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Which of the following can be beaten into thin sheets?

A. Zinc

B. Phosphorus

C. Sulphur

D. Oxygen​

During hyperventilation, the pH of the blood increases (becomes more alkaline), while the carbon dioxide (CO2) level decreases. These changes are consistent with the prediction.

Hyperventilation refers to an increased rate and depth of breathing, leading to the removal of excess carbon dioxide from the body. As a result, the concentration of carbon dioxide in the blood decreases. Carbon dioxide reacts with water to form carbonic acid (H2CO3), which dissociates into bicarbonate ions (HCO3-) and hydrogen ions (H+). By reducing the carbon dioxide level, there is less production of H+ ions, resulting in an increase in blood pH, making it more alkaline.

The observed changes in pH and carbon dioxide levels during hyperventilation are consistent with the predicted response. Increased ventilation causes more carbon dioxide to be expelled from the body, shifting the equilibrium of the carbonic acid-bicarbonate buffer system. As a consequence, the pH of the blood rises, leading to alkalosis. These changes can be confirmed through blood gas analysis or other diagnostic tests.

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Among the following compounds, Sodium nitrate and CH₄ are neither an acid nor a base.

Sodium nitrate is an alkali metal salt which is made from the neutralization of a strong base (NaOH) with a strong acid (HNO₃). It has a pH value equal to 7. Therefore, sodium nitrate is neutral.

CH₄ has a neutral pH, of around 7. If a substance is acidic in nature, it must contain in the form where that can be released into water. But CH₄ is not acidic or basic as all the four hydrogen are bound tightly to the carbon atom and cannot be released, i.e., CH₄ has all of its valence electrons in bonding pair and bonding pairs are too stable to donate under normal conditions.

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Answer:

Double displacement reaction

Explanation:

Chemical equation:

H₃PO₄ + NaBr      →    HBr + Na₃PO₄

Balanced chemical equation:

H₃PO₄ + 3NaBr      →    3HBr + Na₃PO₄

Step one:

H₃PO₄ + NaBr      →    HBr + Na₃PO₄

On left side of equation                  On right side pf equation

H = 3                                                   H = 1

P =  1                                                    P = 1

O = 4                                                    O = 4

Na = 1                                                   Na = 3

Br = 1                                                     Br = 1

Step 2:

H₃PO₄ + NaBr      →    3HBr + Na₃PO₄

On left side of equation                  On right side pf equation

H = 3                                                   H = 3

P =  1                                                    P = 1

O = 4                                                    O = 4

Na = 1                                                   Na = 3

Br = 1                                                     Br = 3

Step 3:

H₃PO₄ + 3NaBr      →    3HBr + Na₃PO₄

On left side of equation                  On right side pf equation

H = 3                                                   H = 3

P =  1                                                    P = 1

O = 4                                                    O = 4

Na = 3                                                   Na = 3

Br = 3                                                     Br = 3

Type of chemical reaction:

The given reaction is double displacement reaction on which cation and anion of both reactants are replace with each other.

Based on the rate law, the equivalent expression to d[NO₂]/dt is -2k[O₃][NO₂]; option B.

A rate law gives a mathematical explanation of how variations in a substance's amount affect the rate of a chemical reaction.

To determine the equivalent expression to d[NO₂]/dt, differentiate the rate law with respect to [NO₂].

d/dt[k[O₃][NO₂]] = k[d[O₃]/dt][NO₂] + k[O₃][d[NO₂]/dt]

We assume d[O₃]/dt is a constant = k1 (since it is not given in the rate law)

The coefficient for NO₂ is -2,

Substituting in the equation above:

d[NO₂]/dt = (-2k/k1)[O₃][NO₂]

d[NO₂]/dt = -2k[O₃][NO₂]/k1

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Answer:Nucleic acid,glucose,and amino acids

Answer:

When the Tower formed around 50 million years ago, it was one to two miles below the Earth's surface. The harder igneous rock of the Tower is more resistant to erosion, and the gray columns of Devils Tower began to stand out above the surrounding landscape.

Explanation:

The inorganic substance with the chemical formula BaSO4 is barium sulfate (or sulphate). It is a tasteless, crystalline white substance that is insoluble in water.

A barium cation and a sulfate anion are the two elements that make up barium sulfate. There are four oxygen atoms joined to the sulfur. A sulfate salt of barium, known as BaSO4, is present in the mineral barite. It is a white crystalline substance that is soluble in strong acids but insoluble in water and alcohol.

Elements include both barium and bromine. Barium is a metal belonging to Group 2 of the modern periodic table, and bromine is a non-metal belonging to Group 17 (halogen).

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Being an acid, Sulfuric acid reacts with most bases to give its corresponding sulphate.

Sulfuric acid is a type of acid which is colorless oily liquid. Sulfuric acid is highly soluble in water and while dissolving it releases big amount of heat. Sulfuric acid is very acidic in nature that it will burn wood and most other organic matter on contact, but is unlikely to cause a fire. Density of this acid is 15 lb / gal.

Sulfuric acid is highly acidic in nature and due to this it is used in the cleaning of metals, removal of impurities from oil, manufacturing of chemicals.

Being an acid, sulfuric acid reacts with most of the bases to give its corresponding sulphate.

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The valproic acid contains 0.0645 milligrams

1000 microgram = 1 milligram

From the question given, the following data were obtained:

We can convert 64.5 micrograms to milligrams as illustrated below:

1000 microgram = 1 milligram

Therefore,

64.5 micrograms = (64.5 micrograms × 1 milligram) / 1000 microgram

64.5 micrograms = 0.0645 milligrams

Thus, the valproic acid contains 0.0645 milligrams

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Answer:

I believe it's copper

Explanation:

The reasoning being that Copper = 9.0 g/cm and the mystery item has 5.0 cm so 9*5 = 45 something like that

Explanation:

N2 has 7 electrons. There are two electrons in first shell and five electrons in second shell.

hope this helps you.

Answer:

Because its not a pure substance. It is a combination of pure substances.

Explanation:

Answer:

Hydrogen gas

Explanation:

During electrolysis of acidified water, H+ ions are reduced to H2 gas at the negative carbon electrode (cathode) and hence hydrogen gas is liberated at cathode.

Answer:

About 60 grams.  

Explanation:

The on point answer is 61.28 grams.

The molecule that contains 6 atoms comprising a single functional group is Hexanol, under the condition that the given molecule is that of an alcohol.

Its molecules contain 6 carbon atoms. The finishing -ol states an alcohol (the OH functional group), and the hex- stem presents  that there are six carbon atoms in the LCC. The OH group is assembled to the second carbon atom.
Functional groups are considered as specified groups of atoms within molecules that are the reason for characteristic chemical reactions of those molecules . Some examples of functional groups include alcohols, aldehydes, ketones, carboxylic acids, esters, ethers, halogens, amines and amides.
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The complete question
Name a molecule that contains 6 carbon atoms with a single functional group that is an alcohol

The percentage by mass of water in the hydrate \(CuSO^{4}.5H^{2}O\) is 47.6%.

The percentage composition of each of the following compounds are

1.a. NaClO:

The molar mass of NaClO =

22.99 g/mol + 35.45 g/mol + 15.99 g/mol = 74.43 g/mol

Percentage composition of Na =

(22.99 g/mol / 74.43 g/mol) *  100 \ percent \ = 30.9percent

Percentage composition of Cl =

(35.45 g/mol / 74.43 g/mol) *  100percent \ =  47.6percent

Percentage composition of O =

(15.99 g/mol / 74.43 g/mol) * 100percent \ =  21.5percent

Therefore, the percentage composition of NaClO is approximately:

30.9% Na, 47.6% Cl, and 21.5% O.

1.b. \(Al^{2}(SO^{3})^{3}\):

The molar mass of \(Al^{2}(SO^{3})^{3}\) = \(2 * (26.98 g/mol) + 3 * (32.06 g/mol + 3 * 16.00 g/mol) = 342.14 g/mol\)

Percentage composition of Al =

\((2 * 26.98 g/mol / 342.14 g/mol) * 100 \ = 3.99\)%

Percentage composition of S =

\((3 * 32.06 g/mol / 342.14 g/mol) * 100 \ = 8.99\)%

Percentage composition of O =

\((9 * 16.00 g/mol / 342.14 g/mol) * 100 \ = 10.47\)%

Therefore, the percentage composition of \(Al^{2}(SO^{3})^{3}\) is approximately:

3.99% Al, 8.99% S, and 10.47% O.

1.c. \(C^{2}H^{5}COOH\):

The molar mass of \(C^{2}H^{5}COOH\) = \(2 * (12.01 g/mol) + 6 * (1.01 g/mol) + 12.01 g/mol + 16.00 g/mol = 60.05 g/mol\)

Percentage composition of C =

\((2 * 12.01 g/mol / 60.05 g/mol) * 100 \ = 40.0\)%

Percentage composition of H =

\((6 * 1.01 g/mol / 60.05 g/mol) * 100\ \ = 10.1\)%

Percentage composition of O = \((2 * 16.00 g/mol + 12.01 g/mol / 60.05 g/mol) * 100 \ = 49.9\)%

Therefore, the percentage composition of \(C^{2}H^{5}COOH\) is approximately:

40.0% C, 10.1% H, and 49.9% O.

1.d. \(BeCl^2\):
The molar mass of \(BeCl^2\) = \(9.01 g/mol + 2 * 35.45 g/mol = 79.91 g/mol\)

Percentage composition of Be = \((9.01 g/mol / 79.91 g/mol) * 100 \ = 11.3\)%

Percentage composition of Cl =

\((2 * 35.45 g/mol / 79.91 g/mol)* 100 \ = 88.7\)%

Therefore, the percentage composition of \(BeCl^2\) is approximately:

11.3% Be and 88.7% Cl.

2. \(CuSO^{4}.5H^{2}O\):

Mass of CuSO4.5H2O = 8.40 g

Mass of anhydrous \(CuSO^{4}\) = mass of \(CuSO^{4}.5H^{2}O\) - mass of water

Mass of water = mass of \(CuSO^{4}.5H^{2}O\) - mass of anhydrous CuSO4

\(= 8.40 g - 4.40 g= 4.00 g\)

So, the mass of water in the hydrate is 4.00 g.

To determine the percentage by mass of water in the hydrate, we need to divide the mass of water by the mass of the entire compound (\(CuSO^{4}.5H^{2}O\)) and multiply by 100%:

Percentage by mass of water = (mass of water/mass of \(CuSO^{4}.5H^{2}O\)) x 100%

\(= (4.00 g/8.40 g) * 100= 47.6\)%

Therefore, the percentage by mass of water in the hydrate \(CuSO^{4}.5H^{2}O\) is 47.6%.

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Explanation:

here's the answer to your question

13.41 moles are present in 2.20 kg of sodium phosphate.

A mole is defined as 6.02214076 × \(10^{23}\)of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

The molar mass of sodium phosphate is 163.94 g/mol.

2.20 kg = 2200g

\(Moles = \frac{2200g}{163.94 g/mol.}\)

Moles = 13.41954374 = 13.41 moles

Hence, 13.41 moles are present in 2.20 kg of sodium phosphate.

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Answer:

10250.8

Explanation:

Formula

multiply the energy value by 4184

Answer:

B. K= 2 , L= 4

D. K= 2 , L= 8 , M= 1

E. K= 2, L= 8 , M= 8

G. K=2 , L= 8, M= 8, N= 7

Answer:

hope it helps.

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Answer:1 Answer. A chemical equation is balanced when the number of each kind of atom is the same on both sides of the reaction,,

Answer:

If each side of the equation has the same number of atoms of a given element, that element is balanced. If all elements are balanced, the equation is balanced.

Aldehydes and ketones are known for their sweet and sometimes pungent odors. Aldehydes usually gives pleseant smell than ketones.Thus, aldehyde is the organic compound you would rather smell.

Aldehyde have sharp and irritating odors. As the molecular weight increases the odors and becomes pleasant. Aldehydes contain a carbon-hydrogen bond that is easily broken, allowing them to evaporate quickly and produce a strong,sweet smell. Large molecular weight aldehyde are found often in perfumes formaldehyde have amell like dead fish which used for preservation of dead bishes. Ketones have sweet and pleasant odors. They contain a carbon-oxygen double bond that is more difficult to break, resulting in a weaker, less pleasant smell. The smaller ketones have but not strong odor acetone which generally used for fingernail like polish remover. We can say that aldehydes are more pungent than ketone.

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The balanced chemical equation between pottasium and chlorine is as follows: 2K + Cl₂ → 2KCl. It is a combination reaction.

A chemical reaction is a process, typically involving the breaking or making of interatomic bonds, in which one or more substances are changed into others.

According to this question, a chemical reaction occurs between potassium metal and chlorine gas to form pottasium chloride as follows:

2K + Cl₂ → 2KCl

The chemical reaction is a combination reaction because it involves the combination of two elements to form a compound.

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Answer:

Li

Explanation:

The statement is FALSE. Non-ferrous metals can be hardened by heat treatment, although the mechanisms and processes involved may differ from ferrous metals.

Heat treatment techniques such as precipitation hardening can be used to increase the strength of non-ferrous metals. Non-ferrous metals are metals or alloys that do not include iron (or iron allotropes, such as ferrite, etc.) in significant quantities. Non-ferrous metals are employed because they have desired qualities like reduced weight (for example, aluminium), greater conductivity (for example, copper), non-magnetic characteristics, or corrosion resistance (for example, zinc), even though they are often more expensive than ferrous metals. In the iron and steel sectors, several non-ferrous materials are also employed. Bauxite, for instance, is used as a flux in blast furnaces, whereas wolframite, pyrolusite, and chromite are utilised to create ferrous alloys.

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The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).

The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.

There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.

More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.

Thus, the correct option is E.

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The mass of 0.5 mole of the element is approximately 6.025 grams.

To calculate the mass of 0.5 mole of the element, we need to know the molar mass of the element.

Given that the mass of 2 x 10^21 atoms of the element is 0.4 grams, we can use this information to find the molar mass.

The number of atoms in 1 mole of any substance is given by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol.

First, we calculate the molar mass of the element using the given information:

Molar mass = Mass of 2 x 10^21 atoms / Number of moles of 2 x 10^21 atoms

Molar mass = 0.4 g / (2 x 10^21 atoms / (6.022 x 10^23 atoms/mol))

Molar mass ≈ 0.4 g / (3.32 x 10^-2 mol)

Molar mass ≈ 12.05 g/mol

Now that we know the molar mass of the element is approximately 12.05 g/mol, we can calculate the mass of 0.5 mole of the element:

Mass = Molar mass x Number of moles

Mass = 12.05 g/mol x 0.5 mol

Mass = 6.025 grams

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