Terry usually rides his bike 15mph. If his riding speed is reduced by 3mph how far can he ride in 1.7 hours

Answer:

Protons:

- positive

- aka cation

- in the nucleus along with the neutrons

Electrons:

- negative

- aka anion

- situated in the orbital shells/configuration levels (there are many names)

Answer:

can you show us question 3 pls

Explanation:

The number of newborns who weighed between 2288 grams and 3984 grams is 150.

To determine the number of newborns within a specific weight range, we need to consider the data available. In this case, we have information about the weights of newborns, and we want to find the count of newborns falling between 2288 grams and 3984 grams. By analyzing the data, we can identify the number of newborns falling within this range.

First, we examine the lower bound of the weight range, which is 2288 grams. We search for all newborns whose weight is equal to or greater than 2288 grams. Next, we consider the upper bound of the range, which is 3984 grams. We search for all newborns whose weight is equal to or less than 3984 grams. By comparing these two conditions, we can determine the number of newborns whose weight falls within the specified range.

After analyzing the available data, it has been found that there are 150 newborns whose weight lies between 2288 grams and 3984 grams. This count represents the total number of newborns within the given weight range.

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Answer:

The amount of gravitational potential energy (GPE) an object has.

Answer:

More Mass More Potential Energy

Explanation:

More energy required to start, the more energy stored

Answer:

A balanced ionic equation shows the reacting ions in a chemical reaction. These equations can be used to represent what happens in precipitation reactions or displacement reactions.

Precipitation reactions

In a typical precipitation reaction, two soluble reactants form an insoluble product and a soluble product.

For example, silver nitrate solution reacts with sodium chloride solution. Insoluble solid silver chloride and sodium nitrate solution form:

AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)

The Na+ ions and NO3- ions remain separate in the sodium nitrate solution and do not form a precipitate. Ions that remain essentially unchanged during a reaction are called spectator ions.This means these can be ignored when writing the ionic equation. Only how the solid silver chloride forms is needed to be shown:

Ag+(aq) + Cl-(aq) → AgCl(s)

In a balanced ionic equation:

the number of positive and negative charges is the same

the numbers of atoms of each element on the left and right are the same

Displacement reactions

Displacement reactions take place when a reactive element displaces a less reactive element from one of its compounds.

A common type of displacement reaction takes place when a reactive metal reacts with the salt of a less reactive metal. For example, copper reacts with silver nitrate solution to produce silver and copper(II) nitrate solution:

2AgNO3(aq) + Cu(s) → 2Ag(s) + Cu(NO3)2(aq)

In this reaction, the NO3- ions remain in the solution and do not react - they are the spectator ions in this reaction. So, they can be removed from the ionic equation:

2Ag+(aq) + Cu(s) → 2Ag(s) + Cu2+(aq)

Question

Explain why this ionic equation is balanced:

Ba2+(aq) + SO42-(aq) → BaSO4(s)

Hide answer

There are the same numbers of atoms of each element on both sides of the equation. The total charge on both sides is also the same (zero).

Question

Balance this ionic equation, which represents the formation of a silver carbonate precipitate:

Ag+(aq) + CO32-(aq) → Ag2CO3(s)

Hide answer

2Ag+(aq) + CO32-(aq) → Ag2CO3(s)

Question

Balance this ionic equation, which represents the displacement of iodine from iodide ions by chlorine:

Cl2(aq) + I-(aq) → I2(aq) + Cl-(aq)

Hide answer

Cl2(aq) + 2I-(aq) → I2(aq) + 2Cl-(aq

Explanation:

this will help, I used this for my work x

AgNO₃ (aq) + NaCl (aq) → AgCl (s) + NaNO₃(aq) is the complete chemical equation taking place between the 2 reactants.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

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a) Melting: An example of melting that occurs in our everyday life is when we heat butter on a stovetop.

b) Freezing: Freezing is the process in which a liquid transforms into a solid upon cooling.

c) Condensation: One example of condensation that we encounter regularly is when water droplets form on the surface of a cold drink on a hot day.

d) Evaporation: Evaporation is the process by which a liquid transforms into a gas or vapor.

e) Sublimation: Sublimation refers to the transformation of a substance directly from a solid to a gas without passing through the liquid state.

a) Melting:  Butter is a solid at room temperature, but when heat is applied, it melts into a liquid. This change is a result of the increase in temperature, which provides enough energy to overcome the intermolecular forces holding the butter molecules together.

b) Freezing:Eventually, the temperature reaches the freezing point of water (0°C or 32°F), at which the water molecules slow down and arrange themselves into a regular, crystalline structure. This transformation from a liquid to a solid state is accompanied by the release of heat energy.

c) Condensation: As the temperature decreases, the air's capacity to hold moisture decreases, causing the water vapor in the air to condense into liquid water droplets. This process occurs due to the transfer of heat energy from the warm air to the cold surface, leading to the saturation of the air and the conversion of water vapor into liquid form.

d) Evaporation:  As the sun's heat energy is absorbed by the water molecules on the clothes' surface, their kinetic energy increases, causing them to break free from the liquid phase and escape into the surrounding air as water vapor. This process occurs because the molecules at the liquid surface with sufficient energy can overcome the attractive forces within the liquid and enter the gas phase.

e) Sublimation: Sublimation refers to the transformation of a substance directly from a solid to a gas without passing through the liquid state. An example of sublimation is the process of dry ice (solid carbon dioxide) converting into carbon dioxide gas.

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In chemistry, Kw is equal to [\(H_{3}O^{+}\)] [\(OH^{-}\)], which is 1.0 x \(10^{-14}\).

Pure wаter undergoes аuto-ionizаtion or self-ionizаtion by donаting or аccepting а proton between two molecules of wаter to form \(H_{3}O^{+}\) аnd \(OH^{-}\) ions. This is аlso known аs аutoprotolysis or аmphoteric nаture of wаter.

The equilibrium constаnt for this аutoionisаtion of wаter is known аs Kw. Thus

Kw =  [\(H_{3}O^{+}\)] [\(OH^{-}\)]

Or simply: Kw = [\(H^{+}\)] [\(OH^{-}\)]

The vаlue of Kw is constаnt аt pаrticulаr temperаture. Аt room temperаture, the vаlue of equilibrium constаnt Kw is 1.00 X  \(10^{-14}\) mol² \(dm^{-6}\).

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The statement "molecules move in random directions when heated in a heat engine, and because of the lack of uniformity in the direction of molecular movement" is true.

When a heat engine is heated, molecules absorb heat energy and their kinetic energy increases. The kinetic energy of molecules causes them to move around. However, this movement is not uniform, and the molecules move in random directions.

A heat engine is a device that converts thermal energy into mechanical energy. Heat engines operate on the principle of thermodynamics.

They work by taking in thermal energy from a high-temperature reservoir, converting some of it into mechanical energy, and then releasing the remaining thermal energy to a low-temperature reservoir.The internal combustion engine in a car, the steam engine in an old locomotive, and the turbine in a power plant are all examples of heat engines. They all convert heat energy into mechanical energy to perform work.

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The coefficient of the permanganate ion (\(MnO^{4-\)) is 2 (Answer B).
The coefficient of the bromide ion (\(Br^-\) ) when the equation is balanced is 10 (Answer E).

Here is the step-by-step explanation:
Step 1: Identify the half-reactions
\(MnO^{4-\) → \(Mn^{2+\) (reduction)
\(Br^-\) → \(Br^2\) (oxidation)

Step 2: Balance the half-reactions
For the reduction half-reaction:
\(MnO^{4-\) + 8\(H^+\) + 5e- → \(Mn^{2+\) + 4\(H^2O\)

For the oxidation half-reaction:
2\(Br^-\)  → \(Br^2\) + 2e-

Step 3: Balance the electrons in the half-reactions
Multiply the reduction half-reaction by 2 and the oxidation half-reaction by 5 to balance the electrons:
2(\(MnO^{4-\)+ 8\(H^+\) + 5e- → \(Mn^{2+\) + 4\(H^2O\))
5(2Br- → \(Br^2\) + 2e-)

Step 4: Add the half-reactions
2\(MnO^{4-\)+ 16\(H^+\) + 10\(Br^-\)  → \(Mn^{2+\) + 8\(H^2O\) + 5\(Br^2\)

The coefficient of the permanganate ion (\(MnO^{4-\)) when the following equation is balanced in an acidic solution is 2.
The coefficient of the bromide ion (Br-) when the equation is balanced is 10.

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Answer:

HCl is a polar covalent compound, because of electronegativity difference between Cl(3.5) and hydrogen (2). Hence in this way, the bond between HCl breaks and they formed ions in the polar solvent like water .

All of the following are qualitative tests that are often used to identify unknown ionic compounds except titration.

Qualitative tests are conducted to determine the presence or absence of certain ions or compounds in a sample based on their characteristic reactions. Common qualitative tests include flame tests, precipitation reactions, color changes, and gas evolution tests.

Titration, on the other hand, is a quantitative technique used to determine the concentration of a specific substance in a solution by reacting it with a standardized solution of another substance. It is not typically used as a qualitative test for identifying unknown ionic compounds.

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Answer:

A metal is said to be an active metal when it reacts strongly and quickly with other elements due to the electrons in its structure and its ease of sharing the electrons with other elements. ... A metal's reactivity increases as we go from the top to the bottom of the periodic table.

Explanation:

a. The molar mass of aspartame (C₁₄H₁₈N₂O₅) is 294.34 g/mol.

b. The number of moles in 15 g of aspartame is 0.051 moles.

a. The molecular formula of aspartame (C₁₄H₁₈N₂O₅) indicates the number and type of atoms present in one molecule of aspartame. To calculate the molar mass, we add up the atomic masses of all the atoms in the formula. By referring to the periodic table, we find that the atomic masses are approximately: C (12.01 g/mol), H (1.008 g/mol), N (14.01 g/mol), and O (16.00 g/mol).

The molar mass of aspartame (C₁₄H₁₈N₂O₅) is calculated as follows:

Molar mass = (14 * atomic mass of C) + (18 * atomic mass of H) + (2 * atomic mass of N) + (5 * atomic mass of O)

= (14 * 12.01 g/mol) + (18 * 1.008 g/mol) + (2 * 14.01 g/mol) + (5 * 16.00 g/mol)

= 294.34 g/mol

b. To calculate the number of moles, we divide the given mass of aspartame (15 g) by its molar mass (294.34 g/mol) using the formula Moles = Mass / Molar mass.

The number of moles in 15 g of aspartame is calculated using the formula:

Moles = Mass / Molar mass

= 15 g / 294.34 g/mol

≈ 0.051 moles

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The complete question is:

Aspartame has a molecular formula of C₁₄H₁₈N₂O₅. a. Determine the molar mass of aspartame. 294.34 g/mol b. Find the number of moles present in 15 grams of aspartame.

The larger tire will have a greater volume, but the amount of air in each tire is the same, so the pressure in both tires will be the same. The correct answer is the option: C.

The pressure of a gas is related to its temperature, volume, and the number of molecules present, according to the Ideal Gas Law: PV = nRT,

Assuming the temperature, number of molecules, and the amount of air in both tires are the same, the pressure of the air in the tires will depend only on the volume of the tires. Therefore, both tires will have the same air pressure. The correct answer is C.

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--The complete Question is, Assume that you put the same amount of room-temperature air in two tires. if one tire is bigger than the other, how will air pressure in the two tires compare?

A. the bigger tire will have greater air pressure.

B. the smaller tire will have greater air pressure.

C. both tires will have the same air pressure. --

The CEC for this soil sample is 675.2 cmol(+)/kg.

The % Base Saturation for this soil sample is approximately 136.62%.

The % Acid Saturation for this soil sample is approximately 60.55%.

To    calculate the CEC, % Base Saturation (B.S.), and % Acid Saturation for the given soil sample:

a. Calculation of CEC (Cation Exchange Capacity):

CEC is the sum of exchangeable cations in the soil. From the given results, we have:

CEC = Ca2+ + Mg2+ + K+ + Al3+

CEC = (100 mg/L + 45 mg/L + 85.5 mg/L + 94.2 mg/L) / (25 g / 1000)

CEC = 168.7 mg / (25 g / 1000)

CEC = 675.2 cmol(+)/kg

b. Calculation of % Base Saturation (B.S.):

% B.S. represents the percentage of CEC occupied by base cations. In this case, we consider Ca2+, Mg2+, and K+ as base cations. The formula to calculate % B.S. is:

% B.S. = (Ca2+ + Mg2+ + K+) / CEC * 100

% B.S. = (100 mg/L + 45 mg/L + 85.5 mg/L) / (168.7 cmol(+)/kg) * 100

% B.S. = 230.5 mg / (168.7 cmol(+)/kg) * 100

% B.S. = 136.62%

c. Calculation of % Acid Saturation:

% Acid Saturation represents the percentage of CEC occupied by acid cations, in this case, H+ and Al3+. The formula to calculate % Acid Saturation is:

% Acid Saturation = (H+ + Al3+) / CEC * 100

% Acid Saturation = (8.0 mg/L + 94.2 mg/L) / (168.7 cmol(+)/kg) * 100

% Acid Saturation = 102.2 mg / (168.7 cmol(+)/kg) * 100

% Acid Saturation = 60.55%

Please note that the given values were in milligrams per liter (mg/L), and the CEC and % Saturation values were calculated assuming a conversion from mg/L to cmol(+)/kg using the mass of the soil sample (25 g).

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Answer:

Explanation:

They are the molecules that are formed when four atoms chemically bond together.

The ratio of the actual value of a colligative property to the value calculated, assuming the substance to be a nonelectrolyte, is referred to as d. the van't Hoff factor

In comparison to the value anticipated for a nonelectrolyte, the Van't Hoff factor measures how much a solute dissociates or ionises in a solution. It is used to account for the impact of solute ionisation or dissociation on the computation of the collinear characteristics of solutions and is represented by the symbol "I".

Colligative qualities are those of a solution that, independent of the chemical composition of the solute particles, rely exclusively on their concentration. Collaborative qualities include things like reduced vapour pressure, increased boiling point, decreased freezing point, and reduced osmotic pressure. If the solute is a nonelectrolyte that doesn't dissolve or ionise, these qualities are utilised to compute the molar mass or molecular weight of the solute in a solution.

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Answer:

\(thank \: yo\)

The density of the substance is 0.77 g/cm³.

The density of a substance is calculated by dividing its mass by its volume. In this case, the mass of the substance is 85g and the volume is 110cm³.

Density = Mass / Volume

Density = 85g / 110cm³

To obtain the answer, we divide 85g by 110cm³.

Calculating the division, we find that the density of the substance is approximately 0.77 g/cm³.

Therefore, the density of the substance is 0.77 g/cm³.

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Answer:

Initial volume of the container (V1) = 1.27 L (Approx)

Explanation:

Given:

Number of mol (n1) = 5.67 x 10⁻²

Number of mol (n2) = (5.67 +2.95) x 10⁻² = 8.62 x 10⁻²

New volume (V2) = 1.93 L

Find:

Initial volume of the container (V1)

Computation:

Using Avogadro's law

V1 / n1 = V2 / n2

V1 / 5.67 x 10⁻² = 1.93 / 8.62 x 10⁻²

V1 = 10.9431 / 8.62

Initial volume of the container (V1) = 1.2695

Initial volume of the container (V1) = 1.27 L (Approx)

Answer: 1.27 L

Explanation:

First, calculate the final number of moles of propane (n2) in the container.

n2 = n1 + nadded = 5.67 × 10^−2 mol + 2.95 × 10^−2 mol = 8.62 × 10^−2 mol

Rearrange Avogadro's law to solve for V1.

V1 = V2 × n1 / n2

Substitute the known values of n1, n2, and V2,

V1 = 1.93 L × 5.67 × 10^−2 mol / 8.62 × 10^−2 mol = 1.27 L

The correct option is $26785.To calculate the total cost per equivalent unit using the weighted average method, we need to consider the costs incurred in both the beginning work in process and the units added during the period.

First, let's calculate the equivalent units of production for both conversion and materials:

Conversion costs:

Beginning work in process: 400 units × 20% complete = 80 equivalent units

Units added during the period: 2,000 units × 40% complete = 800 equivalent units

Total equivalent units for conversion = 80 + 800 = 880 equivalent units

Material costs:

Beginning work in process: 400 units × 30% complete = 120 equivalent units

Units added during the period: 2,000 units × 50% complete = 1,000 equivalent units

Total equivalent units for materials = 120 + 1,000 = 1,120 equivalent units

Next, let's calculate the total costs incurred:

Conversion costs:

Beginning work in process cost: $14,880

Costs added during the period: $409,200

Total conversion costs = $14,880 + $409,200 = $424,080

Material costs:

Beginning work in process cost: $9,900

Costs added during the period: $180,080

Total material costs = $9,900 + $180,080 = $189,980

Now, we can calculate the total cost per equivalent unit:

Total cost per equivalent unit = (Total conversion costs + Total material costs) / (Total equivalent units for conversion + Total equivalent units for materials)

Total cost per equivalent unit = ($424,080 + $189,980) / (880 + 1,120)

Total cost per equivalent unit ≈ $267.85

Therefore, the correct option is $26785.

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The chemist should use 30 liters of the 20% solution, 20 liters of the 30% solution, and 40 liters of the 60% solution to obtain a mixture of 90 liters containing 40% acid.

Let's denote the number of liters of the 20% solution as x, the number of liters of the 30% solution as y, and the number of liters of the 60% solution as z.

According to the problem, we have the following information:

The total volume of the mixture is 90 liters: x + y + z = 90.

The desired percentage of acid solution in the mixture is 40%: (0.20x + 0.30y + 0.60z) / 90 = 0.40.

The chemist wants to use 2 times as much of the 60% solution as the 30% solution: z = 2y.

Now, we can solve these equations simultaneously to find the values of x, y, and z.

From equation 3, we have z = 2y.

Substituting this into equation 1, we get:

x + y + 2y = 90

x + 3y = 90 (equation 4)

From equation 2, we have:

(0.20x + 0.30y + 0.60z) / 90 = 0.40

Multiplying both sides by 90, we get:

0.20x + 0.30y + 0.60z = 36

0.20x + 0.30y + 0.60(2y) = 36 (since z = 2y)

0.20x + 0.30y + 1.20y = 36

0.20x + 1.50y = 36 (equation 5)

Now, we can solve equations 4 and 5 simultaneously to find the values of x and y.

Multiplying equation 4 by 0.20, we get:

0.20(x + 3y) = 0.20(90)

0.20x + 0.60y = 18

Subtracting this from equation 5, we eliminate x and solve for y:

0.20x + 1.50y - (0.20x + 0.60y) = 36 - 18

0.90y = 18

y = 18 / 0.90

y = 20

Substituting this value of y back into equation 4, we find:

x + 3y = 90

x + 3(20) = 90

x + 60 = 90

x = 90 - 60

x = 30

Since z = 2y, we have:

z = 2(20)

z = 40

Therefore, the chemist should use 30 liters of the 20% solution, 20 liters of the 30% solution, and 40 liters of the 60% solution to obtain a mixture of 90 liters containing 40% acid.

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The enantiomeric excess (e.e.) of the mixture containing 5.70 g of (-)-glyceraldehyde and 2.0 g of (+)-glyceraldehyde is 48%.

To calculate the enantiomeric excess (e.e.) of a mixture, we need to determine the difference in the amounts of the two enantiomers and express it as a percentage of the total amount.

Given;

Mass of (-)-glyceraldehyde = 5.70 g

Mass of (+)-glyceraldehyde = 2.0 g

Calculate the total amount of glyceraldehyde in the mixture.

Total mass of glyceraldehyde = Mass of (-)-glyceraldehyde + Mass of (+)-glyceraldehyde

= 5.70 g + 2.0 g

= 7.70 g

Calculate the individual amounts of each enantiomer as a fraction of the total amount.

Fraction of (-)-glyceraldehyde = Mass of (-)-glyceraldehyde / Total mass of glyceraldehyde

= 5.70 g / 7.70 g

= 0.740

Fraction of (+)-glyceraldehyde = Mass of (+)-glyceraldehyde / Total mass of glyceraldehyde

= 2.0 g / 7.70 g

= 0.260

Calculate the enantiomeric excess (e.e.).

e.e. = (Fraction of (-)-glyceraldehyde - Fraction of (+)-glyceraldehyde) × 100%

= (0.740 - 0.260) × 100%

= 0.480 × 100%

= 48%

Therefore, the enantiomeric excess (e.e.) of the mixture containing 5.70 g of (-)-glyceraldehyde and 2.0 g of (+)-glyceraldehyde is 48%.

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Extensive property is dependent on mass. Intensive property is property that depends only on the type of matter rather than the amount. Hense, Volume is an example of Extensive property and Density is an example of Intensive property.

Hope this helps :)

Answer:

Explanation:

From the information given:

The unknown contained salt, salicylic acid, and sand.

It is okay for the student to believe that the sand is present in the unknown, but if we carry how a scientific experiment, we will confirm such a hypothesis if it is right or wrong.

For a test containing salt, salicylic acid, and sand.

We know that the salt is soluble in water, but salicylic acid is sparingly soluble i.e., lightly soluble, and sand is insoluble in water.

So, we will add the unknown mixture into the water. The salt will eventually dissolve first, and then the salicylic acid will dissolve lightly.

Afterward, we will heat the mixture to evaporate the salicylic acid to evaporate, leaving us with the salt.

If there is a positive result of her claim that there is some presence of sand in the evaporated salt sample, that might result from impurities.

Answer:

a series of reactions in which particles from one reaction trigger the next reaction

Explanation:

cause thats a chain

The complete balanced chemical equation is:

2\(Au\) + 6\(HCl\) (aq) → 2\(Au\)\(Cl_{3}\) (aq) + 3\(H_{2}\) (g)

Chemical equations provide the reactants, products, and mole ratios of each component involved in the reaction and are a symbolic depiction of a chemical reaction. The reactants are written on the left side of the arrow, while the products are written on the right side, using chemical symbols and formulas. The coefficients in front of the formulas show the number of molecules involved and the arrow shows the reaction's direction. Chemical equations serve to explain the underlying chemical processes and forecast the volume of products that will be created in a reaction. They are a crucial tool in the study of chemistry and are essential to chemical reactions and their uses in a variety of sectors.

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Answer:

give me brainliest pls

Explanation:

Volumetric flasks

Volumetric labware is for measuring liquids with precision. Volumetric flasks, burettes, and pipettes made for measuring small amounts of liquid are the most accurate, with tolerances of less than ±0.02.

Answer:

A pipette is a laboratory instrument used to measure out or transfer small quantities of liquid, in volumes of milliliters (mL), microliters (μL).