URGENT!!!!

So my home work spent quite make sense to me right now. my brain is apparently not working right now!

When “it says make a display (dot plot, box plot, or histogram) of the data set and explain why you chose the type of display to represent this data set.”

What would I need to do on that? It would be great if I could get some step by step instructions on how I should work that out?


(Only needing instructions for question 6, don’t mind the other stuff)

Answer:

y=9

Step-by-step explanation:

Answer:

y = 9

Step-by-step explanation:

Step 1:

y = 3 + 8 - x        Equation

Step 2:

y = 3 + 8 - 2       Input x value

Step 3:

y = 11 - 2        Combine Like Terms

Answer:

y = 9

Hope This Helps :)

Answer:

6.92820323028

Step-by-step explanation:

its more closer to 7 because 6×6=36 and 7×7=49

Answer:

Step-by-step explanation:

4x-8<5x+4

4x<5x+12

-x<12

flip sign

x > -12

Answer:

-12 < x

Step-by-step explanation:

4x-8<5x+4​

Subtract 4x from each side

4x-4x-8<5x-4x+4​

-8 < x+4

Subtract 4 from each side

-8-4 < x+4-4

-12 < x

Answer:

C

Step-by-step explanation:

N = st

Number of toothpicks = (number of students) x (toothpicks)

D.

Answer:777

Step-by-step explanation: I do not care

There are 333 pages are in my book.

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

There are more than 200 pages but fewer than 800 in my book.

And, All the digits of my number are the same and the number is divisible by 9.

Now,

Let a number with three same digit = xxx

So, We get;

200 < xxx < 800

Since, the number is divisible by 9.

So, By the rule of the number divide by 9, we get;

x + x + x = 9k

3x = 9k

for k = 1;

x = 3

Thus, Number of pages = 333

Therefore,  

There are 333 pages are in my book.

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Answer:

Subtract 7 from both sides which gives you 2x=12

x=6

1 (hide)

2 (disattracted)

3(...)

4(younger)

5(decided)

6(big)

7(wide)

8(down)

9(stopped)

10(

The approximate mean for the given data set is 27.6, rounded to one decimal place.

To approximate the mean for the given data set, we can calculate the weighted average of the class midpoints, where each midpoint is multiplied by its corresponding frequency.

The class midpoints can be obtained by taking the average of the lower and upper class limits.

For the given data set, the class midpoints would be:

Midpoint of 0-8: (0 + 8) / 2 = 4

Midpoint of 9-17: (9 + 17) / 2 = 13

Midpoint of 18-26: (18 + 26) / 2 = 22

Midpoint of 27-35: (27 + 35) / 2 = 31

Midpoint of 36-44: (36 + 44) / 2 = 40

Midpoint of 45-53: (45 + 53) / 2 = 49

Next, we calculate the weighted average by multiplying each midpoint by its corresponding frequency, and then dividing the sum of these products by the total frequency.

Using the given frequencies, the weighted average would be:

(2 * 4 + 12 * 13 + 5 * 22 + 12 * 31 + 14 * 40 + 5 * 49) / (2 + 12 + 5 + 12 + 14 + 5) = 27.6

Therefore, the approximate mean for the given data set is 27.6, rounded to one decimal place.

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Answer:

3 cm

Step-by-step explanation:

Find the value of x:

\(5-2x=-4x+9\)

\(-2x+4x=-5+9\)

\(2x=4\)

\(x=4/2\)

\(x=2\)

Find one side of the triangle by adding 2 as the value x:

\(=5-2x\)

\(=5-2(2)\)

\(=5-4\)

\(=1\)

Perimeter of the triangle:

1 × 3 = 3cm

Answer:

C

Step-by-step explanation:

64.93

The  social security tax deducted from Gary's gross pay is $64.93.

This is the tax levied on both employers and employee to develop social security program.

The social security tax deducted from Gary's gross pay is calculated as follows;

Tax = Amount x rate

Tax = $1,047.30 x 0.062

Tax = $64.93

Thus, the  social security tax deducted from Gary's gross pay is $64.93.

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The value of the test statistic for the given hypotheses is 2.8.

To determine the value of the test statistic for the given hypothesis and sample data, we need to use the formula for calculating the test statistic for a one-sample t-test.

The test statistic formula is given by:

\(t = (x -\mu ) / (s / \sqrt n)\)

Plugging in the given values into the test statistic formula, we get:

t = (53.5 - 50) / (10 / √64)

  = (3.5) / (10 / 8)

  = (3.5) / (1.25)

  = 2.8

Therefore, the value of the test statistic for the given hypothesis, sample size, sample mean, and sample standard deviation is 2.8.

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Answer:

3/8

Step-by-step explanation:

Since the greatest is 3 1/2 and the least it 3 1/8

3 1/2 - 3 1/8 = 3/8

Approximately 2.28% of the bottles would be expected to have less than 58 ounces.

To determine the proportion (or percentage) of bottles expected to have less than 58 ounces, we need to calculate the z-score and then use the standard normal distribution table.

First, let's calculate the z-score using the formula:

z = (x - μ) / σ

where:

z = (58 - 64) / 3 = -2

Next, we need to find the corresponding area under the standard normal curve for a z-score of -2.

By referring to a standard normal distribution table or using a calculator, we can find that the area to the left of -2 is approximately 0.0228.

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Answer:

The answer is B

Answer:

i can only answer the first question, it is b!

Step-by-step explanation:

hope that helped :)

Answer:

John is 3 and Annie is 5 because to be half of someone's age while being to years younger it would have to be 2 and 4 - but then a year passed and so the are now 3 and 5.

Step-by-step explanation:

The present  age of John is  3 years

The present age of Annie is 5 years  

Given that John is 2 years younger than Annie's age

Let the present age of John be "J"

Let the present age of Annie be "A"

According to the given situation

\(\rm J = A -2........(1)\\\)

One year ago the age of John = \(\rm J-1\)

One year ago the age of Annie = \(\rm A -1\)

According to the given situation

\(\rm\dfrac{A-1}{2}= J-1.........(2)\)

On solving for equations (1) and (2) we get

A = 5 and J = 3

So the present  age of Annie is  5 years

The present age of John is 3 Years  

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The statement cross-tabulation with two variables is known as twice-tabulation is false because there is no such term as "twice-tabulation" in the context of statistical analysis.

Cross-tabulation, also known as contingency table analysis, involves the analysis of categorical variables by creating a table that shows the frequency or distribution of one variable based on the levels of another variable.

It allows for the examination of the relationship between two variables, highlighting any associations or patterns that may exist. Each cell in the cross-tabulation table represents the count or proportion of observations that fall into specific combinations of categories from the two variables.

The term "twice-tabulation" does not exist in statistical literature and is not commonly used to refer to cross-tabulation with two variables. The correct term to describe this statistical technique is simply cross-tabulation or contingency table analysis.

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Answer:

Step-by-step explanation:

The value of y is given in equation 2

Putting value of y = 3x in equation 1

Y = - x + 4

3x = - x + 4

Bringing like terms on one side

3x + x = 4

4x = 4

x = 4/4 = 1

Now putting value of x = 1 in equation 2

Y = 3x

Y = 3(1) = 3

To determine the constant amount that can be withdrawn each year for 20 years, we need to calculate the annuity payment using the present value of an annuity formula.

Inherited amount: RM300,000

Interest rate: 7% per year

Number of years: 20

Using the present value of an annuity formula:

PV = P * [(1 - (1 + r)^(-n)) / r]

Where:

PV = Present value (inherited amount)

P = Annuity payment (constant amount to be withdrawn each year)

r = Interest rate per period (7% or 0.07)

n = Number of periods (20 years)

Plugging in the values:

300,000 = P * [(1 - (1 + 0.07)^(-20)) / 0.07]

Solving this equation, we find that the constant amount that can be withdrawn each year is approximately RM15,000.

Therefore, the correct answer is A. RM15,000.

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Answer:

doesn't make sense...

Step-by-step explanation:

Answer:

It would double in size

Step-by-step explanation:

Judging as the circumference of a circle is dependent on the diameter, a circle whose diameter doubled in size would double.

An example would be a circle with the circumference of 20. It's radius would be 10 rather than 5. The circumference of the circle with a diameter of 10 would be roughly 31, while the circle with a diameter of 20 would have a circumference of roughly 62.

Answer:

6.66 miles

Step-by-step explanation:

Miles run in 27 minutes = 3 miles

Miles run in 1 minute = 3÷27 miles = \(\frac{1}{9}\)

1 hour = 60 minutes

Therefore,

Miles run in 60 minutes = \(\frac{1}{9}\) × 60

                                        = \(\frac{20}{3}\) miles OR 6.66 miles

Answer:

2nd one

Step-by-step explanation:

sorry if that is incorrect it should be right though

Answer:

45.5 ft sqaured

Step-by-step explanation:

Ex 8. the solution to the differential equation y'' + y = t² with initial condition y(0) = -2 and y'(0) = 0 is y(t) = t² - 2. Ex 9. the isolated form of Y(s) for the given differential equation and initial conditions is: Y(s) = (1/(s - 3) + 6/s⁴ + s² + 2s + 4) / (s³ + s)

a) To find the Laplace transform of the given differential equation y'' + y = t², we first take the Laplace transform of both sides of the equation. Let's denote the Laplace transform of y(t) as Y(s).

Applying the Laplace transform to the equation, we get:

s²Y(s) - sy(0) - y'(0) + Y(s) = 1/s³

Substituting the initial conditions y(0) = -2 and y'(0) = 0, we have:

s²Y(s) + 2s + Y(s) = 1/s³

Now, let's isolate Y(s):

s²Y(s) + Y(s) = 1/s³ - 2s

(Y(s))(s² + 1) = 1/s³ - 2s

Y(s) = (1/s³ - 2s) / (s² + 1)

b) To find y(t) from the Laplace transform Y(s), we can apply the inverse Laplace transform. In this case, we need to use partial fraction decomposition to simplify the expression.

Y(s) = (1/s³ - 2s) / (s² + 1)

Y(s) = (1/s³) / (s² + 1) - 2s / (s² + 1)

Y(s) = 1/s³ * 1/(s² + 1) - 2s / (s² + 1)

Using partial fraction decomposition, we can express 1/(s² + 1) as A/(s + i) + B/(s - i), where i represents the imaginary unit.

1/(s² + 1) = (A/(s + i)) + (B/(s - i))

Multiplying through by (s + i)(s - i), we get:

1 = A(s - i) + B(s + i)

Expanding and equating the coefficients of the corresponding powers of s, we have:

0s² + 0s + 1 = (A + B)s + (B - A)i

Equating the coefficients, we get:

A + B = 0 (coefficient of s)

B - A = 1 (constant term)

Solving these equations, we find A = -1/2 and B = 1/2.

Now, we can rewrite Y(s) as:

Y(s) = 1/s³ * (-1/2)/(s + i) + 1/s³ * (1/2)/(s - i) - 2s / (s² + 1)

Taking the inverse Laplace transform of each term using standard formulas, we find:

y(t) = (-1/2)e^(-it) + (1/2)e^(it) - 2sin(t)

Since e^(-it) and e^(it) represent complex conjugates, their sum simplifies to:

y(t) = -2sin(t)

EXERCISE 9:

To find the Laplace transform of y''' + y' = e^(3t) + t³ with initial conditions y(0) = 1, y'(0) = 2, y''(0) = 3, we can follow a similar process as before. However, without solving the equation, we can isolate Y(s) by applying the Laplace transform to both sides of the equation and using the initial conditions:

s³Y(s) - s²y(0) - sy'(0) - y''(0) + sY(s) - y(0) = 1/(s - 3) + 6/s⁴

Substituting the initial conditions, we have:

s³Y(s) - s² - 2s - 3 + sY(s) - 1 = 1/(s - 3) + 6/s⁴

Now, let's isolate Y(s):

s³Y(s) + sY(s) = 1/(s - 3) + 6/s⁴ + s² + 2s + 4

(Y(s))(s³ + s) = 1/(s - 3) + 6/s⁴ + s² + 2s + 4

Y(s) = (1/(s - 3) + 6/s⁴ + s² + 2s + 4) / (s³ + s)

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Answer:

\(1.25\cdot10^{5}\) \(or\) \(125000\)

Step-by-step explanation:

\(--------------------------------------------\)

\(1)\) \(64\cdot10^{6}\) = \(64000000\)

\(2 )\) \(32\cdot10^{6}\) = \(32000000\)

\(3)\) \(16\cdot10^{6}\) = \(16000000\)

\(4)\) \(8\cdot10^{6}\) = \(8000000\)

\(5)\) \(4\cdot10^{6}\) = \(4000000\)

\(6)\) \(2\cdot10^{6}\) = \(2000000\)

\(7)\) \(1\cdot10^{6}\) = \(1000000\)

\(8)\) \(5\cdot10^{5}\) = \(500000\)

\(9)\) \(2.5\cdot10^{5}\) = \(250000\)

\(10)\) \(1.25\cdot10^{5}\) = \(125000\)

\(--------------------------------------------\)

The way I solved this question was by dividing each scientific form by two.

\(--------------------------------------------\)

Hope this helps! <3

\(--------------------------------------------\)

Answer:

a) 1.0m

b) 5.9m

Step-by-step explanation:

(a) The distance of the foot of the ladder from the wall

cos∅ = adj/hyp

cos80 = adj/6

multiply both sides by 6

6 * cos 80 = adj

1.041889066001582 = adj

to 1 dp

1.0m

-------------------------------

(b) The height above the ground at which the upper end of the ladder touches the wall

sin∅ = opp/hyp

sin80 = opp/6

6 * sin80 = opp

5.908846518073248 = opp

To 1 dp

5.9m

Answer:

(A) and (E)

Mark brainliest !!

The matrix of \(t\) relative to the basis \(b'\) is \(A' = \begin{bmatrix} -9 & 7 \\ -37 & 43 \end{bmatrix}\).

\(\textbf{To find the matrix of } t \textbf{ relative to the basis } b', \textbf{we have to follow some steps. The steps are described below:}\)

First, we have to find the images of basis vectors under the transformation \(t\). \(t(-1,1) = (-9,7)\) and \(t(1,-5) = (-37,43)\).

Represent the image vectors of the basis in the standard basis. We use these vectors as columns in the matrix of \(t\) in the basis \(b'\).

\((-9,7) = -9(1,0) + 7(0,1) = (-9,7) = -9(-1,1) + 7(1,-5)\)

\((-37,43) = -37(1,0) + 43(0,1) = (-37,43) = -37(-1,1) + 43(1,-5)\)

Hence, we can write the following equation: \(A[x]_{b'} = [x]_S\)

Where \(A[x]_{b'}\) is the main answer in the form of a matrix, and \([x]_S\) is the coordinate of \([x]_{b'}\) with respect to the standard basis.

Now, we will write the equations with the coordinates of the basis vectors of \(b'\).

\(A[1,0] = [-9, -37]\) and \(A[0,1] = [7, 43]\)

Now we will write the matrix of \(A\) as follows:

\(A = \begin{bmatrix} -9 & 7 \\ -37 & 43 \end{bmatrix}\)

Thus, the matrix of \(t\) relative to the basis \(b'\) is \(A' = \begin{bmatrix} -9 & 7 \\ -37 & 43 \end{bmatrix}\).

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