Suppose the gravitational force between two massive spheres is 100 N. If the distance between the spheres is divided by 3, what is the force between the masses?

In areas where pests are a problem, metal shields are commonly used as a protective measure between the foundation wall and sill.

Pests such as termites, ants, and rodents can cause significant damage to buildings, particularly in regions where they are prevalent. To prevent these pests from accessing the interior of a structure, metal shields are often installed as a physical barrier between the foundation wall and sill.

The metal shields serve multiple purposes in pest control. Firstly, they create a deterrent for pests attempting to enter the building. The metal material is resistant to chewing and burrowing, making it difficult for pests to penetrate. Secondly, the shields help to minimize potential entry points by sealing off any gaps or cracks that may exist between the foundation and sill. This tight seal restricts the pests' ability to find openings and gain access to the building.

Furthermore, metal shields provide long-lasting protection against pests. Unlike alternative materials, such as wood or plastic, metal shields are less susceptible to deterioration and damage caused by pests or weather conditions. This durability ensures that the protective barrier remains intact over time, maintaining its effectiveness in preventing pest infestations.

In conclusion, metal shields act as a preventive measure in areas where pests pose a problem. By creating a sturdy and impenetrable barrier between the foundation wall and sill, they help keep pests at bay, reducing the risk of infestation and potential damage to buildings.

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The maximum permissible current in the resistor is 0.632 A. The maximum voltage that can be applied across the resistor is 6.32 V.

To determine the maximum permissible current in a 10 Ω, 4 W resistor, we can use the formula: I = √(P/R), where I is the current, P is the power, and R is the resistance.

Substituting the values given, we get: I = √(4/10) = 0.632 A. Therefore, the maximum permissible current in the resistor is 0.632 A.

To find the maximum voltage that can be applied across the resistor, we can use Ohm's law: V = IR, where V is the voltage, I is the current, and R is the resistance.

Substituting the values given and using the maximum permissible current found above, we get: V = (0.632 A) x (10 Ω) = 6.32 V. Therefore, the maximum voltage that can be applied across the resistor is 6.32 V.

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Precise cutting power.

The ratio between the power used to cut the material and the rate at which metal is removed from the material

If we assume that the force needed to cut the material is F and that the cutting tool's velocity is V, then the cutting power is the product of the force and the velocity.

F times V = Power P

Let's use MRR, or metal removal rate.

F×V/MRR

If the rate of metal removal and the speed of the cutting tool are assumed to be constants, then an increase in cutting force will result in an increase in specific energy.

The particular energy will then be.

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Answer:

The Right to Protection: According to the Convention, this right includes freedom from all forms of exploitation, abuse and inhuman or degrading treatment.

Explanation:

They by law have to uphold the standards

Answer:

just know that if the volume is reduced by 10 the the pressure is increased by 10

Answer:

the capacity to do work is called energy

The internal energy change of the mixture is approximately 960.67 kJ.

To calculate the internal energy change of the mixture, we'll consider the energy required to raise the temperature of both the liquid water and vapor components separately.

First, let's calculate the internal energy change for the liquid water component:

Given:

Initial temperature (T1) = 120°C

Final temperature (T2) = 200°C

Quality (x) = 0.20 (20% quality)

Total volume of the tank (V) = 10 L

The mass of the liquid water (ml) can be calculated using the quality and the total volume of the tank:

ml = x * V = 0.20 * 10 = 2 kg

Next, we'll calculate the internal energy change using the specific heat capacity of liquid water (C_l). The specific heat capacity of water is approximately 4.186 J/g°C.

ΔU_l = ml * C_l * (T2 - T1)

     = 2 kg * 4.186 J/g°C * (200°C - 120°C)

     = 2 kg * 4.186 J/g°C * 80°C

     = 670.56 J

Now, let's calculate the internal energy change for the vapor component:

The mass of the vapor (mv) can be calculated using the quality and the total volume of the tank:

mv = (1 - x) * V = (1 - 0.20) * 10 = 8 kg

To calculate the change in internal energy for the vapor component, we'll use the specific enthalpy values for water vapor at T1 and T2. Let's assume the specific enthalpy at 120°C (h1) is 2676 kJ/kg and at 200°C (h2) is 2796 kJ/kg.

ΔU_v = mv * (h2 - h1)

     = 8 kg * (2796 kJ/kg - 2676 kJ/kg)

     = 8 kg * 120 kJ/kg

     = 960 kJ

Finally, the total internal energy change (ΔU) of the mixture is the sum of the internal energy changes of the liquid and vapor components:

ΔU = ΔU_l + ΔU_v

   = 670.56 J + 960 kJ

   = 960.67 kJ

Therefore, the internal energy change of the mixture is approximately 960.67 kJ.

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Answer:

b

Explanation:

Your racquetball opponent has poor reaction time and agility. A good offensive strategy would be to serve Near him to start a rally and keep the ball in play. Thus, option B is correct.

Shuttle run is a sport for athletes. Here, the participants places one foot behind the start line, and runs over and picks up a piece of wood. He/she then runs back and places the wood on the starting line. This sport is used to test the agility, speed , power and muscle strength of the participants.

Agile gives healthcare teams the ability to swiftly identify and solve issues with patient care, acquiring medical supplies, staffing, and a variety of other duties involved in providing healthcare.

Because it helps the product team to more precisely identify the components and Agile features that matter most to end users (whether they be patients or medical staff), an adapted Agile development approach works effectively for the majority of healthcare solution projects.

Therefore, Your racquetball opponent has poor reaction time and agility. A good offensive strategy would be to serve Near him to start a rally and keep the ball in play. Thus, option B is correct.

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The average power developed by the boy during the climb is approximately 29.4 W.

In physics, the amount of energy transferred or converted per unit time is called power.

total height = number of steps x height of each step

total height = 30 x 0.15 m = 4.5 m

Given, time = 60 s

As power = work done / time

work done = force x distance

force = mass x gravity

mass is boy's mass (40 kg) and gravity is acceleration due to gravity (9.81 m/s²).

force = 40 kg x 9.81 m/s² = 392.4 N

The distance that the boy moves is equal to the total height that he has climbed: distance = total height = 4.5 m

work done = force x distance

work done = 392.4 N x 4.5 m = 1765.8 J

power = work done / time

power = 1765.8 J / 60 s

power ≈ 29.4 W

Therefore, the average power developed by the boy during the climb is approximately 29.4 W.

As for the anomalous behavior of water, water has a higher boiling point and melting point as compared to other substances with similar molecular weight. This is due to the strong hydrogen bonding between water molecules, which requires more energy to break the bonds and change the state of water from solid to liquid to gas.

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A battery is connected to two capacitors shown below. the capacitors have air between the plates. The total charge coming out of the power supply: 8.16 × 10⁻⁹ C.

Capacitor 1 has a plate area of 1.5 cm² and an electric field between its plates of 2000 V/m and Capacitor 2 has a plate area of 0.7 cm² and an electric field of 1500 V/m.

Therefore, the total charge coming out of the power supply can be calculated by using the following formula:

Q = C × V,

where Q is the total charge coming out of the power supply.

C is the capacitance of the capacitors.

V is the voltage of the capacitors.

The capacitance of a parallel plate capacitor can be calculated by using the following formula:

C = εA/d,

where C is the capacitance of the capacitor.

ε is the permittivity of air.

A is the area of the capacitor plates.

d is the distance between the plates of the capacitor.

let's calculate the capacitance of the capacitors:

For capacitor 1:

ε = ε₀ = 8.85 × 10⁻¹² F/m²

A = 1.5 cm² = 1.5 × 10⁻⁴ m²d = ?

E = 2000 V/mQ = CV

C = εA/dC₁ = ε₀A/d

C₁ = ε₀A/E₁

C₁ = ε₀A/(V/d)

C₁ = (ε₀A/d) × V⁻¹

C₁ = ε₀A₁/E₁

C₁ = (8.85 × 10⁻¹² F/m²)(1.5 × 10⁻⁴ m²)/(2000 V/m)

C₁ = 6.63 × 10⁻¹⁰ F

For capacitor 2:

ε = ε₀ = 8.85 × 10⁻¹² F/m²

A = 0.7 cm² = 0.7 × 10⁻⁴ m²

d = E = 1500 V/m

Q = CV

C = εA/d

C₂ = ε₀A/d

C₂ = ε₀A/E₂

C₂ = (8.85 × 10⁻¹² F/m²)(0.7 × 10⁻⁴ m²)/(1500 V/m)

C₂ = 3.95 × 10⁻¹¹ F

Total charge coming out of the power supply: Q = C₁V + C₂VQ = (6.63 × 10⁻¹⁰ F)(12 V) + (3.95 × 10⁻¹¹ F)(12 V)Q = 8.16 × 10⁻⁹ C. Therefore, the total charge coming out of the power supply is 8.16 × 10⁻⁹ C.

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The displacement of the train to the west is 478 km.

To find the displacement to the west, we need to use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the straight-line distance from the starting point to the ending point) is equal to the sum of the squares of the lengths of the other two sides.

Let's call the displacement to the west "x". Then, the displacement to the south is 42 km, and the total displacement (the distance traveled by the train) is 478 km. Using the Pythagorean theorem, we can write the following equation:

x^2 + 42^2 = 478^2

Expanding the squares:

x^2 + 42^2 = 478^2

x^2 + 1764 = 229284

x^2 = 227620

x = 478 km

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Answer:

Work, W = F * d, and

Work = change in kinetic energy, so W=deltaKE.

Hence,

deltaKE=F * d

(1/2)*m*v^2 =F * d

d=[(1/2)*m*v^2]/F

d=[(1/2)*0.6*20^2]/5

d=24 m.

Explanation:

Work = change in kinetic energy, so W=deltaKE.

Answer:

Explanation:

A seatbelt is designed to stretch a bit when the car decelerates rapidly. You travel forward a little while being stopped - you do not stop sharply as you would if you hit the dashboard. The seatbelt stretching increases the time over which your momentum is changed, thereby decreasing the force experienced by your body.

Airbags are made from a strong coated fabric. They are stored in a module mounted on the steering wheel and dashboard and side panels of the car. The inflation of them is initiated by crash sensors that activate upon impact at speeds of more than 10-15 miles per hour. They are mounted in several locations on the car body. In a crash, the sensor sends an electrical signal to the airbag which then causes the airbag to deploy. It ignites a chemical propellant which produces nitrogen gas, which then inflates the bag itself.

Answer:

It would depend on the amount of years.

Explanation:

I don’t think this is very helpful-

Have a great day!

Anygays-

After connecting the conducting wire, the spheres will redistribute charges until they both have a charge of -1C.

To determine the new charges on the spheres, we need to consider the principle of charge conservation, which states that the total charge before and after an interaction remains the same.

Let's assume that the spheres have charges Q1 and Q2 initially. In this case, Q1 = -3C and Q2 = +1C.

When a conducting wire is connected between the spheres, charge can redistribute until the system reaches equilibrium. Since the spheres are conducting, charges are free to move within them.

In the final state, the charges on the spheres will redistribute to reach a new equilibrium. Let's assume the new charges on the spheres are Q1' and Q2'.

According to the principle of charge conservation, the total charge before and after the connection remains the same:

Initial total charge = Q1 + Q2 = -3C + 1C = -2C

Final total charge = Q1' + Q2'

Since the total charge remains the same, we can write the equation:

Q1' + Q2' = -2C

Since the spheres are of equal size, we can assume that the charges redistribute equally:

Q1' = -1C

Q2' = -1C

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The question probable may be:

A conducting wire is connected between two conducting spheres of equal size have a charge of -3C and +1C respectively. Find out the new charge on each sphere ?

Option a is correct.

F=GMm/R²

where F is the gravitational force or weight

G is the universal constant of gravitation

M is the mass of Earth

m is the mass of the object

R is the distance between the center of the earth and the object

Given,

initial distance R =4000miles

weight at surface of the earth F=400lb

Let the force be F' for a distance R' from earth's center.

Here R' = radius+ height of the tower = R+4000 miles = 4000 + 4000 = 8000 miles.

Since the other terms in the formula remain constant, the new weight F' can be calculated as follows:

F'/F = R²/R'(otherwise the inverse square law in gravitation)

F'/400=(4000)²/(8000)²

F' = 100 lb

Thus option a is correct.

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The weight of the body on a 4000-mile high tower would still be 400 lbs.

The weight of an object depends on the gravitational acceleration at its location. On the surface of the Earth, the gravitational acceleration is approximately 32 ft/s2. Therefore, a 400 lb body on the Earth's surface would weigh 400 lbs. If the body were placed on a 4000-mile high tower, it would be much farther from the center of the Earth and experience a weaker gravitational pull. The weight of the body would decrease as the square of the ratio of the radii of the tower and the Earth. So, the weight on the tower would be:

Weight on the tower = (400 lb) * (4000 mi/4000 mi)2 = 400 lb * 1 = 400 lb

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Answer:

2=6

3=9

Explanation:

I think this is right I'm not sure but I have done problems like this and did based on what I remember.

The average acceleration of the 3 kg block is 4 m/s².

The given parameters;

According to Newton's third law of motion, action and reaction are equal and opposite.

The force exerted on both blocks are equal and opposite.

\(F = ma\\\\m_1 a_1 = m_2a_2\\\\a_2 = \frac{m_1 a_1}{m_2}\\\\a _2 = \frac{2\times 6}{3} \\\\a_2 = 4 \ m/s^2\)

Thus, the average acceleration of the 3 kg block is 4 m/s².

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Answer:

The work you did in climbing the stairs is the force you applied (your weight) times the distance you moved upward (the height of the stairs.) So yes, climbing stairs is work done.

Explanation:

Hope this helped, nya~ :3

A standing wave is formed by the superposition of two waves traveling in opposite directions, resulting in points of constructive and destructive interference. Anti-nodes are points of maximum displacement, where the amplitude of the wave is at its highest.

To have exactly 2 anti-nodes, we need a standing wave pattern with two peaks of displacement. One possible configuration is the second harmonic, also known as the first overtone.

In the second harmonic, the wave has two complete wavelengths between the two ends of the system. The wave undergoes one complete cycle (from peak to trough and back) within each wavelength. The nodes (points of zero displacement) occur at the ends of the system, while the two anti-nodes (points of maximum displacement) are located in the middle, equidistant from the nodes.

The second harmonic is commonly observed in systems such as strings fixed at both ends or open tubes with one closed end. For example, plucking a guitar string at the halfway point creates a second harmonic standing wave pattern with two anti-nodes.

In summary, a standing wave with exactly 2 anti-nodes corresponds to the second harmonic or the first overtone, where there are two peaks of displacement separated by one complete wavelength.

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Answer:

The principle of conservation of energy states that in a closed system, the energy can neither be created nor destroyed between interacting particles and remains constant or transformed from one form to another

In the jet engine, the release of jet changes the number of interacting particles in the engine, and given that energy cannot be created in the instantaneously closed system of the engine, energy is carried away and therefore lost by particles in the jet exhaust

The conservation of energy principle is therefore obeyed in the condition in which the jet engine losses energy by the release of jet

Explanation:

The conversion of 100mg/dL or 0.10g/dL to drinks depends on the type of alcoholic beverage and the individual's body weight and metabolism. Generally, one standard drink contains around 14 grams of alcohol, which is equal to 140mg/dL or 0.14g/dL in the blood. Therefore, to estimate the number of drinks equivalent to 100mg/dL or 0.10g/dL, we need to divide the alcohol content in the blood by the standard alcohol content per drink.

In this case, 100mg/dL or 0.10g/dL in the blood would be equivalent to around 0.7 standard drinks. However, it's important to note that this is an estimate and not an accurate measurement since several factors can influence an individual's blood alcohol concentration. Moreover, it's crucial to drink responsibly and avoid driving or engaging in any activities that require alertness and coordination when under the influence of alcohol.

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Answer:

Higher temperature makes an object less dense 2. Density governs the state of matter for the object, hence as water becomes less and less dense, it becomes gas (water vapour) 3. Higher temperature makes an object has more pressure, hotter gas has higher pressure.

Explanation:

Relation Between Density and Temperature Temperature is the measure of heat. Density is the measure of how closely any given entity is packed or it is the ratio of the mass of the entity to its volume.

I hope this works

Answer:

\(a=-2.45\ m/s^2\)

Explanation:

An object is traveling at constant acceleration if its changes in speed are constant at the same intervals of time.

The acceleration can be calculated as follows:

\(\displaystyle a=\frac{v_f-v_o}{t}\)

Where vo is the initial speed, vf the final speed and t is the time.

The acceleration and the distance x are related through the following equation:

\(v_f^2=v_o^2+2.a.x\)

The car has an initial speed of vo=7 m/s when the driver stops the car (vf=0) after traveling x=10 m.

The acceleration can be calculated by solving the last equation for a:

\(\displaystyle a=\frac{v_f^2-v_o^2}{2x}\)

\(\displaystyle a=\frac{0-7^2}{2*10}\)

\(\displaystyle a=\frac{-49}{20}\)

\(\boxed{a=-2.45\ m/s^2}\)

Answer: B

Explanation: it is perpendicular to a surface

Answer:

it is perpendicular to a surface

Explanation:

Answer: Friction that acts on a sliding object

Explanation:

The ball will continue according to the concept of Inertia and in a straight line according to Newton's first law of motion.

It states that, an object at rest or in a linear motion will continue to be at rest or in its linear motion except an external force act on it.

Given that a ball is attached to a string and spun in a circular path.

In a circular motion, the speed of the object is the same but the velocity is not because the object tend to move in a different straight line direction.

If the string snaps and the ball continues outward from that point in a straight line path, The Newtonian concept that explain this is the concept of Inertia that emanate from the First Newton's Law of Motion

Therefore, the correct answer is First Newton's Law of Motion

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Answer:

v = -5 m/s

Explanation:

It is given that,

The initial velocity of the ball, u = 25 m/s

We need to find its velocity after 2 seconds in the air.

Let v is the velocity of the ball after 2 seconds. Using equation of motion to find it.

v = u + at

Here, a = -g

v = u -gt

Putting all the values,

v = 25 - (10)(3)

= 25-30

= -5 m/s

So, the velocity of the ball after 3 seconds is 5 m/s and it is in downward direction.

The angular velocity of the bar when θ=50∘ is 4.13 rad/s, as the velocity of the roller at point A is known and the bar is confined to move along vertical and inclined planes.

The problem at hand involves velocity of thea bar that is confined to move along vertical and inclined planes, with a roller attached to it that can move along these planes as well. The roller at point A has a velocity of 8.0 ft/s when the inclined plane makes an angle of 50 degrees with the horizontal. We need to determine the angular velocity of the bar when the inclined plane is at the same angle.

To solve the problem, we can use the principle of conservation of energy, which states that the total energy of a system remains constant if no external work is done on it. In this case, the potential energy of the roller is converted to kinetic energy as it moves down the inclined plane, and the kinetic energy is then transferred to the bar as it rotates. The angular velocity of the bar can be calculated by equating the kinetic energy of the roller to the rotational kinetic energy of the bar.

Using this principle, we can find that the angular velocity of the bar when θ=50∘ is 4.13 rad/s. To find the velocity of the roller at point B when θ=50∘, we can use the relationship between the angular velocity of the bar and the linear velocity of the roller. We know that the linear velocity of the roller is equal to the product of its radius and the angular velocity of the bar. Using this relationship, we can find that the velocity of roller B is 2.06 ft/s.

In conclusion, the angular velocity of the bar can be calculated using the principle of conservation of energy, and the velocity of roller B can be found using the relationship between the angular velocity of the bar and the linear velocity of the roller.

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