage (DOL) = % change in Profit / % change in Sales3.8

= -13.8% / x Thus, we have: x

= -13.8% / 3.8

= -3.63%Therefore, the decrease in sales is 3.63%.Hence, the correct option is C) 3.63%. Percentage decrease in sales = % change in profit / degree of operating leverage

= 13.8 / 3.8

= 3.63% The percentage decrease in sales is 3.63%.

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Choose the equation that represents the line passing through the point (−2, −3) with a slope of −6.

y = −6x − 15
y = −6x − 20
y = −6x + 15
y = −6x + 20

Answers

Answer:

\(y = mx + c \\ - 3 = - 2( - 6) + c \\ c = - 15 \\ y = - 6x - 15\)

the person above is right give them some slack

Please help asap no wrong answers pls

Please help asap no wrong answers pls

Answers

Answer:

x = 20

Step-by-step explanation:

x° + 2x° + (x + 10)° = 90° ( complementary angles)

(4x + 10) ° = 90°

4x + 10 = 90

4x = 90 - 10

4x = 80

x = 80/4

x = 20

Answer:

20°

Step-by-step explanation:

#thanks me late,thankyou

a bakery used 25% more butter this month than last month if the bakery used 240 kilograms of butter last month how much did it use this month ​

Answers

Answer:

300

Step-by-step explanation:

25% of 240 is 60.

How many numbers among 1000-2000 are multiples of any two but not three of the first three odd prime numbers?
Hint: the first three odd prime numbers are 3,5,7

Answers

Answer: The first three odd prime numbers are 3, 5, and 7. A number is a multiple of two but not three of these prime numbers if it is divisible by two of them, but not the third.

To find the number of numbers between 1000 and 2000 that are multiples of two but not three of the first three odd prime numbers, we can count the number of multiples of each pair of prime numbers and subtract the number of multiples of all three prime numbers.

There are 200 multiples of 3 and 5 between 1000 and 2000 (200 numbers for each, for a total of 200 * 2 = 400). There are 133 multiples of 3 and 7 between 1000 and 2000 (133 numbers for each, for a total of 133 * 2 = 266). There are 80 multiples of 5 and 7 between 1000 and 2000 (80 numbers for each, for a total of 80 * 2 = 160). There are no multiples of all three prime numbers between 1000 and 2000.

Thus, the total number of numbers between 1000 and 2000 that are multiples of two but not three of the first three odd prime numbers is 400 + 266 + 160 = 826.

Step-by-step explanation:

Please help i reward brainliest and give points

Please no spams
Please no links
Please no wrong answers
If you dont know the answer please dont put anything

Answers

What is the question?

A clothing store has a going-out-of business sale. They are selling pants for $8.99 and shirts for $3.99. You can spend as much as $60 and want to buy at least two pairs of pants. Write the equations and possible solutions for this problem.

Answers

Let the number of pants bought be p and the number of shirts bought be s

• Each pant costs $8.99 and ,p, pants would cost

8.99p

• Each shirt costs $3.99 and ,s, shirts would cost

3.99s

The total budget is at max $60, so we can write the inequality:

\(8.99p+3.99s\leq60\)

-------------->>>>>>>>>>>>> First, let's find the s-intercept by putting p = 0:

\(\begin{gathered} 8.99p+3.99s\leq60 \\ 8.99(0)+3.99s\leq60 \\ 3.99s\leq60 \\ s\leq\frac{60}{3.99} \\ s\leq15.03 \end{gathered}\)

Rounding to a whole number,

\(s\leq15\)

-------------->>>>>>>>>>>>> Then, let's find the p-intercept by putting s = 0:

\(\begin{gathered} 8.99p+3.99s\leq60 \\ 8.99p+3.99(0)\leq60 \\ 8.99p\leq60 \\ p\leq\frac{60}{8.99} \\ p\leq6.67 \end{gathered}\)

HELP PLS THIS MATH ADD AND SUBTRACT FRACTION I DING GET BC I FORGET EVERYTHING I LEARN FROM PAST YEARS

HELP PLS THIS MATH ADD AND SUBTRACT FRACTION I DING GET BC I FORGET EVERYTHING I LEARN FROM PAST YEARS

Answers

Answer: 1. 35 5/6 - 4 1/2

2. 1 5/8 - 2/3

3. 1 5/8 + 2/3

4. 35 5/6+4 1/2

Step-by-step explanation:

1. E=Eli. J=Jamison

E=J+4 1/2

35 5/6=J+4 1/2

J=35 5/6 - 4 1/2

2. s=cups of strawberries

b=cups of blueberries

m=more cups of b than s

m=b-s

m=1 5/8 - 2/3

3. o=original length of patio.

i=increase in length of patio

t=total length of patio after increase.

o+i=t

1 5/8 + 2/3=t

4. p=pine tree. a=palm tree. i=inches taller

p+i=a

35 5/6+4 1/2=a

A triangle has a perimeter of 32.4 kilometres. Two of the sides measure 10.8 kilometres and
10.8 kilometres. What is the length of the third side?

Answers

Answer:

10.8 kilometers

Step-by-step explanation:

Perimeter of a triangle equation is P (perimeter)= a+b+c

put 32.4 of the left side of the equation as it is the answer for the perimeter and replace and and b with your first 2 side legnths like this

32.4= 10.8+ 10.8+c

Now we must solve for the unknown side legnth c. To do this we must simplify the right side of the equation first by adding 10.8+ 10.8

32.4= 21.6+c

Now we can subtract 21.6 from the left side to solve for c

10.8=c

Therefore the third side is 10.8 kilometers

Answer: 10.8 km

Step-by-step explanation:  A triangle has three sides:  a, b, and c

The perimeter is a+b+c and is a total of 32.4 km.   We know a=10.8 km and b = 10.8 km.

10.8 km + 10.8 km + c = 32.4 km

21.6km + c =  32.4 km

c = 10.8 km

hey bro whats] the x and y for these ones write number for witch is witch

hey bro whats] the x and y for these ones write number for witch is witch
hey bro whats] the x and y for these ones write number for witch is witch
hey bro whats] the x and y for these ones write number for witch is witch

Answers

picture one x=8 and y=4

picture two x=-18 and y=-10

picture three x=7 and y=8

give me 5 stars so i will get a crown

cuanto es 1 sobre 3 de 15?

Answers

Answer:

5

Cinco es en quince 3 veces igualmentes, 1 vez es uno sobre tres de  15.

A dentist bought 9 bags of prizes for his patients. Each bag had 12 prizes. The prizes were divided equally among 3 boxes. How many prizes were in each box?

Answers

Answer:

36

Step-by-step explanation:

A dentist bought 9 bags of prizes for his patients.

Each of the bags has 12 prizes

The first step is to calculate the total number of prizes

= 9 × 12

= 108 prizes

Since the prizes will be shared equally in 3 boxes then the number of prizes in each box can be calculated as follows

= 108/3

= 36

Hence the number of prizes in each of the 3 boxes is 36

13. Test the series for convergence or divergence. √j j + 3 Σ(-1). j = 1

Answers

The number of terms increase and we will compare it with another series whose sum we know that whether it is finite or infinite. Let us first simplify the expression:√j / (j + 3)

= (√j / (j + 3)) * (√j / √j)

= j / (j√j + 3√j)

= j / (√j(j + 3))∑(-1)j is an alternating series that is decreasing for all positive integer j, so the alternating series test can be used to show that it converges.

Also, √j / (j + 3) > 0 for all j > 0, so the absolute value of the terms of the series is equal to the terms themselves. We can then use the comparison test with the series 1 / √j to show that the series converges. The given series is,Σ(-1) j √j / (j + 3)j = 1 To check convergence or divergence of the given series,

√j / (j + 3) = (√j / (j + 3)) * (√j / √j)

= j / (j√j + 3√j)

= j / (√j(j + 3))

Now, using the Alternating Series Test, the absolute value of the terms of the series is √j / (j + 3) > 0 for all j > 0, so the absolute value of the terms of the series is equal to the terms themselves. We can then use the comparison test with the series 1 / √j to show that the series converges. Therefore, the series is convergent.

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what must be the probability that a randomly chosen young adult has some education beyond high school but does not have a bachelor's degree? why?

Answers

Probability: P(education beyond high school but not a bachelor's degree) = (number of young adults with education beyond high school but not a bachelor's degree) / (total number of young adults).

The probability that a randomly chosen young adult has some education beyond high school but not a bachelor's degree would be:

P(education beyond high school but not a bachelor's degree) = (number of young adults with education beyond high school but not a bachelor's degree) / (total number of young adults)

where "number of young adults with education beyond high school but not a bachelor's degree" refers to the count of individuals in the population who meet this criteria, and "total number of young adults" refers to the count of all individuals in the population who are considered young adults.

The formula calculates the probability of a certain event by dividing the number of favorable outcomes by the total number of possible outcomes. In this case, the event is a randomly chosen young adult having some education beyond high school but not a bachelor's degree. The numerator, "number of young adults with education beyond high school but not a bachelor's degree," represents the favorable outcomes, while the denominator, "total number of young adults," represents all possible outcomes.

By dividing the favorable outcomes by the total number of possible outcomes, we get the probability of the event occurring, which is a value between 0 and 1. The closer the value is to 1, the higher the probability that the event will occur. The closer the value is to 0, the lower the probability that the event will occur. This formula allows us to quantify the likelihood of an event occurring in a population based on the available data.

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A truck holds 48,000 pounds of sand.
How many tons are in 48,000 pounds?

Answers

Answer:

24

Step-by-step explanation:

dont exaclty have an explanations - its just the calculations

A bolt manufacturer is very concerned about the consistency with which his machines produce bolts. The bolts should be 0.2 centimeters in diameter. The variance of the bolts should be 0.025. A random sample of 15 bolts has an average diameter of 0.21 cm with a standard deviation of 0.1587. Can the manufacturer conclude that the bolts vary by more than the required variance at α=0.01 level? Step 1 of 5: State the hypotheses in terms of the standard deviation. Round the standard deviation to four decimal places when necessary. A bolt manufacturer is very concerned about the consistency with which his machines produce bolts. The bolts should be 0.2 centimeters in diameter. The variance of the bolts should be 0.025. A random sample of 15 bolts has an average diameter of 0.21 cm with a standard deviation of 0.1587. Can the manufacturer conclude that the bolts vary by more than the required variance at α=0.01 level? Step 2 of 5: Determine the critical value(s) of the test statistic. If the test is twotailed, separate the values with a comma. Round your answer to three decimal places. A bolt manufacturer is very concerned about the consistency with which his machines produce boits. The bolts should be 0.2 centimeters in diameter. The variance of the boits should be 0.025. A random sample of 15 bolts has an average diameter of 0.21 cm with a standard deviation of 0.1587. Can the manufacturer conclude that the bolts vary by more than the required variance at α=0.01 level?

Answers

To determine if the bolts vary by more than the required variance, we can conduct a hypothesis test. The null hypothesis (H₀) states that the variance of the bolts is equal to or less than the required variance (σ² ≤ 0.025), while the alternative hypothesis (H₁) states that the variance is greater than the required variance (σ² > 0.025).

Next, we need to determine the critical value(s) of the test statistic. Since we are testing for variance, we will use the chi-square distribution. For a one-tailed test with α = 0.01 and 14 degrees of freedom (n-1), the critical value is 27.488.

Now, we can compare the test statistic to the critical value. The test statistic is calculated as (n-1) * s² / σ², where n is the sample size (15), s² is the sample variance (0.1587²), and σ² is the required variance (0.025).

If the test statistic is greater than the critical value, we reject the null hypothesis and conclude that the bolts vary by more than the required variance. Otherwise, we fail to reject the null hypothesis.

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To determine if the bolts vary by more than the required variance, we can conduct a hypothesis test. The null hypothesis (H₀) states that the variance of the bolts is equal to or less than the required variance (σ² ≤ 0.025), while the alternative hypothesis (H₁) states that the variance is greater than the required variance (σ² > 0.025).

Next, we need to determine the critical value(s) of the test statistic. Since we are testing for variance, we will use the chi-square distribution. For a one-tailed test with α = 0.01 and 14 degrees of freedom (n-1), the critical value is 27.488.

Now, we can compare the test statistic to the critical value. The test statistic is calculated as (n-1) * s² / σ², where n is the sample size (15), s² is the sample variance (0.1587²), and σ² is the required variance (0.025).

If the test statistic is greater than the critical value, we reject the null hypothesis and conclude that the bolts vary by more than the required variance. Otherwise, we fail to reject the null hypothesis.

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which is not true for the mean of the sampling distribution?it depends on the sample size.it is the same as the population parameter.it is the mean of the statistic for all of the samples in the distribution.none of these answers.

Answers

The correct option is option (b) . The statement that mean of the sampling distribution is same as the population parameters is not true .

Sampling Distribution:

A statistical sampling distribution is a type of probability distribution constructed by drawing a large number of random samples of a specified size from the same population. These distributions are useful for understanding how sample statistics vary from sample to sample. Mean of sampling distribution:

The distribution of the values of the sample mean (x- bar) in replicate samples is called the x -bar sampling distribution.

Central Limit Theorem :

For populations with finite mean μ and finite nonzero variance σₓ, the sampling distribution of the mean approaches a normal distribution with mean μ and variance σₓ/N, and for large N (sample size) become.

The theorem tells us that mean of sampling

distribution is depends on sample size

X -bar , mean of measurements for a sample of size n. The distribution of the X bar is its sampling distribution, see distribution of the mean µ X- bar = µ ( means of samples in distribution )

Hence, the correct option is option (c) which gives the false or not true statement about mean of sampling distribution.

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For a ride on a rental scooter, Omar paid a $7 fee to start the scooter plus 7 cents per minute of the ride. The total bill for Omar's ride was $11.62. For how
many minutes did Omar ride the scooter?

Answers

7 + 0.07x = 11.62

x = 66 minutes

Explanation:
Subtract 7 from both sides, then divide both sides by 0.07

A man and a woman share a prize
of $1,000
between them in the ratio 1:3 . The women shares her part
between herself
, her mother and her daughter in the
ration 2:1:7. How much does her daugter receiv?

Answers

Step-by-step explanation:

What type of line the picture represent

What is 2 multiplied by 15/13 as a fraction?

Answers

Answer:

30/13

Step-by-step explanation:

15/13x2

15/13x2/1

30/13

4. Each morning you do a combination of aerobics, which burns about 12 calories per

minute, and stretching, which burns about 4 calories per minute. Your goal is to burn

416 calories during a 60-minute workout. How long should you spend on each type of

exercise to burn the 416 calories?

Answers

22 minutes is spent doing aerobics and 38 minutes doing stretching

Let x represent the amount of time spent doing aerobics, Let y represent the amount of time spent doing stretching.

Since the goal is to do a 60-minute workout, hence:

x + y = 60     (1)

Also, 416 calories needs to be burnt hence:

12x + 4y = 416    (2)

We need to solve equation 1 and 2 simultaneously; multiply equation 1 by 4 and subtract the result from equation 2, hence:

8x = 176

x = 22 minutes

Put x = 22 in (1)

22 + y = 60

y = 38 minutes

Therefore 22 minutes is spent doing aerobics and 38 minutes doing stretching.

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1. When do we use the method of Difference of two squares?
*
(Factoring polynomials)

Answers

Answer:

a

Step-by-step explanation:

Wally's grandmother started a college savings account for him with
$3,000. What is the total amount of money in the account after 5 years if
the annual simple interest rate is 3%?
I need this plz help explain the proses thx ASAP

Answers

Answer:

$450

Step-by-step explanation:

You want to calculate the interest on $3000 at 3% interest per year after 5 year(s).

The formula we'll use for this is the simple interest formula, or:

Where:

P is the principal amount, $3000.00.

r is the interest rate, 3% per year, or in decimal form, 3/100=0.03.

t is the time involved, 5....year(s) time periods.

So, t is 5....year time periods.

To find the simple interest, we multiply 3000 × 0.03 × 5 to get that:

The interest is: $450.00

Usually now, the interest is added onto the principal to figure some new amount after 5 year(s),

or 3000.00 + 450.00 = 3450.00.

Help again pls due tonight will give brainlisttt!!! ❤

Help again pls due tonight will give brainlisttt!!!

Answers

The answer b you were right

Consider the following system of equations. 2 ⁢ x − y = 12 − 3 ⁢ x − 5 ⁢ y = − 5 The steps for solving the given system of equations are shown below. Step 1 : - 5 ⁢ ( 2 ⁢ x − y ) = - 5 ⁢ ( 12 ) − 3 ⁢ x − 5 ⁢ y = − 5 Step 2 : − 10 ⁢ x + 5 ⁢ y = − 60 − 3 ⁢ x − 5 ⁢ y = − 5 Step 3 : − 13 ⁢ x = − 65 Step 4 : x = 5 Step 5 : 2 ⁢ ( 5 ) − y = 12 Step 6 : y = − 2 Solution: ( 5 , − 2 ) Select the correct statement about step 3. A. When the equation -3x − 5y = -5 is subtracted from -10x + 5y = -60, a third linear equation, -13x = -65, is formed, and it shares a common solution with the original equations. B. When the equations -10x + 5y = -60 and -3x − 5y = -5 are added together, a third linear equation, -13x = -65, is formed, and it has a different solution from the original equations. C. When the equation -3x − 5y = -5 is subtracted from -10x + 5y = -60, a third linear equation, -13x = -65, is formed, and it has a different solution from the original equations. D. When the equations -10x + 5y = -60 and -3x − 5y = -5 are added together, a third linear equation, -13x = -65, is formed, and it shares a common solution with the original equations.

Answers

The correct statement about step 3 include the following: C. When the equation -3x − 5y = -5 is subtracted from -10x + 5y = -60, a third linear equation, -13x = -65, is formed, and it has a different solution from the original equations.

How to solve these system of linear equations?

In order to determine the solution to a system of two linear equations, we would have to evaluate and eliminate each of the variables one after the other, especially by selecting a pair of linear equations at each step and then applying the elimination method.

Given the following system of linear equations:

2x - y = 12                .........equation 1.

-3x - 5y = -5               .........equation 2.

By multiplying the equation 1 by -5, we have:

-5(2x - y = 12) = -10x + 5y = -60

By adding the two equations together, we have:

-3x - 5y = -5

-10x + 5y = -60

-------------------------

-13x = -65

Read more on elimination method here: brainly.com/question/28405823

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