_________would result in a shift the hemoglobin-oxygen dissociation curve to the right. Select the correct statement(s) to fill in the blank. a. An increase in PCO2 b. An increase in temperature c. An increase in pH d. (a) and (b) are correct; (c) is incorrect e. (a), (b), and (c) are all correct

Answer:

weight of hydrogen÷eq weight of hydrogen=weight of metal÷equivalent weight of metal

yo formula lagayera nikalne

yesma pressure ko kei kaam hunna

Answer:

Hii,kusha

ek problem hó rahi hai mujhe

Answer: ferrous salts

Explanation:

done

The precipitate that forms when aqueous solutions of barium nitrate and sodium sulfate are mixed is barium sulphate.

Barium Nitrate is a colorless to white, odorless, crystalline powder. It is used in making fireworks, for green lights and neon lights, and in ceramic glazes.

Sodium Sulfate Anhydrous is the anhydrous, sodium salt form of sulfuric acid. Sodium ion is the principal cation of the extracellular fluid and plays a large part in the therapy of fluid and electrolyte disturbances.

When aqueous solutions of barium nitrate and sodium sulfate are mixed is barium sulphate, one soluble salt, sodium nitrate, and an insoluble salt, barium sulphate.

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A combination of acid and amine which have similar molecular masses would be used for the reaction.

When two substances which are capable of diffusion are placed at extreme ends of a sealed tube, each of them will diffuse towards the opposite end of the tube.

If the 2 substances which are capable of reacting to form a white ring like in the case of the acid and the amine, the point at which the white ring will form would depend on the rate of diffusion of each substance.

According to Graham's law of diffusion, "the rate of diffusion of substances is inversely proportional to the square root of their molecular masses".

Thus, when 2 substances (gases) with similar molecular masses are left to diffuse in the opposing ends of a sealed tube they will diffuse to meet around the halfway point between the two ends of the tube where they can react to form a white ring.

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Answer:

False, 17.03*10 = 170.3g not 17

Answer:

A lunar phase is simply the shape of the sunlit part of the Moon, as seen from Earth. Phases are so strikingly obvious that we almost take them for granted. Moreover, they can be observed easily throughout the month from the backyard or via a simple glance out the window.

The Moon's shape changes for the following reasons:

The Moon orbits Earth.

Both Earth and the Moon orbit the Sun.

The Moon's orbit is the same length as the time it spins on its axis (about 28 Earth days), which means that we see the same part of the lunar surface all month.

The Sun illuminates both Earth and the Moon.

Get to Know the Lunar Phases

There are eight phases of the Moon to track each month.

New Moon: During New Moon, the side of the Moon facing us is not illuminated by the Sun. At this time, the Moon is not up at night, but it is up during the day. We just can't see it. Solar eclipses can occur during the New Moon, depending on how the Sun, Earth, and Moon line up in their orbits.

Waxing Crescent: As the Moon waxes (grows) into its crescent phase, it begins to show up low in the sky right after sunset. Look for a silvery-looking crescent. The side facing the sunset direction will be lit up.

First Quarter: Seven days after New Moon, the Moon is in first quarter. Only half of it is visible for the first half of the evening, and then it sets.

Waxing Gibbous: After First Quarter, the Moon appears to grow into a gibbous shape. Most of it is visible, except for a dark sliver that shrinks over the next seven nights. Look for the Moon at this time during the afternoon, too.

Full Moon: During the Full Moon, the Sun lights up the entire surface of the Moon that faces Earth. It rises just as the Sun sets and disappears beneath the western horizon when the Sun rises the next morning. This is the brightest phase of the Moon and it washes out the nearby part of the sky, making it difficult to see stars and faint objects such as nebulae.

Ever hear of a Super Moon? That's a Full Moon that happens when the Moon is closest in its orbit to Earth. The press likes to make a big deal about this, but it's really a very natural thing: On occasion, the Moon's orbit brings it closer to Earth. Not every month has a Super Moon. Despite the hype about Super Moons in the media, it's difficult for the average observer to notice one, because the Moon might appear only slightly larger in the sky than normal. In fact, the well-known astronomer Neil deGrasse Tyson pointed out that the difference between a regular Full Moon and a Super Moon is analogous to the difference between a 16-inch pizza and a 16.1-inch pizza.

Lunar eclipses occur only at Full Moons because the Moon is passing directly between Earth and the Sun in its orbit. Due to other perturbations in its orbit, not every Full Moon results in an eclipse.

The other Full Moon variation that often grabs media attention is a "Blue Moon." That's the name given to the second Full Moon that occurs in the same month. These don't happen all the time, and the Moon certainly doesn't appear blue. Full Moons also have colloquial names based on folklore. It's worth reading about some of these names; they tell fascinating stories about early cultures.

Waning Gibbous: After the glorious appearance of Full Moon, the lunar shape starts to wane, meaning it gets smaller. It's visible later at night and into the early morning, and we see a steadily shrinking shape of the lunar surface that's being lit up. The side that is lit up is facing toward the Sun, in this case, the sunrise direction. During this phase, look for the Moon during the day—it should be in the sky in the morning.

Last Quarter: At Last Quarter, we see exactly half the sunlit surface of the Moon. It can be seen in the early morning and daytime sky.

Waning Crescent: The last phase of the Moon before returning to New Moon is called Waning Crescent, and it is exactly what it says: a steadily-shrinking crescent phase. We can see only a small sliver from Earth. It's visible in the early morning, and by the end of the 28-day lunar cycle, it has vanished almost entirely. That brings us back to New Moon to start the new cycle.

Citation for work-Petersen, Carolyn Collins. "The Once-Mysterious Phases of the Moon Explained." ThoughtCo, Aug. 27, 2020, thoughtco.com/what-are-moon-phases-3883581.

Explanation:  

Something shorter-The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon. Each phase repeats itself every 29.5 days. The same half of the Moon always faces the Earth, because of tidal locking. So the phases will always occur over the same half of the Moon's surface.

Answer:

A

Explanation:

1) List known data.

Moles of sugar: 0.500

Mass of water: 0.750 kg

2) List unknown data.

Boiling point elevation:

3) Set the equation for boiling point elevation

ΔT: change in temperature

Kb: Ebulloscopic constant (0.512 ºC/molal).

m: molality.

4) Molality of the solution

5) Plug in values in the equation

The change in the boiling point is 0.341ºC.

Answer:

D. Ruler

Explanation:

Use the formula to find the volume of a cuboid by measuring the length, width, and height and multiplying all of them by each other.

Intracellular Na+ and K+ concentrations were estimated, but the exact ratio of gNa to gK and the stabilized membrane potential upon increased K+ permeability determined .

a. To estimate the intracellular Na+ and K+ concentrations, we can use the Goldman-Hodgkin-Katz equation, which describes the resting membrane potential based on the relative permeabilities and concentrations of ions. The equation is as follows:

V = (RT/zF) * ln((PNa[Na+]o + PK[K+]o + PCl[Cl-]i)/(PNa[Na+]i + PK[K+]i + PCl[Cl-]o))

Where:

V = Membrane potential

R = Gas constant (8.314 J/(mol·K))

T = Temperature in Kelvin (37°C = 310 K)

z = Valence of the ion (+1 for Na+ and K+)

F = Faraday's constant (96,485 C/mol)

P = Permeability of the ion

[ ]o = Extracellular concentration

[ ]i = Intracellular concentration

We have the following information:

V = -46 mV

[Na+]o = 145 mM

[K+]o = 5.6 mM

[Na+]i = ?

[K+]i = ?

Plugging in the values, we can rearrange the equation to solve for [Na+]i:

ln((PNa[Na+]o + PK[K+]o)/(PNa[Na+]i + PK[K+]i)) = (V * z * F) / (RT)

Now, let's assume that the membrane is impermeable to Cl-. This means that PCl = 0, and we can simplify the equation further:

ln((PNa[Na+]o)/(PNa[Na+]i)) = (V * z * F) / (RT)

Since we're given the resting potential with Na+ replaced by an impermeant ion, the equation becomes:

ln([Na+]o/[Na+]i) = ((-60 mV - (-46 mV)) * z * F) / (RT)

Solving for [Na+]i:

[Na+]i = [Na+]o * e^(((-60 mV - (-46 mV)) * z * F) / (RT))

Given that ENa (equilibrium potential for Na+) is +35 mV, we know that ENa = (RT/zF) * ln([Na+]o/[Na+]i). We can rearrange this equation to solve for [Na+]i:

[Na+]i = [Na+]o * e^((ENa * z * F) / (RT))

Substituting the values, we have:

[Na+]i = 145 mM * e^((35 mV * 1 * 96,485 C/mol) / (8.314 J/(mol·K) * 310 K))

Calculating this expression gives us the estimated intracellular Na+ concentration.

Similarly, we can estimate the intracellular K+ concentration using the same equation but substituting the values for K+.

b. The ratio of gNa to gK that accounts for the normal resting potential can be calculated using the Goldman equation. The Goldman equation is an extension of the Goldman-Hodgkin-Katz equation and takes into account the conductances of the ions. It is given by:

V = (RT/F) * ln((gNa[Na+]o + gK[K+]o + gCl[Cl-]i)/(gNa[Na+]i + gK[K+]i + gCl[Cl-]o))

Since we are interested in the normal resting potential, we can use the values from part a:

V = -46 mV

[Na+]o = 145 mM

[K+]o = 5.6 mM

[Na+]i =

Estimated intracellular Na+ concentration from part a

[K+]i = Estimated intracellular K+ concentration from part a

We need to find the ratio gNa/gK. However, we can assume that the membrane is impermeable to Cl- (gCl = 0) and ignore Na+ efflux in the Na-free saline condition. This simplifies the equation:

ln((gNa[Na+]o)/(gNa[Na+]i)) = (V * F) / (RT)

Assuming gNa and gK are constants, we can rewrite the equation:

gNa/gK = ([Na+]i/[Na+]o) * e^((V * F) / (RT))

Substituting the values, we can calculate the ratio gNa/gK.

c. In the normal saline condition, if the cell suddenly becomes more permeable to K+, the membrane potential would tend to shift toward the equilibrium potential of potassium (EK). The equilibrium potential for an ion is given by the Nernst equation:

EK = (RT/zF) * ln([K+]o/[K+]i)

Assuming the membrane becomes more permeable to K+, we can approximate the membrane potential using the Goldman-Hodgkin-Katz equation:

V = (RT/F) * ln((gNa[Na+]o + gK[K+]o + gCl[Cl-]i)/(gNa[Na+]i + gK[K+]i + gCl[Cl-]o))

When the membrane becomes more permeable to K+, the gK term in the denominator would increase. As a result, the value inside the logarithm would decrease, causing the membrane potential to become more negative. It would stabilize when the membrane potential reaches the equilibrium potential for potassium (EK).

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The complete question is:

Electrical activity of an approximately spherical neuron in culture was recorded with intracellular electrodes. The experiments were carried out at 37°C. The normal saline bathing the cell contained 145 mM Na+ and 5.6 mM K+. In this normal saline the resting potential was measured to be -46 mV, but if the Na+ was replaced with an impermeant ion (i.e. the cell was bathed in a Na-free solution) the resting potential changed to -60 mV. You may assume that in normal saline the ENa was +35 mV, that the membrane is impermeable to Cl-, that Ca++ is not directly involved, and to simplify the issue you can ignore Na+ efflux in the Na-free saline condition.

a. Estimate the intracellular Na+ and K+ concentrations

. b. What ratio of gNa to gK would account for the normal resting potential?

c. In the normal saline condition, if you suddenly made the cell more permeable to K+, what would happen to cell’s membrane potential? At what value would it stabilize?

However, I can provide a written reaction scheme and mechanism for the reactions involved.  

Reaction scheme:

Synthesis of Benzimidazole:

O-phenylenediamine + formic acid → benzimidazole + water

Formation of C14H12N2:

Benzimidazole + nBuLi → intermediate A

Intermediate A + PhCH2Br → C14H12N2 + LiBr

Mechanism:

Synthesis of Benzimidazole:

The reaction between O-phenylenediamine and formic acid is an acid-catalyzed condensation reaction, which proceeds through a series of proton transfers and dehydration steps to yield benzimidazole and water.

Formation of C14H12N2:

The first step involves the deprotonation of the imidazole ring in benzimidazole by nBuLi to generate an intermediate A. The intermediate A is then attacked by the benzyl bromide at the benzylic carbon, which leads to the formation of a new carbon-carbon bond and elimination of the lithium bromide (LiBr) leaving group. The final product is C14H12N2.

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The percent by mass of acetic acid in the vinegar is 2.33%.

Below are the steps to solve the given problem using the data table given below:

Step 1: Calculate the mass of the vinegar. Given,Mass of flask and vinegar solution- 25.17gMass of flask- 15.12gMass of vinegar solution = Mass of flask and vinegar solution - Mass of flask= 25.17 g - 15.12 g= 10.05 g

Step 2: Calculate the moles of NaOH used in the titration.Molarity of NaOH solution is 0.1 M.Moles of NaOH = Molarity × Volume of NaOH usedMoles of NaOH = 0.1 M × 39.00 mL (since the initial volume of NaOH is 0.00 mL)Moles of NaOH = 0.0039 moles

Step 3: Determine the moles of acetic acid used in the reaction.The balanced chemical equation for the reaction between NaOH and acetic acid (the main component of vinegar) is given below:CH3COOH + NaOH → CH3COONa + H2OMoles of NaOH = Moles of CH3COOH (since they react in a 1:1 ratio)Moles of CH3COOH = 0.0039 moles

Step 4: Calculate the mass of acetic acid used in the reaction.Molar mass of acetic acid is 60.05 g/mol.Mass of CH3COOH = Moles of CH3COOH × Molar mass of CH3COOH= 0.0039 moles × 60.05 g/mol= 0.234 gStep 5: Calculate the percent by mass of acetic acid in the vinegar.Percent by mass of acetic acid = (Mass of CH3COOH / Mass of vinegar solution) × 100%= (0.234 g / 10.05 g) × 100%= 2.33%.

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answer is: O

o goes from 0 to -2, so it is the element that is reduced

hope this helps! ;)

Answer:

I'd say Mg.

Explanation:

The reducing agent is the agent that is oxidized (losses electrons).

The oxidizing agent is the agent that is reduced (gains electrons).

For the mentioned reaction:

2Mg + O2→ 2MgO.

Mg (oxid. no. = 0) is converted to MgO (oxid. no. of Mg = +2), which means that Mg losses 2 electrons and is oxidized.

So, the reducing agent is Mg.

Answer:

p=F/A.Explanation:

"To insure proper operation of an oxygen cylinder regulator, make sure no oil residue is present" is true because oil residue can compromise the functioning of an oxygen cylinder regulator.

Explanation: It is true that to ensure proper operation of an oxygen cylinder regulator, it is important to make sure that no oil residue is present. Oxygen cylinders contain highly concentrated oxygen that can react violently with oil or grease, leading to combustion or explosions. Oil residue can contaminate the regulator and pose a significant safety risk.

Therefore, it is crucial to keep oxygen cylinders and their regulators free from any oil or grease to maintain safe and proper functioning.

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Answer:

the answer is decaying wood

Answer:

The pressure on the shower side of the curtain will be lower than the pressure on the outside at the same height from the floor, causing the curtain to move toward the lower pressure. The problem with this explanation is that the curtain will suck inward toward a cold shower, too.

Answer:

What are the options

Explanation:

Tell me

The final product of the e1 reactions and fractional distillation lab exercise was a liquid at room temperature. let us say that you wanted to purify that product via recrystallization at room temperature. No, because a recrystallization requires that a compound forms solid crystals and the product is a liquid.

A solid must first be dissolved into a solution, after which it must be left to crystallize gradually. This results in compounds with a high level of purity, which is demonstrated by the existence of uniform crystals. Recrystallization is a tricky process to do properly.

The solvent should be non-volatile, non-flammable, and non-carcinogenic. 50 to 120°C should be the boiling point of the solvent. Impurities ought to be soluble in the cold solvent or insoluble in the hot solvent, respectively. The compound and solvent must not interact in any way.

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Answer:

2.91 moles NH₃

Explanation:

To find the answer, you need to use Avogadro's number to convert between molecules and moles. It is important to arrange the ratio/conversion in a way that allows for the cancellation of units. The final answer should have 3 sig figs because the given value (1.75) also has 3 sig figs.

Avogadro's Number:

6.022 x 10²³ molecules = 1 mole

1.75 x 10²⁴ molecules NH₃                      1 mole
--------------------------------------  x  ------------------------------------  = 2.91 moles NH₃
                                                  6.022 x 10²³ molecules

It's possible that the student made an error during the experiment, such as not measuring the volume of water correctly or making a mistake in the calculation. It's also possible that there were external factors that affected the measurement, such as the temperature of the water, the equipment used, or the presence of impurities in the water.

What is Density?

Density is a physical property of matter that describes how much mass is contained in a given volume of a substance. It is calculated by dividing the mass of an object by its volume, and is typically expressed in units such as grams per cubic centimeter (g/cm³) or kilograms per cubic meter (kg/m³).

In simpler terms, density is a measure of how closely packed the atoms or molecules are within a substance. Substances with a higher density have more mass per unit volume, while substances with a lower density have less mass per unit volume. For example, lead is a dense material with a density of about 11.3 g/cm³, while air is much less dense with a density of about 0.0012 g/cm³ at room temperature and atmospheric pressure.

To determine the cause of the discrepancy, the student could repeat the experiment multiple times to see if the results are consistent, use different methods or equipment to measure the density of water, or compare the results with other published values to see if they are within an acceptable range. It's important for the student to identify and correct any sources of error to ensure the accuracy of their results.

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Answer:

nonvenomous

Explanation:

Answer:

Around a quarter of all snake species are identified as being venomous. Most are harmless, but others have potent venom and at least five species, including the boomslang (Dispholidus typus), have caused human fatalities.

Explanation:this what go ogle has to say

Answer:

Chemistry is the scientific discipline involved with elements and compounds composed of atoms, molecules and ions: their composition, structure, properties, behavior and the changes they undergo during a reaction with other substances.

n the scope of its subject, chemistry occupies an intermediate position between physics and biology.[5] It is sometimes called the central science because it provides a foundation for understanding both basic and applied scientific disciplines at a fundamental level.[6] For example, chemistry explains aspects of plant chemistry (botany), the formation of igneous rocks (geology), how atmospheric ozone is formed and how environmental pollutants are degraded (ecology), the properties of the soil on the moon (cosmochemistry), how medications work (pharmacology), and how to collect DNA evidence at a crime scene (forensics).

Chemistry addresses topics such as how atoms and molecules interact via chemical bonds to form new chemical compounds. There are two types of chemical bonds: 1. Primary Chemical bonds e.g covalent bonds, in which atoms share one or more electron(s); ionic bonds, in which an atom donates one or more electrons to another atom to produce ions (cations and anions); Metallic bonds and 2. Secondary chemical bonds e.g. hydrogen bonds;Van der Waals force bonds, ion-ion interaction, ion-dipole interaction etc.

Explanation:

need thanks and make me brainiest if it helps you

Answer:

3s^1 would be 3s^2

Explanation:

The combustion reaction is the process by which a chemical substance or hydrocarbon reacts with oxygen to produce carbon dioxide and water while also releasing energy in the form of light and heat.

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No idea what this is for, but I hope you have an amazing day:)

The width of the window is 11.984 f t.

A Norman window is constructed by adjoining a semicircle to the top of an ordinary rectangular window.

Let the width of the window be xft.

Hence the window here is norman window

So The diameter of semicircle too is xft.

Hence the formula used here will be;

x²  ₓ   (1+ \(\frac{\pi }{8}\))

As the question indicated that the the total area of the square and the semicircle is to be 200 f t 2 .

So

(1+ \(\frac{\pi }{8}\))  x² = 200

Now separate the x from formula

x =  \(\sqrt{200/ 1+ \pi /8}\)

x=  \(\sqrt{200/ 1+ \pi /8}\)

Now take the LCM of \(\frac{\pi }{8}\) as follows

x=  \(\sqrt{1600/ 8+\pi }\)

Now put the value of \(\pi\) which is 3.14

x=  \(\sqrt{1600/ 8 +3.14}\)

Now add 8+ 3.14

x=  \(\sqrt{1600/ 11.14159}\)

Now divide the values as follows

x=   \(\sqrt{143.6}\)

Take the square root of 143.6

x=  11.984

So the answer is 11.984 f t

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Answer:

true

Explanation:

70.6 litres of bromine trifluoride is required to produce 106 liters of fluorine gas according to the following reaction provided that all gases are at the same temperature and pressure.

Since, 2BrF3 (g) gives Br2 (g) + 3 F2 (g)

Here 2 mole BrF3 produces 3 mole F2

If volume produced of F2 is 106 litres

Therefore, volume of BrF3 =?

Since, v1 is directly proportional to n1

Therefore, v1/n1 = v2/n2

v1/2moles = 106 litres/3 moles

v1= 212/3 = 70.6 litres

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