A man rides up in an elevator at 12 m. He gains 6500 J of gravitational potential energy. what is the man's mass?
Answers
Answer:
We know that potential energy of a body;
= mass(m)× gravitational acceleration(g) × height(h)
Lets find out the mass of the body
P.E. = mgh
=> 6500J = mass × 9.8m/s^2 × 12m
=>6500J = mass × ( 9.8 × 12 ) × ( m/s^2 × m)
=> 6500 Nm = m × 117.6 × m^2 / s^2
=> 6500/117.6 Ns^2/m = mass [°.° Ns^2/m = kg]
=> 55.272 Kg = mass
Therefore the mass of the body = 55.272 kg ~ 60 kg (Ans)
Hope it helps you
Related Questions
Three two-port circuits, namely Circuit 1 , Circuit 2 , and Circuit 3 , are interconnected in cascade. The input port of Circuit 1 is driven by a 6 A de current source in parallel with an internal resistance of 30Ω. The output port of Circuit 3 drives an adjustable load impedance ZL. The corresponding parameters for Circuit 1, Circuit 2, and Circuit 3, are as follows. Circuit 1: G=[0.167S0.5−0.51.25Ω] Circuit 2: Circuit 3: Y=[200×10−6−800×10−640×10−640×10−6]S Z=[33534000−3100310000]Ω a) Find the a-parameters of the cascaded network. b) Find ZL such that maximum power is transferred from the cascaded network to ZL. c) Evaluate the maximum power that the cascaded two-port network can deliver to ZI.
Answers
a) The A-parameters of the cascaded network are defined by (4 points)Answer:a_11 = 0.149 S^0.5 - 0.0565a_12 = -0.115 S^0.5 - 0.0352a_21 = 136 S^0.5 - 133a_22 = -89.5 S^0.5 + 135b) Find ZL such that maximum power is transferred from the cascaded network to ZL. (2 pointsZ). The maximum power transfer to load impedance ZL occurs when the load is equal to the complex conjugate of the source impedance.
We can calculate the source impedance as follows: Rs = 30 Ω || 1/0.167^2 = 31.2 ΩThe equivalent impedance of circuits 2 and 3 connected in cascade is: Zeq = Z2 + Z3 + Z2 Z3 Y2Z2 + Y3 (Z2 + Z3) + Y2 Y3If we substitute the corresponding values: Zeq = 6.875 - j10.75ΩNow we can determine the value of the load impedance: ZL = Rs* Zeq/(Rs + Zeq)ZL = 17.6 - j8.9Ωc) Evaluate the maximum power that the cascaded two-port network can deliver to ZI. (2 points). The maximum power that can be delivered to the load is half the power available in the source.
We can determine the available power as follows: P = (I_s)^2 * Rs /2P = 558 mW. Now we can calculate the maximum power transferred to the load using the value of ZL:$$P_{load} = \frac{V_{load}^2}{4 Re(Z_L)}$$$$V_{load} = a_{21} I_s Z_2 Z_3$$So,$$P_{load} = \frac{(a_{21} I_s Z_2 Z_3)^2}{4 Re(Z_L)}$$Substitute the corresponding values:$$P_{load} = 203.2 m W $$. Therefore, the maximum power that can be delivered to the load is 203.2 mW.
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After 20 seconds, a 200-kg object increases its velocity from 15 m/s to 40 m/s. Determine the impulse applied to the object. (Also show your work so I can understand it better and ty)
Answers
Answer:
Imp_{1-2}=5000[kg*m/s]
Explanation:
In order to solve this problem, we must use the principle of conservation of momentum, which is defined as the product of mass by Velocity.
It must be defined that the impulse after the force is applied is equal to the momentum before the impulse applied on the body.
ΣPbefore = ΣPafter
P = momentum = m*v [kg*m/s]
In this way, we will construct the following equation.
\((m_{1}*v_{1})+ Imp_{1-2}=(m_{1}*v_{2})\)
where:
m₁ = mass of the object = 200 [kg]
v₁ = velocity of the object before the impulse = 15 [m/s]
v₂ = velocity of the object after the impulse = 40 [m/s]
Now replacing:
\((200*15) + Imp_{1-2} = (200*40)\\Imp_{1-2}=5000[kg*m/s]\)
6.(i) An electron travels along the x axis with a velocity v = (v0,0,0). Its 3D coordinates are (0,0,0) when it enters a region of length L within which a constant and weak magnetic field of B = (0,B0,0) is applied. The effect of the weak magnetic field is to cause a small deviation in the path of the electron so that it does not pass through the point (1,0,0) which it would do in the case of Bo = 0. Find an expression for the location (x,y,z) of the electron after it has travelled a distance L in the x direction. [6 marks) (ii) An energetic collision between a fast electron and an electron at rest is used to create an electron-positron pair. Show that for this to happen, the minimum amount of kinetic energy of the fast electron must be at least 6mec?, where me is the mass of the electron. [10 marks]
Answers
(i) The location of the electron after traveling a distance L in the x direction is x = v0L, y = B0L²/2v0, and z = 0.
(ii) The minimum kinetic energy of the fast electron required to create an electron-positron pair is 6mec².
(i) The expression for the location (x, y, z) of the electron after traveling a distance L in the x direction is x = v0L, y = B0L²/2v0, and z = 0. This accounts for the deviation caused by the weak magnetic field.
When a magnetic field is applied perpendicular to the initial velocity of the electron, it experiences a Lorentz force that causes it to deviate from its original path. In this case, the magnetic field is in the y-direction, so the electron will experience a force in the y-direction. By integrating the equation of motion, the expressions for x, y, and z can be derived.
(ii) The minimum amount of kinetic energy of the fast electron required to create an electron-positron pair is 6mec², where me is the mass of the electron.
In order for an energetic collision between a fast electron and an electron at rest to create an electron-positron pair, the total energy must be conserved. The rest mass energy of an electron-positron pair is 2mec². Since the fast electron has initial kinetic energy, a minimum kinetic energy of 6mec² is required to ensure that the total energy is sufficient to produce the electron-positron pair. This minimum energy accounts for the creation of two particles with rest mass energy.
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(i) The location of the electron after traveling a distance L in the x direction is given by the expression:
r = (L, 0, 0) + (0, v0, 0)t + (1/2)(q/m)(v0B0t^2)y
(ii) The minimum amount of kinetic energy required for the creation of an electron-positron pair in an energetic collision between a fast electron and an electron at rest is 6mec^2.
(i) The location of the electron after traveling a distance L in the x direction can be determined using the expression:
r = (L, 0, 0) + (0, v0, 0)t + (1/2)(q/m)(v0B0t^2)y. This equation takes into account the initial position, the velocity, the time of travel, and the magnetic field applied. The force acting on the electron due to the magnetic field is given by the Lorentz force equation, which can be used to calculate the acceleration and subsequent position of the electron.
(ii) To create an electron-positron pair in an energetic collision, the minimum amount of kinetic energy required for the fast electron is 6mec^2. This is obtained by calculating the difference between the total energy of the electron-positron pair and their rest mass energy. The Lorentz factor, γ, is used to express the total energy, and it is dependent on the velocity of the fast electron. By deriving and simplifying the inequality E - E0 ≥ mec^2(γ - 2) ≥ 0, the minimum kinetic energy requirement is determined to be 6mec^2.
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name any two instruments based on archimede's principle
Answers
Two instruments based on Archimedes' principle
LactometershydrometersExplanation:
Archimedes' principle states -
when a body is partially or completely immersed in a fluid , the fluid exerts an upward force on the body which is equal to the weight of the fluid displaced by the body.OR
when a body is immersed fully of partially in a fluid , it experiences an upward force that is equal to the weight of the fluid displaced by it.Applicatios : Lactometer , hydrometer.
Can someone please give me the (Answers) to this? ... please ...
Answers
Answer:
Jake’s horse will only need to exert enough force to make the carriage accelerate. Even though the carriage will pull on the horse as well, that force is not enough to make the horse accelerate in the direction of the carriage because it is only strong enough to make the carriage accelerate, not the horse.
Explanation:
Additional info: the horse has more mass than the carriage does so it would require a stronger force to make the horse accelerate.
Answer: Jake’s horse will only need to exert enough force to make the carriage accelerate .Since the horse has a greater mass than the carriage, it requires a stronger force to make the horse accelerate.
Explanation: Sorry it took so long lol
A box weighing 10 N is sitting on a surface that is tilted upward at a 45⁰ angle. The normal force is __________ 10 N.
a. equal to
b. less than
c. greater than
Answers
The normal force is less than the 10 N
Since we are given a box weight that is 10 N tilted at 45⁰, so the formula we refer from the figure to for calculating the normal force is:
N=mg⋅cos θ , where mg is the weight of the box and θ is the angle at which the box is shifted.
The flatter the incline to be, the normal force becomes greater. The littler an angle gets to be making the greater the esteem of cosine gets to be, and along these lines the greater the normal force becomes.
So, we get that the normal force will be
= 10 cos 45 (Since the value of mg is 10 N and θ = 45⁰)
= 7.07 N
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if two coils placed next to one another have a mutual inductance of 5.50 mh, what voltage (in v) is induced in one when the 4.00 a current in the other is switched off in 40.0 ms?
Answers
If two coils placed next to one another have a mutual inductance of 5.50 mH, what voltage (in V) is induced in one when the 4.00 A current in the other is switched off in 40.0 ms?
The voltage induced in one coil is 550 V.
The mutual inductance (M) is given as 5.50 mH (or 0.0055 H). The change in current (∆I) is 4.00 A, and the time taken to switch off the current (∆t) is 40.0 ms (or 0.040 s). To find the induced voltage, we can use the formula:
V = M * (∆I/∆t)
Plugging in the given values:
V = 0.0055 H * (4.00 A / 0.040 s)
V = 550 V
Summary: When a 4.00 A current in one of the two coils with a mutual inductance of 5.50 mH is switched off in 40.0 ms, a voltage of 550 V is induced in the other coil.
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a student weighing 490 N stands on a spring scale on earth. what is the students mass(gravity is 9.8 m/s
Answers
Answer:
Mass, m of the student is 50kg.
Explanation:
Given the following data;
Weight of student = 490N
Acceleration due to gravity = 9.8m/s
Weight is the product of the mass of an object or body multiplied by gravity.
Mathematically, weight is;
\( W = mg\)
Where;
W represents the weight of a body measured in Newton.
m represents the mass of a body measured in kilograms.
a represents acceleration due to gravity measured in metre per seconds.
\( m = \frac{W}{g}\)
\( m = \frac{490}{9.8}\)
Mass, m = 50kg.
Therefore, the mass of the student is 50kg.
What does Newton's first law describe?
O A. Forces that act in a direction opposite to an applied force
B. The tendency of stationary objects to remain at rest
C. The four fundamental forces of nature
D. Balanced and unbalanced forces
Answers
(b) What is the probability that the electron can be detected in the middle one third of well, region (b)
Answers
In order to determine the probability that an electron can be detected in the middle one-third of a well region, we need to take into account the wave function and the boundary conditions.The wave function represents the probability density of finding the electron in a particular location within the well. The boundary conditions are determined by the geometry of the well, which can be rectangular, triangular, or other shapes.
The Schrodinger equation is used to calculate the wave function and determine the probability density of finding the electron in a particular location. The wave function is a complex function that describes the position and momentum of the electron. It is also used to calculate the energy of the electron in the well.The probability of finding the electron in the middle one-third of the well can be determined by integrating the probability density over the middle one-third of the well region. This will give us the probability of finding the electron in that region. The integral can be evaluated using numerical methods or analytical methods, depending on the complexity of the wave function and the boundary conditions.In general, the probability of finding the electron in the middle one-third of the well will depend on the shape of the well, the energy of the electron, and the boundary conditions. For example, if the well is rectangular and the electron is in the ground state, then the probability of finding the electron in the middle one-third of the well will be high. However, if the well is triangular and the electron is in an excited state, then the probability of finding the electron in the middle one-third of the well will be lower.For such more question on probability
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the olympic swimmer swims to the end of the 50 m pool and back 4 times. calculate the distance covered.
Answers
Answer:
400 m
Explanation:
The swimmer swims 50 meters to one end of the pool but has to swim back therefore you double 50 which would be 100 meters. Then you have to multiply 100 by 4 since the swimmer did it 4 times.
what is the ratio of electrostatic force and the gravitational force between a proton and an electron?
Answers
Answer:
Explanation:
electron attraction between electron and nucleus = centripetal force of the orbiting electron
In fact, Bohr model depicts the atom as a nucleus surrounded by electrons in circular orbit around it, similar to the planets around the Sun. The centripetal force that keeps the electrons in circular motion around the nucles is provided by the electrostatic force between the electrons and the nucleus.
Answer:
Fg = G M m / R^2 the gravitational force (M proton, m electron)
Fe = K e^2 / R^2 the electrical force where K = 9 *10E9 and e = charge
Fe / Fg = K e^2 / (G M m)
Fe / Fg = 9 * 10E9 * (1.6 * 10E-19)^2 / (6.67 * 10E-11 * 1.67 * 10E-27 * 9.11 * 10E-31
9 * 1.6^2 / (6.67 * 1.67 * 9.11) * 10^-29 / 10^-69
= 2.27 * 10E39 for the ratio of the two forces
find the projection of u = −i j k onto v = 5i j − 6k.
Answers
The vector that results when one vector is divided into two additional vectors, known as component vectors, is referred to as a vector projection. Additionally, one will be perpendicular to the second vector, and one will be parallel to it.
projection of u on v=
\(\frac{u.v}{|v|} \\\\=\frac{-i+j+\pi .[5i+j-6\pi ]}{\sqrt{25+1+36} } \\\\ =\frac{-5+1-6}{\sqrt{62} } \\=\frac{-10}{\sqrt{62} }\)
The component of u with regard to v is the distance we cover when traversing u and is indicated by the letters v u. The projection of u onto v is known as the vector parallel to v. A unit vector in the direction of v is multiplied by the scalar comp v u to produce the vector known as proj v u, which represents the projection of u onto v. Proj v u is the vector obtained by drawing an arrow instead of the blue line segment that represents comp v u.
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Wish me Luck ! ! !
Im about to take my Fall 2020 Semester Physics Exam!
Answers
Answer:
Good Luck :)
Have a great day:)
Hello please answer this I need it right now
Nonsense:report
Right answer:brainliest
Answers
Answer:
do you have an answer key
Explanation:
When displacement a is added to displacement b the result is displacement c that has components cx=+3.0cm,cy=+6.0cm and cz=+4.0cm.displacement a and b are in the same direction,but the magnitude of a is only half of that of .find the components of a
Answers
The components of displacement a are ax=+1.5 cm, ay=+3.0 cm, and az=+2.0 cm.
What are the components of displacement a?To find the components of displacement a, we know that the magnitude of a is half that of c. Since displacement a and b are in the same direction, the components of a will have the same direction as c. However, the magnitude of a will be half of the magnitude of c. Therefore, we can calculate the components of a by multiplying the components of c by 0.5.
The given question asks for the components of a, which are the individual values that describe its direction and magnitude. By finding the components of a, we can understand how its displacement contributes to the overall result of displacement c.
Displacement c has components cx=+3.0 cm, cy=+6.0 cm, and cz=+4.0 cm. Since displacement a and b are in the same direction, we can infer that the components of a will have the same signs as c. However, the magnitude of a is only half that of c. Therefore, to find the components of a, we multiply the components of c by 0.5. This yields ax=+1.5 cm, ay=+3.0 cm, and az=+2.0 cm as the components of a.
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The angular speed of a rotating platform changes from ω0 = 4.4 rad/s to ω = 8.8 rad/s at a constant rate as the platform moves through an angle Δθ = 5.5 radians. The platform has a radius of R = 34 cm.
A) Calculate the angular acceleration of the platform α in rad/s2.
B) Calculate the tangential acceleration at in m/s2 of a point on the surface of the platform at the outer edge.
C) Calculate the final centripetal acceleration ac, in m/s2, of a point at the outer edge of the platform.
Answers
MAIN ANSWER in 30 WORDS:
A) α = 8.8 rad/s^2; B) at = 118.8 m/s^2; C) ac = 413.52 m/s^2.
EXPLANATION PART IN 120 WORDS:
A) Angular acceleration α can be calculated using the formula α = (ω - ω0)/Δθ. Substituting values, we get α = (8.8 - 4.4)/5.5 = 0.8 rad/s^2.
B) Tangential acceleration at can be calculated using the formula at = Rα, where R is the radius of the platform. Substituting values, we get at = 34 × 0.8 = 27.2 m/s^2.
C) Final centripetal acceleration ac can be calculated using the formula ac = Rω^2, where ω is the final angular velocity. Substituting values, we get ac = 34 × 8.8^2 = 413.52 m/s^2.
Therefore, the angular acceleration is 0.8 rad/s^2, the tangential acceleration at the outer edge of the platform is 27.2 m/s^2, and the final centripetal acceleration at the outer edge of the platform is 413.52 m/s^2.
The angular acceleration of the platform is 0.8 rad/s^2, the tangential acceleration at the outer edge of the platform is 27.2 m/s^2, and the final centripetal acceleration at the outer edge of the platform is 2617.6 m/s^2.
A) The angular acceleration α of the platform can be calculated using the formula: α = (ω^2 - ω0^2) / (2Δθ). Plugging in the values, we get α = (8.8^2 - 4.4^2) / (2 * 5.5) = 44/11 rad/s².
B) The tangential acceleration at of a point on the outer edge can be calculated using the formula: at = α * R. Converting R to meters, we get R = 0.34 m. Thus, at = (44/11) * 0.34 = 1.36 m/s².
C) The final centripetal acceleration ac can be calculated using the formula: ac = ω^2 * R. Plugging in the values, we get ac = 8.8^2 * 0.34 = 26.424 m/s².
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which correctly describes how the energy of a wave on the electromagnetic spectrum depends on wavelength and frequency?
Answers
Answer:
The answer to this question is given below in this explanation section.
Explanation:
"electromagnetic spectrum depends on wavelength and frequency"
When electromagnetic radiation interacts with single atoms and molecule,its behavior also depends on the amount of energy per quantum(photon)it carries wave number =1/wavelength in cm speed of light=wavelength x frequency energy = Planck's constant x frequency.
Electromagnetic radiation interacts with matter in different parts of the spectrum.
Electromagnetic radiation interacts with matter in different ways in different parts of the spectrum.The types of interaction can be so different that it seems justified to refer to different types of radiation.There is a continuum containing all these different kind of electromagnetic radiation.Thus we refer to spectrum but divide it up based on the different interaction with matter.
Answer:
Energy increases with decreasing wavelength and increasing frequency.
Explanation:
(21) A car covered a distance of 180 km. with velocity magnitude 20 m./sec. on a straight road, then the time taken to cover this distance =
Answers
Answer:
i got u
Explanation:
To find the time taken to cover a distance of 180 km with velocity magnitude 20 m/sec, we can use the formula:
time = distance / velocity
Converting the distance to meters, we get:
180 km = 180,000 m
Plugging in the values, we get:
time = 180,000 m / 20 m/sec
Simplifying, we get:
time = 9,000 seconds
Therefore, the time taken to cover a distance of 180 km with velocity magnitude 20 m/sec is 9,000 seconds.
Please answer the question in the middle
Answers
A student watches as a trash can lid moves across a yard. Which of these could have caused the trash can lid to move?
Answers
Answer:
wind energy
Explanation:
Wind energy can be defined as a form of a solar energy. It is generated by the immense force of the wind that blows in an area. Wind energy is a useful energy and is mostly used to generate electricity. It is clean source of energy.
In the context, trash can lid is being blown away by the wind energy and it is seen moving across the yard. The energy of the wind forces the lid of the trash can to move from one place to another against friction. Thus, wind energy caused the trash can lid to move across the yard as seen by a student.
meme on newtons law of motion (should me made ur self not from any searh engine)
Answers
The primary gas in a volcano is: carbon dioxide, sulfur dioxide, water vapor, nitrogen.
Answers
Answer:
The primary components in volcanic gas are water vapor, carbon dioxide and sulfur (either sulfur dioxide or hydrogen sulfide). But you can also find nitrogen, argon, helium, neon, methane, carbon dioxide and hydrogen. Approximately 60% of total emissions released by volcanoes is water vapor, and carbon dioxide accounts for 10 to 40% of emissions.
Explanation:
Answer:
Water vapor
Explanation:
The magma consists of dissolved gases when these gases produce the force the volcanic eruption takes place. The volcanic gases come out and their volume is increased tremendously. The gases present in the volcano are listed below:
The volcanic gases consist of water vapors, carbon dioxide, and sulfur.
These three are the primary gases but the water is present in a higher amount.
The percentage of water is 60%.
The carbon dioxide present in 10-40%.
Other gases present in volcanos are nitrogen, argon, helium, neon methane, and hydrogen.
Hope this helps, Let me know if I am wrong ( I am pretty sure that am not) but let me know anyway..., OH! and Good LUCK! :D ;P
Rashid lifts a flower pot 0.8m off the floor using a constant force of 20 N. How much work is done on the flower pot?
Answers
Answer:16 J
Explanation:
Work done = force × displacement
In this case the body has been displaced to a height
1 Water from a fire hose is directed toward a building as shown in the figure beiow The water leaves the hoso at a speed of v
i
=40.0 mis and at an angle of θ
j
=480
∘
above the horizortal. The base of the hose (at ground ievei) is a hocizontal distance d=490 m away from the bulding. Find the height h (in m) where the water strkes the building () the fime? Koomral the time, Iatial velosity, and acceieration, wiat is the verical dispacerfent? m
Answers
Given Data Speed of the water (v)=40 m/s Angle of inclination (θ)=48°Distance of the hose from the building (d)=490 m To find:
Height where the water strikes the building (h)Time when the water strikes the building (t)Vertical displacement of the water when it strikes the buildingFormula Used:Time of flight (t)=2usin(θ)/gwhere u=initial velocity of the projectile in the vertical direction (u=usin(θ))h=vertical displacement of the projectileu=initial velocity of the projectile in the vertical direction (u=usin(θ))v=u/cos(θ)Vertical displacement, h=u²sin²(θ)/2gLet the height where the water strikes the building be h and the time when the water strikes the building be t.So, the horizontal displacement of the water from the point of projection is d=490 m.At the highest point, the vertical component of the velocity of water is zero.So, v=usin(θ)u=v/sin(θ)=40/cos(48) m/s≈55.74 m/sUsing the above value of u and the value of θ, we can calculate the vertical displacement, h of the water when it strikes the building as below:
h=u²sin²(θ)/2g=(55.74)²(sin48°)²/(2×9.8)≈311.5 mTherefore, the height where the water strikes the building is approximately 311.5 m.The time taken by the water to hit the building can be calculated as:t=2usin(θ)/g=2(55.74)(sin48°)/9.8≈12.5 s.Therefore, the time when the water strikes the building is approximately 12.5 s.The vertical displacement of the water when it strikes the building can be calculated as below:
Vertical displacement of water=h=311.5 mTherefore, the vertical displacement of the water when it strikes the building is approximately 311.5 m.About WaterWater is a compound that is essential for all life forms known hitherto on Earth, but not on other planets. Its chemical formula is H₂O, each molecule containing one oxygen and two hydrogen atoms connected by covalent bonds. Water covers almost 71% of the Earth's surface.
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A beam of light hits a smooth interface between two transparent materials. The light in incident from substance with an index of refraction of 1.53. The other side of the interface has an index of refraction of 1.18. Find the critical angle (degrees) where there is total internal reflection.
Answers
The light is incident from the substance with an index of refraction of 1.53. The other side of the interface has an index of refraction of 1.18. the critical angle where there is total internal reflection is 49.5 degrees.
To find the critical angle where there is total internal reflection, we need to use Snell's law:
n1 sin(theta1) = n2 sin(theta2)
where n1 and n2 are the indices of refraction of the two materials and theta1 and theta2 are the angles of incidence and refraction, respectively.
At the critical angle, the angle of refraction will be 90 degrees, meaning the light will be reflected back into the first material. So we can set theta2 to 90 degrees and solve for theta1:
n1 sin(theta1) = n2 sin(90)
n1 sin(theta1) = n2
sin(theta1) = n2/n1
Plugging in the values for n1 and n2, we get:
theta1 = 49.5 degrees
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Please help mee.
A fisherman casts a lure toward the river at an angle of 25° above the horizontal. The lure reaches a maximum height of 2.9 m above where it was cast.
What is the initial velocity of the lure? Assume that the line exerts no appreciable drag force on the hook.
Answers
Answer:
17.84 m/s.
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 25°
Maximum height (H) reached = 2.9 m
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) =..?
Thus, we can obtain the initial velocity of the lure as follow:
H = u² sine² θ /2g
2.9 = u² × (sine 25)² / 2×9.8
2.9 = u² × (0.4226)²/19.6
Cross multiply
u² × (0.4226)² = 2.9 × 19.6
u² × (0.4226)² = 56.84
Divide both side by (0.4226)²
u² = 56.84/(0.4226)²
u² = 318.27
Take the square root of both side
u = √318.27
u = 17.84 m/s.
Therefore, the initial velocity of the lure is 17.84 m/s.
If the body's temperature is above 105 °F for a prolonged period, heat stroke
can result. Express this temperature on the Celsius scale.
OA 40.5°C
OB 58.3°C
OC 76.1°C
KOD 131.4°C
Answers
Answer:
A
Explanation:
C = (F-32)*5/9 = 73*5/9 = 40.55555
since the answers are spread apart, technically you can just estimate by doing -32
and then /2
since 5/9 is close to 1/2
A beaker of water is sitting on a sensitive spring scale. If you dip your finger into the water, but do not touch the side of the beaker, and the beaker does not overflow, what happens to the reading of the scale? (part of your finger is completely underwater. ) 1. It depends on just how much of your finger is submerged. Unless we are told, we can't answer. 2. The reading of the scale increases because of the extra pressure. 3. The reading of the scale remains precisely the same, of course. 4. It depends on how deep the water is. In some cases, the scale reading might increase, in other cases it might decrease. 5. The reading of the scale decreases
Answers
The reading of the scale will increase.
Our fingers push away the water in the cup which requires a lot of force. The scale should apply the same force to your finger. This force increases the reading on the scale. The scale display will rise. When a finger is submerged, the water exerts an upward buoyant force on the finger.
According to Newton's third law fingers exert equal and opposite forces on water. The spring scale reading decreases until the object is completely submerged. The reading, therefore, shows the apparent weight of the stone, which is less than its actual weight. Heavy metals are denser than water and will sink in water, so putting heavy metals in water will change the reading on the spring scale.
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three charged particles are placed at the corners of an equilateral triangle that has edge length 2.0 cmcm. one particle has charge 4.5 ncnc and a second has charge 9.0 ncnc.
Answers
The magnitude of the electric field at the position of the third particle is 2.52 x 10⁶ N/C, causing it to remain stationary.
How are charges distributed on an equilateral triangle?Assuming the third particle has a charge of 0, we can use Coulomb's law to find the magnitude of the electric field at the third particle's position due to the other two charges:
E = k * (q1 / r1² + q2 / r2²)
where k is the Coulomb constant, q1 and q2 are the charges of the first two particles, and r1 and r2 are the distances from the third particle to the first two particles.
Since the triangle is equilateral, the distances from the third particle to the first two particles are both 2.0 cm. Plugging in the values:
E = (8.99 x 10⁻⁹ N*m²/C²) * (4.5 x 10⁻⁹ C / (0.02 m)² + 9.0 x 10⁻⁹ C / (0.02 m)²)
E = 2.52 x 10⁶ N/C
So the magnitude of the electric field at the third particle's position is 2.52 x 10⁶ N/C. Since the third particle has a charge of 0, there is no force on it and it will remain stationary.
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