What are the coordinates of the image R(90°,0)(JKLO)=J'K'L'O'
Answers
The image of the figure after rotating by counterclockwise about the origin is J' = (-1, -1), K' = (-2, -1), L' = (-1, 4,) and O' = (-3, -2)
Rotating the figure 90 counterclockwise about the originFrom the question, we have the following parameters that can be used in our computation:
The coordinates are
J = (-1, 1)
K = (-1, 2)
L = (4, 1)
O = (-2, 3)
The rule of rotating a figure 90 counterclockwise about the origin is
(x,y) = (-y,x)
So, we have
J' = (-1, -1)
K' = (-2, -1)
L' = (-1, 4,)
O' = (-3, -2)
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Question
What are the coordinates of the image R(90°,0)(JKLO)=J'K'L'O'
J = (-1, 1) K = (-1, 2) L = (4, 1) O = (-2, 3)
Related Questions
√√96
√8
Ο 213
Ο 4
Ο 222
D. 12
Answers
Answer:
2sqr3, the first option
Step-by-step explanation:
Which term can be added to the list so that the greatest common factor of the three terms is 12h3?
36h3, 12h6, __________
Answers
The term that can be added to the list so that the greatest common factor of the three terms 12h3 36h3, 12h6, is 48h5
How can the term be known?A group of numbers' greatest common factor (GCF) is the biggest factor that all the numbers have in common. For instance, 12, 20, and 24 all share two characteristics.
The term that can fit in to the list so the GCF is 12h3 would be 48h5, this is so because 48 is first divisible by 12 without any fraction, and we can remove upon dividing 3 h's from this term as it contains a total of 5 h's.
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I need help with this question and can you please add the step by step
Answers
Answer: it looks like it will be 1.5
Step-by-step explanation:
A factory worker can package 150 games in 15 minutes. How many games can he package per minute
Answers
In a statistics activity, students are asked to spin a penny and a dime and determine the proportion of times that each lands with tails up. The students believe that since a dime is lighter, it will have a lower proportion of times landing tails up compared to the penny. The students are instructed to spin the penny and the dime 30 times and record the number of times each lands tails up. For one student, the penny lands tails side up 18 times, and the dime lands tails side up 20 times. Let pD = the true proportion of times a dime will land tails up and pP = the true proportion of times a penny will land tails up. Which of the following is the correct standardized test statistic and P-value for the hypotheses, ?
Find the z-table here.
, P-value=0.592
, P-value = 0.296
z = StartStartFraction 0.60 minus 0.67 OverOver StartRoot StartFraction (0.63) (0.40) Over 30 EndFraction + StartFraction (0.67) (0.33) Over 30 EndFraction EndRoot EndEndFraction, P-value = 0.296
z = StartStartFraction 0.67 minus 0.60 OverOver StartRoot StartFraction (0.60) (0.40) Over 30 EndFraction + StartFraction (0.67) (0.33) Over 30 EndFraction EndRoot EndEndFraction, P-value = 0.592
Answers
The correct standardized test statistic is z = -0.7722, and the correct P-value is 0.2207.
To determine the correct standardized test statistic and P-value for the hypotheses, we need to perform a hypothesis test to compare the proportions of times the penny and the dime land with tails up.
Let pP be the true proportion of times the penny lands tails up, and let pD be the true proportion of times the dime lands tails up.
The null hypothesis (H0) is that there is no difference between the proportions of times the penny and the dime land tails up: pP = pD.
The alternative hypothesis (H1) is that there is a difference between the proportions: pP ≠ pD.
To conduct the hypothesis test, we can use the two-proportion z-test formula:
z = (pP - pD) / √[(pP * (1 - pP) / nP) + (pD * (1 - pD) / nD)]
where nP and nD are the respective sample sizes for the penny and the dime.
In this case, the student spun the penny 30 times and recorded 18 tails side up, so nP = 30 and pP = 18/30 = 0.60.
The dime was spun 30 times with 20 tails side up, so nD = 30 and pD = 20/30 = 0.67.
Substituting these values into the z-test formula, we get:
z = (0.60 - 0.67) / √[(0.60 * 0.40 / 30) + (0.67 * 0.33 / 30)]
= -0.07 / √[(0.024 / 30) + (0.2211 / 30)]
= -0.07 / √(0.0008 + 0.0074)
= -0.07 / √0.0082
≈ -0.07 / 0.0905
≈ -0.7722
Using a z-table or a statistical software, we can find the P-value associated with a z-score of -0.7722. The P-value turns out to be approximately 0.2207.
Therefore, the correct standardized test statistic is z = -0.7722, and the correct P-value is 0.2207.
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TIME REMAINING
57:38
VX
The local office supply store charges $0.08 per page to make photocopies. Lionel paid $20.00 for a set of copies. How many
pages did Lionel have copied?
Answers
Step-by-step explanation:
Charges per page = $0.08
Amount Lionel paid = $20.00
No of pages = 20 ÷ 0.08 = 250 pages
Answer:
250 pages
Step-by-step explanation:
Number of photocopies = Total amount÷ cost per page
\(=\frac{20}{0.08}\\\\= 250\)
deigo has $500 dolars in his saving account each month he takes out $20 to pay for karate class. let m be the number of months write an expression yo show the total amount ain deigos saving account after m months
Answers
The expression shows the total amount in Diego's savings account after m months is 500 - 20m.
What is the total amount?
Two numbers are added together to form the sum. It is simple to figure out the sum of small integers. You can add two numbers using your fingertips. When two or more numbers are added together, a mathematical sum or maths sum is the outcome. It is the sum of the numbers when they are added up.
Here, we have
Given: Deigo has $500 in his saving account each month he takes out $20 to pay for karate class.
Let m be the number of months. Write an expression to show the total amount in Diego's savings account after m months.
The expression:
= 500 - 20m
Here m is the number of months
Hence, the expression shows the total amount in Diego's savings account after m months is 500 - 20m.
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6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Mofor has homework assignments in five subjects. He only has time to do two of
them.
Answers
The decision of which two homework assignments to complete depends on Mofor's individual circumstances and priorities.
If Mofor only has time to do two homework assignments out of the five subjects, he will need to choose which subjects to prioritize. The specific subjects he chooses to work on will depend on various factors such as his strengths, weaknesses, upcoming deadlines, and personal preferences. Here are a few strategies he could consider:
1. Prioritize based on importance: Mofor can prioritize the homework assignments that carry more weight in terms of grades or have upcoming deadlines. This way, he ensures that he completes the assignments that have a higher impact on his overall academic performance.
2. Focus on challenging subjects: If Mofor finds certain subjects more difficult or time-consuming, he can prioritize those assignments to allocate more time and effort to them. This approach allows him to concentrate on improving his understanding and performance in subjects that require extra attention.
3. Balance workload: Mofor can choose to distribute his efforts evenly across subjects, selecting two assignments from different subjects. This strategy ensures that he maintains a balanced workload and avoids neglecting any particular subject.
The decision of which two homework assignments to complete depends on Mofor's individual circumstances and priorities. It is essential for him to consider his academic goals, time constraints, and personal strengths to make an informed decision.
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Find the measures of the sides of the sides of triangle JKL then classify it by its sides if J(-7, -7), K(-9 1), L(-1, -1)
Answers
\(~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ J(\stackrel{x_1}{-7}~,~\stackrel{y_1}{-7})\qquad K(\stackrel{x_2}{-9}~,~\stackrel{y_2}{1}) ~\hfill JK=\sqrt{(~~ -9- (-7)~~)^2 + (~~ 1- (-7)~~)^2} \\\\\\ ~\hfill JK=\sqrt{( -2)^2 + ( 8)^2} \implies \boxed{JK=\sqrt{ 68 }}\)
\(K(\stackrel{x_1}{-9}~,~\stackrel{y_1}{1})\qquad L(\stackrel{x_2}{-1}~,~\stackrel{y_2}{-1}) ~\hfill KL=\sqrt{(~~ -1- (-9)~~)^2 + (~~ -1- 1~~)^2} \\\\\\ ~\hfill KL=\sqrt{( 8)^2 + ( -2)^2} \implies \boxed{KL=\sqrt{ 68 }} \\\\\\ L(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1})\qquad J(\stackrel{x_2}{-7}~,~\stackrel{y_2}{-7}) ~\hfill LJ=\sqrt{(~~ -7- (-1)~~)^2 + (~~ -7- (-1)~~)^2} \\\\\\ ~\hfill LJ=\sqrt{( -6)^2 + (-6)^2} \implies \boxed{LJ=\sqrt{ 72 }}\)
well, let's notice, the triangle has two sides that are twins, JK and KL, that means is an isosceles, and isosceles triangle is a triangle with twin sides.
I’ve attached a photo
Solve for n:
3/4f-5/2n=2
n=
Answers
Answer:
\(n=\frac{3f-8}{10}\)
Step-by-step explanation:
So we have the equation:
\(\frac{3}{4}f-\frac{5}{2}n=2\)
First, remove all the fractions by multiplying by the LCM of the denominator.
The LCM of 4 and 2 is 4. Thus:
\(4(\frac{3}{4}f-\frac{5}{2}n)=4(2)\)
Distribute:
\(4(\frac{3}{4}f})-4(\frac{5}{2}n})=4(2)\)
Simplify:
\(3f-10n=8\)
Subtract 3f from both sides:
\((3f-10n)-3f=(8)-3f\\-10n=8-3f\)
Divide both sides by -10:
\(n=\frac{8-3f}{-10}\)
Divide by -1:
\(n=\frac{3f-8}{10}\)
And this is our answer :)
n = (3f - 8)/10
Step-by-step explanation:3f/4 - ²⁾5n/2 = ⁴⁾2
3f - 10n = 8
3f - 8 = 10n
n = (3f - 8)/10
Which of the following is the correct point-slope equation for the line that passes through the point (-6, -1) and is parallel to the line given by y = 7x + 31?
Answers
Answer:
A. y + 1 = 7(x + 6)
Step-by-step explanation:
1) Point slope form is
y - y1 = m(x - x1)
where m is the slope and (x1, y1) is a point on the line
2) Parallel lines have the same slope
in this case m = 7
-------------------------------
Plug in m = 7 and (x1, y1) = (-6, -1)
y + 1 = 7(x + 6)
which is answer A
Can someone help me how to do this task please?
Answers
Answer:
11/12
Step-by-step explanation:
what is the negative square root of 81/49 in fraction form
Answers
Answer:
-9/7.
Step-by-step explanation:
√81 = 9 and √49 = 7
but we need the negative square root
which is -9/7.
Question 11 of 37
What is the volume of the triangular prism shown below?
15
9
Answers
Answer:
the correct answer is B. 135 cu. units
Find the area of the rectangle shown
7 1/2 ft
5 1/4ft
Answers
Answer:
39 3/8 ft ^2
Step-by-step explanation:
To find the area of a rectangle, multiply the length times the width.
A = l*w
= 7 1/2 * 5 1/4
Change the mixed numbers to improper fractions.
A = 15/2 * 21/4
=315/8
Change back to a mixed number.
8 goes into 315 39 times with 3 left over.
= 39 3/8
Answer:
Area = 39.375 ft²
(you can round to 39.4)
Step-by-step explanation:
Find the area of the rectangle shown
7 1/2 ft
5 1/4ft
7 1/2 = 7.5 ft
5 1/4 = 5.25 ft
Area = L x W
Area = 7.5 x 5.25
Area = 39.375
what would be the answers for these ????
Answers
Answer:
Step-by-step explanation: the y would be 50
5. If m 6 = x, m 7 = x – 20, and m 11 = 80 then x =
Answers
Answer:
6
Step-by-step explanation:
Answer is there the value of this
What are the numerical measures of each angle?
Answers
Answer:
<1 and <3 equal 29 degrees
<2 ans <4 equal 151 degrees
Step-by-step explanation:
instructions in pic :)
Please help quick! I will give brainliest
Answers
Answer:
1. A
2. B.
3. 2^3 or 8
4. C.
Step-by-step explanation:
use mathaway
What is the volume of an 8-inch by 4-inch by 4
1) 2-inch rectangular box?
Answer________ cubic inches
Answers
Answer is 128 cubic inches
The volume of the given box is 64 inch³
What is volume?Volume, which is measured in cubic units, is the 3-dimensional space occupied by matter or encircled by a surface. The cubic meter (m³), a derived unit, is the SI unit of volume. Volume is another word for capacity.
The length, width, and height of a rectangular box are multiplied to get its volume.
As a result, the following formula may be used to determine the volume of an 8 inches by 4 inches by 2 inches rectangular box:
Volume is calculated using the formula LWH.
Volume is =8 * 4 * 2 inches.
64 cubic inches is the volume.
The rectangular box measures 8 by 4 by 2 inches and thus has a volume of 64 cubic inches.
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Question 2
A box contains 22 coloured pencils.
6 pencils are pink, 9 pencils are blue and 7 pencils are yellow.
Write down the ratio pink pencils : not pink pencils.
Give your answer in its simplest form.
Answers
Answer:
3/8 or 3:8
Step-by-step explanation:
pink : not pink
6 : 16
Think of it as a fraction. Simplify it in the same way.
6/16 simplifies to 3/8
So the pink:notpink ratio is 3/8 or 3:8
when simplified it becomes 3:8
Given the following sets, find the set (A U B) n (AUC).
U= {1, 2, 3, ..., 10}
A=(2, 5, 7, 10}
B = {1, 2, 3)
C={1, 2, 3, 4, 5}
Answers
The set (A U B) n (A U C) is {2, 5, 7, 10}. A.
To find the set (A U B) n (A U C), we first need to calculate the union of sets A and B, and then calculate the union of that result with set C. Finally, we find the intersection of these two sets.
Set A U B:
The union of sets A and B, denoted as A U B, is the combination of all elements from both sets without any repetitions.
A contains the elements 2, 5, 7, and 10, while B contains the elements 1, 2, and 3.
A U B consists of the elements {1, 2, 3, 5, 7, 10}.
Set (A U B) U C:
Next, we calculate the union of the set (A U B) with set C, denoted as (A U B) U C. A U B contains the elements {1, 2, 3, 5, 7, 10} and C contains the elements {1, 2, 3, 4, 5}.
Taking the union of these two sets results in {1, 2, 3, 4, 5, 7, 10}.
Finding the intersection:
Finally, we find the intersection of (A U B) U C with A U C. A U C consists of the elements {2, 5, 7, 10}.
The intersection of these two sets is the combination of common elements.
The common elements are {2, 5, 7, 10}.
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what are the x intercepts of y=x^2-x-12
Answers
y intercept: (0,-12)
Hope this helps!
Answer:
The person at the top is right. Give them brainliest
Please help.
What is 74+35.6?
Thank you
Answers
Answer:
The sum of
74 and 35.6 is 109.6
Step-by-step explanation:
109.6
Now enjoy a free meme thing
Alice and Bob each have a certain amount of money. If Alice receives n dollars from Bob, then she will have 7 times as much money as Bob. If, on the other hand, she gives n dollars to Bob, then she will have 2 times as much money as Bob. If neither gives the other any money, what is the ratio of the amount of money Alice has to the amount Bob has?
Answers
The ratio of the amount of money Alice has to the amount Bob has is approximately 3.36 : 1.
How to find the ratio of money ?According to the problem, two equations can be set up:
If Alice receives n dollars from Bob, then she will have 7 times as much money as Bob. This gives us the equation:
A + n = 7(B - n)
If Alice gives n dollars to Bob, then she will have 2 times as much money as Bob. This gives us the second equation:
A - n = 2(B + n)
We can rearrange these equations to make them easier to solve:
8n = 7B - A
3n = A - 2B
Setting these equal to each other, since they are both equal to 24n, gives:
21B - 3A = 8A - 16B
37B = 11A
A / B = 37 / 11
= 3. 36
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#9
Identify an example of a solid from which a triangular, hexagonal, and trapezoidal cross section can be formed.
O cone
O sphere
O cylinder
O triangular prism
hexagonal prism
Answers
Dos campañas suenas a intervalos de 26 y 78 minutos respectivamente ¿A que hora sonarán juntas otra vez si empieza simultáneamente a las 12 del mediodía
Answers
Find the solution to the following system of equations using the addition method. 5x - 3y = 12 -4x + 3y = 5 (13, -4)
Answers
Answer: You didn't give answer choices but I think the answer would be (17, 73/3)
2.
It takes Troy 3 hours to mow his family's large lawn. With his little brother's help, he can
finish the job in only 2 hours. How long would it take the little brother to mow the entire
lawn alone ?
(A) 4 hr
(B) 5 hr
(C) 5.5 hr
(D) 6 hr
(E) 6.75 hr
Answers
Answer:
It takes four hours because the little bro is alone and only one lawn mower is used